Combo problem
by soryn, Apr 22, 2025, 6:33 AM
The school A has m1 boys and m2 girls, and ,the school B has n1 boys and n2 girls. Each school is represented by one team formed by p students,boys and girls. If f(k) is the number of cases for which,the twice schools has,togheter k girls, fund f(k) and the valute of k, for which f(k) is maximum.
Combo with cyclic sums
by oVlad, Apr 21, 2025, 1:41 PM
In
of the vertices of the regular polygon
we write the number
and in the remaining ones we write the number
Let
be the number written on the vertex
A vertex is good if
for any integers
and
such that
Note that the indices are taken modulo
Determine the greatest possible value of
such that, regardless of numbering, there always exists a good vertex.






![\[x_i+x_{i+1}+\cdots+x_j>0\quad\text{and}\quad x_i+x_{i-1}+\cdots+x_k>0,\]](http://latex.artofproblemsolving.com/b/f/4/bf4cf984af7f310c1eb90b6b37126bfca9181305.png)





Two very hard parallel
by jayme, Apr 21, 2025, 12:46 PM
Dear Mathlinkers,
1. ABC a triangle
2. D, E two point on the segment BC so that BD = DE= EC
3. M, N the midpoint of ED, AE
4. H the orthocenter of the acutangle triangle ADE
5. 1, 2 the circumcircle of the triangle DHM, EHN
6. P, Q the second point of intersection of 1 and BM, 2 and CN
7. U, V the second points of intersection of 2 and MN, PQ.
Prove : UV is parallel to PM.
Sincerely
Jean-Louis
1. ABC a triangle
2. D, E two point on the segment BC so that BD = DE= EC
3. M, N the midpoint of ED, AE
4. H the orthocenter of the acutangle triangle ADE
5. 1, 2 the circumcircle of the triangle DHM, EHN
6. P, Q the second point of intersection of 1 and BM, 2 and CN
7. U, V the second points of intersection of 2 and MN, PQ.
Prove : UV is parallel to PM.
Sincerely
Jean-Louis
Number theory
by XAN4, Apr 20, 2025, 9:44 AM
Prove that there exists infinitely many positive integers
such that
and
.



FE solution too simple?
by Yiyj1, Apr 9, 2025, 3:26 AM
Find all functions
such that the equality
holds for all pairs of real numbers
.
My solution
I feel like my solution is too simple. Is there something I did wrong or something I missed?



My solution
Clearly,
is an obvious solution. Now, let
. Then, we have
or
. Therefore, the solutions are
.





I feel like my solution is too simple. Is there something I did wrong or something I missed?
Stronger inequality than an old result
by KhuongTrang, Aug 1, 2024, 3:13 PM
Problem. Find the best constant
satisfying
holds for all 

![$$(ab+bc+ca)\left[\frac{1}{(a+b)^{2}}+\frac{1}{(b+c)^{2}}+\frac{1}{(c+a)^{2}}\right]\ge \frac{9}{4}+k\cdot\frac{a(a-b)(a-c)+b(b-a)(b-c)+c(c-a)(c-b)}{(a+b+c)^{3}}$$](http://latex.artofproblemsolving.com/f/6/e/f6ed10f7fff1cc94edd8f451e75718a0916a8bfa.png)

This post has been edited 2 times. Last edited by KhuongTrang, Aug 2, 2024, 6:43 AM
R+ FE with arbitrary constant
by CyclicISLscelesTrapezoid, Jul 5, 2023, 7:22 PM
Let
be a given positive real and
be the set of all positive reals. Find all functions
such that ![\[f((c+1)x+f(y))=f(x+2y)+2cx \quad \textrm{for all } x,y \in \mathbb{R}_{>0}.\]](//latex.artofproblemsolving.com/b/0/6/b069e7b7ec1e277f4a4ce85a99434fdb54eb02f3.png)



![\[f((c+1)x+f(y))=f(x+2y)+2cx \quad \textrm{for all } x,y \in \mathbb{R}_{>0}.\]](http://latex.artofproblemsolving.com/b/0/6/b069e7b7ec1e277f4a4ce85a99434fdb54eb02f3.png)
This post has been edited 2 times. Last edited by CyclicISLscelesTrapezoid, Jul 5, 2023, 7:24 PM
Inequality with n-gon sides
by mihaig, Feb 25, 2022, 6:46 AM
If
are are the lengths of the sides of a
gon such that
then
![$$(n-2)\left[\sum_{i=1}^{n}{\frac{a_i^2}{(1-a_i)^2}}-\frac n{(n-1)^2}\right]\geq(2n-1)\left(\sum_{i=1}^{n}{\frac{a_i}{1-a_i}}-\frac n{n-1}\right)^2.$$](//latex.artofproblemsolving.com/9/3/e/93e5529518807b92cd9e0382f5fb07a293128b04.png)
When do we have equality?
(V. Cîrtoaje and L. Giugiuc, 2021)



![$$(n-2)\left[\sum_{i=1}^{n}{\frac{a_i^2}{(1-a_i)^2}}-\frac n{(n-1)^2}\right]\geq(2n-1)\left(\sum_{i=1}^{n}{\frac{a_i}{1-a_i}}-\frac n{n-1}\right)^2.$$](http://latex.artofproblemsolving.com/9/3/e/93e5529518807b92cd9e0382f5fb07a293128b04.png)
When do we have equality?
(V. Cîrtoaje and L. Giugiuc, 2021)
Incircle of a triangle is tangent to (ABC)
by amar_04, Mar 2, 2021, 3:36 AM
Let
be a scalene triangle,
be the median through
, and
be the incircle. Let
touch
at point
and segment
meet
for the second time at point
. Let
be the triangle formed by lines
and
and the tangent to
at
. Prove that the incircle of triangle
is tangent to the circumcircle of triangle
.

















"Where wisdom and valor fail, all that remains is faith. . . And it can overcome all." -Toa Mata Tahu
Archives





































































Shouts
Submit
536 shouts
Tags
About Owner
- Posts: 3075
- Joined: Dec 24, 2011
Blog Stats
- Blog created: Jan 14, 2012
- Total entries: 600
- Total visits: 1581981
- Total comments: 771
Search Blog