https://artofproblemsolving.com/wiki/api.php?action=feedcontributions&user=Nparkamc8&feedformat=atomAoPS Wiki - User contributions [en]2024-03-29T05:06:21ZUser contributionsMediaWiki 1.31.1https://artofproblemsolving.com/wiki/index.php?title=2012_AMC_8_Problems/Problem_1&diff=1382432012 AMC 8 Problems/Problem 12020-11-23T20:17:59Z<p>Nparkamc8: /* Problem */</p>
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<div>==Problem==<br />
Rachelle uses 3 pounds of meat to make 8 hamburgers for her family. How many pounds of meat does she need to make 24 hamburgers for a neighbourhood picnic?<br />
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<math>\textbf{(A)}\hspace{.05in}6 \qquad \textbf{(B)}\hspace{.05in}6\dfrac23 \qquad \textbf{(C)}\hspace{.05in}7\dfrac12 \qquad \textbf{(D)}\hspace{.05in}8 \qquad \textbf{(E)}\hspace{.05in}9 </math><br />
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==Solution 1==<br />
Since Rachelle uses <math>3</math> pounds of meat to make <math>8</math> hamburgers, she uses <math>\frac{3}{8}</math> pounds of meat to make one hamburger. She'll need 24 times that amount of meat for 24 hamburgers, or <math>\frac{3}{8} \cdot 24 = \boxed{\textbf{(E)}\ 9}</math>.<br />
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==Solution 2==<br />
So we have the proportion <math>\frac{3}{8}</math> = <math>\frac{x}{24}</math> to solve for x, multiply the left side of the equation by <math>\frac{3}{3}</math>. We find that x=9. ~Andrew_Lu<br />
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==See Also==<br />
{{AMC8 box|year=2012|before=First Problem|num-a=2}}<br />
{{MAA Notice}}</div>Nparkamc8https://artofproblemsolving.com/wiki/index.php?title=2012_AMC_8_Problems/Problem_1&diff=1382422012 AMC 8 Problems/Problem 12020-11-23T20:17:45Z<p>Nparkamc8: /* Problem */</p>
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<div>==Problem==<br />
Rachelle uses 3 pounds of meat to make 8 hamburgers for her family. How many pounds of meat does she need to make 24 hamburgers for a neighbourhood picniczzzzzzz?<br />
<br />
<math>\textbf{(A)}\hspace{.05in}6 \qquad \textbf{(B)}\hspace{.05in}6\dfrac23 \qquad \textbf{(C)}\hspace{.05in}7\dfrac12 \qquad \textbf{(D)}\hspace{.05in}8 \qquad \textbf{(E)}\hspace{.05in}9 </math><br />
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==Solution 1==<br />
Since Rachelle uses <math>3</math> pounds of meat to make <math>8</math> hamburgers, she uses <math>\frac{3}{8}</math> pounds of meat to make one hamburger. She'll need 24 times that amount of meat for 24 hamburgers, or <math>\frac{3}{8} \cdot 24 = \boxed{\textbf{(E)}\ 9}</math>.<br />
<br />
==Solution 2==<br />
So we have the proportion <math>\frac{3}{8}</math> = <math>\frac{x}{24}</math> to solve for x, multiply the left side of the equation by <math>\frac{3}{3}</math>. We find that x=9. ~Andrew_Lu<br />
<br />
==See Also==<br />
{{AMC8 box|year=2012|before=First Problem|num-a=2}}<br />
{{MAA Notice}}</div>Nparkamc8