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Contests & Programs AMC and other contests, summer programs, etc.
AMC and other contests, summer programs, etc.
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Contests & Programs AMC and other contests, summer programs, etc.
AMC and other contests, summer programs, etc.
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jmo cutoff
cakeiswaybetterthancookie   37
N 16 minutes ago by studymoremath
Source: me
You guys NEED to stop freaking out about JMO cutoffs Its likely going to be in the early-mid 210's assuming an average level aime( 2021 aime?) So if you have a 110+ on the amc 10, you are in contention for USAJMO- its not LIKELY but its possible. My guess is maybe 15ish percent? really, too many people are freaking out about cutoffs- at the end of the day, most of you have next year and the year after that and can always keep improving. You got this!
37 replies
cakeiswaybetterthancookie
Today at 1:10 AM
studymoremath
16 minutes ago
9 When To Start Grinding Math Again
Existing_Human1   142
N 17 minutes ago by MathNerdRabbit103
For context, I got a 103.5 on AMC 10B, so I am not sure if I made AIME. I have AMC 8 and Mathcoutns coming up as competitions
142 replies
Existing_Human1
Nov 23, 2024
MathNerdRabbit103
17 minutes ago
how to prep for AIME
CharviA   4
N 25 minutes ago by orangebear
I'm in 8th grade and I got a 129 on the 10b. For the record I got rly lucky because I guessed e for the last two questions since there were practically no e's on the sheet and there was a lot of combinatorics, which ,fortunately, im relatively good at. This is my first time qualifying for aime and I am currently mocking 3-5. How should I prepare for aime to get at least an 8? thanks
4 replies
CharviA
an hour ago
orangebear
25 minutes ago
No more topics!
Problem 2
evt917   50
N Nov 17, 2024 by sadas123
Source: 2024 AMC 12B #2 / AMC 10B #2
What is $10! - 7! \cdot 6!$?

$
\textbf{(A) }-120 \qquad
\textbf{(B) }0 \qquad
\textbf{(C) }120 \qquad
\textbf{(D) }600 \qquad
\textbf{(E) }720 \qquad
$
50 replies
evt917
Nov 13, 2024
sadas123
Nov 17, 2024
Problem 2
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Source: 2024 AMC 12B #2 / AMC 10B #2
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froliop
58 posts
#37
Y by
Jack_w wrote:
Divisible by $6!$ so $\textbf{(E) }720$

LMAOO
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AbhayAttarde01
1154 posts
#38
Y by
Jack_w wrote:
Divisible by $6!$ so $\textbf{(E) }720$

no bro why :sob:
its $3628800-5040*720$
which is $3628800-3628800$
which is $\boxed{\textbf{(B) }0}$
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blueberryfaygo_55
338 posts
#39
Y by
Reducing modulo $7$ kills
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pingpongmerrily
2543 posts
#40
Y by
AbhayAttarde01 wrote:
Jack_w wrote:
Divisible by $6!$ so $\textbf{(E) }720$

no bro why :sob:
its $3628800-5040*720$
which is $3628800-3628800$
which is $\boxed{\textbf{(B) }0}$

bro why are you bashing :skull:
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GAMER100
2107 posts
#41
Y by
GAMER100 wrote:
andrewcheng wrote:
Jack_w wrote:
Divisible by $6!$ so $\textbf{(E) }720$

you poor poor fool

Stop bullying him, guys. We all make mistakes. In fact, this is a good way to narrow down the answers, he only missed that $0$ was also divisible by $6!$.

In fact, $0$ is the only one divisible by $7!$, so he was pretty close to a really quick clever answer!
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AbhayAttarde01
1154 posts
#42
Y by
pingpongmerrily wrote:
AbhayAttarde01 wrote:
Jack_w wrote:
Divisible by $6!$ so $\textbf{(E) }720$

no bro why :sob:
its $3628800-5040*720$
which is $3628800-3628800$
which is $\boxed{\textbf{(B) }0}$

bro why are you bashing :skull:

I didn't do the AMC 10 unfortunately (I'm in 9th but I didn't complete precalc bc I'm on algebra 2) so I decided to bash becase
no time limit!
its very freeing
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ethanzhang1001
980 posts
#43
Y by
AbhayAttarde01 wrote:
I didn't do the AMC 10 unfortunately (I'm in 9th but I didn't complete precalc bc I'm on algebra 2)
its very freeing

ok what why you can still take it it's only algebra and geometry
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Alex_Yang
373 posts
#44
Y by
Jack_w wrote:
Divisible by $6!$ so $\textbf{(E) }720$

Erm acc it should be divis by $7!$ so $0$
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Yiyj1
1005 posts
#45
Y by
just memorize that $10!=6!\cdot7!$ stop trying to do all those mod tricks or whatnot just memorize it at least that's what i did

saved me a few seconds so i could solve number 25 just in time :cool:
This post has been edited 1 time. Last edited by Yiyj1, Nov 16, 2024, 6:26 AM
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youngjin
190 posts
#46
Y by
unironically one of the nicest problems on the test
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AbhayAttarde01
1154 posts
#47
Y by
ethanzhang1001 wrote:
AbhayAttarde01 wrote:
I didn't do the AMC 10 unfortunately (I'm in 9th but I didn't complete precalc bc I'm on algebra 2)
its very freeing

ok what why you can still take it it's only algebra and geometry

I haven't completed algebra 2 yet that's why
I finish algebra 2 in like the end of January (yes in half a school year I have to complete it
This post has been edited 1 time. Last edited by AbhayAttarde01, Nov 16, 2024, 2:55 PM
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MC_ADe
135 posts
#48 • 3 Y
Y by AbhayAttarde01, evt917, giratina3
I can confirm E due to engineers induction
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jb2015007
675 posts
#49
Y by
i just bashed it out in fear of sillying it
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Catcumber
104 posts
#50 • 2 Y
Y by forestcaller2010, AbhayAttarde01
Jack_w wrote:
Divisible by $6!$ so $\textbf{(E) }720$

Divisible by 1 so $\textbf{(A) }-120$
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sadas123
139 posts
#51
Y by
evt917 wrote:
What is $10! - 7! \cdot 6!$?

$
\textbf{(A) }-120 \qquad
\textbf{(B) }0 \qquad
\textbf{(C) }120 \qquad
\textbf{(D) }600 \qquad
\textbf{(E) }720 \qquad
$
I got 0 because if you do 10!-7!x6! you just get that 8x9x10-6! which simplifies to 720-720 which gets you the answer of "0" This was like number 1 on AMC 10 b
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