https://artofproblemsolving.com/wiki/api.php?action=feedcontributions&user=Scientest&feedformat=atomAoPS Wiki - User contributions [en]2024-03-28T11:17:16ZUser contributionsMediaWiki 1.31.1https://artofproblemsolving.com/wiki/index.php?title=2004_AMC_12A_Problems/Problem_3&diff=979802004 AMC 12A Problems/Problem 32018-09-29T05:35:30Z<p>Scientest: /* Solution 2 */</p>
<hr />
<div>==Problem==<br />
For how many ordered pairs of positive integers <math>(x,y)</math> is <math>x + 2y = 100</math>?<br />
<br />
<math>\text {(A)} 33 \qquad \text {(B)} 49 \qquad \text {(C)} 50 \qquad \text {(D)} 99 \qquad \text {(E)}100</math><br />
<br />
==Solution 1==<br />
Every integer value of <math>y</math> leads to an integer solution for <math>x</math><br />
Since <math>y</math> must be positive, <math>y\geq 1</math><br />
<br />
Also, <math>y = \frac{100-x}{2}</math><br />
Since <math>x</math> must be positive, <math>y < 50</math><br />
<br />
<math>1 \leq y < 50</math><br />
This leaves <math>49</math> values for y, which mean there are <math>49</math> solutions to the equation <math>\Rightarrow \mathrm{(B)}</math><br />
<br />
==Solution 2==<br />
If <math>x</math> and <math>2y</math> must each be positive integers, then we can say that <math>x</math> is at least 1 and <math>2y</math> is at least 1. From there, we want to find out how many ways there are to distribute the other 98 ones (the smallest positive integer addends of 100). 98 identical objects can be distributed to two distinct bins in 99 ways (think stars and bars), yet this 99 is an overcount. Because <math>y</math> must be an integer, <math>2y</math> must be even; thus only <math>\left\lfloor \frac{99}{2} \right\rfloor = \boxed{ 49 \implies B}</math> ways exist to distribute these ones.<br />
<br />
==See Also==<br />
<br />
{{AMC12 box|year=2004|ab=A|num-b=2|num-a=4}}<br />
{{MAA Notice}}</div>Scientesthttps://artofproblemsolving.com/wiki/index.php?title=1992_AHSME_Problems&diff=956621992 AHSME Problems2018-06-28T16:30:50Z<p>Scientest: /* Problem 26 */ This editor should really learn to use the "Show preview" function</p>
<hr />
<div>== Problem 1 ==<br />
<br />
If <math>3(4x+5\pi)=P</math> then <math>6(8x+10\pi)=</math><br />
<br />
<math>\text{(A) } 2P\quad<br />
\text{(B) } 4P\quad<br />
\text{(C) } 6P\quad<br />
\text{(D) } 8P\quad<br />
\text{(E) } 18P</math><br />
<br />
[[1992 AHSME Problems/Problem 1|Solution]]<br />
<br />
== Problem 2 ==<br />
An urn is filled with coins and beads, all of which are either silver or gold. Twenty percent of the objects in the urn are beads. Forty percent of the coins in the urn are silver. What percent of objects in the urn are gold coins?<br />
<br />
<math>\text{(A) } 40\%\quad<br />
\text{(B) } 48\%\quad<br />
\text{(C) } 52\%\quad<br />
\text{(D) } 60\%\quad<br />
\text{(E) } 80\%</math><br />
<br />
[[1992 AHSME Problems/Problem 2|Solution]]<br />
<br />
== Problem 3 ==<br />
If <math>m>0</math> and the points <math>(m,3)</math> and <math>(1,m)</math> lie on a line with slope <math>m</math>, then <math>m=</math><br />
<br />
<math>\text{(A) } 1\quad<br />
\text{(B) } \sqrt{2}\quad<br />
\text{(C) } \sqrt{3}\quad<br />
\text{(D) } 2\quad<br />
\text{(E) } \sqrt{5}</math><br />
<br />
[[1992 AHSME Problems/Problem 3|Solution]]<br />
<br />
== Problem 4 ==<br />
<br />
<br />
If <math>a,b</math> and <math>c</math> are positive integers and <math>a</math> and <math>b</math> are odd, then <math>3^a+(b-1)^2c</math> is<br />
<br />
<math>\text{(A) odd for all choices of c} \quad<br />
\text{(B) even for all choices of c} \quad\\<br />
\text{(C) odd if c is even; even if c is odd} \quad\\<br />
\text{(D) odd if c is odd; even if c is even} \quad\\<br />
\text{(E) odd if c is not a multiple of 3; even if c is a multiple of 3} </math><br />
<br />
[[1992 AHSME Problems/Problem 4|Solution]]<br />
<br />
== Problem 5 ==<br />
<br />
<math>6^6+6^6+6^6+6^6+6^6+6^6=</math><br />
<br />
<math>\text{(A) } 6^6 \quad<br />
\text{(B) } 6^7\quad<br />
\text{(C) } 36^6\quad<br />
\text{(D) } 6^{36}\quad<br />
\text{(E) } 36^{36}</math><br />
<br />
[[1992 AHSME Problems/Problem 5|Solution]]<br />
<br />
== Problem 6 ==<br />
<br />
If <math>x>y>0</math> , then <math>\frac{x^y y^x}{y^y x^x}=</math><br />
<br />
<br />
<math>\text{(A) } (x-y)^{y/x}\quad<br />
\text{(B) } \left(\frac{x}{y}\right)^{x-y}\quad<br />
\text{(C) } 1\quad<br />
\text{(D) } \left(\frac{x}{y}\right)^{y-x}\quad<br />
\text{(E) } (x-y)^{x/y}</math><br />
<br />
[[1992 AHSME Problems/Problem 6|Solution]]<br />
<br />
== Problem 7 ==<br />
The ratio of <math>w</math> to <math>x</math> is <math>4:3</math>, of <math>y</math> to <math>z</math> is <math>3:2</math> and of <math>z</math> to <math>x</math> is <math>1:6</math>. What is the ratio of <math>w</math> to <math>y</math>?<br />
<br />
<math>\text{(A) } 1:3\quad<br />
\text{(B) } 16:3\quad<br />
\text{(C) } 20:3\quad<br />
\text{(D) } 27:4\quad<br />
\text{(E) } 12:1</math><br />
<br />
[[1992 AHSME Problems/Problem 7|Solution]]<br />
<br />
== Problem 8 ==<br />
<asy><br />
draw((-10,-10)--(-10,10)--(10,10)--(10,-10)--cycle,dashed+linewidth(.75));<br />
draw((-7,-7)--(-7,7)--(7,7)--(7,-7)--cycle,dashed+linewidth(.75));<br />
draw((-10,-10)--(10,10),dashed+linewidth(.75));<br />
draw((-10,10)--(10,-10),dashed+linewidth(.75));<br />
fill((10,10)--(10,9)--(9,9)--(9,10)--cycle,black);<br />
fill((9,9)--(9,8)--(8,8)--(8,9)--cycle,black);<br />
fill((8,8)--(8,7)--(7,7)--(7,8)--cycle,black);<br />
fill((-10,-10)--(-10,-9)--(-9,-9)--(-9,-10)--cycle,black);<br />
fill((-9,-9)--(-9,-8)--(-8,-8)--(-8,-9)--cycle,black);<br />
fill((-8,-8)--(-8,-7)--(-7,-7)--(-7,-8)--cycle,black);<br />
fill((10,-10)--(10,-9)--(9,-9)--(9,-10)--cycle,black);<br />
fill((9,-9)--(9,-8)--(8,-8)--(8,-9)--cycle,black);<br />
fill((8,-8)--(8,-7)--(7,-7)--(7,-8)--cycle,black);<br />
fill((-10,10)--(-10,9)--(-9,9)--(-9,10)--cycle,black);<br />
fill((-9,9)--(-9,8)--(-8,8)--(-8,9)--cycle,black);<br />
fill((-8,8)--(-8,7)--(-7,7)--(-7,8)--cycle,black);<br />
</asy><br />
<br />
A square floor is tiled with congruent square tiles. The tiles on the two diagonals of the floor are black. The rest of the tiles are white. If there are 101 black tiles, then the total number of tiles is<br />
<br />
<math>\text{(A) } 121\quad<br />
\text{(B) } 625\quad<br />
\text{(C) } 676\quad<br />
\text{(D) } 2500\quad<br />
\text{(E) } 2601</math><br />
<br />
<br />
[[1992 AHSME Problems/Problem 8|Solution]]<br />
<br />
== Problem 9 ==<br />
<asy><br />
draw((-7,0)--(7,0),black+linewidth(.75));<br />
draw((-3*sqrt(3),0)--(-2*sqrt(3),3)--(-sqrt(3),0)--(0,3)--(sqrt(3),0)--(2*sqrt(3),3)--(3*sqrt(3),0),black+linewidth(.75));<br />
draw((-2*sqrt(3),0)--(-1*sqrt(3),3)--(0,0)--(sqrt(3),3)--(2*sqrt(3),0),black+linewidth(.75));<br />
</asy><br />
<br />
Five equilateral triangles, each with side <math>2\sqrt{3}</math>, are arranged so they are all on the same side of a line containing one side of each vertex. Along this line, the midpoint of the base of one triangle is a vertex of the next. The area of the region of the plane that is covered by the union of the five triangular regions is<br />
<br />
<math>\text{(A) 10} \quad<br />
\text{(B) } 12\quad<br />
\text{(C) } 15\quad<br />
\text{(D) } 10\sqrt{3}\quad<br />
\text{(E) } 12\sqrt{3}</math><br />
<br />
[[1992 AHSME Problems/Problem 9|Solution]]<br />
<br />
== Problem 10 ==<br />
<br />
The number of positive integers <math>k</math> for which the equation<br />
<cmath>kx-12=3k</cmath><br />
has an integer solution for <math>x</math> is<br />
<br />
<math>\text{(A) } 3\quad<br />
\text{(B) } 4\quad<br />
\text{(C) } 5\quad<br />
\text{(D) } 6\quad<br />
\text{(E) } 7</math><br />
<br />
<br />
[[1992 AHSME Problems/Problem 10|Solution]]<br />
<br />
== Problem 11 ==<br />
<asy><br />
draw(circle((0,0),18),black+linewidth(.75));<br />
draw(circle((0,0),6),black+linewidth(.75));<br />
draw((-18,0)--(18,0)--(-14,8*sqrt(2))--cycle,black+linewidth(.75));<br />
dot((-18,0));dot((18,0));dot((-14,8*sqrt(2)));<br />
MP("A",(-18,0),W);MP("C",(18,0),E);MP("B",(-14,8*sqrt(2)),W);<br />
</asy><br />
<br />
The ratio of the radii of two concentric circles is <math>1:3</math>. If <math>\overline{AC}</math> is a diameter of the larger circle, <math>\overline{BC}</math> is a chord of the larger circle that is tangent to the smaller circle, and <math>AB=12</math>, then the radius of the larger circle is<br />
<br />
<math>\text{(A) } 13\quad<br />
\text{(B) } 18\quad<br />
\text{(C) } 21\quad<br />
\text{(D) } 24\quad<br />
\text{(E) } 26</math><br />
<br />
[[1992 AHSME Problems/Problem 11|Solution]]<br />
<br />
== Problem 12 ==<br />
Let <math>y=mx+b</math> be the image when the line <math>x-3y+11=0</math> is reflected across the <math>x</math>-axis. The value of <math>m+b</math> is<br />
<br />
<math>\text{(A) -6} \quad<br />
\text{(B) } -5\quad<br />
\text{(C) } -4\quad<br />
\text{(D) } -3\quad<br />
\text{(E) } -2</math><br />
<br />
[[1992 AHSME Problems/Problem 12|Solution]]<br />
<br />
== Problem 13 ==<br />
<br />
How many pairs of positive integers <math>(a,b)</math> with <math>a+b\le 100</math> satisfy the equation<br />
<br />
<cmath>\frac{a+b^{-1}}{a^{-1}+b}=13?</cmath><br />
<br />
<math>\text{(A) } 1\quad<br />
\text{(B) } 5\quad<br />
\text{(C) } 7\quad<br />
\text{(D) } 9\quad<br />
\text{(E) } 13</math><br />
<br />
[[1992 AHSME Problems/Problem 13|Solution]]<br />
<br />
== Problem 14 ==<br />
Which of the following equations have the same graph?<br />
<br />
<math>I.\quad y=x-2 \qquad II.\quad y=\frac{x^2-4}{x+2}\qquad III.\quad (x+2)y=x^2-4</math><br />
<br />
<math>\text{(A) I and II only} \quad<br />
\text{(B) I and III only} \quad<br />
\text{(C) II and III only} \quad<br />
\text{(D) I,II,and III} \quad \\<br />
\text{(E) None. All of the equations have different graphs} </math><br />
<br />
[[1992 AHSME Problems/Problem 14|Solution]]<br />
<br />
== Problem 15 ==<br />
<br />
Let <math>i=\sqrt{-1}</math>. Define a sequence of complex numbers by<br />
<br />
<cmath>z_1=0,\quad z_{n+1}=z_{n}^2+i \text{ for } n\ge1.</cmath><br />
In the complex plane, how far from the origin is <math>z_{111}</math>?<br />
<br />
<math>\text{(A) } 1\quad<br />
\text{(B) } \sqrt{2}\quad<br />
\text{(C) } \sqrt{3}\quad<br />
\text{(D) } \sqrt{110}\quad<br />
\text{(E) } \sqrt{2^{55}}</math><br />
<br />
[[1992 AHSME Problems/Problem 15|Solution]]<br />
<br />
== Problem 16 ==<br />
If<br />
<cmath>\frac{y}{x-z}=\frac{x+y}{z}=\frac{x}{y}</cmath><br />
for three positive numbers <math>x,y</math> and <math>z</math>, all different, then <math>\frac{x}{y}=</math><br />
<br />
<math>\text{(A) } \frac{1}{2}\quad<br />
\text{(B) } \frac{3}{5}\quad<br />
\text{(C) } \frac{2}{3}\quad<br />
\text{(D) } \frac{5}{3}\quad<br />
\text{(E) } 2</math><br />
<br />
[[1992 AHSME Problems/Problem 16|Solution]]<br />
<br />
== Problem 17 ==<br />
The 2-digit integers from 19 to 92 are written consecutively to form the integer <math>N=192021\cdots9192</math>. Suppose that <math>3^k</math> is the highest power of 3 that is a factor of <math>N</math>. What is <math>k</math>?<br />
<br />
<math>\text{(A) } 0\quad<br />
\text{(B) } 1\quad<br />
\text{(C) } 2\quad<br />
\text{(D) } 3\quad<br />
\text{(E) more than } 3</math><br />
<br />
[[1992 AHSME Problems/Problem 17|Solution]]<br />
<br />
== Problem 18 ==<br />
The increasing sequence of positive integers <math>a_1,a_2,a_3,\cdots </math> has the property that<br />
<br />
<cmath>a_{n+2}=a_n+a_{n+1} \text{ for all } n\ge 1.</cmath><br />
<br />
If <math>a_7=120</math>, then <math>a_8</math> is<br />
<br />
<math>\text{(A) } 128\quad<br />
\text{(B) } 168\quad<br />
\text{(C) } 193\quad<br />
\text{(D) } 194\quad<br />
\text{(E) } 210</math><br />
<br />
[[1992 AHSME Problems/Problem 18|Solution]]<br />
<br />
== Problem 19 ==<br />
<br />
<br />
For each vertex of a solid cube, consider the tetrahedron determined by the vertex and the midpoints of the three edges that meet at that vertex. The portion of the cube that remains when these eight tetrahedra are cut away is called a cubeoctahedron. The ratio of the volume of the cubeoctahedron to the volume of the original cube is closest to which of these?<br />
<br />
<math>\text{(A) } 75\%\quad<br />
\text{(B) } 78\%\quad<br />
\text{(C) } 81\%\quad<br />
\text{(D) } 84\%\quad<br />
\text{(E) } 87\%</math><br />
<br />
[[1992 AHSME Problems/Problem 19|Solution]]<br />
<br />
== Problem 20 ==<br />
<br />
<asy><br />
draw((1,0)--(2*cos(pi/8),2*sin(pi/8))--(cos(pi/4),sin(pi/4))--(2*cos(3*pi/8),2*sin(3*pi/8))--(cos(pi/2),sin(pi/2))--(2*cos(5*pi/8),2*sin(5*pi/8))--(cos(3*pi/4),sin(3*pi/4))--(2*cos(7*pi/8),2*sin(7*pi/8))--(-1,0),black+linewidth(.75));<br />
MP("A_1",(2*cos(5*pi/8),2*sin(5*pi/8)),N);MP("A_2",(2*cos(3*pi/8),2*sin(3*pi/8)),N);MP("A_3",(2*cos(1*pi/8),2*sin(1*pi/8)),N);<br />
MP("A_n",(2*cos(7*pi/8),2*sin(7*pi/8)),N);<br />
MP("B_1",(cos(4*pi/8),sin(4*pi/8)),S);MP("B_2",(cos(2*pi/8),sin(2*pi/8)),S);MP("B_n",(cos(6*pi/8),sin(6*pi/8)),S);<br />
</asy><br />
Part of an "n-pointed regular star" is shown. It is a simple closed polygon in which all <math>2n</math> edges are congruent, angles <math>A_1,A_2,\cdots,A_n</math> are congruent, and angles <math>B_1,B_2,\cdots,B_n</math> are congruent. If the acute angle at <math>A_1</math> is <math>10^\circ</math> less than the acute angle at <math>B_1</math>, then <math>n=</math><br />
<br />
<math>\text{(A) } 12\quad<br />
\text{(B) } 18\quad<br />
\text{(C) } 24\quad<br />
\text{(D) } 36\quad<br />
\text{(E) } 60</math><br />
<br />
[[1992 AHSME Problems/Problem 20|Solution]]<br />
<br />
== Problem 21 ==<br />
<br />
For a finite sequence <math>A=(a_1,a_2,...,a_n)</math> of numbers, the ''Cesáro sum'' of A is defined to be <br />
<math>\frac{S_1+\cdots+S_n}{n}</math> , where <math>S_k=a_1+\cdots+a_k</math> and <math>1\leq k\leq n</math>. If the Cesáro sum of<br />
the 99-term sequence <math>(a_1,...,a_{99})</math> is 1000, what is the Cesáro sum of the 100-term sequence <br />
<math>(1,a_1,...,a_{99})</math>?<br />
<br />
<math>\text{(A) } 991\quad<br />
\text{(B) } 999\quad<br />
\text{(C) } 1000\quad<br />
\text{(D) } 1001\quad<br />
\text{(E) } 1009</math><br />
<br />
[[1992 AHSME Problems/Problem 21|Solution]]<br />
<br />
== Problem 22 ==<br />
<br />
Ten points are selected on the positive <math>x</math>-axis,<math>X^+</math>, and five points are selected on the positive <math>y</math>-axis,<math>Y^+</math>. The fifty segments connecting the ten points on <math>X^+</math> to the five points on <math>Y^+</math> are drawn. What is the maximum possible number of points of intersection of these fifty segments that could lie in the interior of the first quadrant?<br />
<br />
<math>\text{(A) } 250\quad<br />
\text{(B) } 450\quad<br />
\text{(C) } 500\quad<br />
\text{(D) } 1250\quad<br />
\text{(E) } 2500</math><br />
<br />
[[1992 AHSME Problems/Problem 22|Solution]]<br />
<br />
<br />
== Problem 23 ==<br />
<br />
Let <math>S</math> be a subset of <math>\{1,2,3,...,50\}</math> such that no pair of distinct elements in <math>S</math> has a sum divisible by <math>7</math>. What is the maximum number of elements in <math>S</math>?<br />
<br />
<math>\text{(A) } 6\quad<br />
\text{(B) } 7\quad<br />
\text{(C) } 14\quad<br />
\text{(D) } 22\quad<br />
\text{(E) } 23</math><br />
<br />
[[1992 AHSME Problems/Problem 23|Solution]]<br />
<br />
== Problem 24 ==<br />
<br />
Let <math>ABCD</math> be a parallelogram of area <math>10</math> with <math>AB=3</math> and <math>BC=5</math>. Locate <math>E,F</math> and <math>G</math> on segments <math>\overline{AB},\overline{BC}</math> and <math>\overline{AD}</math>, respectively, with <math>AE=BF=AG=2</math>. Let the line through <math>G</math> parallel to <math>\overline{EF}</math> intersect <math>\overline{CD}</math> at <math>H</math>. The area of quadrilateral <math>EFHG</math> is<br />
<br />
<math>\text{(A) } 4\quad<br />
\text{(B) } 4.5\quad<br />
\text{(C) } 5\quad<br />
\text{(D) } 5.5\quad<br />
\text{(E) } 6</math><br />
<br />
[[1992 AHSME Problems/Problem 24|Solution]]<br />
<br />
== Problem 25 ==<br />
<br />
In <math>\triangle{ABC}</math>, <math>\angle{ABC}=120^\circ,AB=3</math> and <math>BC=4</math>. If perpendiculars constructed to <math>\overline{AB}</math> at <math>A</math> and to <math>\overline{BC}</math> at <math>C</math> meet at <math>D</math>, then <math>CD=</math><br />
<br />
<math>\text{(A) } 3\quad<br />
\text{(B) } \frac{8}{\sqrt{3}}\quad<br />
\text{(C) } 5\quad<br />
\text{(D) } \frac{11}{2}\quad<br />
\text{(E) } \frac{10}{\sqrt{3}}</math><br />
<br />
[[1992 AHSME Problems/Problem 25|Solution]]<br />
<br />
== Problem 26 ==<br />
<asy><br />
fill((1,0)--arc((1,0),2,180,225)--cycle,grey);<br />
fill((-1,0)--arc((-1,0),2,315,360)--cycle,grey);<br />
fill((0,-1)--arc((0,-1),2-sqrt(2),225,315)--cycle,grey);<br />
fill((0,0)--arc((0,0),1,180,360)--cycle,white);<br />
draw((1,0)--arc((1,0),2,180,225)--(1,0),black+linewidth(1));<br />
draw((-1,0)--arc((-1,0),2,315,360)--(-1,0),black+linewidth(1));<br />
draw((0,0)--arc((0,0),1,180,360)--(0,0),black+linewidth(1));<br />
draw(arc((0,-1),2-sqrt(2),225,315),black+linewidth(1));<br />
draw((0,0)--(0,-1),black+linewidth(1));<br />
MP("C",(0,0),N);MP("A",(-1,0),N);MP("B",(1,0),N);<br />
MP("D",(0,-.8),NW);MP("E",(1-sqrt(2),-sqrt(2)),SW);MP("F",(-1+sqrt(2),-sqrt(2)),SE);<br />
</asy><br />
<br />
Semicircle <math>\widehat{AB}</math> has center <math>C</math> and radius <math>1</math>. Point <math>D</math> is on <math>\widehat{AB}</math> and <math>\overline{CD}\perp\overline{AB}</math>. Extend <math>\overline{BD}</math> and <math>\overline{AD}</math> to <math>E</math> and <math>F</math>, respectively, so that circular arcs <math>\widehat{AE}</math> and <math>\widehat{BF}</math> have <math>B</math> and <math>A</math> as their respective centers. Circular arc <math>\widehat{EF}</math> has center <math>D</math>. The area of the shaded "smile" <math>AEFBDA</math>, is<br />
<br />
<math>\text{(A) } \left(2-\sqrt{2}\right)\pi\quad<br />
\text{(B) } 2\pi-\pi \sqrt{2}-1\quad<br />
\text{(C) } \left(1-\frac{\sqrt{2}}{2}\right)\pi\quad\\<br />
\text{(D) } \frac{5\pi}{2}-\pi\sqrt{2}-1\quad<br />
\text{(E) } \left(3-2\sqrt{2}\right)\pi</math><br />
<br />
<br />
[[1992 AHSME Problems/Problem 26|Solution]]<br />
<br />
== Problem 27 ==<br />
<br />
<br />
A circle of radius <math>r</math> has chords <math>\overline{AB}</math> of length <math>10</math> and <math>\overline{CD}</math> of length 7. When <math>\overline{AB}</math> and <math>\overline{CD}</math> are extended through <math>B</math> and <math>C</math>, respectively, they intersect at <math>P</math>, which is outside of the circle. If <math>\angle{APD}=60^\circ</math> and <math>BP=8</math>, then <math>r^2=</math><br />
<br />
<math>\text{(A) } 70\quad<br />
\text{(B) } 71\quad<br />
\text{(C) } 72\quad<br />
\text{(D) } 73\quad<br />
\text{(E) } 74</math><br />
[[1992 AHSME Problems/Problem 27|Solution]]<br />
<br />
== Problem 28 ==<br />
<br />
Let <math>i=\sqrt{-1}</math>. The product of the real parts of the roots of <math>z^2-z=5-5i</math> is<br />
<br />
<math>\text{(A) } -25\quad<br />
\text{(B) } -6\quad<br />
\text{(C) } -5\quad<br />
\text{(D) } \frac{1}{4}\quad<br />
\text{(E) } 25</math><br />
<br />
[[1992 AHSME Problems/Problem 28|Solution]]<br />
<br />
== Problem 29 ==<br />
An "unfair" coin has a <math>2/3</math> probability of turning up heads. If this coin is tossed <math>50</math> times, what is the probability that the total number of heads is even?<br />
<br />
<math>\text{(A) } 25\left(\frac{2}{3}\right)^{50}\quad<br />
\text{(B) } \frac{1}{2}\left(1-\frac{1}{3^{50}}\right)\quad<br />
\text{(C) } \frac{1}{2}\quad<br />
\text{(D) } \frac{1}{2}\left(1+\frac{1}{3^{50}}\right)\quad<br />
\text{(E) } \frac{2}{3}</math><br />
<br />
[[1992 AHSME Problems/Problem 29|Solution]]<br />
<br />
== Problem 30 ==<br />
<br />
Let <math>ABCD</math> be an isosceles trapezoid with bases <math>AB=92</math> and <math>CD=19</math>. Suppose <math>AD=BC=x</math> and a circle with center on <math>\overline{AB}</math> is tangent to segments <math>\overline{AD}</math> and <math>\overline{BC}</math>. If <math>m</math> is the smallest possible value of <math>x</math>, then <math>m^2</math>=<br />
<br />
<math>\text{(A) } 1369\quad<br />
\text{(B) } 1679\quad<br />
\text{(C) } 1748\quad<br />
\text{(D) } 2109\quad<br />
\text{(E) } 8825</math><br />
<br />
[[1992 AHSME Problems/Problem 30|Solution]]<br />
<br />
== See also ==<br />
<br />
* [[AMC 12 Problems and Solutions]]<br />
* [[Mathematics competition resources]]<br />
<br />
{{AHSME box|year=1992|before=[[1991 AHSME]]|after=[[1993 AHSME]]}} <br />
<br />
{{MAA Notice}}</div>Scientesthttps://artofproblemsolving.com/wiki/index.php?title=1992_AHSME_Problems&diff=956611992 AHSME Problems2018-06-28T16:30:19Z<p>Scientest: /* Problem 26 */</p>
<hr />
<div>== Problem 1 ==<br />
<br />
If <math>3(4x+5\pi)=P</math> then <math>6(8x+10\pi)=</math><br />
<br />
<math>\text{(A) } 2P\quad<br />
\text{(B) } 4P\quad<br />
\text{(C) } 6P\quad<br />
\text{(D) } 8P\quad<br />
\text{(E) } 18P</math><br />
<br />
[[1992 AHSME Problems/Problem 1|Solution]]<br />
<br />
== Problem 2 ==<br />
An urn is filled with coins and beads, all of which are either silver or gold. Twenty percent of the objects in the urn are beads. Forty percent of the coins in the urn are silver. What percent of objects in the urn are gold coins?<br />
<br />
<math>\text{(A) } 40\%\quad<br />
\text{(B) } 48\%\quad<br />
\text{(C) } 52\%\quad<br />
\text{(D) } 60\%\quad<br />
\text{(E) } 80\%</math><br />
<br />
[[1992 AHSME Problems/Problem 2|Solution]]<br />
<br />
== Problem 3 ==<br />
If <math>m>0</math> and the points <math>(m,3)</math> and <math>(1,m)</math> lie on a line with slope <math>m</math>, then <math>m=</math><br />
<br />
<math>\text{(A) } 1\quad<br />
\text{(B) } \sqrt{2}\quad<br />
\text{(C) } \sqrt{3}\quad<br />
\text{(D) } 2\quad<br />
\text{(E) } \sqrt{5}</math><br />
<br />
[[1992 AHSME Problems/Problem 3|Solution]]<br />
<br />
== Problem 4 ==<br />
<br />
<br />
If <math>a,b</math> and <math>c</math> are positive integers and <math>a</math> and <math>b</math> are odd, then <math>3^a+(b-1)^2c</math> is<br />
<br />
<math>\text{(A) odd for all choices of c} \quad<br />
\text{(B) even for all choices of c} \quad\\<br />
\text{(C) odd if c is even; even if c is odd} \quad\\<br />
\text{(D) odd if c is odd; even if c is even} \quad\\<br />
\text{(E) odd if c is not a multiple of 3; even if c is a multiple of 3} </math><br />
<br />
[[1992 AHSME Problems/Problem 4|Solution]]<br />
<br />
== Problem 5 ==<br />
<br />
<math>6^6+6^6+6^6+6^6+6^6+6^6=</math><br />
<br />
<math>\text{(A) } 6^6 \quad<br />
\text{(B) } 6^7\quad<br />
\text{(C) } 36^6\quad<br />
\text{(D) } 6^{36}\quad<br />
\text{(E) } 36^{36}</math><br />
<br />
[[1992 AHSME Problems/Problem 5|Solution]]<br />
<br />
== Problem 6 ==<br />
<br />
If <math>x>y>0</math> , then <math>\frac{x^y y^x}{y^y x^x}=</math><br />
<br />
<br />
<math>\text{(A) } (x-y)^{y/x}\quad<br />
\text{(B) } \left(\frac{x}{y}\right)^{x-y}\quad<br />
\text{(C) } 1\quad<br />
\text{(D) } \left(\frac{x}{y}\right)^{y-x}\quad<br />
\text{(E) } (x-y)^{x/y}</math><br />
<br />
[[1992 AHSME Problems/Problem 6|Solution]]<br />
<br />
== Problem 7 ==<br />
The ratio of <math>w</math> to <math>x</math> is <math>4:3</math>, of <math>y</math> to <math>z</math> is <math>3:2</math> and of <math>z</math> to <math>x</math> is <math>1:6</math>. What is the ratio of <math>w</math> to <math>y</math>?<br />
<br />
<math>\text{(A) } 1:3\quad<br />
\text{(B) } 16:3\quad<br />
\text{(C) } 20:3\quad<br />
\text{(D) } 27:4\quad<br />
\text{(E) } 12:1</math><br />
<br />
[[1992 AHSME Problems/Problem 7|Solution]]<br />
<br />
== Problem 8 ==<br />
<asy><br />
draw((-10,-10)--(-10,10)--(10,10)--(10,-10)--cycle,dashed+linewidth(.75));<br />
draw((-7,-7)--(-7,7)--(7,7)--(7,-7)--cycle,dashed+linewidth(.75));<br />
draw((-10,-10)--(10,10),dashed+linewidth(.75));<br />
draw((-10,10)--(10,-10),dashed+linewidth(.75));<br />
fill((10,10)--(10,9)--(9,9)--(9,10)--cycle,black);<br />
fill((9,9)--(9,8)--(8,8)--(8,9)--cycle,black);<br />
fill((8,8)--(8,7)--(7,7)--(7,8)--cycle,black);<br />
fill((-10,-10)--(-10,-9)--(-9,-9)--(-9,-10)--cycle,black);<br />
fill((-9,-9)--(-9,-8)--(-8,-8)--(-8,-9)--cycle,black);<br />
fill((-8,-8)--(-8,-7)--(-7,-7)--(-7,-8)--cycle,black);<br />
fill((10,-10)--(10,-9)--(9,-9)--(9,-10)--cycle,black);<br />
fill((9,-9)--(9,-8)--(8,-8)--(8,-9)--cycle,black);<br />
fill((8,-8)--(8,-7)--(7,-7)--(7,-8)--cycle,black);<br />
fill((-10,10)--(-10,9)--(-9,9)--(-9,10)--cycle,black);<br />
fill((-9,9)--(-9,8)--(-8,8)--(-8,9)--cycle,black);<br />
fill((-8,8)--(-8,7)--(-7,7)--(-7,8)--cycle,black);<br />
</asy><br />
<br />
A square floor is tiled with congruent square tiles. The tiles on the two diagonals of the floor are black. The rest of the tiles are white. If there are 101 black tiles, then the total number of tiles is<br />
<br />
<math>\text{(A) } 121\quad<br />
\text{(B) } 625\quad<br />
\text{(C) } 676\quad<br />
\text{(D) } 2500\quad<br />
\text{(E) } 2601</math><br />
<br />
<br />
[[1992 AHSME Problems/Problem 8|Solution]]<br />
<br />
== Problem 9 ==<br />
<asy><br />
draw((-7,0)--(7,0),black+linewidth(.75));<br />
draw((-3*sqrt(3),0)--(-2*sqrt(3),3)--(-sqrt(3),0)--(0,3)--(sqrt(3),0)--(2*sqrt(3),3)--(3*sqrt(3),0),black+linewidth(.75));<br />
draw((-2*sqrt(3),0)--(-1*sqrt(3),3)--(0,0)--(sqrt(3),3)--(2*sqrt(3),0),black+linewidth(.75));<br />
</asy><br />
<br />
Five equilateral triangles, each with side <math>2\sqrt{3}</math>, are arranged so they are all on the same side of a line containing one side of each vertex. Along this line, the midpoint of the base of one triangle is a vertex of the next. The area of the region of the plane that is covered by the union of the five triangular regions is<br />
<br />
<math>\text{(A) 10} \quad<br />
\text{(B) } 12\quad<br />
\text{(C) } 15\quad<br />
\text{(D) } 10\sqrt{3}\quad<br />
\text{(E) } 12\sqrt{3}</math><br />
<br />
[[1992 AHSME Problems/Problem 9|Solution]]<br />
<br />
== Problem 10 ==<br />
<br />
The number of positive integers <math>k</math> for which the equation<br />
<cmath>kx-12=3k</cmath><br />
has an integer solution for <math>x</math> is<br />
<br />
<math>\text{(A) } 3\quad<br />
\text{(B) } 4\quad<br />
\text{(C) } 5\quad<br />
\text{(D) } 6\quad<br />
\text{(E) } 7</math><br />
<br />
<br />
[[1992 AHSME Problems/Problem 10|Solution]]<br />
<br />
== Problem 11 ==<br />
<asy><br />
draw(circle((0,0),18),black+linewidth(.75));<br />
draw(circle((0,0),6),black+linewidth(.75));<br />
draw((-18,0)--(18,0)--(-14,8*sqrt(2))--cycle,black+linewidth(.75));<br />
dot((-18,0));dot((18,0));dot((-14,8*sqrt(2)));<br />
MP("A",(-18,0),W);MP("C",(18,0),E);MP("B",(-14,8*sqrt(2)),W);<br />
</asy><br />
<br />
The ratio of the radii of two concentric circles is <math>1:3</math>. If <math>\overline{AC}</math> is a diameter of the larger circle, <math>\overline{BC}</math> is a chord of the larger circle that is tangent to the smaller circle, and <math>AB=12</math>, then the radius of the larger circle is<br />
<br />
<math>\text{(A) } 13\quad<br />
\text{(B) } 18\quad<br />
\text{(C) } 21\quad<br />
\text{(D) } 24\quad<br />
\text{(E) } 26</math><br />
<br />
[[1992 AHSME Problems/Problem 11|Solution]]<br />
<br />
== Problem 12 ==<br />
Let <math>y=mx+b</math> be the image when the line <math>x-3y+11=0</math> is reflected across the <math>x</math>-axis. The value of <math>m+b</math> is<br />
<br />
<math>\text{(A) -6} \quad<br />
\text{(B) } -5\quad<br />
\text{(C) } -4\quad<br />
\text{(D) } -3\quad<br />
\text{(E) } -2</math><br />
<br />
[[1992 AHSME Problems/Problem 12|Solution]]<br />
<br />
== Problem 13 ==<br />
<br />
How many pairs of positive integers <math>(a,b)</math> with <math>a+b\le 100</math> satisfy the equation<br />
<br />
<cmath>\frac{a+b^{-1}}{a^{-1}+b}=13?</cmath><br />
<br />
<math>\text{(A) } 1\quad<br />
\text{(B) } 5\quad<br />
\text{(C) } 7\quad<br />
\text{(D) } 9\quad<br />
\text{(E) } 13</math><br />
<br />
[[1992 AHSME Problems/Problem 13|Solution]]<br />
<br />
== Problem 14 ==<br />
Which of the following equations have the same graph?<br />
<br />
<math>I.\quad y=x-2 \qquad II.\quad y=\frac{x^2-4}{x+2}\qquad III.\quad (x+2)y=x^2-4</math><br />
<br />
<math>\text{(A) I and II only} \quad<br />
\text{(B) I and III only} \quad<br />
\text{(C) II and III only} \quad<br />
\text{(D) I,II,and III} \quad \\<br />
\text{(E) None. All of the equations have different graphs} </math><br />
<br />
[[1992 AHSME Problems/Problem 14|Solution]]<br />
<br />
== Problem 15 ==<br />
<br />
Let <math>i=\sqrt{-1}</math>. Define a sequence of complex numbers by<br />
<br />
<cmath>z_1=0,\quad z_{n+1}=z_{n}^2+i \text{ for } n\ge1.</cmath><br />
In the complex plane, how far from the origin is <math>z_{111}</math>?<br />
<br />
<math>\text{(A) } 1\quad<br />
\text{(B) } \sqrt{2}\quad<br />
\text{(C) } \sqrt{3}\quad<br />
\text{(D) } \sqrt{110}\quad<br />
\text{(E) } \sqrt{2^{55}}</math><br />
<br />
[[1992 AHSME Problems/Problem 15|Solution]]<br />
<br />
== Problem 16 ==<br />
If<br />
<cmath>\frac{y}{x-z}=\frac{x+y}{z}=\frac{x}{y}</cmath><br />
for three positive numbers <math>x,y</math> and <math>z</math>, all different, then <math>\frac{x}{y}=</math><br />
<br />
<math>\text{(A) } \frac{1}{2}\quad<br />
\text{(B) } \frac{3}{5}\quad<br />
\text{(C) } \frac{2}{3}\quad<br />
\text{(D) } \frac{5}{3}\quad<br />
\text{(E) } 2</math><br />
<br />
[[1992 AHSME Problems/Problem 16|Solution]]<br />
<br />
== Problem 17 ==<br />
The 2-digit integers from 19 to 92 are written consecutively to form the integer <math>N=192021\cdots9192</math>. Suppose that <math>3^k</math> is the highest power of 3 that is a factor of <math>N</math>. What is <math>k</math>?<br />
<br />
<math>\text{(A) } 0\quad<br />
\text{(B) } 1\quad<br />
\text{(C) } 2\quad<br />
\text{(D) } 3\quad<br />
\text{(E) more than } 3</math><br />
<br />
[[1992 AHSME Problems/Problem 17|Solution]]<br />
<br />
== Problem 18 ==<br />
The increasing sequence of positive integers <math>a_1,a_2,a_3,\cdots </math> has the property that<br />
<br />
<cmath>a_{n+2}=a_n+a_{n+1} \text{ for all } n\ge 1.</cmath><br />
<br />
If <math>a_7=120</math>, then <math>a_8</math> is<br />
<br />
<math>\text{(A) } 128\quad<br />
\text{(B) } 168\quad<br />
\text{(C) } 193\quad<br />
\text{(D) } 194\quad<br />
\text{(E) } 210</math><br />
<br />
[[1992 AHSME Problems/Problem 18|Solution]]<br />
<br />
== Problem 19 ==<br />
<br />
<br />
For each vertex of a solid cube, consider the tetrahedron determined by the vertex and the midpoints of the three edges that meet at that vertex. The portion of the cube that remains when these eight tetrahedra are cut away is called a cubeoctahedron. The ratio of the volume of the cubeoctahedron to the volume of the original cube is closest to which of these?<br />
<br />
<math>\text{(A) } 75\%\quad<br />
\text{(B) } 78\%\quad<br />
\text{(C) } 81\%\quad<br />
\text{(D) } 84\%\quad<br />
\text{(E) } 87\%</math><br />
<br />
[[1992 AHSME Problems/Problem 19|Solution]]<br />
<br />
== Problem 20 ==<br />
<br />
<asy><br />
draw((1,0)--(2*cos(pi/8),2*sin(pi/8))--(cos(pi/4),sin(pi/4))--(2*cos(3*pi/8),2*sin(3*pi/8))--(cos(pi/2),sin(pi/2))--(2*cos(5*pi/8),2*sin(5*pi/8))--(cos(3*pi/4),sin(3*pi/4))--(2*cos(7*pi/8),2*sin(7*pi/8))--(-1,0),black+linewidth(.75));<br />
MP("A_1",(2*cos(5*pi/8),2*sin(5*pi/8)),N);MP("A_2",(2*cos(3*pi/8),2*sin(3*pi/8)),N);MP("A_3",(2*cos(1*pi/8),2*sin(1*pi/8)),N);<br />
MP("A_n",(2*cos(7*pi/8),2*sin(7*pi/8)),N);<br />
MP("B_1",(cos(4*pi/8),sin(4*pi/8)),S);MP("B_2",(cos(2*pi/8),sin(2*pi/8)),S);MP("B_n",(cos(6*pi/8),sin(6*pi/8)),S);<br />
</asy><br />
Part of an "n-pointed regular star" is shown. It is a simple closed polygon in which all <math>2n</math> edges are congruent, angles <math>A_1,A_2,\cdots,A_n</math> are congruent, and angles <math>B_1,B_2,\cdots,B_n</math> are congruent. If the acute angle at <math>A_1</math> is <math>10^\circ</math> less than the acute angle at <math>B_1</math>, then <math>n=</math><br />
<br />
<math>\text{(A) } 12\quad<br />
\text{(B) } 18\quad<br />
\text{(C) } 24\quad<br />
\text{(D) } 36\quad<br />
\text{(E) } 60</math><br />
<br />
[[1992 AHSME Problems/Problem 20|Solution]]<br />
<br />
== Problem 21 ==<br />
<br />
For a finite sequence <math>A=(a_1,a_2,...,a_n)</math> of numbers, the ''Cesáro sum'' of A is defined to be <br />
<math>\frac{S_1+\cdots+S_n}{n}</math> , where <math>S_k=a_1+\cdots+a_k</math> and <math>1\leq k\leq n</math>. If the Cesáro sum of<br />
the 99-term sequence <math>(a_1,...,a_{99})</math> is 1000, what is the Cesáro sum of the 100-term sequence <br />
<math>(1,a_1,...,a_{99})</math>?<br />
<br />
<math>\text{(A) } 991\quad<br />
\text{(B) } 999\quad<br />
\text{(C) } 1000\quad<br />
\text{(D) } 1001\quad<br />
\text{(E) } 1009</math><br />
<br />
[[1992 AHSME Problems/Problem 21|Solution]]<br />
<br />
== Problem 22 ==<br />
<br />
Ten points are selected on the positive <math>x</math>-axis,<math>X^+</math>, and five points are selected on the positive <math>y</math>-axis,<math>Y^+</math>. The fifty segments connecting the ten points on <math>X^+</math> to the five points on <math>Y^+</math> are drawn. What is the maximum possible number of points of intersection of these fifty segments that could lie in the interior of the first quadrant?<br />
<br />
<math>\text{(A) } 250\quad<br />
\text{(B) } 450\quad<br />
\text{(C) } 500\quad<br />
\text{(D) } 1250\quad<br />
\text{(E) } 2500</math><br />
<br />
[[1992 AHSME Problems/Problem 22|Solution]]<br />
<br />
<br />
== Problem 23 ==<br />
<br />
Let <math>S</math> be a subset of <math>\{1,2,3,...,50\}</math> such that no pair of distinct elements in <math>S</math> has a sum divisible by <math>7</math>. What is the maximum number of elements in <math>S</math>?<br />
<br />
<math>\text{(A) } 6\quad<br />
\text{(B) } 7\quad<br />
\text{(C) } 14\quad<br />
\text{(D) } 22\quad<br />
\text{(E) } 23</math><br />
<br />
[[1992 AHSME Problems/Problem 23|Solution]]<br />
<br />
== Problem 24 ==<br />
<br />
Let <math>ABCD</math> be a parallelogram of area <math>10</math> with <math>AB=3</math> and <math>BC=5</math>. Locate <math>E,F</math> and <math>G</math> on segments <math>\overline{AB},\overline{BC}</math> and <math>\overline{AD}</math>, respectively, with <math>AE=BF=AG=2</math>. Let the line through <math>G</math> parallel to <math>\overline{EF}</math> intersect <math>\overline{CD}</math> at <math>H</math>. The area of quadrilateral <math>EFHG</math> is<br />
<br />
<math>\text{(A) } 4\quad<br />
\text{(B) } 4.5\quad<br />
\text{(C) } 5\quad<br />
\text{(D) } 5.5\quad<br />
\text{(E) } 6</math><br />
<br />
[[1992 AHSME Problems/Problem 24|Solution]]<br />
<br />
== Problem 25 ==<br />
<br />
In <math>\triangle{ABC}</math>, <math>\angle{ABC}=120^\circ,AB=3</math> and <math>BC=4</math>. If perpendiculars constructed to <math>\overline{AB}</math> at <math>A</math> and to <math>\overline{BC}</math> at <math>C</math> meet at <math>D</math>, then <math>CD=</math><br />
<br />
<math>\text{(A) } 3\quad<br />
\text{(B) } \frac{8}{\sqrt{3}}\quad<br />
\text{(C) } 5\quad<br />
\text{(D) } \frac{11}{2}\quad<br />
\text{(E) } \frac{10}{\sqrt{3}}</math><br />
<br />
[[1992 AHSME Problems/Problem 25|Solution]]<br />
<br />
== Problem 26 ==<br />
<asy><br />
fill((1,0)--arc((1,0),2,180,225)--cycle,grey);<br />
fill((-1,0)--arc((-1,0),2,315,360)--cycle,grey);<br />
fill((0,-1)--arc((0,-1),2-sqrt(2),225,315)--cycle,grey);<br />
fill((0,0)--arc((0,0),1,180,360)--cycle,white);<br />
draw((1,0)--arc((1,0),2,180,225)--(1,0),black+linewidth(1));<br />
draw((-1,0)--arc((-1,0),2,315,360)--(-1,0),black+linewidth(1));<br />
draw((0,0)--arc((0,0),1,180,360)--(0,0),black+linewidth(1));<br />
draw(arc((0,-1),2-sqrt(2),225,315),black+linewidth(1));<br />
draw((0,0)--(0,-1),black+linewidth(1));<br />
MP("C",(0,0),N);MP("A",(-1,0),N);MP("B",(1,0),N);<br />
MP("D",(0,-.8),NW);MP("E",(1-sqrt(2),-sqrt(2)),SW);MP("F",(-1+sqrt(2),-sqrt(2)),SE);<br />
</asy><br />
<br />
Semicircle <math>\widehat{AB}</math> has center <math>C</math> and radius <math>1</math>. Point <math>D</math> is on <math>\widehat{AB}</math> and <math>\overline{CD}\perp\overline{AB}</math>. Extend <math>\overline{BD}</math> and <math>\overline{AD}</math> to <math>E</math> and <math>F</math>, respectively, so that circular arcs <math>\widehat{AE}</math> and <math>\widehat{BF}</math> have <math>B</math> and <math>A</math> as their respective centers. Circular arc <math>\widehat{EF}</math> has center <math>D</math>. The area of the shaded "smile" <math>AEFBDA</math>, is<br />
<br />
<math>\text{(A) } (2-\sqrt{2})\pi\quad<br />
\text{(B) } 2\pi-\pi \sqrt{2}-1\quad<br />
\text{(C) } \left(1-\frac{\sqrt{2}}{2}\right)\pi\quad\\<br />
\text{(D) } \frac{5\pi}{2}-\pi\sqrt{2}-1\quad<br />
\text{(E) } \left(3-2\sqrt{2}\right)\pi</math><br />
<br />
<br />
[[1992 AHSME Problems/Problem 26|Solution]]<br />
<br />
== Problem 27 ==<br />
<br />
<br />
A circle of radius <math>r</math> has chords <math>\overline{AB}</math> of length <math>10</math> and <math>\overline{CD}</math> of length 7. When <math>\overline{AB}</math> and <math>\overline{CD}</math> are extended through <math>B</math> and <math>C</math>, respectively, they intersect at <math>P</math>, which is outside of the circle. If <math>\angle{APD}=60^\circ</math> and <math>BP=8</math>, then <math>r^2=</math><br />
<br />
<math>\text{(A) } 70\quad<br />
\text{(B) } 71\quad<br />
\text{(C) } 72\quad<br />
\text{(D) } 73\quad<br />
\text{(E) } 74</math><br />
[[1992 AHSME Problems/Problem 27|Solution]]<br />
<br />
== Problem 28 ==<br />
<br />
Let <math>i=\sqrt{-1}</math>. The product of the real parts of the roots of <math>z^2-z=5-5i</math> is<br />
<br />
<math>\text{(A) } -25\quad<br />
\text{(B) } -6\quad<br />
\text{(C) } -5\quad<br />
\text{(D) } \frac{1}{4}\quad<br />
\text{(E) } 25</math><br />
<br />
[[1992 AHSME Problems/Problem 28|Solution]]<br />
<br />
== Problem 29 ==<br />
An "unfair" coin has a <math>2/3</math> probability of turning up heads. If this coin is tossed <math>50</math> times, what is the probability that the total number of heads is even?<br />
<br />
<math>\text{(A) } 25\left(\frac{2}{3}\right)^{50}\quad<br />
\text{(B) } \frac{1}{2}\left(1-\frac{1}{3^{50}}\right)\quad<br />
\text{(C) } \frac{1}{2}\quad<br />
\text{(D) } \frac{1}{2}\left(1+\frac{1}{3^{50}}\right)\quad<br />
\text{(E) } \frac{2}{3}</math><br />
<br />
[[1992 AHSME Problems/Problem 29|Solution]]<br />
<br />
== Problem 30 ==<br />
<br />
Let <math>ABCD</math> be an isosceles trapezoid with bases <math>AB=92</math> and <math>CD=19</math>. Suppose <math>AD=BC=x</math> and a circle with center on <math>\overline{AB}</math> is tangent to segments <math>\overline{AD}</math> and <math>\overline{BC}</math>. If <math>m</math> is the smallest possible value of <math>x</math>, then <math>m^2</math>=<br />
<br />
<math>\text{(A) } 1369\quad<br />
\text{(B) } 1679\quad<br />
\text{(C) } 1748\quad<br />
\text{(D) } 2109\quad<br />
\text{(E) } 8825</math><br />
<br />
[[1992 AHSME Problems/Problem 30|Solution]]<br />
<br />
== See also ==<br />
<br />
* [[AMC 12 Problems and Solutions]]<br />
* [[Mathematics competition resources]]<br />
<br />
{{AHSME box|year=1992|before=[[1991 AHSME]]|after=[[1993 AHSME]]}} <br />
<br />
{{MAA Notice}}</div>Scientesthttps://artofproblemsolving.com/wiki/index.php?title=1992_AHSME_Problems&diff=956601992 AHSME Problems2018-06-28T16:30:02Z<p>Scientest: /* Problem 26 */</p>
<hr />
<div>== Problem 1 ==<br />
<br />
If <math>3(4x+5\pi)=P</math> then <math>6(8x+10\pi)=</math><br />
<br />
<math>\text{(A) } 2P\quad<br />
\text{(B) } 4P\quad<br />
\text{(C) } 6P\quad<br />
\text{(D) } 8P\quad<br />
\text{(E) } 18P</math><br />
<br />
[[1992 AHSME Problems/Problem 1|Solution]]<br />
<br />
== Problem 2 ==<br />
An urn is filled with coins and beads, all of which are either silver or gold. Twenty percent of the objects in the urn are beads. Forty percent of the coins in the urn are silver. What percent of objects in the urn are gold coins?<br />
<br />
<math>\text{(A) } 40\%\quad<br />
\text{(B) } 48\%\quad<br />
\text{(C) } 52\%\quad<br />
\text{(D) } 60\%\quad<br />
\text{(E) } 80\%</math><br />
<br />
[[1992 AHSME Problems/Problem 2|Solution]]<br />
<br />
== Problem 3 ==<br />
If <math>m>0</math> and the points <math>(m,3)</math> and <math>(1,m)</math> lie on a line with slope <math>m</math>, then <math>m=</math><br />
<br />
<math>\text{(A) } 1\quad<br />
\text{(B) } \sqrt{2}\quad<br />
\text{(C) } \sqrt{3}\quad<br />
\text{(D) } 2\quad<br />
\text{(E) } \sqrt{5}</math><br />
<br />
[[1992 AHSME Problems/Problem 3|Solution]]<br />
<br />
== Problem 4 ==<br />
<br />
<br />
If <math>a,b</math> and <math>c</math> are positive integers and <math>a</math> and <math>b</math> are odd, then <math>3^a+(b-1)^2c</math> is<br />
<br />
<math>\text{(A) odd for all choices of c} \quad<br />
\text{(B) even for all choices of c} \quad\\<br />
\text{(C) odd if c is even; even if c is odd} \quad\\<br />
\text{(D) odd if c is odd; even if c is even} \quad\\<br />
\text{(E) odd if c is not a multiple of 3; even if c is a multiple of 3} </math><br />
<br />
[[1992 AHSME Problems/Problem 4|Solution]]<br />
<br />
== Problem 5 ==<br />
<br />
<math>6^6+6^6+6^6+6^6+6^6+6^6=</math><br />
<br />
<math>\text{(A) } 6^6 \quad<br />
\text{(B) } 6^7\quad<br />
\text{(C) } 36^6\quad<br />
\text{(D) } 6^{36}\quad<br />
\text{(E) } 36^{36}</math><br />
<br />
[[1992 AHSME Problems/Problem 5|Solution]]<br />
<br />
== Problem 6 ==<br />
<br />
If <math>x>y>0</math> , then <math>\frac{x^y y^x}{y^y x^x}=</math><br />
<br />
<br />
<math>\text{(A) } (x-y)^{y/x}\quad<br />
\text{(B) } \left(\frac{x}{y}\right)^{x-y}\quad<br />
\text{(C) } 1\quad<br />
\text{(D) } \left(\frac{x}{y}\right)^{y-x}\quad<br />
\text{(E) } (x-y)^{x/y}</math><br />
<br />
[[1992 AHSME Problems/Problem 6|Solution]]<br />
<br />
== Problem 7 ==<br />
The ratio of <math>w</math> to <math>x</math> is <math>4:3</math>, of <math>y</math> to <math>z</math> is <math>3:2</math> and of <math>z</math> to <math>x</math> is <math>1:6</math>. What is the ratio of <math>w</math> to <math>y</math>?<br />
<br />
<math>\text{(A) } 1:3\quad<br />
\text{(B) } 16:3\quad<br />
\text{(C) } 20:3\quad<br />
\text{(D) } 27:4\quad<br />
\text{(E) } 12:1</math><br />
<br />
[[1992 AHSME Problems/Problem 7|Solution]]<br />
<br />
== Problem 8 ==<br />
<asy><br />
draw((-10,-10)--(-10,10)--(10,10)--(10,-10)--cycle,dashed+linewidth(.75));<br />
draw((-7,-7)--(-7,7)--(7,7)--(7,-7)--cycle,dashed+linewidth(.75));<br />
draw((-10,-10)--(10,10),dashed+linewidth(.75));<br />
draw((-10,10)--(10,-10),dashed+linewidth(.75));<br />
fill((10,10)--(10,9)--(9,9)--(9,10)--cycle,black);<br />
fill((9,9)--(9,8)--(8,8)--(8,9)--cycle,black);<br />
fill((8,8)--(8,7)--(7,7)--(7,8)--cycle,black);<br />
fill((-10,-10)--(-10,-9)--(-9,-9)--(-9,-10)--cycle,black);<br />
fill((-9,-9)--(-9,-8)--(-8,-8)--(-8,-9)--cycle,black);<br />
fill((-8,-8)--(-8,-7)--(-7,-7)--(-7,-8)--cycle,black);<br />
fill((10,-10)--(10,-9)--(9,-9)--(9,-10)--cycle,black);<br />
fill((9,-9)--(9,-8)--(8,-8)--(8,-9)--cycle,black);<br />
fill((8,-8)--(8,-7)--(7,-7)--(7,-8)--cycle,black);<br />
fill((-10,10)--(-10,9)--(-9,9)--(-9,10)--cycle,black);<br />
fill((-9,9)--(-9,8)--(-8,8)--(-8,9)--cycle,black);<br />
fill((-8,8)--(-8,7)--(-7,7)--(-7,8)--cycle,black);<br />
</asy><br />
<br />
A square floor is tiled with congruent square tiles. The tiles on the two diagonals of the floor are black. The rest of the tiles are white. If there are 101 black tiles, then the total number of tiles is<br />
<br />
<math>\text{(A) } 121\quad<br />
\text{(B) } 625\quad<br />
\text{(C) } 676\quad<br />
\text{(D) } 2500\quad<br />
\text{(E) } 2601</math><br />
<br />
<br />
[[1992 AHSME Problems/Problem 8|Solution]]<br />
<br />
== Problem 9 ==<br />
<asy><br />
draw((-7,0)--(7,0),black+linewidth(.75));<br />
draw((-3*sqrt(3),0)--(-2*sqrt(3),3)--(-sqrt(3),0)--(0,3)--(sqrt(3),0)--(2*sqrt(3),3)--(3*sqrt(3),0),black+linewidth(.75));<br />
draw((-2*sqrt(3),0)--(-1*sqrt(3),3)--(0,0)--(sqrt(3),3)--(2*sqrt(3),0),black+linewidth(.75));<br />
</asy><br />
<br />
Five equilateral triangles, each with side <math>2\sqrt{3}</math>, are arranged so they are all on the same side of a line containing one side of each vertex. Along this line, the midpoint of the base of one triangle is a vertex of the next. The area of the region of the plane that is covered by the union of the five triangular regions is<br />
<br />
<math>\text{(A) 10} \quad<br />
\text{(B) } 12\quad<br />
\text{(C) } 15\quad<br />
\text{(D) } 10\sqrt{3}\quad<br />
\text{(E) } 12\sqrt{3}</math><br />
<br />
[[1992 AHSME Problems/Problem 9|Solution]]<br />
<br />
== Problem 10 ==<br />
<br />
The number of positive integers <math>k</math> for which the equation<br />
<cmath>kx-12=3k</cmath><br />
has an integer solution for <math>x</math> is<br />
<br />
<math>\text{(A) } 3\quad<br />
\text{(B) } 4\quad<br />
\text{(C) } 5\quad<br />
\text{(D) } 6\quad<br />
\text{(E) } 7</math><br />
<br />
<br />
[[1992 AHSME Problems/Problem 10|Solution]]<br />
<br />
== Problem 11 ==<br />
<asy><br />
draw(circle((0,0),18),black+linewidth(.75));<br />
draw(circle((0,0),6),black+linewidth(.75));<br />
draw((-18,0)--(18,0)--(-14,8*sqrt(2))--cycle,black+linewidth(.75));<br />
dot((-18,0));dot((18,0));dot((-14,8*sqrt(2)));<br />
MP("A",(-18,0),W);MP("C",(18,0),E);MP("B",(-14,8*sqrt(2)),W);<br />
</asy><br />
<br />
The ratio of the radii of two concentric circles is <math>1:3</math>. If <math>\overline{AC}</math> is a diameter of the larger circle, <math>\overline{BC}</math> is a chord of the larger circle that is tangent to the smaller circle, and <math>AB=12</math>, then the radius of the larger circle is<br />
<br />
<math>\text{(A) } 13\quad<br />
\text{(B) } 18\quad<br />
\text{(C) } 21\quad<br />
\text{(D) } 24\quad<br />
\text{(E) } 26</math><br />
<br />
[[1992 AHSME Problems/Problem 11|Solution]]<br />
<br />
== Problem 12 ==<br />
Let <math>y=mx+b</math> be the image when the line <math>x-3y+11=0</math> is reflected across the <math>x</math>-axis. The value of <math>m+b</math> is<br />
<br />
<math>\text{(A) -6} \quad<br />
\text{(B) } -5\quad<br />
\text{(C) } -4\quad<br />
\text{(D) } -3\quad<br />
\text{(E) } -2</math><br />
<br />
[[1992 AHSME Problems/Problem 12|Solution]]<br />
<br />
== Problem 13 ==<br />
<br />
How many pairs of positive integers <math>(a,b)</math> with <math>a+b\le 100</math> satisfy the equation<br />
<br />
<cmath>\frac{a+b^{-1}}{a^{-1}+b}=13?</cmath><br />
<br />
<math>\text{(A) } 1\quad<br />
\text{(B) } 5\quad<br />
\text{(C) } 7\quad<br />
\text{(D) } 9\quad<br />
\text{(E) } 13</math><br />
<br />
[[1992 AHSME Problems/Problem 13|Solution]]<br />
<br />
== Problem 14 ==<br />
Which of the following equations have the same graph?<br />
<br />
<math>I.\quad y=x-2 \qquad II.\quad y=\frac{x^2-4}{x+2}\qquad III.\quad (x+2)y=x^2-4</math><br />
<br />
<math>\text{(A) I and II only} \quad<br />
\text{(B) I and III only} \quad<br />
\text{(C) II and III only} \quad<br />
\text{(D) I,II,and III} \quad \\<br />
\text{(E) None. All of the equations have different graphs} </math><br />
<br />
[[1992 AHSME Problems/Problem 14|Solution]]<br />
<br />
== Problem 15 ==<br />
<br />
Let <math>i=\sqrt{-1}</math>. Define a sequence of complex numbers by<br />
<br />
<cmath>z_1=0,\quad z_{n+1}=z_{n}^2+i \text{ for } n\ge1.</cmath><br />
In the complex plane, how far from the origin is <math>z_{111}</math>?<br />
<br />
<math>\text{(A) } 1\quad<br />
\text{(B) } \sqrt{2}\quad<br />
\text{(C) } \sqrt{3}\quad<br />
\text{(D) } \sqrt{110}\quad<br />
\text{(E) } \sqrt{2^{55}}</math><br />
<br />
[[1992 AHSME Problems/Problem 15|Solution]]<br />
<br />
== Problem 16 ==<br />
If<br />
<cmath>\frac{y}{x-z}=\frac{x+y}{z}=\frac{x}{y}</cmath><br />
for three positive numbers <math>x,y</math> and <math>z</math>, all different, then <math>\frac{x}{y}=</math><br />
<br />
<math>\text{(A) } \frac{1}{2}\quad<br />
\text{(B) } \frac{3}{5}\quad<br />
\text{(C) } \frac{2}{3}\quad<br />
\text{(D) } \frac{5}{3}\quad<br />
\text{(E) } 2</math><br />
<br />
[[1992 AHSME Problems/Problem 16|Solution]]<br />
<br />
== Problem 17 ==<br />
The 2-digit integers from 19 to 92 are written consecutively to form the integer <math>N=192021\cdots9192</math>. Suppose that <math>3^k</math> is the highest power of 3 that is a factor of <math>N</math>. What is <math>k</math>?<br />
<br />
<math>\text{(A) } 0\quad<br />
\text{(B) } 1\quad<br />
\text{(C) } 2\quad<br />
\text{(D) } 3\quad<br />
\text{(E) more than } 3</math><br />
<br />
[[1992 AHSME Problems/Problem 17|Solution]]<br />
<br />
== Problem 18 ==<br />
The increasing sequence of positive integers <math>a_1,a_2,a_3,\cdots </math> has the property that<br />
<br />
<cmath>a_{n+2}=a_n+a_{n+1} \text{ for all } n\ge 1.</cmath><br />
<br />
If <math>a_7=120</math>, then <math>a_8</math> is<br />
<br />
<math>\text{(A) } 128\quad<br />
\text{(B) } 168\quad<br />
\text{(C) } 193\quad<br />
\text{(D) } 194\quad<br />
\text{(E) } 210</math><br />
<br />
[[1992 AHSME Problems/Problem 18|Solution]]<br />
<br />
== Problem 19 ==<br />
<br />
<br />
For each vertex of a solid cube, consider the tetrahedron determined by the vertex and the midpoints of the three edges that meet at that vertex. The portion of the cube that remains when these eight tetrahedra are cut away is called a cubeoctahedron. The ratio of the volume of the cubeoctahedron to the volume of the original cube is closest to which of these?<br />
<br />
<math>\text{(A) } 75\%\quad<br />
\text{(B) } 78\%\quad<br />
\text{(C) } 81\%\quad<br />
\text{(D) } 84\%\quad<br />
\text{(E) } 87\%</math><br />
<br />
[[1992 AHSME Problems/Problem 19|Solution]]<br />
<br />
== Problem 20 ==<br />
<br />
<asy><br />
draw((1,0)--(2*cos(pi/8),2*sin(pi/8))--(cos(pi/4),sin(pi/4))--(2*cos(3*pi/8),2*sin(3*pi/8))--(cos(pi/2),sin(pi/2))--(2*cos(5*pi/8),2*sin(5*pi/8))--(cos(3*pi/4),sin(3*pi/4))--(2*cos(7*pi/8),2*sin(7*pi/8))--(-1,0),black+linewidth(.75));<br />
MP("A_1",(2*cos(5*pi/8),2*sin(5*pi/8)),N);MP("A_2",(2*cos(3*pi/8),2*sin(3*pi/8)),N);MP("A_3",(2*cos(1*pi/8),2*sin(1*pi/8)),N);<br />
MP("A_n",(2*cos(7*pi/8),2*sin(7*pi/8)),N);<br />
MP("B_1",(cos(4*pi/8),sin(4*pi/8)),S);MP("B_2",(cos(2*pi/8),sin(2*pi/8)),S);MP("B_n",(cos(6*pi/8),sin(6*pi/8)),S);<br />
</asy><br />
Part of an "n-pointed regular star" is shown. It is a simple closed polygon in which all <math>2n</math> edges are congruent, angles <math>A_1,A_2,\cdots,A_n</math> are congruent, and angles <math>B_1,B_2,\cdots,B_n</math> are congruent. If the acute angle at <math>A_1</math> is <math>10^\circ</math> less than the acute angle at <math>B_1</math>, then <math>n=</math><br />
<br />
<math>\text{(A) } 12\quad<br />
\text{(B) } 18\quad<br />
\text{(C) } 24\quad<br />
\text{(D) } 36\quad<br />
\text{(E) } 60</math><br />
<br />
[[1992 AHSME Problems/Problem 20|Solution]]<br />
<br />
== Problem 21 ==<br />
<br />
For a finite sequence <math>A=(a_1,a_2,...,a_n)</math> of numbers, the ''Cesáro sum'' of A is defined to be <br />
<math>\frac{S_1+\cdots+S_n}{n}</math> , where <math>S_k=a_1+\cdots+a_k</math> and <math>1\leq k\leq n</math>. If the Cesáro sum of<br />
the 99-term sequence <math>(a_1,...,a_{99})</math> is 1000, what is the Cesáro sum of the 100-term sequence <br />
<math>(1,a_1,...,a_{99})</math>?<br />
<br />
<math>\text{(A) } 991\quad<br />
\text{(B) } 999\quad<br />
\text{(C) } 1000\quad<br />
\text{(D) } 1001\quad<br />
\text{(E) } 1009</math><br />
<br />
[[1992 AHSME Problems/Problem 21|Solution]]<br />
<br />
== Problem 22 ==<br />
<br />
Ten points are selected on the positive <math>x</math>-axis,<math>X^+</math>, and five points are selected on the positive <math>y</math>-axis,<math>Y^+</math>. The fifty segments connecting the ten points on <math>X^+</math> to the five points on <math>Y^+</math> are drawn. What is the maximum possible number of points of intersection of these fifty segments that could lie in the interior of the first quadrant?<br />
<br />
<math>\text{(A) } 250\quad<br />
\text{(B) } 450\quad<br />
\text{(C) } 500\quad<br />
\text{(D) } 1250\quad<br />
\text{(E) } 2500</math><br />
<br />
[[1992 AHSME Problems/Problem 22|Solution]]<br />
<br />
<br />
== Problem 23 ==<br />
<br />
Let <math>S</math> be a subset of <math>\{1,2,3,...,50\}</math> such that no pair of distinct elements in <math>S</math> has a sum divisible by <math>7</math>. What is the maximum number of elements in <math>S</math>?<br />
<br />
<math>\text{(A) } 6\quad<br />
\text{(B) } 7\quad<br />
\text{(C) } 14\quad<br />
\text{(D) } 22\quad<br />
\text{(E) } 23</math><br />
<br />
[[1992 AHSME Problems/Problem 23|Solution]]<br />
<br />
== Problem 24 ==<br />
<br />
Let <math>ABCD</math> be a parallelogram of area <math>10</math> with <math>AB=3</math> and <math>BC=5</math>. Locate <math>E,F</math> and <math>G</math> on segments <math>\overline{AB},\overline{BC}</math> and <math>\overline{AD}</math>, respectively, with <math>AE=BF=AG=2</math>. Let the line through <math>G</math> parallel to <math>\overline{EF}</math> intersect <math>\overline{CD}</math> at <math>H</math>. The area of quadrilateral <math>EFHG</math> is<br />
<br />
<math>\text{(A) } 4\quad<br />
\text{(B) } 4.5\quad<br />
\text{(C) } 5\quad<br />
\text{(D) } 5.5\quad<br />
\text{(E) } 6</math><br />
<br />
[[1992 AHSME Problems/Problem 24|Solution]]<br />
<br />
== Problem 25 ==<br />
<br />
In <math>\triangle{ABC}</math>, <math>\angle{ABC}=120^\circ,AB=3</math> and <math>BC=4</math>. If perpendiculars constructed to <math>\overline{AB}</math> at <math>A</math> and to <math>\overline{BC}</math> at <math>C</math> meet at <math>D</math>, then <math>CD=</math><br />
<br />
<math>\text{(A) } 3\quad<br />
\text{(B) } \frac{8}{\sqrt{3}}\quad<br />
\text{(C) } 5\quad<br />
\text{(D) } \frac{11}{2}\quad<br />
\text{(E) } \frac{10}{\sqrt{3}}</math><br />
<br />
[[1992 AHSME Problems/Problem 25|Solution]]<br />
<br />
== Problem 26 ==<br />
<asy><br />
fill((1,0)--arc((1,0),2,180,225)--cycle,grey);<br />
fill((-1,0)--arc((-1,0),2,315,360)--cycle,grey);<br />
fill((0,-1)--arc((0,-1),2-sqrt(2),225,315)--cycle,grey);<br />
fill((0,0)--arc((0,0),1,180,360)--cycle,white);<br />
draw((1,0)--arc((1,0),2,180,225)--(1,0),black+linewidth(1));<br />
draw((-1,0)--arc((-1,0),2,315,360)--(-1,0),black+linewidth(1));<br />
draw((0,0)--arc((0,0),1,180,360)--(0,0),black+linewidth(1));<br />
draw(arc((0,-1),2-sqrt(2),225,315),black+linewidth(1));<br />
draw((0,0)--(0,-1),black+linewidth(1));<br />
MP("C",(0,0),N);MP("A",(-1,0),N);MP("B",(1,0),N);<br />
MP("D",(0,-.8),NW);MP("E",(1-sqrt(2),-sqrt(2)),SW);MP("F",(-1+sqrt(2),-sqrt(2)),SE);<br />
</asy><br />
<br />
Semicircle <math>\widehat{AB}</math> has center <math>C</math> and radius <math>1</math>. Point <math>D</math> is on <math>\widehat{AB}</math> and <math>\overline{CD}\perp\overline{AB}</math>. Extend <math>\overline{BD}</math> and <math>\overline{AD}</math> to <math>E</math> and <math>F</math>, respectively, so that circular arcs <math>\widehat{AE}</math> and <math>\widehat{BF}</math> have <math>B</math> and <math>A</math> as their respective centers. Circular arc <math>\widehat{EF}</math> has center <math>D</math>. The area of the shaded "smile" <math>AEFBDA</math>, is<br />
<br />
<math>\text{(A) } (2-\sqrt{2})\pi\quad<br />
\text{(B) } 2\pi-\pi \sqrt{2}-1\quad<br />
\text{(C) } \left(1-\frac{\sqrt{2}}{2}\right)\pi\quad\\<br />
\text{(D) } \frac{5\pi}{2}-\pi\sqrt{2}-1\quad<br />
\text{(E) } \right(3-2\sqrt{2}\left)\pi</math><br />
<br />
<br />
[[1992 AHSME Problems/Problem 26|Solution]]<br />
<br />
== Problem 27 ==<br />
<br />
<br />
A circle of radius <math>r</math> has chords <math>\overline{AB}</math> of length <math>10</math> and <math>\overline{CD}</math> of length 7. When <math>\overline{AB}</math> and <math>\overline{CD}</math> are extended through <math>B</math> and <math>C</math>, respectively, they intersect at <math>P</math>, which is outside of the circle. If <math>\angle{APD}=60^\circ</math> and <math>BP=8</math>, then <math>r^2=</math><br />
<br />
<math>\text{(A) } 70\quad<br />
\text{(B) } 71\quad<br />
\text{(C) } 72\quad<br />
\text{(D) } 73\quad<br />
\text{(E) } 74</math><br />
[[1992 AHSME Problems/Problem 27|Solution]]<br />
<br />
== Problem 28 ==<br />
<br />
Let <math>i=\sqrt{-1}</math>. The product of the real parts of the roots of <math>z^2-z=5-5i</math> is<br />
<br />
<math>\text{(A) } -25\quad<br />
\text{(B) } -6\quad<br />
\text{(C) } -5\quad<br />
\text{(D) } \frac{1}{4}\quad<br />
\text{(E) } 25</math><br />
<br />
[[1992 AHSME Problems/Problem 28|Solution]]<br />
<br />
== Problem 29 ==<br />
An "unfair" coin has a <math>2/3</math> probability of turning up heads. If this coin is tossed <math>50</math> times, what is the probability that the total number of heads is even?<br />
<br />
<math>\text{(A) } 25\left(\frac{2}{3}\right)^{50}\quad<br />
\text{(B) } \frac{1}{2}\left(1-\frac{1}{3^{50}}\right)\quad<br />
\text{(C) } \frac{1}{2}\quad<br />
\text{(D) } \frac{1}{2}\left(1+\frac{1}{3^{50}}\right)\quad<br />
\text{(E) } \frac{2}{3}</math><br />
<br />
[[1992 AHSME Problems/Problem 29|Solution]]<br />
<br />
== Problem 30 ==<br />
<br />
Let <math>ABCD</math> be an isosceles trapezoid with bases <math>AB=92</math> and <math>CD=19</math>. Suppose <math>AD=BC=x</math> and a circle with center on <math>\overline{AB}</math> is tangent to segments <math>\overline{AD}</math> and <math>\overline{BC}</math>. If <math>m</math> is the smallest possible value of <math>x</math>, then <math>m^2</math>=<br />
<br />
<math>\text{(A) } 1369\quad<br />
\text{(B) } 1679\quad<br />
\text{(C) } 1748\quad<br />
\text{(D) } 2109\quad<br />
\text{(E) } 8825</math><br />
<br />
[[1992 AHSME Problems/Problem 30|Solution]]<br />
<br />
== See also ==<br />
<br />
* [[AMC 12 Problems and Solutions]]<br />
* [[Mathematics competition resources]]<br />
<br />
{{AHSME box|year=1992|before=[[1991 AHSME]]|after=[[1993 AHSME]]}} <br />
<br />
{{MAA Notice}}</div>Scientesthttps://artofproblemsolving.com/wiki/index.php?title=1992_AHSME_Problems&diff=956591992 AHSME Problems2018-06-28T16:29:35Z<p>Scientest: /* Problem 29 */ LaTeX formatting</p>
<hr />
<div>== Problem 1 ==<br />
<br />
If <math>3(4x+5\pi)=P</math> then <math>6(8x+10\pi)=</math><br />
<br />
<math>\text{(A) } 2P\quad<br />
\text{(B) } 4P\quad<br />
\text{(C) } 6P\quad<br />
\text{(D) } 8P\quad<br />
\text{(E) } 18P</math><br />
<br />
[[1992 AHSME Problems/Problem 1|Solution]]<br />
<br />
== Problem 2 ==<br />
An urn is filled with coins and beads, all of which are either silver or gold. Twenty percent of the objects in the urn are beads. Forty percent of the coins in the urn are silver. What percent of objects in the urn are gold coins?<br />
<br />
<math>\text{(A) } 40\%\quad<br />
\text{(B) } 48\%\quad<br />
\text{(C) } 52\%\quad<br />
\text{(D) } 60\%\quad<br />
\text{(E) } 80\%</math><br />
<br />
[[1992 AHSME Problems/Problem 2|Solution]]<br />
<br />
== Problem 3 ==<br />
If <math>m>0</math> and the points <math>(m,3)</math> and <math>(1,m)</math> lie on a line with slope <math>m</math>, then <math>m=</math><br />
<br />
<math>\text{(A) } 1\quad<br />
\text{(B) } \sqrt{2}\quad<br />
\text{(C) } \sqrt{3}\quad<br />
\text{(D) } 2\quad<br />
\text{(E) } \sqrt{5}</math><br />
<br />
[[1992 AHSME Problems/Problem 3|Solution]]<br />
<br />
== Problem 4 ==<br />
<br />
<br />
If <math>a,b</math> and <math>c</math> are positive integers and <math>a</math> and <math>b</math> are odd, then <math>3^a+(b-1)^2c</math> is<br />
<br />
<math>\text{(A) odd for all choices of c} \quad<br />
\text{(B) even for all choices of c} \quad\\<br />
\text{(C) odd if c is even; even if c is odd} \quad\\<br />
\text{(D) odd if c is odd; even if c is even} \quad\\<br />
\text{(E) odd if c is not a multiple of 3; even if c is a multiple of 3} </math><br />
<br />
[[1992 AHSME Problems/Problem 4|Solution]]<br />
<br />
== Problem 5 ==<br />
<br />
<math>6^6+6^6+6^6+6^6+6^6+6^6=</math><br />
<br />
<math>\text{(A) } 6^6 \quad<br />
\text{(B) } 6^7\quad<br />
\text{(C) } 36^6\quad<br />
\text{(D) } 6^{36}\quad<br />
\text{(E) } 36^{36}</math><br />
<br />
[[1992 AHSME Problems/Problem 5|Solution]]<br />
<br />
== Problem 6 ==<br />
<br />
If <math>x>y>0</math> , then <math>\frac{x^y y^x}{y^y x^x}=</math><br />
<br />
<br />
<math>\text{(A) } (x-y)^{y/x}\quad<br />
\text{(B) } \left(\frac{x}{y}\right)^{x-y}\quad<br />
\text{(C) } 1\quad<br />
\text{(D) } \left(\frac{x}{y}\right)^{y-x}\quad<br />
\text{(E) } (x-y)^{x/y}</math><br />
<br />
[[1992 AHSME Problems/Problem 6|Solution]]<br />
<br />
== Problem 7 ==<br />
The ratio of <math>w</math> to <math>x</math> is <math>4:3</math>, of <math>y</math> to <math>z</math> is <math>3:2</math> and of <math>z</math> to <math>x</math> is <math>1:6</math>. What is the ratio of <math>w</math> to <math>y</math>?<br />
<br />
<math>\text{(A) } 1:3\quad<br />
\text{(B) } 16:3\quad<br />
\text{(C) } 20:3\quad<br />
\text{(D) } 27:4\quad<br />
\text{(E) } 12:1</math><br />
<br />
[[1992 AHSME Problems/Problem 7|Solution]]<br />
<br />
== Problem 8 ==<br />
<asy><br />
draw((-10,-10)--(-10,10)--(10,10)--(10,-10)--cycle,dashed+linewidth(.75));<br />
draw((-7,-7)--(-7,7)--(7,7)--(7,-7)--cycle,dashed+linewidth(.75));<br />
draw((-10,-10)--(10,10),dashed+linewidth(.75));<br />
draw((-10,10)--(10,-10),dashed+linewidth(.75));<br />
fill((10,10)--(10,9)--(9,9)--(9,10)--cycle,black);<br />
fill((9,9)--(9,8)--(8,8)--(8,9)--cycle,black);<br />
fill((8,8)--(8,7)--(7,7)--(7,8)--cycle,black);<br />
fill((-10,-10)--(-10,-9)--(-9,-9)--(-9,-10)--cycle,black);<br />
fill((-9,-9)--(-9,-8)--(-8,-8)--(-8,-9)--cycle,black);<br />
fill((-8,-8)--(-8,-7)--(-7,-7)--(-7,-8)--cycle,black);<br />
fill((10,-10)--(10,-9)--(9,-9)--(9,-10)--cycle,black);<br />
fill((9,-9)--(9,-8)--(8,-8)--(8,-9)--cycle,black);<br />
fill((8,-8)--(8,-7)--(7,-7)--(7,-8)--cycle,black);<br />
fill((-10,10)--(-10,9)--(-9,9)--(-9,10)--cycle,black);<br />
fill((-9,9)--(-9,8)--(-8,8)--(-8,9)--cycle,black);<br />
fill((-8,8)--(-8,7)--(-7,7)--(-7,8)--cycle,black);<br />
</asy><br />
<br />
A square floor is tiled with congruent square tiles. The tiles on the two diagonals of the floor are black. The rest of the tiles are white. If there are 101 black tiles, then the total number of tiles is<br />
<br />
<math>\text{(A) } 121\quad<br />
\text{(B) } 625\quad<br />
\text{(C) } 676\quad<br />
\text{(D) } 2500\quad<br />
\text{(E) } 2601</math><br />
<br />
<br />
[[1992 AHSME Problems/Problem 8|Solution]]<br />
<br />
== Problem 9 ==<br />
<asy><br />
draw((-7,0)--(7,0),black+linewidth(.75));<br />
draw((-3*sqrt(3),0)--(-2*sqrt(3),3)--(-sqrt(3),0)--(0,3)--(sqrt(3),0)--(2*sqrt(3),3)--(3*sqrt(3),0),black+linewidth(.75));<br />
draw((-2*sqrt(3),0)--(-1*sqrt(3),3)--(0,0)--(sqrt(3),3)--(2*sqrt(3),0),black+linewidth(.75));<br />
</asy><br />
<br />
Five equilateral triangles, each with side <math>2\sqrt{3}</math>, are arranged so they are all on the same side of a line containing one side of each vertex. Along this line, the midpoint of the base of one triangle is a vertex of the next. The area of the region of the plane that is covered by the union of the five triangular regions is<br />
<br />
<math>\text{(A) 10} \quad<br />
\text{(B) } 12\quad<br />
\text{(C) } 15\quad<br />
\text{(D) } 10\sqrt{3}\quad<br />
\text{(E) } 12\sqrt{3}</math><br />
<br />
[[1992 AHSME Problems/Problem 9|Solution]]<br />
<br />
== Problem 10 ==<br />
<br />
The number of positive integers <math>k</math> for which the equation<br />
<cmath>kx-12=3k</cmath><br />
has an integer solution for <math>x</math> is<br />
<br />
<math>\text{(A) } 3\quad<br />
\text{(B) } 4\quad<br />
\text{(C) } 5\quad<br />
\text{(D) } 6\quad<br />
\text{(E) } 7</math><br />
<br />
<br />
[[1992 AHSME Problems/Problem 10|Solution]]<br />
<br />
== Problem 11 ==<br />
<asy><br />
draw(circle((0,0),18),black+linewidth(.75));<br />
draw(circle((0,0),6),black+linewidth(.75));<br />
draw((-18,0)--(18,0)--(-14,8*sqrt(2))--cycle,black+linewidth(.75));<br />
dot((-18,0));dot((18,0));dot((-14,8*sqrt(2)));<br />
MP("A",(-18,0),W);MP("C",(18,0),E);MP("B",(-14,8*sqrt(2)),W);<br />
</asy><br />
<br />
The ratio of the radii of two concentric circles is <math>1:3</math>. If <math>\overline{AC}</math> is a diameter of the larger circle, <math>\overline{BC}</math> is a chord of the larger circle that is tangent to the smaller circle, and <math>AB=12</math>, then the radius of the larger circle is<br />
<br />
<math>\text{(A) } 13\quad<br />
\text{(B) } 18\quad<br />
\text{(C) } 21\quad<br />
\text{(D) } 24\quad<br />
\text{(E) } 26</math><br />
<br />
[[1992 AHSME Problems/Problem 11|Solution]]<br />
<br />
== Problem 12 ==<br />
Let <math>y=mx+b</math> be the image when the line <math>x-3y+11=0</math> is reflected across the <math>x</math>-axis. The value of <math>m+b</math> is<br />
<br />
<math>\text{(A) -6} \quad<br />
\text{(B) } -5\quad<br />
\text{(C) } -4\quad<br />
\text{(D) } -3\quad<br />
\text{(E) } -2</math><br />
<br />
[[1992 AHSME Problems/Problem 12|Solution]]<br />
<br />
== Problem 13 ==<br />
<br />
How many pairs of positive integers <math>(a,b)</math> with <math>a+b\le 100</math> satisfy the equation<br />
<br />
<cmath>\frac{a+b^{-1}}{a^{-1}+b}=13?</cmath><br />
<br />
<math>\text{(A) } 1\quad<br />
\text{(B) } 5\quad<br />
\text{(C) } 7\quad<br />
\text{(D) } 9\quad<br />
\text{(E) } 13</math><br />
<br />
[[1992 AHSME Problems/Problem 13|Solution]]<br />
<br />
== Problem 14 ==<br />
Which of the following equations have the same graph?<br />
<br />
<math>I.\quad y=x-2 \qquad II.\quad y=\frac{x^2-4}{x+2}\qquad III.\quad (x+2)y=x^2-4</math><br />
<br />
<math>\text{(A) I and II only} \quad<br />
\text{(B) I and III only} \quad<br />
\text{(C) II and III only} \quad<br />
\text{(D) I,II,and III} \quad \\<br />
\text{(E) None. All of the equations have different graphs} </math><br />
<br />
[[1992 AHSME Problems/Problem 14|Solution]]<br />
<br />
== Problem 15 ==<br />
<br />
Let <math>i=\sqrt{-1}</math>. Define a sequence of complex numbers by<br />
<br />
<cmath>z_1=0,\quad z_{n+1}=z_{n}^2+i \text{ for } n\ge1.</cmath><br />
In the complex plane, how far from the origin is <math>z_{111}</math>?<br />
<br />
<math>\text{(A) } 1\quad<br />
\text{(B) } \sqrt{2}\quad<br />
\text{(C) } \sqrt{3}\quad<br />
\text{(D) } \sqrt{110}\quad<br />
\text{(E) } \sqrt{2^{55}}</math><br />
<br />
[[1992 AHSME Problems/Problem 15|Solution]]<br />
<br />
== Problem 16 ==<br />
If<br />
<cmath>\frac{y}{x-z}=\frac{x+y}{z}=\frac{x}{y}</cmath><br />
for three positive numbers <math>x,y</math> and <math>z</math>, all different, then <math>\frac{x}{y}=</math><br />
<br />
<math>\text{(A) } \frac{1}{2}\quad<br />
\text{(B) } \frac{3}{5}\quad<br />
\text{(C) } \frac{2}{3}\quad<br />
\text{(D) } \frac{5}{3}\quad<br />
\text{(E) } 2</math><br />
<br />
[[1992 AHSME Problems/Problem 16|Solution]]<br />
<br />
== Problem 17 ==<br />
The 2-digit integers from 19 to 92 are written consecutively to form the integer <math>N=192021\cdots9192</math>. Suppose that <math>3^k</math> is the highest power of 3 that is a factor of <math>N</math>. What is <math>k</math>?<br />
<br />
<math>\text{(A) } 0\quad<br />
\text{(B) } 1\quad<br />
\text{(C) } 2\quad<br />
\text{(D) } 3\quad<br />
\text{(E) more than } 3</math><br />
<br />
[[1992 AHSME Problems/Problem 17|Solution]]<br />
<br />
== Problem 18 ==<br />
The increasing sequence of positive integers <math>a_1,a_2,a_3,\cdots </math> has the property that<br />
<br />
<cmath>a_{n+2}=a_n+a_{n+1} \text{ for all } n\ge 1.</cmath><br />
<br />
If <math>a_7=120</math>, then <math>a_8</math> is<br />
<br />
<math>\text{(A) } 128\quad<br />
\text{(B) } 168\quad<br />
\text{(C) } 193\quad<br />
\text{(D) } 194\quad<br />
\text{(E) } 210</math><br />
<br />
[[1992 AHSME Problems/Problem 18|Solution]]<br />
<br />
== Problem 19 ==<br />
<br />
<br />
For each vertex of a solid cube, consider the tetrahedron determined by the vertex and the midpoints of the three edges that meet at that vertex. The portion of the cube that remains when these eight tetrahedra are cut away is called a cubeoctahedron. The ratio of the volume of the cubeoctahedron to the volume of the original cube is closest to which of these?<br />
<br />
<math>\text{(A) } 75\%\quad<br />
\text{(B) } 78\%\quad<br />
\text{(C) } 81\%\quad<br />
\text{(D) } 84\%\quad<br />
\text{(E) } 87\%</math><br />
<br />
[[1992 AHSME Problems/Problem 19|Solution]]<br />
<br />
== Problem 20 ==<br />
<br />
<asy><br />
draw((1,0)--(2*cos(pi/8),2*sin(pi/8))--(cos(pi/4),sin(pi/4))--(2*cos(3*pi/8),2*sin(3*pi/8))--(cos(pi/2),sin(pi/2))--(2*cos(5*pi/8),2*sin(5*pi/8))--(cos(3*pi/4),sin(3*pi/4))--(2*cos(7*pi/8),2*sin(7*pi/8))--(-1,0),black+linewidth(.75));<br />
MP("A_1",(2*cos(5*pi/8),2*sin(5*pi/8)),N);MP("A_2",(2*cos(3*pi/8),2*sin(3*pi/8)),N);MP("A_3",(2*cos(1*pi/8),2*sin(1*pi/8)),N);<br />
MP("A_n",(2*cos(7*pi/8),2*sin(7*pi/8)),N);<br />
MP("B_1",(cos(4*pi/8),sin(4*pi/8)),S);MP("B_2",(cos(2*pi/8),sin(2*pi/8)),S);MP("B_n",(cos(6*pi/8),sin(6*pi/8)),S);<br />
</asy><br />
Part of an "n-pointed regular star" is shown. It is a simple closed polygon in which all <math>2n</math> edges are congruent, angles <math>A_1,A_2,\cdots,A_n</math> are congruent, and angles <math>B_1,B_2,\cdots,B_n</math> are congruent. If the acute angle at <math>A_1</math> is <math>10^\circ</math> less than the acute angle at <math>B_1</math>, then <math>n=</math><br />
<br />
<math>\text{(A) } 12\quad<br />
\text{(B) } 18\quad<br />
\text{(C) } 24\quad<br />
\text{(D) } 36\quad<br />
\text{(E) } 60</math><br />
<br />
[[1992 AHSME Problems/Problem 20|Solution]]<br />
<br />
== Problem 21 ==<br />
<br />
For a finite sequence <math>A=(a_1,a_2,...,a_n)</math> of numbers, the ''Cesáro sum'' of A is defined to be <br />
<math>\frac{S_1+\cdots+S_n}{n}</math> , where <math>S_k=a_1+\cdots+a_k</math> and <math>1\leq k\leq n</math>. If the Cesáro sum of<br />
the 99-term sequence <math>(a_1,...,a_{99})</math> is 1000, what is the Cesáro sum of the 100-term sequence <br />
<math>(1,a_1,...,a_{99})</math>?<br />
<br />
<math>\text{(A) } 991\quad<br />
\text{(B) } 999\quad<br />
\text{(C) } 1000\quad<br />
\text{(D) } 1001\quad<br />
\text{(E) } 1009</math><br />
<br />
[[1992 AHSME Problems/Problem 21|Solution]]<br />
<br />
== Problem 22 ==<br />
<br />
Ten points are selected on the positive <math>x</math>-axis,<math>X^+</math>, and five points are selected on the positive <math>y</math>-axis,<math>Y^+</math>. The fifty segments connecting the ten points on <math>X^+</math> to the five points on <math>Y^+</math> are drawn. What is the maximum possible number of points of intersection of these fifty segments that could lie in the interior of the first quadrant?<br />
<br />
<math>\text{(A) } 250\quad<br />
\text{(B) } 450\quad<br />
\text{(C) } 500\quad<br />
\text{(D) } 1250\quad<br />
\text{(E) } 2500</math><br />
<br />
[[1992 AHSME Problems/Problem 22|Solution]]<br />
<br />
<br />
== Problem 23 ==<br />
<br />
Let <math>S</math> be a subset of <math>\{1,2,3,...,50\}</math> such that no pair of distinct elements in <math>S</math> has a sum divisible by <math>7</math>. What is the maximum number of elements in <math>S</math>?<br />
<br />
<math>\text{(A) } 6\quad<br />
\text{(B) } 7\quad<br />
\text{(C) } 14\quad<br />
\text{(D) } 22\quad<br />
\text{(E) } 23</math><br />
<br />
[[1992 AHSME Problems/Problem 23|Solution]]<br />
<br />
== Problem 24 ==<br />
<br />
Let <math>ABCD</math> be a parallelogram of area <math>10</math> with <math>AB=3</math> and <math>BC=5</math>. Locate <math>E,F</math> and <math>G</math> on segments <math>\overline{AB},\overline{BC}</math> and <math>\overline{AD}</math>, respectively, with <math>AE=BF=AG=2</math>. Let the line through <math>G</math> parallel to <math>\overline{EF}</math> intersect <math>\overline{CD}</math> at <math>H</math>. The area of quadrilateral <math>EFHG</math> is<br />
<br />
<math>\text{(A) } 4\quad<br />
\text{(B) } 4.5\quad<br />
\text{(C) } 5\quad<br />
\text{(D) } 5.5\quad<br />
\text{(E) } 6</math><br />
<br />
[[1992 AHSME Problems/Problem 24|Solution]]<br />
<br />
== Problem 25 ==<br />
<br />
In <math>\triangle{ABC}</math>, <math>\angle{ABC}=120^\circ,AB=3</math> and <math>BC=4</math>. If perpendiculars constructed to <math>\overline{AB}</math> at <math>A</math> and to <math>\overline{BC}</math> at <math>C</math> meet at <math>D</math>, then <math>CD=</math><br />
<br />
<math>\text{(A) } 3\quad<br />
\text{(B) } \frac{8}{\sqrt{3}}\quad<br />
\text{(C) } 5\quad<br />
\text{(D) } \frac{11}{2}\quad<br />
\text{(E) } \frac{10}{\sqrt{3}}</math><br />
<br />
[[1992 AHSME Problems/Problem 25|Solution]]<br />
<br />
== Problem 26 ==<br />
<asy><br />
fill((1,0)--arc((1,0),2,180,225)--cycle,grey);<br />
fill((-1,0)--arc((-1,0),2,315,360)--cycle,grey);<br />
fill((0,-1)--arc((0,-1),2-sqrt(2),225,315)--cycle,grey);<br />
fill((0,0)--arc((0,0),1,180,360)--cycle,white);<br />
draw((1,0)--arc((1,0),2,180,225)--(1,0),black+linewidth(1));<br />
draw((-1,0)--arc((-1,0),2,315,360)--(-1,0),black+linewidth(1));<br />
draw((0,0)--arc((0,0),1,180,360)--(0,0),black+linewidth(1));<br />
draw(arc((0,-1),2-sqrt(2),225,315),black+linewidth(1));<br />
draw((0,0)--(0,-1),black+linewidth(1));<br />
MP("C",(0,0),N);MP("A",(-1,0),N);MP("B",(1,0),N);<br />
MP("D",(0,-.8),NW);MP("E",(1-sqrt(2),-sqrt(2)),SW);MP("F",(-1+sqrt(2),-sqrt(2)),SE);<br />
</asy><br />
<br />
Semicircle <math>\widehat{AB}</math> has center <math>C</math> and radius <math>1</math>. Point <math>D</math> is on <math>\widehat{AB}</math> and <math>\overline{CD}\perp\overline{AB}</math>. Extend <math>\overline{BD}</math> and <math>\overline{AD}</math> to <math>E</math> and <math>F</math>, respectively, so that circular arcs <math>\widehat{AE}</math> and <math>\widehat{BF}</math> have <math>B</math> and <math>A</math> as their respective centers. Circular arc <math>\widehat{EF}</math> has center <math>D</math>. The area of the shaded "smile" <math>AEFBDA</math>, is<br />
<br />
<math>\text{(A) } (2-\sqrt{2})\pi\quad<br />
\text{(B) } 2\pi-\pi \sqrt{2}-1\quad<br />
\text{(C) } (1-\frac{\sqrt{2}}{2})\pi\quad\\<br />
\text{(D) } \frac{5\pi}{2}-\pi\sqrt{2}-1\quad<br />
\text{(E) } (3-2\sqrt{2})\pi</math><br />
<br />
<br />
[[1992 AHSME Problems/Problem 26|Solution]]<br />
<br />
== Problem 27 ==<br />
<br />
<br />
A circle of radius <math>r</math> has chords <math>\overline{AB}</math> of length <math>10</math> and <math>\overline{CD}</math> of length 7. When <math>\overline{AB}</math> and <math>\overline{CD}</math> are extended through <math>B</math> and <math>C</math>, respectively, they intersect at <math>P</math>, which is outside of the circle. If <math>\angle{APD}=60^\circ</math> and <math>BP=8</math>, then <math>r^2=</math><br />
<br />
<math>\text{(A) } 70\quad<br />
\text{(B) } 71\quad<br />
\text{(C) } 72\quad<br />
\text{(D) } 73\quad<br />
\text{(E) } 74</math><br />
[[1992 AHSME Problems/Problem 27|Solution]]<br />
<br />
== Problem 28 ==<br />
<br />
Let <math>i=\sqrt{-1}</math>. The product of the real parts of the roots of <math>z^2-z=5-5i</math> is<br />
<br />
<math>\text{(A) } -25\quad<br />
\text{(B) } -6\quad<br />
\text{(C) } -5\quad<br />
\text{(D) } \frac{1}{4}\quad<br />
\text{(E) } 25</math><br />
<br />
[[1992 AHSME Problems/Problem 28|Solution]]<br />
<br />
== Problem 29 ==<br />
An "unfair" coin has a <math>2/3</math> probability of turning up heads. If this coin is tossed <math>50</math> times, what is the probability that the total number of heads is even?<br />
<br />
<math>\text{(A) } 25\left(\frac{2}{3}\right)^{50}\quad<br />
\text{(B) } \frac{1}{2}\left(1-\frac{1}{3^{50}}\right)\quad<br />
\text{(C) } \frac{1}{2}\quad<br />
\text{(D) } \frac{1}{2}\left(1+\frac{1}{3^{50}}\right)\quad<br />
\text{(E) } \frac{2}{3}</math><br />
<br />
[[1992 AHSME Problems/Problem 29|Solution]]<br />
<br />
== Problem 30 ==<br />
<br />
Let <math>ABCD</math> be an isosceles trapezoid with bases <math>AB=92</math> and <math>CD=19</math>. Suppose <math>AD=BC=x</math> and a circle with center on <math>\overline{AB}</math> is tangent to segments <math>\overline{AD}</math> and <math>\overline{BC}</math>. If <math>m</math> is the smallest possible value of <math>x</math>, then <math>m^2</math>=<br />
<br />
<math>\text{(A) } 1369\quad<br />
\text{(B) } 1679\quad<br />
\text{(C) } 1748\quad<br />
\text{(D) } 2109\quad<br />
\text{(E) } 8825</math><br />
<br />
[[1992 AHSME Problems/Problem 30|Solution]]<br />
<br />
== See also ==<br />
<br />
* [[AMC 12 Problems and Solutions]]<br />
* [[Mathematics competition resources]]<br />
<br />
{{AHSME box|year=1992|before=[[1991 AHSME]]|after=[[1993 AHSME]]}} <br />
<br />
{{MAA Notice}}</div>Scientesthttps://artofproblemsolving.com/wiki/index.php?title=2018_AIME_II_Problems/Problem_6&diff=934932018 AIME II Problems/Problem 62018-03-25T18:50:41Z<p>Scientest: /* Solution */</p>
<hr />
<div>==Problem==<br />
<br />
A real number <math>a</math> is chosen randomly and uniformly from the interval <math>[-20, 18]</math>. The probability that the roots of the polynomial<br />
<br />
<math>x^4 + 2ax^3 + (2a - 2)x^2 + (-4a + 3)x - 2</math><br />
<br />
are all real can be written in the form <math>\dfrac{m}{n}</math>, where <math>m</math> and <math>n</math> are relatively prime positive integers. Find <math>m + n</math>.<br />
<br />
==Solution==<br />
<br />
The polynomial we are given is rather complicated, so we could use [[Rational Root Theorem]] to turn the given polynomial into a degree-2 polynomial. With Rational Root Theorem, <math>x = 1, -1, 2, -2</math> are all possible roots. Upon plugging these roots into the polynomial, <math>x = -2</math> and <math>x = 1</math> make the polynomial equal 0 and thus, they are roots that we can factor out.<br />
<br />
The polynomial becomes:<br />
<br />
<math>(x - 1)(x + 2)(x^2 + (2a - 1)x + 1)</math><br />
<br />
Since we know <math>1</math> and <math>-2</math> are real numbers, we only need to focus on the quadratic.<br />
<br />
We should set the discriminant of the quadratic greater than or equal to 0.<br />
<br />
<math>(2a - 1)^2 - 4 \geq 0</math>.<br />
<br />
This simplifies to:<br />
<br />
<math>a \geq \dfrac{3}{2}</math><br />
<br />
or<br />
<br />
<math>a \leq -\dfrac{1}{2}</math><br />
<br />
This means that the interval <math>\left(-\dfrac{1}{2}, \dfrac{3}{2}\right)</math> is the "bad" interval. The length of the interval where <math>a</math> can be chosen from is 38 units long, while the bad interval is 2 units long. Therefore, the good interval is 36 units long.<br />
<br />
<math>\dfrac{36}{38} = \dfrac{18}{19}</math><br />
<br />
<math>18 + 19 = \boxed{037}</math><br />
<br />
==See Also==<br />
<br />
{{AIME box|year=2018|n=II|num-b=5|num-a=7}}<br />
{{MAA Notice}}</div>Scientesthttps://artofproblemsolving.com/wiki/index.php?title=2018_AIME_II_Problems/Problem_5&diff=934822018 AIME II Problems/Problem 52018-03-25T08:05:01Z<p>Scientest: /* Solution 2 */</p>
<hr />
<div>==Problem==<br />
<br />
Suppose that <math>x</math>, <math>y</math>, and <math>z</math> are complex numbers such that <math>xy = -80 - 320i</math>, <math>yz = 60</math>, and <math>zx = -96 + 24i</math>, where <math>i</math> <math>=</math> <math>\sqrt{-1}</math>. Then there are real numbers <math>a</math> and <math>b</math> such that <math>x + y + z = a + bi</math>. Find <math>a^2 + b^2</math>.<br />
<br />
==Solution 1==<br />
<br />
First we evaluate the magnitudes. <math>|xy|=80\sqrt{17}</math>, <math>|yz|=60</math>, and <math>|zx|=24\sqrt{17}</math>. Therefore, <math>|x^2y^2z^2|=17\cdot80\cdot60\cdot24</math>, or <math>|xyz|=240\sqrt{34}</math>. Divide to find that <math>|z|=3\sqrt{2}</math>, <math>|x|=40\sqrt{34}</math>, and <math>|y|=10\sqrt{2}</math>.<br />
<asy><br />
draw((0,0)--(4,0));<br />
dot((4,0),red);<br />
draw((0,0)--(-4,0));<br />
draw((0,0)--(0,-4));<br />
draw((0,0)--(-4,1));<br />
dot((-4,1),red);<br />
draw((0,0)--(-1,-4));<br />
dot((-1,-4),red);<br />
draw((0,0)--(4,4),red);<br />
draw((0,0)--(4,-4),red);<br />
</asy><br />
This allows us to see that the argument of <math>y</math> is <math>\frac{\pi}{4}</math>, and the argument of <math>z</math> is <math>-\frac{\pi}{4}</math>. We need to convert the polar form to a standard form. Simple trig identities show <math>y=10+10i</math> and <math>z=3-3i</math>. More division is needed to find what <math>x</math> is. <cmath>x=-20-12i</cmath> <cmath>x+y+z=-7-5i</cmath> <cmath>(-7)^2+(-5)^2=\boxed{074}</cmath><br />
<cmath>QED\blacksquare</cmath><br />
Written by [[User:A1b2|a1b2]]<br />
==Solution 2==<br />
Dividing the first equation by the second equation given, we find that <math>\frac{xy}{yz}=\frac{x}{z}=\frac{-80-320i}{60}=-\frac{4}{3}-\frac{16}{3}i \implies x=z\left(-\frac{4}{3}-\frac{16}{3}i\right)</math>. Substituting this into the third equation, we get <math>z^2=\frac{-96+24i}{-\frac{4}{3}-\frac{16}{3}i}=3\cdot \frac{-24+6i}{-1-4i}=3\cdot \frac{(-24+6i)(-1+4i)}{1+16}=3\cdot \frac{-102i}{17}=-18i</math>. Taking the square root of this is equivalent to halving the argument and taking the square root of the magnitude. Furthermore, the second equation given tells us that the argument of <math>y</math> is the negative of that of <math>z</math>, and their magnitudes multiply to <math>60</math>. Thus we have <math>z=\sqrt{-18i}=3-3i</math> and <math>3\sqrt{2}\cdot |y|=60 \implies |y|=10\sqrt{2} \implies y=10+10i</math>. To find <math>x</math>, we can use the previous substitution we made to find that <math>x=z\left(-\frac{4}{3}-\frac{16}{3}i\right)=-\frac{4}{3}\cdot (3-3i)(1+4i)=-4(1-i)(1+4i)=-4(5+3i)=-20-12i</math><br />
Therefore, <math>x+y+z=(-20+10+3)+(-12+10-3)i=-7-5i \implies a^2+b^2=(-7)^2+(-5)^2=49+25=\boxed{074}</math><br />
Solution by ktong<br />
{{AIME box|year=2018|n=II|num-b=4|num-a=6}}<br />
{{MAA Notice}}</div>Scientesthttps://artofproblemsolving.com/wiki/index.php?title=User:Scientest&diff=93481User:Scientest2018-03-25T08:04:26Z<p>Scientest: Blanked the page</p>
<hr />
<div></div>Scientesthttps://artofproblemsolving.com/wiki/index.php?title=2018_AIME_II_Problems/Problem_5&diff=934802018 AIME II Problems/Problem 52018-03-25T08:02:49Z<p>Scientest: /* Solution 2 */</p>
<hr />
<div>==Problem==<br />
<br />
Suppose that <math>x</math>, <math>y</math>, and <math>z</math> are complex numbers such that <math>xy = -80 - 320i</math>, <math>yz = 60</math>, and <math>zx = -96 + 24i</math>, where <math>i</math> <math>=</math> <math>\sqrt{-1}</math>. Then there are real numbers <math>a</math> and <math>b</math> such that <math>x + y + z = a + bi</math>. Find <math>a^2 + b^2</math>.<br />
<br />
==Solution 1==<br />
<br />
First we evaluate the magnitudes. <math>|xy|=80\sqrt{17}</math>, <math>|yz|=60</math>, and <math>|zx|=24\sqrt{17}</math>. Therefore, <math>|x^2y^2z^2|=17\cdot80\cdot60\cdot24</math>, or <math>|xyz|=240\sqrt{34}</math>. Divide to find that <math>|z|=3\sqrt{2}</math>, <math>|x|=40\sqrt{34}</math>, and <math>|y|=10\sqrt{2}</math>.<br />
<asy><br />
draw((0,0)--(4,0));<br />
dot((4,0),red);<br />
draw((0,0)--(-4,0));<br />
draw((0,0)--(0,-4));<br />
draw((0,0)--(-4,1));<br />
dot((-4,1),red);<br />
draw((0,0)--(-1,-4));<br />
dot((-1,-4),red);<br />
draw((0,0)--(4,4),red);<br />
draw((0,0)--(4,-4),red);<br />
</asy><br />
This allows us to see that the argument of <math>y</math> is <math>\frac{\pi}{4}</math>, and the argument of <math>z</math> is <math>-\frac{\pi}{4}</math>. We need to convert the polar form to a standard form. Simple trig identities show <math>y=10+10i</math> and <math>z=3-3i</math>. More division is needed to find what <math>x</math> is. <cmath>x=-20-12i</cmath> <cmath>x+y+z=-7-5i</cmath> <cmath>(-7)^2+(-5)^2=\boxed{074}</cmath><br />
<cmath>QED\blacksquare</cmath><br />
Written by [[User:A1b2|a1b2]]<br />
==Solution 2==<br />
Dividing the first equation by the second equation given, we find that <math>\frac{xy}{yz}=\frac{x}{z}=\frac{-80-320i}{60}=-\frac{4}{3}-\frac{16}{3}i \implies x=z\left(-\frac{4}{3}-\frac{16}{3}i\right)</math>. Substituting this into the third equation, we get <math>z^2=\frac{-96+24i}{-\frac{4}{3}-\frac{16}{3}i}=3\cdot \frac{-24+6i}{-1-4i}=3\cdot \frac{(-24+6i)(-1+4i)}{1+16}=3\cdot \frac{-102i}{17}=-18i</math>. Taking the square root of this is equivalent to halving the argument and taking the square root of the magnitude. Furthermore, the second equation given tells us that the argument of <math>y</math> is the negative of that of <math>z</math>, and their magnitudes multiply to <math>60</math>. Thus we have <math>z=\sqrt{-18i}=3-3i</math> and <math>3\sqrt{2}\cdot |y|=60 \implies |y|=10\sqrt{2} \implies y=10+10i</math>. To find <math>x</math>, we can use the previous substitution we made to find that <math>x=z(-\frac{4}{3}-\frac{16}{3}i)=-\frac{4}{3}\cdot (3-3i)(1+4i)=-4(1-i)(1+4i)=-4(5+3i)=-20-12i</math><br />
Therefore, <math>x+y+z=(-20+10+3)+(-12+10-3)i=-7-5i \implies a^2+b^2=(-7)^2+(-5)^2=49+25=\boxed{074}</math><br />
Solution by ktong<br />
{{AIME box|year=2018|n=II|num-b=4|num-a=6}}<br />
{{MAA Notice}}</div>Scientesthttps://artofproblemsolving.com/wiki/index.php?title=2005_AIME_II_Problems/Problem_9&diff=933602005 AIME II Problems/Problem 92018-03-21T09:57:51Z<p>Scientest: /* Solution 1 */</p>
<hr />
<div>== Problem ==<br />
For how many positive integers <math> n </math> less than or equal to <math>1000</math> is <math> (\sin t + i \cos t)^n = \sin nt + i \cos nt </math> true for all real <math> t </math>?<br />
<br />
== Solution ==<br />
=== Solution 1 ===<br />
We know by [[De Moivre's Theorem]] that <math>(\cos t + i \sin t)^n = \cos nt + i \sin nt</math> for all [[real number]]s <math>t</math> and all [[integer]]s <math>n</math>. So, we'd like to somehow convert our given expression into a form from which we can apply De Moivre's Theorem. <br />
<br />
Recall the [[trigonometric identities]] <math>\cos \left(\frac{\pi}2 - u\right) = \sin u</math> and <math>\sin \left(\frac{\pi}2 - u\right) = \cos u</math> hold for all real <math>u</math>. If our original equation holds for all <math>t</math>, it must certainly hold for <math>t = \frac{\pi}2 - u</math>. Thus, the question is equivalent to asking for how many [[positive integer]]s <math>n \leq 1000</math> we have that <math>\left(\sin\left(\frac\pi2 - u\right) + i \cos\left(\frac\pi 2 - u\right)\right)^n = \sin n \left(\frac\pi2 -u \right) + i\cos n \left(\frac\pi2 - u\right)</math> holds for all real <math>u</math>.<br />
<br />
<math>\left(\sin\left(\frac\pi2 - u\right) + i \cos\left(\frac\pi 2 - u\right)\right)^n = \left(\cos u + i \sin u\right)^n = \cos nu + i\sin nu</math>. We know that two [[complex number]]s are equal if and only if both their [[real part]] and [[imaginary part]] are equal. Thus, we need to find all <math>n</math> such that <math>\cos n u = \sin n\left(\frac\pi2 - u\right)</math> and <math>\sin nu = \cos n\left(\frac\pi2 - u\right)</math> hold for all real <math>u</math>.<br />
<br />
<math>\sin x = \cos y</math> if and only if either <math>x + y = \frac \pi 2 + 2\pi \cdot k</math> or <math>x - y = \frac\pi2 + 2\pi\cdot k</math> for some integer <math>k</math>. So from the equality of the real parts we need either <math>nu + n\left(\frac\pi2 - u\right) = \frac\pi 2 + 2\pi \cdot k</math>, in which case <math>n = 1 + 4k</math>, or we need <math>-nu + n\left(\frac\pi2 - u\right) = \frac\pi 2 + 2\pi \cdot k</math>, in which case <math>n</math> will depend on <math>u</math> and so the equation will not hold for all real values of <math>u</math>. Checking <math>n = 1 + 4k</math> in the equation for the imaginary parts, we see that it works there as well, so exactly those values of <math>n</math> congruent to <math>1 \pmod 4</math> work. There are <math>\boxed{250}</math> of them in the given range.<br />
<br />
=== Solution 2 ===<br />
This problem begs us to use the familiar identity <math>e^{it} = \cos(t) + i \sin(t)</math>. Notice, <math>\sin(t) + i \cos(t) = i(\cos(t) - i \sin(t)) = i e^{-it}</math> since <math>\sin(-t) = -\sin(t)</math>. Using this, <math>(\sin(t) + i \cos(t))^n = \sin(nt) + i \cos(nt)</math> is recast as <math>(i e^{-it})^n = i e^{-itn}</math>. Hence we must have <math>i^n = i \Rightarrow i^{n-1} = 1 \Rightarrow n \equiv 1 \bmod{4}</math>. Thus since <math>1000</math> is a multiple of <math>4</math> exactly one quarter of the residues are congruent to <math>1</math> hence we have <math>\boxed{250}</math>.<br />
<br />
=== Solution 3 ===<br />
We can rewrite <math>\sin(t)</math> as <math>\cos\left(\frac{\pi}{2}-t\right)</math> and <math>\cos(t)</math> as <math>\sin\left(\frac{\pi}{2}-t\right)</math>. This means that <math>\sin t + i\cos t = e^{i\left(\frac{\pi}{2}-t\right)}=\frac{e^{\frac{\pi i}{2}}}{e^{it}}</math>. This theorem also tells us that <math>e^{\frac{\pi i}{2}}=i</math>, so <math>\sin t + i\cos t = \frac{i}{e^{it}}</math>. By the same line of reasoning, we have <math>\sin nt + i\cos nt = \frac{i}{e^{int}}</math>.<br />
<br />
For the statement in the question to be true, we must have <math>\left(\frac{i}{e^{it}}\right)^n=\frac{i}{e^{int}}</math>. The left hand side simplifies to <math>\frac{i^n}{e^{int}}</math>. We cancel the denominators and find that the only thing that needs to be true is that <math>i^n=i</math>. This is true if <math>n\equiv1\pmod{4}</math>, and there are <math>\boxed{250}</math> such numbers between <math>1</math> and <math>1000</math>. Solution by Zeroman<br />
[[Category:Intermediate Algebra Problems]]<br />
<br />
{{MAA Notice}}<br />
<br />
==See Also==<br />
{{AIME box|year=2005|n=II|num-b=8|num-a=10}}</div>Scientesthttps://artofproblemsolving.com/wiki/index.php?title=Area&diff=86952Area2017-08-09T02:34:26Z<p>Scientest: /* Area of Triangle */</p>
<hr />
<div>In [[mathematics]], '''area''' refers to the size of the region that a two-[[dimension]]al figure occupies.<br />
<br />
It is often possible to find the area of a region bounded by parts of [[circle]]s and [[line segment]]s through elementary means. One can find the area of even more complex regions via the use of [[calculus]].<br />
<br />
[[Rectangle]]s are the most basic figures whose area we can study. It makes sense that the area of a rectangle with length <math>l</math> and width <math>w</math> is simply <math> l\cdot w</math>.<br />
<br />
Once we know the area of a rectangle, we can easily find the area of a [[triangle]] by just noting that if our triangle has base <math>b</math> and height <math>h</math>, then the rectangle with length <math>b</math> and width <math>h</math> has exactly twice as much area as the original triangle. Thus, the area of a triangle is<br />
<br />
<center><math>A=\frac 12 bh.</math></center><br />
<br />
We can now find the area of any [[polygon]] by breaking it up into triangles.<br />
<br />
== Notation ==<br />
The letters <math>A</math> and <math>K</math> are frequently used to stand for area. When there are multiple regions under consideration, subscripts are often employed: <math> A_1, K_2,\ldots</math> might be used to denote the areas of particular regions, or <math> A_{ABC}, K_{BCD},\ldots</math>. For example, <math> K_{ABCDEF}</math> would mean the area of [[hexagon]] <math>ABCDEF</math>.<br />
<br />
An alternative notation is to use square brackets around the name of the region to denote its area, e.g. <math> [ABC]</math> for the area of triangle <math>\triangle ABC</math>. <br />
<br />
== Area of Regular Polygons ==<br />
The area of any [[regular polygon]] can be found as follows:<br />
<br />
Inscribe the figure, with <math>n</math> sides of length <math>s</math>, in a circle and draw a line from two adjacent vertices to the [[circumcenter]]. This creates a triangle that is <math>\frac{1}{n},</math> of the total area (consider the regular [[octagon]] below as an example).<br />
<br />
<center>[[Image:Regularoctagon.PNG]]</center><br />
<br />
Drawing the [[apothem]] creates two [[right triangle]]s, each with an [[angle]] of <math>\frac{180}{n}^{\circ}</math> at the top vertex. If the polygon has side length <math>s</math>, the height of the triangle can be found using [[trigonometry]] to be of length <math>\frac s2 \cot \frac{180}{n}^{\circ}</math>.<br />
<br />
The area of each triangle is <math>\frac12</math> the base times the height, which can also be expressed as <math>\frac{s^2}{4} \cot\frac{180}{n}^{\circ}</math> and the area of the entire polygon is <math>\frac{n\cdot s^2}{4} \cot\frac{180}{n}^{\circ}</math>.<br />
<br />
== Area of Triangle ==<br />
There are many ways to find the area of a [[triangle]]. In all of these formulae, <math>{K}</math> will be used to indicate area.<br />
<br />
* <math>K=\frac{bh}{2}</math> where <math>b</math> is a base and <math>h</math> is the altitude of the triangle to that base.<br />
* [[Heron's formula]]: <math>K=\sqrt{s(s-a)(s-b)(s-c)}</math>, where <math>a, b</math> and <math>c</math> are the lengths of the sides and <math>s</math> is the [[semi-perimeter]] <math>s=\frac{a+b+c}{2}</math>.<br />
* <math>K=rs</math>, where <math>r</math> is the radius of the [[incircle]] and s is the semi-perimeter.<br />
* <math>K=\frac{ab\sin{\theta}}{2}</math> where <math>a</math> and <math>b</math> are adjacent sides of the triangle and <math>\theta</math> is the measure of the angle between them.<br />
* <math>K=\frac{abc}{4R}</math>, where <math>a,b,c </math> are the lengths of the sides of the triangle and <math>R </math> is the [[circumradius]].<br />
* <math>\frac{1}{K}=4\sqrt{H(H-h_a^{-1})(H-h_b^{-1})(H-h_c^{-1})}</math>, where <math>H=\frac{(h_a^{-1}+h_b^{-1}+h_c^{-1})}{2}</math> and the triangle has altitudes <math>h_a</math>, <math>h_b</math>, <math>h_c</math>.<br />
<br />
== Area of a Quadrilateral ==<br />
To find the area of most [[quadrilateral]]s, you must divide the quadrilateral up into smaller triangles and find the area of each triangle. However, some quadrilaterals have special formulas to find their areas. Again, <math>K</math> is the area.<br />
<br />
* [[Kite]] - <math>K=\frac{d_1\cdot d_2}{2}</math> where the <math>d</math>s represent the lengths of the diagonals of the kite.<br />
<br />
* [[Parallelogram]] - <math>{K=bh}</math>, where <math>b</math> is the base and <math>h</math> is the height to that base.<br />
<br />
* [[Trapezoid]] - <math>K=\frac{b_1+b_2}{2}\cdot h</math>, where the <math>b</math>s are the parallel sides and <math>h</math> is the distance between those bases.<br />
<br />
* [[Rhombus]] - a special case of a kite and parallelogram, so either formula may be used here.<br />
<br />
* [[Rectangle]] - <math>{K=lw}</math>, where <math>l</math> is the length of the rectangle and <math>w</math> is the width. (This is a special case of the formula for a parallelogram where the height and a side happen to coincide.)<br />
<br />
* [[Square (geometry) | Square]] - <math>K=s^2</math>, where <math>s</math> is the length of a side.<br />
<br />
* Any quadrilateral - <math>K=\sqrt{(s-a)(s-b)(s-c)(s-d)-abcd\cos^2\left(\dfrac{B+D}{2}\right)}</math>, where <math>s</math> is the semiperimeter, <math>a</math>, <math>b</math>, <math>c</math>, and <math>d</math> are the side lengths, and <math>B</math> and <math>D</math> are the measures of angles <math>B</math> and <math>D</math>, respectively.<br />
<br />
* [[Cyclic quadrilateral]] - <math>K=\sqrt{(s-a)(s-b)(s-c)(s-d)}</math> where <math>s</math> is the semiperimeter and <math>a</math>, <math>b</math>, <math>c</math>, and <math>d</math> are the side lengths. (This is a special case of the formula for the area of any quadrilateral; <math>\cos^2\left(\dfrac{B+D}{2}\right)=0</math>.)<br />
<br />
==See Also==<br />
[[Pick's Theorem]]<br />
<br />
[[Shoelace Theorem]]<br />
<br />
[[Category:Geometry]]</div>Scientesthttps://artofproblemsolving.com/wiki/index.php?title=User_talk:Scientest&diff=78676User talk:Scientest2016-05-21T20:34:52Z<p>Scientest: </p>
<hr />
<div>Someone wanna post something?</div>Scientesthttps://artofproblemsolving.com/wiki/index.php?title=User:Scientest&diff=78675User:Scientest2016-05-21T20:34:20Z<p>Scientest: </p>
<hr />
<div>Well, you found my page. Here's some stuff.<br />
<br />
Birthday: Nov 28<br />
<br />
Favorite video game: Xenoblade Chronicles<br />
Currently playing: PMD Explorers of Sky, Pokemon Platinum, Kirby Mass Attack, Fire Emblem Radiant Dawn<br />
<br />
SSBM Mains: Marth, Jigglypuff, Falco<br />
SSBM Others: Pikachu, Pichu, Roy, Fox<br />
<br />
SSB4 Mains: Shulk, Kirby, Bowser<br />
SSB4 Others: Marth, Ike, Lucario, Greninja, Yoshi<br />
<br />
Favorite Pokemon: Swellow</div>Scientesthttps://artofproblemsolving.com/wiki/index.php?title=User:Scientest&diff=78410User:Scientest2016-05-03T16:33:50Z<p>Scientest: </p>
<hr />
<div>Well, you found my page. Here's some stuff.<br />
<br />
Birthday: Nov 28<br />
<br />
Favorite video game: Xenoblade Chronicles<br />
<br />
SSBM Mains: Marth, Jigglypuff<br />
<br />
SSBM Others: Falco, Pikachu, Pichu, Roy, Fox<br />
<br />
SSBB Mains: Marth, Lucario<br />
<br />
SSB4 Mains: Shulk, Kirby, Bowser<br />
<br />
SSB4 Others: Marth, Ike, Lucario, Greninja, Yoshi<br />
<br />
Favorite Pokemon: Swellow</div>Scientesthttps://artofproblemsolving.com/wiki/index.php?title=User:Scientest&diff=63247User:Scientest2014-08-30T17:26:41Z<p>Scientest: </p>
<hr />
<div>Well you found my page. Here's some stuff.<br />
<br />
Birthday: Nov 28<br />
Favorite video game: Xenoblade Chronicles<br />
Fav Smash Characters: Lucario, Jigglypuff, Marth<br />
Fav Book: Lord of the Rings :)</div>Scientesthttps://artofproblemsolving.com/wiki/index.php?title=User:Chutney&diff=56879User:Chutney2013-08-09T16:40:15Z<p>Scientest: Blanked the page</p>
<hr />
<div></div>Scientesthttps://artofproblemsolving.com/wiki/index.php?title=User:Chutney&diff=56878User:Chutney2013-08-09T16:39:51Z<p>Scientest: Created page with "STAR TREK FTW!!!"</p>
<hr />
<div>STAR TREK FTW!!!</div>Scientesthttps://artofproblemsolving.com/wiki/index.php?title=User_talk:Scientest&diff=56732User talk:Scientest2013-07-26T01:03:31Z<p>Scientest: </p>
<hr />
<div>Well? Do some math!<br />
<br />
Prove: <math>c^2=a^2+b^2-2ab\cdot \cos (C)</math> for some sides of a triangle <math>a, b, </math> and <math>c</math>, and <math>C</math> being the largest angle of a triangle.</div>Scientesthttps://artofproblemsolving.com/wiki/index.php?title=Grigori_Perelman&diff=56714Grigori Perelman2013-07-24T11:38:58Z<p>Scientest: </p>
<hr />
<div>Grigori Perelman is Russian mathematician that has made multiple discoveries in the field of geometry topology. <br />
He is famous for solving one of the [[Millennium Problems]], the [[Poincaré Conjecture]]<br />
{{Stub}}</div>Scientesthttps://artofproblemsolving.com/wiki/index.php?title=User_talk:Scientest&diff=56713User talk:Scientest2013-07-24T11:38:21Z<p>Scientest: </p>
<hr />
<div>Well? Do some math!<br />
<br />
Prove: <math>c^2=a^2+b^2-2ab\cdot \cos (C)</math></div>Scientesthttps://artofproblemsolving.com/wiki/index.php?title=Torus&diff=56712Torus2013-07-24T11:36:53Z<p>Scientest: </p>
<hr />
<div>A torus is a shape that is the result of gluing opposite sides of a square together (with necessary bending and twisting). It resembles a donut shape.<br />
<br />
{{stub}}</div>Scientesthttps://artofproblemsolving.com/wiki/index.php?title=Torus&diff=56711Torus2013-07-24T11:36:31Z<p>Scientest: Created page with "A torus is a shape that is the result of gluing opposite sides of a square together (with necessary bending and twisting). {{stub}}"</p>
<hr />
<div>A torus is a shape that is the result of gluing opposite sides of a square together (with necessary bending and twisting).<br />
<br />
{{stub}}</div>Scientesthttps://artofproblemsolving.com/wiki/index.php?title=User:Scientest&diff=56651User:Scientest2013-07-15T11:12:57Z<p>Scientest: Replaced content with "Stop wasting your time. Do some math.
Like this:
<math>\sqrt i=?</math>"</p>
<hr />
<div>Stop wasting your time. Do some math.<br />
Like this:<br />
<br />
<math>\sqrt i=?</math></div>Scientesthttps://artofproblemsolving.com/wiki/index.php?title=User:Scientest&diff=52625User:Scientest2013-05-01T18:02:31Z<p>Scientest: /* Bio */</p>
<hr />
<div> [[File:Warning.gif]]<br />
"Let us blow this popsicle stand! Okay, so maybe it's an ice pop stand, but whatever." –Sci at a school athletic event<br />
<br />
Hi there. Welcome to my Wiki page. I wrote this mainly in third person, so enjoy this while it lasts. And take heed of my warning. Scroll all the way down. Yikes. Well, have fun here! If you get bored, you can always go the forums.<br />
=Bio=<br />
Scientest is almost 12. He loves using <math>\text{\text\LaTeX}</math> and playing Plants vs. Zombies. He goes by the nickname Sci. He has done Algebra 1 (Summer 2011) and Counting and Probability (Fall-Spring 2011-2012) Sci plays the violin and the viola and loves math. He enjoys Plants vs. Zombies and cannot wait for P vs. Z 2 to come out. He also enjoys ClubPenguin (Look out for Inventapeng), Animal Jam, and Pokemon. He is impending the next generation of Pokemon. <br />
==Name==<br />
His first name is Andrew. He snipped his last name from an FF post<br />
<br />
==Favorites==<br />
===Color===<br />
Pink: "It rocks"<br />
===Games on iPod/iPad=== <br />
Plants vs. Zombies: "I especially like it when the zombies eat your brains. Lol."<br />
<br />
Anthill<br />
<br />
Ouch!<br />
<br />
Worms 2<br />
<br />
Jetpack Joyride<br />
<br />
===Favorite Avatar Game=== <br />
Club Penguin, Runner-up: Animal Jam<br />
<br />
===TV Show=== <br />
''Wild Kratts'': "Who knew how amazing nature is?"<br />
<br />
Runner-up: Pokémon Anime<br />
<br />
===Subject=== <br />
Math!<br />
===Catch Phrases===<br />
"Technically speaking... uh, no" <br />
<br />
"Let us blow this popsicle stand!"<br />
<br />
"Can you say, 'no?'"<br />
<br />
===Comic===<br />
''Foxtrot'': "Jason is so funny." <br />
<br />
Comments: Dantx5: I agree.<br />
<br />
==Websites==<br />
Sci has an account on Club Penguin, Art of Problem Solving, Animal Jam, and EarIAm.<br />
<br />
==AoPS History==<br />
Sci posts a lot in the Fun Factory.<br />
===Stats===<br />
Sci joined AoPS on Feb 22, 2011, 8:44 am<br />
<br />
=Currency=<br />
IQ Points (IQP) are his currency. He also has Coins.<br />
<br />
==Conversions==<br />
One IQP is the same as 6 [[User:Knittingfrenzy18 |RC]], or 10 [[User:EuclidGenius |Qwerty]]<br />
<br />
One coin is 90 IPQs<br />
<br />
==Value==<br />
Coins are low in value, so they are easy to get. On the other hand, IQPs are extremely hard to get<br />
<br />
=CSS's=<br />
[http://www.artofproblemsolving.com/Forum/viewtopic.php?f=624&t=447899 Plants vs Zombies 1 v1.0 CSS]<br />
<br />
=Fun Facts=<br />
In his old blog, Sci posted Locker must-haves, a graphing calculator, books, and a picture of his crush<br />
<br />
Sci has played violin for approximately 8 years<br />
<br />
=Mathemagical Carreer=<br />
*NOTE TO SELF: FILL OUT</div>Scientesthttps://artofproblemsolving.com/wiki/index.php?title=User:Scientest&diff=52624User:Scientest2013-05-01T18:01:39Z<p>Scientest: /* Schoolhouse Rock song */</p>
<hr />
<div> [[File:Warning.gif]]<br />
"Let us blow this popsicle stand! Okay, so maybe it's an ice pop stand, but whatever." –Sci at a school athletic event<br />
<br />
Hi there. Welcome to my Wiki page. I wrote this mainly in third person, so enjoy this while it lasts. And take heed of my warning. Scroll all the way down. Yikes. Well, have fun here! If you get bored, you can always go the forums.<br />
=Bio=<br />
Scientest is almost 12. He loves using <math>\text{\text\LaTeX}</math> and playing Plants vs. Zombies. He goes by the nickname Sci. He has done Algebra 1 (Summer 2011) and Counting and Probability (Fall-Spring 2011-2012) Sci plays the violin and the viola and loves math. He enjoys Plants vs. Zombies and cannot wait for P vs. Z 2 to come out. He also enjoys ClubPenguin (Look out for Inventapeng), Poptropica, Ninjago, and Pokemon<br />
==Name==<br />
His first name is Andrew. He snipped his last name from an FF post<br />
<br />
==Favorites==<br />
===Color===<br />
Pink: "It rocks"<br />
===Games on iPod/iPad=== <br />
Plants vs. Zombies: "I especially like it when the zombies eat your brains. Lol."<br />
<br />
Anthill<br />
<br />
Ouch!<br />
<br />
Worms 2<br />
<br />
Jetpack Joyride<br />
<br />
===Favorite Avatar Game=== <br />
Club Penguin, Runner-up: Animal Jam<br />
<br />
===TV Show=== <br />
''Wild Kratts'': "Who knew how amazing nature is?"<br />
<br />
Runner-up: Pokémon Anime<br />
<br />
===Subject=== <br />
Math!<br />
===Catch Phrases===<br />
"Technically speaking... uh, no" <br />
<br />
"Let us blow this popsicle stand!"<br />
<br />
"Can you say, 'no?'"<br />
<br />
===Comic===<br />
''Foxtrot'': "Jason is so funny." <br />
<br />
Comments: Dantx5: I agree.<br />
<br />
==Websites==<br />
Sci has an account on Club Penguin, Art of Problem Solving, Animal Jam, and EarIAm.<br />
<br />
==AoPS History==<br />
Sci posts a lot in the Fun Factory.<br />
===Stats===<br />
Sci joined AoPS on Feb 22, 2011, 8:44 am<br />
=Currency=<br />
IQ Points (IQP) are his currency. He also has Coins.<br />
<br />
==Conversions==<br />
One IQP is the same as 6 [[User:Knittingfrenzy18 |RC]], or 10 [[User:EuclidGenius |Qwerty]]<br />
<br />
One coin is 90 IPQs<br />
<br />
==Value==<br />
Coins are low in value, so they are easy to get. On the other hand, IQPs are extremely hard to get<br />
<br />
=CSS's=<br />
[http://www.artofproblemsolving.com/Forum/viewtopic.php?f=624&t=447899 Plants vs Zombies 1 v1.0 CSS]<br />
<br />
=Fun Facts=<br />
In his old blog, Sci posted Locker must-haves, a graphing calculator, books, and a picture of his crush<br />
<br />
Sci has played violin for approximately 8 years<br />
<br />
=Mathemagical Carreer=<br />
*NOTE TO SELF: FILL OUT</div>Scientesthttps://artofproblemsolving.com/wiki/index.php?title=User:Scientest&diff=52623User:Scientest2013-05-01T18:01:29Z<p>Scientest: /* Favorite Avatar Game */</p>
<hr />
<div> [[File:Warning.gif]]<br />
"Let us blow this popsicle stand! Okay, so maybe it's an ice pop stand, but whatever." –Sci at a school athletic event<br />
<br />
Hi there. Welcome to my Wiki page. I wrote this mainly in third person, so enjoy this while it lasts. And take heed of my warning. Scroll all the way down. Yikes. Well, have fun here! If you get bored, you can always go the forums.<br />
=Bio=<br />
Scientest is almost 12. He loves using <math>\text{\text\LaTeX}</math> and playing Plants vs. Zombies. He goes by the nickname Sci. He has done Algebra 1 (Summer 2011) and Counting and Probability (Fall-Spring 2011-2012) Sci plays the violin and the viola and loves math. He enjoys Plants vs. Zombies and cannot wait for P vs. Z 2 to come out. He also enjoys ClubPenguin (Look out for Inventapeng), Poptropica, Ninjago, and Pokemon<br />
==Name==<br />
His first name is Andrew. He snipped his last name from an FF post<br />
<br />
==Favorites==<br />
===Color===<br />
Pink: "It rocks"<br />
===Schoolhouse Rock song=== <br />
"I like them all, but my personal favorite is ''Interplanet Janet''"<br />
===Games on iPod/iPad=== <br />
Plants vs. Zombies: "I especially like it when the zombies eat your brains. Lol."<br />
<br />
Anthill<br />
<br />
Ouch!<br />
<br />
Worms 2<br />
<br />
Jetpack Joyride<br />
<br />
===Favorite Avatar Game=== <br />
Club Penguin, Runner-up: Animal Jam<br />
<br />
===TV Show=== <br />
''Wild Kratts'': "Who knew how amazing nature is?"<br />
<br />
Runner-up: Pokémon Anime<br />
<br />
===Subject=== <br />
Math!<br />
===Catch Phrases===<br />
"Technically speaking... uh, no" <br />
<br />
"Let us blow this popsicle stand!"<br />
<br />
"Can you say, 'no?'"<br />
<br />
===Comic===<br />
''Foxtrot'': "Jason is so funny." <br />
<br />
Comments: Dantx5: I agree.<br />
<br />
==Websites==<br />
Sci has an account on Club Penguin, Art of Problem Solving, Animal Jam, and EarIAm.<br />
<br />
==AoPS History==<br />
Sci posts a lot in the Fun Factory.<br />
===Stats===<br />
Sci joined AoPS on Feb 22, 2011, 8:44 am<br />
=Currency=<br />
IQ Points (IQP) are his currency. He also has Coins.<br />
<br />
==Conversions==<br />
One IQP is the same as 6 [[User:Knittingfrenzy18 |RC]], or 10 [[User:EuclidGenius |Qwerty]]<br />
<br />
One coin is 90 IPQs<br />
<br />
==Value==<br />
Coins are low in value, so they are easy to get. On the other hand, IQPs are extremely hard to get<br />
<br />
=CSS's=<br />
[http://www.artofproblemsolving.com/Forum/viewtopic.php?f=624&t=447899 Plants vs Zombies 1 v1.0 CSS]<br />
<br />
=Fun Facts=<br />
In his old blog, Sci posted Locker must-haves, a graphing calculator, books, and a picture of his crush<br />
<br />
Sci has played violin for approximately 8 years<br />
<br />
=Mathemagical Carreer=<br />
*NOTE TO SELF: FILL OUT</div>Scientesthttps://artofproblemsolving.com/wiki/index.php?title=User:Scientest&diff=52622User:Scientest2013-05-01T18:01:15Z<p>Scientest: /* Fun Facts */</p>
<hr />
<div> [[File:Warning.gif]]<br />
"Let us blow this popsicle stand! Okay, so maybe it's an ice pop stand, but whatever." –Sci at a school athletic event<br />
<br />
Hi there. Welcome to my Wiki page. I wrote this mainly in third person, so enjoy this while it lasts. And take heed of my warning. Scroll all the way down. Yikes. Well, have fun here! If you get bored, you can always go the forums.<br />
=Bio=<br />
Scientest is almost 12. He loves using <math>\text{\text\LaTeX}</math> and playing Plants vs. Zombies. He goes by the nickname Sci. He has done Algebra 1 (Summer 2011) and Counting and Probability (Fall-Spring 2011-2012) Sci plays the violin and the viola and loves math. He enjoys Plants vs. Zombies and cannot wait for P vs. Z 2 to come out. He also enjoys ClubPenguin (Look out for Inventapeng), Poptropica, Ninjago, and Pokemon<br />
==Name==<br />
His first name is Andrew. He snipped his last name from an FF post<br />
<br />
==Favorites==<br />
===Color===<br />
Pink: "It rocks"<br />
===Schoolhouse Rock song=== <br />
"I like them all, but my personal favorite is ''Interplanet Janet''"<br />
===Games on iPod/iPad=== <br />
Plants vs. Zombies: "I especially like it when the zombies eat your brains. Lol."<br />
<br />
Anthill<br />
<br />
Ouch!<br />
<br />
Worms 2<br />
<br />
Jetpack Joyride<br />
<br />
===Favorite Avatar Game=== <br />
Club Penguin, Runner-up: Poptropica<br />
===TV Show=== <br />
''Wild Kratts'': "Who knew how amazing nature is?"<br />
<br />
Runner-up: Pokémon Anime<br />
<br />
===Subject=== <br />
Math!<br />
===Catch Phrases===<br />
"Technically speaking... uh, no" <br />
<br />
"Let us blow this popsicle stand!"<br />
<br />
"Can you say, 'no?'"<br />
<br />
===Comic===<br />
''Foxtrot'': "Jason is so funny." <br />
<br />
Comments: Dantx5: I agree.<br />
<br />
==Websites==<br />
Sci has an account on Club Penguin, Art of Problem Solving, Animal Jam, and EarIAm.<br />
<br />
==AoPS History==<br />
Sci posts a lot in the Fun Factory.<br />
===Stats===<br />
Sci joined AoPS on Feb 22, 2011, 8:44 am<br />
=Currency=<br />
IQ Points (IQP) are his currency. He also has Coins.<br />
<br />
==Conversions==<br />
One IQP is the same as 6 [[User:Knittingfrenzy18 |RC]], or 10 [[User:EuclidGenius |Qwerty]]<br />
<br />
One coin is 90 IPQs<br />
<br />
==Value==<br />
Coins are low in value, so they are easy to get. On the other hand, IQPs are extremely hard to get<br />
<br />
=CSS's=<br />
[http://www.artofproblemsolving.com/Forum/viewtopic.php?f=624&t=447899 Plants vs Zombies 1 v1.0 CSS]<br />
<br />
=Fun Facts=<br />
In his old blog, Sci posted Locker must-haves, a graphing calculator, books, and a picture of his crush<br />
<br />
Sci has played violin for approximately 8 years<br />
<br />
=Mathemagical Carreer=<br />
*NOTE TO SELF: FILL OUT</div>Scientesthttps://artofproblemsolving.com/wiki/index.php?title=User:Scientest&diff=52621User:Scientest2013-05-01T18:00:32Z<p>Scientest: /* Games on iPod/iPad */</p>
<hr />
<div> [[File:Warning.gif]]<br />
"Let us blow this popsicle stand! Okay, so maybe it's an ice pop stand, but whatever." –Sci at a school athletic event<br />
<br />
Hi there. Welcome to my Wiki page. I wrote this mainly in third person, so enjoy this while it lasts. And take heed of my warning. Scroll all the way down. Yikes. Well, have fun here! If you get bored, you can always go the forums.<br />
=Bio=<br />
Scientest is almost 12. He loves using <math>\text{\text\LaTeX}</math> and playing Plants vs. Zombies. He goes by the nickname Sci. He has done Algebra 1 (Summer 2011) and Counting and Probability (Fall-Spring 2011-2012) Sci plays the violin and the viola and loves math. He enjoys Plants vs. Zombies and cannot wait for P vs. Z 2 to come out. He also enjoys ClubPenguin (Look out for Inventapeng), Poptropica, Ninjago, and Pokemon<br />
==Name==<br />
His first name is Andrew. He snipped his last name from an FF post<br />
<br />
==Favorites==<br />
===Color===<br />
Pink: "It rocks"<br />
===Schoolhouse Rock song=== <br />
"I like them all, but my personal favorite is ''Interplanet Janet''"<br />
===Games on iPod/iPad=== <br />
Plants vs. Zombies: "I especially like it when the zombies eat your brains. Lol."<br />
<br />
Anthill<br />
<br />
Ouch!<br />
<br />
Worms 2<br />
<br />
Jetpack Joyride<br />
<br />
===Favorite Avatar Game=== <br />
Club Penguin, Runner-up: Poptropica<br />
===TV Show=== <br />
''Wild Kratts'': "Who knew how amazing nature is?"<br />
<br />
Runner-up: Pokémon Anime<br />
<br />
===Subject=== <br />
Math!<br />
===Catch Phrases===<br />
"Technically speaking... uh, no" <br />
<br />
"Let us blow this popsicle stand!"<br />
<br />
"Can you say, 'no?'"<br />
<br />
===Comic===<br />
''Foxtrot'': "Jason is so funny." <br />
<br />
Comments: Dantx5: I agree.<br />
<br />
==Websites==<br />
Sci has an account on Club Penguin, Art of Problem Solving, Animal Jam, and EarIAm.<br />
<br />
==AoPS History==<br />
Sci posts a lot in the Fun Factory.<br />
===Stats===<br />
Sci joined AoPS on Feb 22, 2011, 8:44 am<br />
=Currency=<br />
IQ Points (IQP) are his currency. He also has Coins.<br />
<br />
==Conversions==<br />
One IQP is the same as 6 [[User:Knittingfrenzy18 |RC]], or 10 [[User:EuclidGenius |Qwerty]]<br />
<br />
One coin is 90 IPQs<br />
<br />
==Value==<br />
Coins are low in value, so they are easy to get. On the other hand, IQPs are extremely hard to get<br />
<br />
=CSS's=<br />
[http://www.artofproblemsolving.com/Forum/viewtopic.php?f=624&t=447899 Plants vs Zombies 1 v1.0 CSS]<br />
<br />
=Fun Facts=<br />
In his old blog, Sci posted Locker must-haves, a graphing calculator, books, and a picture of his crush<br />
<br />
Sci has played violin for approximately 7 years<br />
<br />
=Mathemagical Carreer=<br />
*NOTE TO SELF: FILL OUT</div>Scientesthttps://artofproblemsolving.com/wiki/index.php?title=User:Scientest&diff=52620User:Scientest2013-05-01T18:00:15Z<p>Scientest: /* Catch Phrases */</p>
<hr />
<div> [[File:Warning.gif]]<br />
"Let us blow this popsicle stand! Okay, so maybe it's an ice pop stand, but whatever." –Sci at a school athletic event<br />
<br />
Hi there. Welcome to my Wiki page. I wrote this mainly in third person, so enjoy this while it lasts. And take heed of my warning. Scroll all the way down. Yikes. Well, have fun here! If you get bored, you can always go the forums.<br />
=Bio=<br />
Scientest is almost 12. He loves using <math>\text{\text\LaTeX}</math> and playing Plants vs. Zombies. He goes by the nickname Sci. He has done Algebra 1 (Summer 2011) and Counting and Probability (Fall-Spring 2011-2012) Sci plays the violin and the viola and loves math. He enjoys Plants vs. Zombies and cannot wait for P vs. Z 2 to come out. He also enjoys ClubPenguin (Look out for Inventapeng), Poptropica, Ninjago, and Pokemon<br />
==Name==<br />
His first name is Andrew. He snipped his last name from an FF post<br />
<br />
==Favorites==<br />
===Color===<br />
Pink: "It rocks"<br />
===Schoolhouse Rock song=== <br />
"I like them all, but my personal favorite is ''Interplanet Janet''"<br />
===Games on iPod/iPad=== <br />
Plants vs. Zombies: "I especially like it when the zombies eat your brains. Lol."<br />
<br />
Anthill<br />
<br />
Ouch!<br />
<br />
===Favorite Avatar Game=== <br />
Club Penguin, Runner-up: Poptropica<br />
===TV Show=== <br />
''Wild Kratts'': "Who knew how amazing nature is?"<br />
<br />
Runner-up: Pokémon Anime<br />
<br />
===Subject=== <br />
Math!<br />
===Catch Phrases===<br />
"Technically speaking... uh, no" <br />
<br />
"Let us blow this popsicle stand!"<br />
<br />
"Can you say, 'no?'"<br />
<br />
===Comic===<br />
''Foxtrot'': "Jason is so funny." <br />
<br />
Comments: Dantx5: I agree.<br />
<br />
==Websites==<br />
Sci has an account on Club Penguin, Art of Problem Solving, Animal Jam, and EarIAm.<br />
<br />
==AoPS History==<br />
Sci posts a lot in the Fun Factory.<br />
===Stats===<br />
Sci joined AoPS on Feb 22, 2011, 8:44 am<br />
=Currency=<br />
IQ Points (IQP) are his currency. He also has Coins.<br />
<br />
==Conversions==<br />
One IQP is the same as 6 [[User:Knittingfrenzy18 |RC]], or 10 [[User:EuclidGenius |Qwerty]]<br />
<br />
One coin is 90 IPQs<br />
<br />
==Value==<br />
Coins are low in value, so they are easy to get. On the other hand, IQPs are extremely hard to get<br />
<br />
=CSS's=<br />
[http://www.artofproblemsolving.com/Forum/viewtopic.php?f=624&t=447899 Plants vs Zombies 1 v1.0 CSS]<br />
<br />
=Fun Facts=<br />
In his old blog, Sci posted Locker must-haves, a graphing calculator, books, and a picture of his crush<br />
<br />
Sci has played violin for approximately 7 years<br />
<br />
=Mathemagical Carreer=<br />
*NOTE TO SELF: FILL OUT</div>Scientesthttps://artofproblemsolving.com/wiki/index.php?title=User:Scientest&diff=52619User:Scientest2013-05-01T17:59:59Z<p>Scientest: /* Websites */</p>
<hr />
<div> [[File:Warning.gif]]<br />
"Let us blow this popsicle stand! Okay, so maybe it's an ice pop stand, but whatever." –Sci at a school athletic event<br />
<br />
Hi there. Welcome to my Wiki page. I wrote this mainly in third person, so enjoy this while it lasts. And take heed of my warning. Scroll all the way down. Yikes. Well, have fun here! If you get bored, you can always go the forums.<br />
=Bio=<br />
Scientest is almost 12. He loves using <math>\text{\text\LaTeX}</math> and playing Plants vs. Zombies. He goes by the nickname Sci. He has done Algebra 1 (Summer 2011) and Counting and Probability (Fall-Spring 2011-2012) Sci plays the violin and the viola and loves math. He enjoys Plants vs. Zombies and cannot wait for P vs. Z 2 to come out. He also enjoys ClubPenguin (Look out for Inventapeng), Poptropica, Ninjago, and Pokemon<br />
==Name==<br />
His first name is Andrew. He snipped his last name from an FF post<br />
<br />
==Favorites==<br />
===Color===<br />
Pink: "It rocks"<br />
===Schoolhouse Rock song=== <br />
"I like them all, but my personal favorite is ''Interplanet Janet''"<br />
===Games on iPod/iPad=== <br />
Plants vs. Zombies: "I especially like it when the zombies eat your brains. Lol."<br />
<br />
Anthill<br />
<br />
Ouch!<br />
<br />
===Favorite Avatar Game=== <br />
Club Penguin, Runner-up: Poptropica<br />
===TV Show=== <br />
''Wild Kratts'': "Who knew how amazing nature is?"<br />
<br />
Runner-up: Pokémon Anime<br />
<br />
===Subject=== <br />
Math!<br />
===Catch Phrases===<br />
"Technically speaking... uh, no" <br />
"Let us blow this popsicle stand!"<br />
"Can you say, 'no?'"<br />
<br />
===Comic===<br />
''Foxtrot'': "Jason is so funny." <br />
<br />
Comments: Dantx5: I agree.<br />
<br />
==Websites==<br />
Sci has an account on Club Penguin, Art of Problem Solving, Animal Jam, and EarIAm.<br />
<br />
==AoPS History==<br />
Sci posts a lot in the Fun Factory.<br />
===Stats===<br />
Sci joined AoPS on Feb 22, 2011, 8:44 am<br />
=Currency=<br />
IQ Points (IQP) are his currency. He also has Coins.<br />
<br />
==Conversions==<br />
One IQP is the same as 6 [[User:Knittingfrenzy18 |RC]], or 10 [[User:EuclidGenius |Qwerty]]<br />
<br />
One coin is 90 IPQs<br />
<br />
==Value==<br />
Coins are low in value, so they are easy to get. On the other hand, IQPs are extremely hard to get<br />
<br />
=CSS's=<br />
[http://www.artofproblemsolving.com/Forum/viewtopic.php?f=624&t=447899 Plants vs Zombies 1 v1.0 CSS]<br />
<br />
=Fun Facts=<br />
In his old blog, Sci posted Locker must-haves, a graphing calculator, books, and a picture of his crush<br />
<br />
Sci has played violin for approximately 7 years<br />
<br />
=Mathemagical Carreer=<br />
*NOTE TO SELF: FILL OUT</div>Scientesthttps://artofproblemsolving.com/wiki/index.php?title=User:Scientest&diff=52618User:Scientest2013-05-01T17:59:45Z<p>Scientest: /* Games and FF */</p>
<hr />
<div> [[File:Warning.gif]]<br />
"Let us blow this popsicle stand! Okay, so maybe it's an ice pop stand, but whatever." –Sci at a school athletic event<br />
<br />
Hi there. Welcome to my Wiki page. I wrote this mainly in third person, so enjoy this while it lasts. And take heed of my warning. Scroll all the way down. Yikes. Well, have fun here! If you get bored, you can always go the forums.<br />
=Bio=<br />
Scientest is almost 12. He loves using <math>\text{\text\LaTeX}</math> and playing Plants vs. Zombies. He goes by the nickname Sci. He has done Algebra 1 (Summer 2011) and Counting and Probability (Fall-Spring 2011-2012) Sci plays the violin and the viola and loves math. He enjoys Plants vs. Zombies and cannot wait for P vs. Z 2 to come out. He also enjoys ClubPenguin (Look out for Inventapeng), Poptropica, Ninjago, and Pokemon<br />
==Name==<br />
His first name is Andrew. He snipped his last name from an FF post<br />
<br />
==Favorites==<br />
===Color===<br />
Pink: "It rocks"<br />
===Schoolhouse Rock song=== <br />
"I like them all, but my personal favorite is ''Interplanet Janet''"<br />
===Games on iPod/iPad=== <br />
Plants vs. Zombies: "I especially like it when the zombies eat your brains. Lol."<br />
<br />
Anthill<br />
<br />
Ouch!<br />
<br />
===Favorite Avatar Game=== <br />
Club Penguin, Runner-up: Poptropica<br />
===TV Show=== <br />
''Wild Kratts'': "Who knew how amazing nature is?"<br />
<br />
Runner-up: Pokémon Anime<br />
<br />
===Subject=== <br />
Math!<br />
===Catch Phrases===<br />
"Technically speaking... uh, no" <br />
"Let us blow this popsicle stand!"<br />
"Can you say, 'no?'"<br />
<br />
===Comic===<br />
''Foxtrot'': "Jason is so funny." <br />
<br />
Comments: Dantx5: I agree.<br />
<br />
==Websites==<br />
Sci has an account on Poptropica, Club Penguin, Art of Problem Solving, Animal Jam, and EarIAm.<br />
<br />
==AoPS History==<br />
Sci posts a lot in the Fun Factory.<br />
===Stats===<br />
Sci joined AoPS on Feb 22, 2011, 8:44 am<br />
=Currency=<br />
IQ Points (IQP) are his currency. He also has Coins.<br />
<br />
==Conversions==<br />
One IQP is the same as 6 [[User:Knittingfrenzy18 |RC]], or 10 [[User:EuclidGenius |Qwerty]]<br />
<br />
One coin is 90 IPQs<br />
<br />
==Value==<br />
Coins are low in value, so they are easy to get. On the other hand, IQPs are extremely hard to get<br />
<br />
=CSS's=<br />
[http://www.artofproblemsolving.com/Forum/viewtopic.php?f=624&t=447899 Plants vs Zombies 1 v1.0 CSS]<br />
<br />
=Fun Facts=<br />
In his old blog, Sci posted Locker must-haves, a graphing calculator, books, and a picture of his crush<br />
<br />
Sci has played violin for approximately 7 years<br />
<br />
=Mathemagical Carreer=<br />
*NOTE TO SELF: FILL OUT</div>Scientesthttps://artofproblemsolving.com/wiki/index.php?title=User:Scientest&diff=52617User:Scientest2013-05-01T17:59:28Z<p>Scientest: /* Catch Phrases */</p>
<hr />
<div> [[File:Warning.gif]]<br />
"Let us blow this popsicle stand! Okay, so maybe it's an ice pop stand, but whatever." –Sci at a school athletic event<br />
<br />
Hi there. Welcome to my Wiki page. I wrote this mainly in third person, so enjoy this while it lasts. And take heed of my warning. Scroll all the way down. Yikes. Well, have fun here! If you get bored, you can always go the forums.<br />
=Bio=<br />
Scientest is almost 12. He loves using <math>\text{\text\LaTeX}</math> and playing Plants vs. Zombies. He goes by the nickname Sci. He has done Algebra 1 (Summer 2011) and Counting and Probability (Fall-Spring 2011-2012) Sci plays the violin and the viola and loves math. He enjoys Plants vs. Zombies and cannot wait for P vs. Z 2 to come out. He also enjoys ClubPenguin (Look out for Inventapeng), Poptropica, Ninjago, and Pokemon<br />
==Name==<br />
His first name is Andrew. He snipped his last name from an FF post<br />
<br />
==Favorites==<br />
===Color===<br />
Pink: "It rocks"<br />
===Schoolhouse Rock song=== <br />
"I like them all, but my personal favorite is ''Interplanet Janet''"<br />
===Games on iPod/iPad=== <br />
Plants vs. Zombies: "I especially like it when the zombies eat your brains. Lol."<br />
<br />
Anthill<br />
<br />
Ouch!<br />
<br />
===Favorite Avatar Game=== <br />
Club Penguin, Runner-up: Poptropica<br />
===TV Show=== <br />
''Wild Kratts'': "Who knew how amazing nature is?"<br />
<br />
Runner-up: Pokémon Anime<br />
<br />
===Subject=== <br />
Math!<br />
===Catch Phrases===<br />
"Technically speaking... uh, no" <br />
"Let us blow this popsicle stand!"<br />
"Can you say, 'no?'"<br />
<br />
===Comic===<br />
''Foxtrot'': "Jason is so funny." <br />
<br />
Comments: Dantx5: I agree.<br />
<br />
==Websites==<br />
Sci has an account on Poptropica, Club Penguin, Art of Problem Solving, Animal Jam, and EarIAm.<br />
<br />
==AoPS History==<br />
Sci posts a lot in the Fun Factory.<br />
===Stats===<br />
Sci joined AoPS on Feb 22, 2011, 8:44 am<br />
===Games and FF===<br />
Currently, Sci has started the Experimental game [http://www.artofproblemsolving.com/Forum/viewtopic.php?f=535&t=494960 Pokémon Battle]<br />
<br />
=Currency=<br />
IQ Points (IQP) are his currency. He also has Coins.<br />
<br />
==Conversions==<br />
One IQP is the same as 6 [[User:Knittingfrenzy18 |RC]], or 10 [[User:EuclidGenius |Qwerty]]<br />
<br />
One coin is 90 IPQs<br />
<br />
==Value==<br />
Coins are low in value, so they are easy to get. On the other hand, IQPs are extremely hard to get<br />
<br />
=CSS's=<br />
[http://www.artofproblemsolving.com/Forum/viewtopic.php?f=624&t=447899 Plants vs Zombies 1 v1.0 CSS]<br />
<br />
=Fun Facts=<br />
In his old blog, Sci posted Locker must-haves, a graphing calculator, books, and a picture of his crush<br />
<br />
Sci has played violin for approximately 7 years<br />
<br />
=Mathemagical Carreer=<br />
*NOTE TO SELF: FILL OUT</div>Scientesthttps://artofproblemsolving.com/wiki/index.php?title=User:Scientest&diff=52616User:Scientest2013-05-01T17:58:59Z<p>Scientest: /* SpamPol */</p>
<hr />
<div> [[File:Warning.gif]]<br />
"Let us blow this popsicle stand! Okay, so maybe it's an ice pop stand, but whatever." –Sci at a school athletic event<br />
<br />
Hi there. Welcome to my Wiki page. I wrote this mainly in third person, so enjoy this while it lasts. And take heed of my warning. Scroll all the way down. Yikes. Well, have fun here! If you get bored, you can always go the forums.<br />
=Bio=<br />
Scientest is almost 12. He loves using <math>\text{\text\LaTeX}</math> and playing Plants vs. Zombies. He goes by the nickname Sci. He has done Algebra 1 (Summer 2011) and Counting and Probability (Fall-Spring 2011-2012) Sci plays the violin and the viola and loves math. He enjoys Plants vs. Zombies and cannot wait for P vs. Z 2 to come out. He also enjoys ClubPenguin (Look out for Inventapeng), Poptropica, Ninjago, and Pokemon<br />
==Name==<br />
His first name is Andrew. He snipped his last name from an FF post<br />
<br />
==Favorites==<br />
===Color===<br />
Pink: "It rocks"<br />
===Schoolhouse Rock song=== <br />
"I like them all, but my personal favorite is ''Interplanet Janet''"<br />
===Games on iPod/iPad=== <br />
Plants vs. Zombies: "I especially like it when the zombies eat your brains. Lol."<br />
<br />
Anthill<br />
<br />
Ouch!<br />
<br />
===Favorite Avatar Game=== <br />
Club Penguin, Runner-up: Poptropica<br />
===TV Show=== <br />
''Wild Kratts'': "Who knew how amazing nature is?"<br />
<br />
Runner-up: Pokémon Anime<br />
<br />
===Subject=== <br />
Math!<br />
===Catch Phrases===<br />
"Technically speaking... uh, no" and "Let us blow this popsicle stand!"<br />
<br />
===Comic===<br />
''Foxtrot'': "Jason is so funny." <br />
<br />
Comments: Dantx5: I agree.<br />
<br />
==Websites==<br />
Sci has an account on Poptropica, Club Penguin, Art of Problem Solving, Animal Jam, and EarIAm.<br />
<br />
==AoPS History==<br />
Sci posts a lot in the Fun Factory.<br />
===Stats===<br />
Sci joined AoPS on Feb 22, 2011, 8:44 am<br />
===Games and FF===<br />
Currently, Sci has started the Experimental game [http://www.artofproblemsolving.com/Forum/viewtopic.php?f=535&t=494960 Pokémon Battle]<br />
<br />
=Currency=<br />
IQ Points (IQP) are his currency. He also has Coins.<br />
<br />
==Conversions==<br />
One IQP is the same as 6 [[User:Knittingfrenzy18 |RC]], or 10 [[User:EuclidGenius |Qwerty]]<br />
<br />
One coin is 90 IPQs<br />
<br />
==Value==<br />
Coins are low in value, so they are easy to get. On the other hand, IQPs are extremely hard to get<br />
<br />
=CSS's=<br />
[http://www.artofproblemsolving.com/Forum/viewtopic.php?f=624&t=447899 Plants vs Zombies 1 v1.0 CSS]<br />
<br />
=Fun Facts=<br />
In his old blog, Sci posted Locker must-haves, a graphing calculator, books, and a picture of his crush<br />
<br />
Sci has played violin for approximately 7 years<br />
<br />
=Mathemagical Carreer=<br />
*NOTE TO SELF: FILL OUT</div>Scientesthttps://artofproblemsolving.com/wiki/index.php?title=2006_AMC_8_Problems/Problem_21&diff=495492006 AMC 8 Problems/Problem 212012-11-13T04:48:09Z<p>Scientest: /* Problem */</p>
<hr />
<div>==Problem==<br />
An aquarium has a rectangular base that measures <math>100</math> cm by <math>40</math> cm and has a height of <math>50</math> cm. The aquarium is filled with water to a depth of <math>37</math> cm. A rock with volume <math>1000\text{cm}^3</math> is then placed in the aquarium and completely submerged. By how many centimeters does the water level rise? <br />
<br />
<math> \textbf{(A)}\ 0.25\qquad\textbf{(B)}\ 0.5\qquad\textbf{(C)}\ 1\qquad\textbf{(D)}\ 1.25\qquad\textbf{(E)}\ 2.5 </math><br />
<br />
==Solution==<br />
The water level will rise <math>1</math>cm for every <math>100 \cdot 40 = 4000\text{cm}^2</math>. Since <math>1000</math> is <math>\frac{1}{4}</math> of <math>4000</math>, the water will rise <math>\frac{1}{4}\cdot1 = \textbf{(A)}\ 0.25</math><br />
<br />
{{AMC8 box|year=2006|n=II|num-b=20|num-a=22}}</div>Scientesthttps://artofproblemsolving.com/wiki/index.php?title=2006_AMC_8_Problems&diff=495482006 AMC 8 Problems2012-11-13T04:47:52Z<p>Scientest: /* Problem 21 */</p>
<hr />
<div>==Problem 1==<br />
Mindy made three purchases for <math> \textdollar 1.98</math>, <math> \textdollar 5.04 </math>, and <math> \textdollar 9.89</math>. What was her total, to the nearest dollar? <br />
<br />
<math> \textbf{(A)}\ 10\qquad\textbf{(B)}\ 15\qquad\textbf{(C)}\ 16\qquad\textbf{(D)}\ 17\qquad\textbf{(E)}\18</math><br />
<br />
[[2006 AMC 8 Problems/Problem 1|Solution]]<br />
<br />
==Problem 2==<br />
On the AMC 8 contest Billy answers 13 questions correctly, answers 7 questions incorrectly and doesn't answer the last 5. What is his score?<br />
<br />
<math> \textbf{(A)}\ 1\qquad\textbf{(B)}\ 6\qquad\textbf{(C)}\ 13\qquad\textbf{(D)}\ 19\qquad\textbf{(E)}\ 26 </math><br />
<br />
<br />
[[2006 AMC 8 Problems/Problem 2|Solution]]<br />
<br />
==Problem 3==<br />
<br />
<br />
Elisa swims laps in the pool. When she first started, she completed 10 laps in 25 minutes. Now she can finish 12 laps in 24 minutes. By how many minutes has she improved her lap time?<br />
<br />
<math> \textbf{(A)}\ \frac{1}{2}\qquad\textbf{(B)}\ \frac{3}{4}\qquad\textbf{(C)}\ 1\qquad\textbf{(D)}\ 2\qquad\textbf{(E)}\ 3 </math><br />
<br />
<br />
[[2006 AMC 8 Problems/Problem 3|Solution]]<br />
<br />
==Problem 4==<br />
Initially, a spinner points west. Chenille moves it clockwise <math> 2 \dfrac{1}{4}</math> revolutions and then counterclockwise <math> 3 \dfrac{3}{4}</math> revolutions. In what direction does the spinner point after the two moves?<br />
<br />
<asy>size(96);<br />
draw(circle((0,0),1),linewidth(1));<br />
draw((0,0.75)--(0,1.25),linewidth(1));<br />
draw((0,-0.75)--(0,-1.25),linewidth(1));<br />
draw((0.75,0)--(1.25,0),linewidth(1));<br />
draw((-0.75,0)--(-1.25,0),linewidth(1));<br />
label("$N$",(0,1.25), N);<br />
label("$W$",(-1.25,0), W);<br />
label("$E$",(1.25,0), E);<br />
label("$S$",(0,-1.25), S);<br />
draw((0,0)--(-0.5,0),EndArrow);</asy><br />
<br />
<math> \textbf{(A)}\ \text{north} \qquad <br />
\textbf{(B)}\ \text{east} \qquad <br />
\textbf{(C)}\ \text{south} \qquad <br />
\textbf{(D)}\ \text{west} \qquad <br />
\textbf{(E)}\ \text{northwest}</math><br />
<br />
<br />
[[2006 AMC 8 Problems/Problem 4|Solution]]<br />
<br />
==Problem 5==<br />
Points <math> A, B, C</math> and <math> D</math> are midpoints of the sides of the larger square. If the larger square has area 60, what is the area of the smaller square?<br />
<br />
<asy>size(100);<br />
draw((0,0)--(2,0)--(2,2)--(0,2)--cycle,linewidth(1));<br />
draw((0,1)--(1,2)--(2,1)--(1,0)--cycle);<br />
label("$A$", (1,2), N);<br />
label("$B$", (2,1), E);<br />
label("$C$", (1,0), S);<br />
label("$D$", (0,1), W);</asy><br />
<br />
<math> \textbf{(A)}\ 15 \qquad <br />
\textbf{(B)}\ 20 \qquad <br />
\textbf{(C)}\ 24 \qquad <br />
\textbf{(D)}\ 30 \qquad <br />
\textbf{(E)}\ 40</math><br />
<br />
<br />
[[2006 AMC 8 Problems/Problem 5|Solution]]<br />
<br />
==Problem 6==<br />
The letter T is formed by placing two <math> 2 \times 4 </math> inch rectangles next to each other, as shown. What is the perimeter of the T, in inches? <br />
<br />
<asy><br />
size(150);<br />
draw((0,6)--(4,6)--(4,4)--(3,4)--(3,0)--(1,0)--(1,4)--(0,4)--cycle, linewidth(1));</asy><br />
<br />
<math> \textbf{(A)}\ 12\qquad\textbf{(B)}\ 16\qquad\textbf{(C)}\ 20\qquad\textbf{(D)}\ 22\qquad\textbf{(E)}\ 24 </math><br />
<br />
<br />
<br />
[[2006 AMC 8 Problems/Problem 6|Solution]]<br />
<br />
==Problem 7==<br />
<br />
Circle <math> X </math> has a radius of <math> \pi </math>. Circle <math> Y </math> has a circumference of <math> 8 \pi </math>. Circle <math> Z </math> has an area of <math> 9 \pi </math>. List the circles in order from smallest to largest radius. <br />
<br />
<math> \textbf{(A)}\ X, Y, Z\qquad\textbf{(B)}\ Z, X, Y\qquad\textbf{(C)}\ Y, X, Z\qquad\textbf{(D)}\ Z, Y, X\qquad\textbf{(E)}\ X, Z, Y </math><br />
<br />
<br />
[[2006 AMC 8 Problems/Problem 7|Solution]]<br />
<br />
==Problem 8==<br />
<br />
The table shows some of the results of a survey by radiostation KAMC. What percentage of the males surveyed listen to the station? <br />
<br />
<math> \begin{tabular}{|c|c|c|c|}\hline & Listen & Don't Listen & Total\\ \hline Males & ? & 26 & ?\\ \hline Females & 58 & ? & 96\\ \hline Total & 136 & 64 & 200\\ \hline\end{tabular} </math><br />
<br />
<math> \textbf{(A)}\ 39\qquad\textbf{(B)}\ 48\qquad\textbf{(C)}\ 52\qquad\textbf{(D)}\ 55\qquad\textbf{(E)}\ 75 </math><br />
<br />
<br />
[[2006 AMC 8 Problems/Problem 8|Solution]]<br />
<br />
==Problem 9==<br />
<br />
What is the product of <math> \frac{3}{2}\times\frac{4}{3}\times\frac{5}{4}\times\cdots\times\frac{2006}{2005} </math> ?<br />
<br />
<math> \textbf{(A)}\ 1\qquad\textbf{(B)}\ 1002\qquad\textbf{(C)}\ 1003\qquad\textbf{(D)}\ 2005\qquad\textbf{(E)}\ 2006 </math><br />
<br />
<br />
[[2006 AMC 8 Problems/Problem 9|Solution]]<br />
<br />
==Problem 10==<br />
<br />
Jorge's teacher asks him to plot all the ordered pairs <math> (w. l) </math> of positive integers for which <math> w </math> is the width and <math> l </math> is the length of a rectangle with area 12. What should his graph look like?<br />
<br />
<math> \textbf{(A)} </math> <asy><br />
size(75);<br />
draw((0,-1)--(0,13));<br />
draw((-1,0)--(13,0));<br />
dot((1,12));<br />
dot((2,6));<br />
dot((3,4));<br />
dot((4,3));<br />
dot((6,2));<br />
dot((12,1));<br />
label("$l$", (0,6), W);<br />
label("$w$", (6,0), S);</asy><br />
<br />
<math> \textbf{(B)} </math> <asy><br />
size(75);<br />
draw((0,-1)--(0,13));<br />
draw((-1,0)--(13,0));<br />
dot((1,1));<br />
dot((3,3));<br />
dot((5,5));<br />
dot((7,7));<br />
dot((9,9));<br />
dot((11,11));<br />
label("$l$", (0,6), W);<br />
label("$w$", (6,0), S);</asy><br />
<br />
<math> \textbf{(C)} </math> <asy><br />
size(75);<br />
draw((0,-1)--(0,13));<br />
draw((-1,0)--(13,0));<br />
dot((1,11));<br />
dot((3,9));<br />
dot((5,7));<br />
dot((7,5));<br />
dot((9,3));<br />
dot((11,1));<br />
label("$l$", (0,6), W);<br />
label("$w$", (6,0), S);</asy><br />
<br />
<math> \textbf{(D)} </math> <asy><br />
size(75);<br />
draw((0,-1)--(0,13));<br />
draw((-1,0)--(13,0));<br />
dot((1,6));<br />
dot((3,6));<br />
dot((5,6));<br />
dot((7,6));<br />
dot((9,6));<br />
dot((11,6));<br />
label("$l$", (0,6), W);<br />
label("$w$", (6,0), S);</asy><br />
<br />
<math> \textbf{(E)} </math> <asy><br />
size(75);<br />
draw((0,-1)--(0,13));<br />
draw((-1,0)--(13,0));<br />
dot((6,1));<br />
dot((6,3));<br />
dot((6,5));<br />
dot((6,7));<br />
dot((6,9));<br />
dot((6,11));<br />
label("$l$", (0,6), W);<br />
label("$w$", (6,0), S);</asy><br />
<br />
<br />
[[2006 AMC 8 Problems/Problem 10|Solution]]<br />
<br />
==Problem 11==<br />
<br />
How many two-digit numbers have digits whose sum is a perfect square? <br />
<br />
<math> \textbf{(A)}\ 13\qquad\textbf{(B)}\ 16\qquad\textbf{(C)}\ 17\qquad\textbf{(D)}\ 18\qquad\textbf{(E)}\ 19 </math><br />
<br />
<br />
[[2006 AMC 8 Problems/Problem 11|Solution]]<br />
<br />
==Problem 12==<br />
<br />
Antonette gets <math> 70 \% </math> on a 10-problem test, <math> 80 \% </math> on a 20-problem test and <math> 90 \% </math> on a 30-problem test. If the three tests are combined into one 60-problem test, which percent is closest to her overall score? <br />
<br />
<math> \textbf{(A)}\ 40\qquad\textbf{(B)}\ 77\qquad\textbf{(C)}\ 80\qquad\textbf{(D)}\ 83\qquad\textbf{(E)}\ 87 </math><br />
<br />
<br />
[[2006 AMC 8 Problems/Problem 12|Solution]]<br />
<br />
==Problem 13==<br />
<br />
Cassie leaves Escanaba at 8:30 AM heading for Marquette on her bike. She bikes at a uniform rate of 12 miles per hour. Brian leaves Marquette at 9:00 AM heading for Escanaba on his bike. He bikes at a uniform rate of 16 miles per hour. They both bike on the same 62-mile route between Escanaba and Marquette. At what time in the morning do they meet? <br />
<br />
<math> \textbf{(A)}\ 10: 00\qquad\textbf{(B)}\ 10: 15\qquad\textbf{(C)}\ 10: 30\qquad\textbf{(D)}\ 11: 00\qquad\textbf{(E)}\ 11: 30 </math><br />
<br />
<br />
[[2006 AMC 8 Problems/Problem 13|Solution]]<br />
<br />
==Problem 14==<br />
<br />
Problems 14, 15 and 16 involve Mrs. Reed's English assignment. <br />
<br />
A Novel Assignment <br />
<br />
The students in Mrs. Reed's English class are reading the same 760-page novel. Three friends, Alice, Bob and Chandra, are in the class. Alice reads a page in 20 seconds, Bob reads a page in 45 seconds and Chandra reads a page in 30 seconds. <br />
<br />
If Bob and Chandra both read the whole book, Bob will spend how many more seconds reading than Chandra? <br />
<br />
<math> \textbf{(A)}\ 7,600\qquad\textbf{(B)}\ 11,400\qquad\textbf{(C)}\ 12,500\qquad\textbf{(D)}\ 15,200\qquad\textbf{(E)}\ 22,800 </math><br />
<br />
<br />
[[2006 AMC 8 Problems/Problem 14|Solution]]<br />
<br />
==Problem 15==<br />
<br />
Problems 14, 15 and 16 involve Mrs. Reed's English assignment. <br />
<br />
A Novel Assignment <br />
<br />
The students in Mrs. Reed's English class are reading the same 760-page novel. Three friends, Alice, Bob and Chandra, are in the class. Alice reads a page in 20 seconds, Bob reads a page in 45 seconds and Chandra reads a page in 30 seconds. <br />
<br />
Chandra and Bob, who each have a copy of the book, decide that they can save time by "team reading" the novel. In this scheme, Chandra will read from page 1 to a certain page and Bob will read from the next page through page 760, finishing the book. When they are through they will tell each other about the part they read. What is the last page that Chandra should read so that she and Bob spend the same amount of time reading the novel? <br />
<br />
<math> \textbf{(A)}\ 425\qquad\textbf{(B)}\ 444\qquad\textbf{(C)}\ 456\qquad\textbf{(D)}\ 484\qquad\textbf{(E)}\ 506 </math><br />
<br />
<br />
[[2006 AMC 8 Problems/Problem 15|Solution]]<br />
<br />
==Problem 16==<br />
<br />
Problems 14, 15 and 16 involve Mrs. Reed's English assignment. <br />
<br />
A Novel Assignment <br />
<br />
The students in Mrs. Reed's English class are reading the same 760-page novel. Three friends, Alice, Bob and Chandra, are in the class. Alice reads a page in 20 seconds, Bob reads a page in 45 seconds and Chandra reads a page in 30 seconds. <br />
<br />
Before Chandra and Bob start reading, Alice says she would like to team read with them. If they divide the book into three sections so that each reads for the same length of time, how many seconds will each have to read? <br />
<br />
<math> \textbf{(A)}\ 6400\qquad\textbf{(B)}\ 6600\qquad\textbf{(C)}\ 6800\qquad\textbf{(D)}\ 7000\qquad\textbf{(E)}\ 7200 </math><br />
<br />
<br />
[[2006 AMC 8 Problems/Problem 16|Solution]]<br />
<br />
==Problem 17==<br />
<br />
Jeff rotates spinners <math> P </math>, <math> Q </math> and <math> R </math> and adds the resulting numbers. What is the probability that his sum is an odd number? <br />
<br />
<asy><br />
size(200);<br />
path circle=circle((0,0),2);<br />
path r=(0,0)--(0,2);<br />
draw(circle,linewidth(1));<br />
draw(shift(5,0)*circle,linewidth(1));<br />
draw(shift(10,0)*circle,linewidth(1));<br />
draw(r,linewidth(1));<br />
draw(rotate(120)*r,linewidth(1));<br />
draw(rotate(240)*r,linewidth(1));<br />
draw(shift(5,0)*r,linewidth(1));<br />
draw(shift(5,0)*rotate(90)*r,linewidth(1));<br />
draw(shift(5,0)*rotate(180)*r,linewidth(1));<br />
draw(shift(5,0)*rotate(270)*r,linewidth(1));<br />
draw(shift(10,0)*r,linewidth(1));<br />
draw(shift(10,0)*rotate(60)*r,linewidth(1));<br />
draw(shift(10,0)*rotate(120)*r,linewidth(1));<br />
draw(shift(10,0)*rotate(180)*r,linewidth(1));<br />
draw(shift(10,0)*rotate(240)*r,linewidth(1));<br />
draw(shift(10,0)*rotate(300)*r,linewidth(1));<br />
label("$P$", (-2,2));<br />
label("$Q$", shift(5,0)*(-2,2));<br />
label("$R$", shift(10,0)*(-2,2));<br />
label("$1$", (-1,sqrt(2)/2));<br />
label("$2$", (1,sqrt(2)/2));<br />
label("$3$", (0,-1));<br />
label("$2$", shift(5,0)*(-sqrt(2)/2,sqrt(2)/2));<br />
label("$4$", shift(5,0)*(sqrt(2)/2,sqrt(2)/2));<br />
label("$6$", shift(5,0)*(sqrt(2)/2,-sqrt(2)/2));<br />
label("$8$", shift(5,0)*(-sqrt(2)/2,-sqrt(2)/2));<br />
label("$1$", shift(10,0)*(-0.5,1));<br />
label("$3$", shift(10,0)*(0.5,1));<br />
label("$5$", shift(10,0)*(1,0));<br />
label("$7$", shift(10,0)*(0.5,-1));<br />
label("$9$", shift(10,0)*(-0.5,-1));<br />
label("$11$", shift(10,0)*(-1,0));</asy><br />
<br />
<math> \textbf{(A)}\ \frac{1}{4}\qquad\textbf{(B)}\ \frac{1}{3}\qquad\textbf{(C)}\ \frac{1}{2}\qquad\textbf{(D)}\ \frac{2}{3}\qquad\textbf{(E)}\ \frac{3}{4} </math><br />
<br />
<br />
[[2006 AMC 8 Problems/Problem 17|Solution]]<br />
<br />
==Problem 18==<br />
<br />
A cube with 3-inch edges is made using 27 cubes with 1-inch edges. Nineteen of the smaller cubes are white and eight are black. If the eight black cubes are placed at the corners of the larger cube, what fraction of the surface area of the larger cube is white? <br />
<br />
<math> \textbf{(A)}\ \frac{1}{9}\qquad\textbf{(B)}\ \frac{1}{4}\qquad\textbf{(C)}\ \frac{4}{9}\qquad\textbf{(D)}\ \frac{5}{9}\qquad\textbf{(E)}\ \frac{19}{27} </math><br />
<br />
<br />
[[2006 AMC 8 Problems/Problem 18|Solution]]<br />
<br />
==Problem 19==<br />
<br />
Triangle <math> ABC </math> is an isosceles triangle with <math> \overline{AB}=\overline{BC}</math>. Point <math> D </math> is the midpoint of both <math> \overline{BC}</math> and <math> \overline{AE}</math>, and <math> \overline{CE} </math> is 11 units long. Triangle <math> ABD </math> is congruent to triangle <math> ECD </math>. What is the length of <math> \overline{BD} </math>? <br />
<br />
<asy><br />
size(100);<br />
draw((0,0)--(2,4)--(4,0)--(6,4)--cycle--(4,0),linewidth(1));<br />
label("$A$", (0,0), SW);<br />
label("$B$", (2,4), N);<br />
label("$C$", (4,0), SE);<br />
label("$D$", shift(0.2,0.1)*intersectionpoint((0,0)--(6,4),(2,4)--(4,0)), N);<br />
label("$E$", (6,4), NE);</asy><br />
<br />
<math> \textbf{(A)}\ 4\qquad\textbf{(B)}\ 4.5\qquad\textbf{(C)}\ 5\qquad\textbf{(D)}\ 5.5\qquad\textbf{(E)}\ 6 </math><br />
<br />
<br />
[[2006 AMC 8 Problems/Problem 19|Solution]]<br />
<br />
==Problem 20==<br />
<br />
A singles tournament had six players. Each player played every other player only once, with no ties. If Helen won 4 games, Ines won 3 games, Janet won 2 games, Kendra won 2 games and Lara won 2 games, how many games did Monica win? <br />
<br />
<math> \textbf{(A)}\ 0\qquad\textbf{(B)}\ 1\qquad\textbf{(C)}\ 2\qquad\textbf{(D)}\ 3\qquad\textbf{(E)}\ 4 </math><br />
<br />
<br />
[[2006 AMC 8 Problems/Problem 20|Solution]]<br />
<br />
==Problem 21==<br />
<br />
An aquarium has a rectangular base that measures <math> 100 </math> cm by <math> 40 </math> cm and has a height of <math> 50 </math> cm. The aquarium is filled with water to a depth of <math> 37 </math> cm. A rock with volume <math> 1000 \text{ cm}^3 </math> is then placed in the aquarium and completely submerged. By how many centimeters does the water level rise? <br />
<br />
<math> \textbf{(A)}\ 0.25\qquad\textbf{(B)}\ 0.5\qquad\textbf{(C)}\ 1\qquad\textbf{(D)}\ 1.25\qquad\textbf{(E)}\ 2.5 </math><br />
<br />
<br />
[[2006 AMC 8 Problems/Problem 21|Solution]]<br />
<br />
==Problem 22==<br />
<br />
Three different one-digit positive integers are placed in the bottom row of cells. Numbers in adjacent cells are added and the sum is placed in the cell above them. In the second row, continue the same process to obtain a number in the top cell. What is the difference between the largest and smallest numbers possible in the top cell?<br />
<br />
<asy><br />
path cell=((0,0)--(1,0)--(1,1)--(0,1)--cycle);<br />
path sw=((0,0)--(1,sqrt(3)));<br />
path se=((5,0)--(4,sqrt(3)));<br />
draw(cell, linewidth(1));<br />
draw(shift(2,0)*cell, linewidth(1));<br />
draw(shift(4,0)*cell, linewidth(1));<br />
draw(shift(1,3)*cell, linewidth(1));<br />
draw(shift(3,3)*cell, linewidth(1));<br />
draw(shift(2,6)*cell, linewidth(1));<br />
draw(shift(0.45,1.125)*sw, EndArrow);<br />
draw(shift(2.45,1.125)*sw, EndArrow);<br />
draw(shift(1.45,4.125)*sw, EndArrow);<br />
draw(shift(-0.45,1.125)*se, EndArrow);<br />
draw(shift(-2.45,1.125)*se, EndArrow);<br />
draw(shift(-1.45,4.125)*se, EndArrow);<br />
label("$+$", (1.5,1.5));<br />
label("$+$", (3.5,1.5));<br />
label("$+$", (2.5,4.5));</asy><br />
<br />
<math> \textbf{(A)}\ 16\qquad\textbf{(B)}\ 24\qquad\textbf{(C)}\ 25\qquad\textbf{(D)}\ 26\qquad\textbf{(E)}\ 35 </math><br />
<br />
<br />
[[2006 AMC 8 Problems/Problem 22|Solution]]<br />
<br />
==Problem 23==<br />
<br />
A box contains gold coins. If the coins are equally divided among six people, four coins are left over. If the coins are equally divided among five people, three coins are left over. If the box holds the smallest number of coins that meets these two conditions, how many coins are left when equally divided among seven people? <br />
<br />
<math> \textbf{(A)}\ 0\qquad\textbf{(B)}\ 1\qquad\textbf{(C)}\ 2\qquad\textbf{(D)}\ 3\qquad\textbf{(E)}\ 5 </math><br />
<br />
<br />
[[2006 AMC 8 Problems/Problem 23|Solution]]<br />
<br />
==Problem 24==<br />
<br />
In the multiplication problem below <math>A</math>, <math>B</math>, <math>C</math>, <math>D</math> and are different digits. What is <math>A+B</math>? <br />
<br />
<cmath> \begin{tabular}{cccc}& A & B & A\\ \times & & C & D\\ \hline C & D & C & D\\ \end{tabular} </cmath><br />
<br />
<math> \textbf{(A)}\ 1\qquad\textbf{(B)}\ 2\qquad\textbf{(C)}\ 3\qquad\textbf{(D)}\ 4\qquad\textbf{(E)}\ 9 </math><br />
<br />
<br />
[[2006 AMC 8 Problems/Problem 24|Solution]]<br />
<br />
==Problem 25==<br />
<br />
Barry wrote 6 different numbers, one on each side of 3 cards, and laid the cards on a table, as shown. The sums of the two numbers on each of the three cards are equal. The three numbers on the hidden sides are prime numbers. What is the average of the hidden prime numbers? <br />
<br />
<asy><br />
path card=((0,0)--(0,3)--(2,3)--(2,0)--cycle);<br />
draw(card, linewidth(1));<br />
draw(shift(2.5,0)*card, linewidth(1));<br />
draw(shift(5,0)*card, linewidth(1));<br />
label("$44$", (1,1.5));<br />
label("$59$", shift(2.5,0)*(1,1.5));<br />
label("$38$", shift(5,0)*(1,1.5));</asy><br />
<br />
<math> \textbf{(A)}\ 13\qquad\textbf{(B)}\ 14\qquad\textbf{(C)}\ 15\qquad\textbf{(D)}\ 16\qquad\textbf{(E)}\ 17 </math><br />
<br />
<br />
[[2006 AMC 8 Problems/Problem 25|Solution]]</div>Scientesthttps://artofproblemsolving.com/wiki/index.php?title=User:Scientest&diff=49354User:Scientest2012-11-07T18:20:05Z<p>Scientest: /* Fun Facts */</p>
<hr />
<div> [[File:Warning.gif]]<br />
"Let us blow this popsicle stand! Okay, so maybe it's an ice pop stand, but whatever." –Sci at a school athletic event<br />
<br />
Hi there. Welcome to my Wiki page. I wrote this mainly in third person, so enjoy this while it lasts. And take heed of my warning. Scroll all the way down. Yikes. Well, have fun here! If you get bored, you can always go the forums.<br />
=Bio=<br />
Scientest is almost 12. He loves using <math>\text{\text\LaTeX}</math> and playing Plants vs. Zombies. He goes by the nickname Sci. He has done Algebra 1 (Summer 2011) and Counting and Probability (Fall-Spring 2011-2012) Sci plays the violin and the viola and loves math. He enjoys Plants vs. Zombies and cannot wait for P vs. Z 2 to come out. He also enjoys ClubPenguin (Look out for Inventapeng), Poptropica, Ninjago, and Pokemon<br />
==Name==<br />
His first name is Andrew. He snipped his last name from an FF post<br />
<br />
==Favorites==<br />
===Color===<br />
Pink: "It rocks"<br />
===Schoolhouse Rock song=== <br />
"I like them all, but my personal favorite is ''Interplanet Janet''"<br />
===Games on iPod/iPad=== <br />
Plants vs. Zombies: "I especially like it when the zombies eat your brains. Lol."<br />
<br />
Anthill<br />
<br />
Ouch!<br />
<br />
===Favorite Avatar Game=== <br />
Club Penguin, Runner-up: Poptropica<br />
===TV Show=== <br />
''Wild Kratts'': "Who knew how amazing nature is?"<br />
<br />
Runner-up: Pokémon Anime<br />
<br />
===Subject=== <br />
Math!<br />
===Catch Phrases===<br />
"Technically speaking... uh, no" and "Let us blow this popsicle stand!"<br />
<br />
===Comic===<br />
''Foxtrot'': "Jason is so funny." <br />
<br />
Comments: Dantx5: I agree.<br />
<br />
==Websites==<br />
Sci has an account on Poptropica, Club Penguin, Art of Problem Solving, Animal Jam, and EarIAm.<br />
<br />
==AoPS History==<br />
Sci posts a lot in the Fun Factory.<br />
===Stats===<br />
Sci joined AoPS on Feb 22, 2011, 8:44 am<br />
===Games and FF===<br />
Currently, Sci has started the Experimental game [http://www.artofproblemsolving.com/Forum/viewtopic.php?f=535&t=494960 Pokémon Battle]<br />
<br />
=Currency=<br />
IQ Points (IQP) are his currency. He also has Coins.<br />
<br />
==Conversions==<br />
One IQP is the same as 6 [[User:Knittingfrenzy18 |RC]], or 10 [[User:EuclidGenius |Qwerty]]<br />
<br />
One coin is 90 IPQs<br />
<br />
==Value==<br />
Coins are low in value, so they are easy to get. On the other hand, IQPs are extremely hard to get<br />
<br />
=CSS's=<br />
[http://www.artofproblemsolving.com/Forum/viewtopic.php?f=624&t=447899 Plants vs Zombies 1 v1.0 CSS]<br />
<br />
=SpamPol=<br />
Original Article: [[User:Scientest/SpamPol|SpamPol]]<br />
<br />
SpamPolice™ is a small corporation in [[User:Scientest|Scientest's]] blog. SpamPol™ is a spam police organization.<br />
<br />
SpamPolice™, or SpamPol™, lives up to its name<br />
==History==<br />
===Foundation and Early History===<br />
dantx5: SpamPol™ was originally created in Aug-Sept 2011 to stop an anonymous person in algebra class 497 to somehow prevent that user from rating all posts 1. The original members were the members between sci and sassman inclusive. The user finally got figured out, it was a SpamPol™ members sibling who was doing this. And now, Since class 497 has ended, SpamPol™ has grown bigger and has improved a little, but it would improve a lot if everyone in SpamPol™ was helping to stop spam. SpamPol™ mostly occurs in Scis blog, but rarely, Root01's blog.<br />
[note: ytao was not part of the original group]<br />
<br />
Blazefang: In truth, there still is a culprit, it wasn't only your little brother, cause there were 2 people, after you said your brother, it wouldn't make sense, you would need 2 to keep your rating lower than it should have been, the 497 spammer is still on the loose. I actually have an idea, maybe he thought rating it one star meant he thought it was "a 1st rate post" which is positive, so he did the opposite on accident, so when everybody was complaining about the rates, he continued, agreeing with them, when he was the culprit, unknowing, cause that's what I did at the very beginning then I found out a few days later that since it goes up and such. i don't know, just a theory.<br />
<br />
dantx5: and we stopped them by rating all posts in the forum a 6. <br />
<br />
The official start of SpamPol was August 23nd, 2011, but we call it August 19th because that's when inspiration hit us and we started scouting.<br />
<br />
In October 2011, Season 1 ended. Season 2 started in December 2011 and reopened in late April 2012. Season 3 started in May and will end around in mid August. <br />
<br />
NAA: This is hilarious. :)<br />
<br />
El_: vote for "no": http://www.artofproblemsolving.com/Forum/viewtopic.php?f=144&t=478068<br />
<br />
However, since the first mission, SpamPol has been interfering with the job of a moderator, and has received lots of criticism from others.<br />
<br />
MG: spampol ended May 3, 2012<br />
<br />
dantx5: yes, spampol lasted for 9 months, because SpamPol was no match for spam itself.<br />
<br />
El_: no, actually SpamPol is no match for '''itself'''<br />
<br />
dantx5: and now this wiki page has disintegrated into spam.<br />
<br />
El_: CD anyone? ok fine ftw then<br />
<br />
dantx5: maybe... but remember how you quickly joined my CD and then left almost immediately?<br />
<br />
Thkim: Wait what?? This is confusing. Can anyone explain this better?<br />
<br />
dantx5: SpamPol is over.<br />
<br />
StarWarsPol has started, go to el_'s link to find it. Please stop it, its backseat moderation.<br />
<br />
The SpamPol died on May 7th, 2012<br />
<br />
Thanks guys<br />
<br />
pi_Plus_45x23: I do not know this person but who cares about someone who rated posts 1. See [[AoPSWiki:FAQ#Someone_is_marking_all_my_posts_as_spam.2C_what_should_I_do.3F]]<br />
<br />
===Death===<br />
The SpamPol died on May 7th, 2012<br />
<br />
===Probabilities===<br />
SpamPol 2 starts = 10000000000000%<br />
<br />
SpamPol 2 actually helps = 0.009%<br />
<br />
SpamPol 3 starts = 0.01%<br />
<br />
SpamPol 2 reaches 100 members = 0.000055%<br />
<br />
Admins support SpamPol 2 = 0.000000025%<br />
<br />
SpamPol 2 reaches 2000 members = 0.000000003%<br />
<br />
SpamPol 2 spreads to several different websites = 0.0000000111%<br />
<br />
SpamPol 2 reaches 10000 members = 0.000000000000123%<br />
<br />
SpamPol 2 lasts for 15 years = 0.000000000000000000007%<br />
<br />
SpamPol 2 gets a fansite = 0.0000000000000000000000000000017%<br />
<br />
SpamPol 2 gains worldwide fame = 0%<br />
<br />
(Note: Edit this if you think the probablties are wrong somehow.)<br />
<br />
===Ranks===<br />
Members of SpamPol:<br />
<br />
1. Chief/General of the Armies: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=101857 Sci] and [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=107809 Blazefang (second in command)]<br />
<br />
2. General of the Army: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=110445 Root01]<br />
<br />
3. General: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=94400 Calculator3000] and [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=108074 dantx5]<br />
<br />
<math>\pi.</math> Person who like tomatoes and does combinatorics: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=78673 NAA]<br />
<br />
4. Lieutenant General: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=126113 ytao]<br />
<br />
5. Major General: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=110468 avaj]<br />
<br />
6. Brigadier General: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=109650 kev2010]<br />
<br />
7. Colonel: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=101862 sassman]<br />
<br />
8. Lieutenant Colonel: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=101205 teddys123]<br />
<br />
9. Major: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=101119 ChipDale]<br />
<br />
10. Captain: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=101567 mathletepower]<br />
<br />
11. First Lieutenant: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=49043 musicnmath]<br />
<br />
12. Second Lieutenant: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=88673 in8]<br />
<br />
13. Sergeant: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=123093 Daemonheim]<br />
<br />
14. Corporal: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=124048 genesis2]<br />
<br />
15. Specialist: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=141966 StarWarsLiam]<br />
<br />
16. Private First Class:<br />
<br />
17. Private:<br />
<br />
18. Training:<br />
<br />
19. Civilian<br />
<br />
20. Baby Sitting in a Bathtub!<br />
<br />
==Objective==<br />
SpamSpamSpam<br />
<br />
Spam Pol has evolved into spam itself. Anyways, the sine law is cool.<br />
<br />
==Awards==<br />
There is a special award to mathgenius64, because of the fact that he has helped prevent the stopping of spam, and stopped people from backseat moderating<br />
<br />
Sci: I also must blame the policemen/women themselves. This was made for boosting up ratings, not backseat moderating<br />
<br />
Also, I blame myself for getting this snowball rolling in the first place<br />
<br />
===SpamPol Awards 2012===<br />
====dantx5====<br />
''' Gets "2nd most contributors" award'''<br />
<br />
====Scientest====<br />
Spammed in the games forum multiple times<br />
<br />
'''Gets "best spam policeman" award'''<br />
<br />
====AkshajK====<br />
Made an Annoying CSS, made a spammy blog, holds title of most contributors<br />
<br />
'''Gets "most contributors" award'''<br />
====ytao====<br />
Because I'm editing this now.<br />
<br />
''' Gets "best editor" award '''<br />
=Fun Facts=<br />
In his old blog, Sci posted Locker must-haves, a graphing calculator, books, and a picture of his crush<br />
<br />
Sci has played violin for approximately 7 years<br />
<br />
=Mathemagical Carreer=<br />
*NOTE TO SELF: FILL OUT</div>Scientesthttps://artofproblemsolving.com/wiki/index.php?title=User:Scientest&diff=49353User:Scientest2012-11-07T18:19:53Z<p>Scientest: /* SpamPol II */</p>
<hr />
<div> [[File:Warning.gif]]<br />
"Let us blow this popsicle stand! Okay, so maybe it's an ice pop stand, but whatever." –Sci at a school athletic event<br />
<br />
Hi there. Welcome to my Wiki page. I wrote this mainly in third person, so enjoy this while it lasts. And take heed of my warning. Scroll all the way down. Yikes. Well, have fun here! If you get bored, you can always go the forums.<br />
=Bio=<br />
Scientest is almost 12. He loves using <math>\text{\text\LaTeX}</math> and playing Plants vs. Zombies. He goes by the nickname Sci. He has done Algebra 1 (Summer 2011) and Counting and Probability (Fall-Spring 2011-2012) Sci plays the violin and the viola and loves math. He enjoys Plants vs. Zombies and cannot wait for P vs. Z 2 to come out. He also enjoys ClubPenguin (Look out for Inventapeng), Poptropica, Ninjago, and Pokemon<br />
==Name==<br />
His first name is Andrew. He snipped his last name from an FF post<br />
<br />
==Favorites==<br />
===Color===<br />
Pink: "It rocks"<br />
===Schoolhouse Rock song=== <br />
"I like them all, but my personal favorite is ''Interplanet Janet''"<br />
===Games on iPod/iPad=== <br />
Plants vs. Zombies: "I especially like it when the zombies eat your brains. Lol."<br />
<br />
Anthill<br />
<br />
Ouch!<br />
<br />
===Favorite Avatar Game=== <br />
Club Penguin, Runner-up: Poptropica<br />
===TV Show=== <br />
''Wild Kratts'': "Who knew how amazing nature is?"<br />
<br />
Runner-up: Pokémon Anime<br />
<br />
===Subject=== <br />
Math!<br />
===Catch Phrases===<br />
"Technically speaking... uh, no" and "Let us blow this popsicle stand!"<br />
<br />
===Comic===<br />
''Foxtrot'': "Jason is so funny." <br />
<br />
Comments: Dantx5: I agree.<br />
<br />
==Websites==<br />
Sci has an account on Poptropica, Club Penguin, Art of Problem Solving, Animal Jam, and EarIAm.<br />
<br />
==AoPS History==<br />
Sci posts a lot in the Fun Factory.<br />
===Stats===<br />
Sci joined AoPS on Feb 22, 2011, 8:44 am<br />
===Games and FF===<br />
Currently, Sci has started the Experimental game [http://www.artofproblemsolving.com/Forum/viewtopic.php?f=535&t=494960 Pokémon Battle]<br />
<br />
=Currency=<br />
IQ Points (IQP) are his currency. He also has Coins.<br />
<br />
==Conversions==<br />
One IQP is the same as 6 [[User:Knittingfrenzy18 |RC]], or 10 [[User:EuclidGenius |Qwerty]]<br />
<br />
One coin is 90 IPQs<br />
<br />
==Value==<br />
Coins are low in value, so they are easy to get. On the other hand, IQPs are extremely hard to get<br />
<br />
=CSS's=<br />
[http://www.artofproblemsolving.com/Forum/viewtopic.php?f=624&t=447899 Plants vs Zombies 1 v1.0 CSS]<br />
<br />
=SpamPol=<br />
Original Article: [[User:Scientest/SpamPol|SpamPol]]<br />
<br />
SpamPolice™ is a small corporation in [[User:Scientest|Scientest's]] blog. SpamPol™ is a spam police organization.<br />
<br />
SpamPolice™, or SpamPol™, lives up to its name<br />
==History==<br />
===Foundation and Early History===<br />
dantx5: SpamPol™ was originally created in Aug-Sept 2011 to stop an anonymous person in algebra class 497 to somehow prevent that user from rating all posts 1. The original members were the members between sci and sassman inclusive. The user finally got figured out, it was a SpamPol™ members sibling who was doing this. And now, Since class 497 has ended, SpamPol™ has grown bigger and has improved a little, but it would improve a lot if everyone in SpamPol™ was helping to stop spam. SpamPol™ mostly occurs in Scis blog, but rarely, Root01's blog.<br />
[note: ytao was not part of the original group]<br />
<br />
Blazefang: In truth, there still is a culprit, it wasn't only your little brother, cause there were 2 people, after you said your brother, it wouldn't make sense, you would need 2 to keep your rating lower than it should have been, the 497 spammer is still on the loose. I actually have an idea, maybe he thought rating it one star meant he thought it was "a 1st rate post" which is positive, so he did the opposite on accident, so when everybody was complaining about the rates, he continued, agreeing with them, when he was the culprit, unknowing, cause that's what I did at the very beginning then I found out a few days later that since it goes up and such. i don't know, just a theory.<br />
<br />
dantx5: and we stopped them by rating all posts in the forum a 6. <br />
<br />
The official start of SpamPol was August 23nd, 2011, but we call it August 19th because that's when inspiration hit us and we started scouting.<br />
<br />
In October 2011, Season 1 ended. Season 2 started in December 2011 and reopened in late April 2012. Season 3 started in May and will end around in mid August. <br />
<br />
NAA: This is hilarious. :)<br />
<br />
El_: vote for "no": http://www.artofproblemsolving.com/Forum/viewtopic.php?f=144&t=478068<br />
<br />
However, since the first mission, SpamPol has been interfering with the job of a moderator, and has received lots of criticism from others.<br />
<br />
MG: spampol ended May 3, 2012<br />
<br />
dantx5: yes, spampol lasted for 9 months, because SpamPol was no match for spam itself.<br />
<br />
El_: no, actually SpamPol is no match for '''itself'''<br />
<br />
dantx5: and now this wiki page has disintegrated into spam.<br />
<br />
El_: CD anyone? ok fine ftw then<br />
<br />
dantx5: maybe... but remember how you quickly joined my CD and then left almost immediately?<br />
<br />
Thkim: Wait what?? This is confusing. Can anyone explain this better?<br />
<br />
dantx5: SpamPol is over.<br />
<br />
StarWarsPol has started, go to el_'s link to find it. Please stop it, its backseat moderation.<br />
<br />
The SpamPol died on May 7th, 2012<br />
<br />
Thanks guys<br />
<br />
pi_Plus_45x23: I do not know this person but who cares about someone who rated posts 1. See [[AoPSWiki:FAQ#Someone_is_marking_all_my_posts_as_spam.2C_what_should_I_do.3F]]<br />
<br />
===Death===<br />
The SpamPol died on May 7th, 2012<br />
<br />
===Probabilities===<br />
SpamPol 2 starts = 10000000000000%<br />
<br />
SpamPol 2 actually helps = 0.009%<br />
<br />
SpamPol 3 starts = 0.01%<br />
<br />
SpamPol 2 reaches 100 members = 0.000055%<br />
<br />
Admins support SpamPol 2 = 0.000000025%<br />
<br />
SpamPol 2 reaches 2000 members = 0.000000003%<br />
<br />
SpamPol 2 spreads to several different websites = 0.0000000111%<br />
<br />
SpamPol 2 reaches 10000 members = 0.000000000000123%<br />
<br />
SpamPol 2 lasts for 15 years = 0.000000000000000000007%<br />
<br />
SpamPol 2 gets a fansite = 0.0000000000000000000000000000017%<br />
<br />
SpamPol 2 gains worldwide fame = 0%<br />
<br />
(Note: Edit this if you think the probablties are wrong somehow.)<br />
<br />
===Ranks===<br />
Members of SpamPol:<br />
<br />
1. Chief/General of the Armies: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=101857 Sci] and [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=107809 Blazefang (second in command)]<br />
<br />
2. General of the Army: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=110445 Root01]<br />
<br />
3. General: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=94400 Calculator3000] and [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=108074 dantx5]<br />
<br />
<math>\pi.</math> Person who like tomatoes and does combinatorics: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=78673 NAA]<br />
<br />
4. Lieutenant General: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=126113 ytao]<br />
<br />
5. Major General: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=110468 avaj]<br />
<br />
6. Brigadier General: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=109650 kev2010]<br />
<br />
7. Colonel: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=101862 sassman]<br />
<br />
8. Lieutenant Colonel: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=101205 teddys123]<br />
<br />
9. Major: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=101119 ChipDale]<br />
<br />
10. Captain: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=101567 mathletepower]<br />
<br />
11. First Lieutenant: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=49043 musicnmath]<br />
<br />
12. Second Lieutenant: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=88673 in8]<br />
<br />
13. Sergeant: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=123093 Daemonheim]<br />
<br />
14. Corporal: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=124048 genesis2]<br />
<br />
15. Specialist: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=141966 StarWarsLiam]<br />
<br />
16. Private First Class:<br />
<br />
17. Private:<br />
<br />
18. Training:<br />
<br />
19. Civilian<br />
<br />
20. Baby Sitting in a Bathtub!<br />
<br />
==Objective==<br />
SpamSpamSpam<br />
<br />
Spam Pol has evolved into spam itself. Anyways, the sine law is cool.<br />
<br />
==Awards==<br />
There is a special award to mathgenius64, because of the fact that he has helped prevent the stopping of spam, and stopped people from backseat moderating<br />
<br />
Sci: I also must blame the policemen/women themselves. This was made for boosting up ratings, not backseat moderating<br />
<br />
Also, I blame myself for getting this snowball rolling in the first place<br />
<br />
===SpamPol Awards 2012===<br />
====dantx5====<br />
''' Gets "2nd most contributors" award'''<br />
<br />
====Scientest====<br />
Spammed in the games forum multiple times<br />
<br />
'''Gets "best spam policeman" award'''<br />
<br />
====AkshajK====<br />
Made an Annoying CSS, made a spammy blog, holds title of most contributors<br />
<br />
'''Gets "most contributors" award'''<br />
====ytao====<br />
Because I'm editing this now.<br />
<br />
''' Gets "best editor" award '''<br />
=Fun Facts=<br />
In his old blog, Sci posted Locker must-haves, a graphing calculator, books, and a picture of his crush<br />
<br />
Sci has played violin for approximately 6 years<br />
<br />
=Mathemagical Carreer=<br />
*NOTE TO SELF: FILL OUT</div>Scientesthttps://artofproblemsolving.com/wiki/index.php?title=User:Scientest&diff=49352User:Scientest2012-11-07T18:19:38Z<p>Scientest: /* pi_Plus_45x23 */</p>
<hr />
<div> [[File:Warning.gif]]<br />
"Let us blow this popsicle stand! Okay, so maybe it's an ice pop stand, but whatever." –Sci at a school athletic event<br />
<br />
Hi there. Welcome to my Wiki page. I wrote this mainly in third person, so enjoy this while it lasts. And take heed of my warning. Scroll all the way down. Yikes. Well, have fun here! If you get bored, you can always go the forums.<br />
=Bio=<br />
Scientest is almost 12. He loves using <math>\text{\text\LaTeX}</math> and playing Plants vs. Zombies. He goes by the nickname Sci. He has done Algebra 1 (Summer 2011) and Counting and Probability (Fall-Spring 2011-2012) Sci plays the violin and the viola and loves math. He enjoys Plants vs. Zombies and cannot wait for P vs. Z 2 to come out. He also enjoys ClubPenguin (Look out for Inventapeng), Poptropica, Ninjago, and Pokemon<br />
==Name==<br />
His first name is Andrew. He snipped his last name from an FF post<br />
<br />
==Favorites==<br />
===Color===<br />
Pink: "It rocks"<br />
===Schoolhouse Rock song=== <br />
"I like them all, but my personal favorite is ''Interplanet Janet''"<br />
===Games on iPod/iPad=== <br />
Plants vs. Zombies: "I especially like it when the zombies eat your brains. Lol."<br />
<br />
Anthill<br />
<br />
Ouch!<br />
<br />
===Favorite Avatar Game=== <br />
Club Penguin, Runner-up: Poptropica<br />
===TV Show=== <br />
''Wild Kratts'': "Who knew how amazing nature is?"<br />
<br />
Runner-up: Pokémon Anime<br />
<br />
===Subject=== <br />
Math!<br />
===Catch Phrases===<br />
"Technically speaking... uh, no" and "Let us blow this popsicle stand!"<br />
<br />
===Comic===<br />
''Foxtrot'': "Jason is so funny." <br />
<br />
Comments: Dantx5: I agree.<br />
<br />
==Websites==<br />
Sci has an account on Poptropica, Club Penguin, Art of Problem Solving, Animal Jam, and EarIAm.<br />
<br />
==AoPS History==<br />
Sci posts a lot in the Fun Factory.<br />
===Stats===<br />
Sci joined AoPS on Feb 22, 2011, 8:44 am<br />
===Games and FF===<br />
Currently, Sci has started the Experimental game [http://www.artofproblemsolving.com/Forum/viewtopic.php?f=535&t=494960 Pokémon Battle]<br />
<br />
=Currency=<br />
IQ Points (IQP) are his currency. He also has Coins.<br />
<br />
==Conversions==<br />
One IQP is the same as 6 [[User:Knittingfrenzy18 |RC]], or 10 [[User:EuclidGenius |Qwerty]]<br />
<br />
One coin is 90 IPQs<br />
<br />
==Value==<br />
Coins are low in value, so they are easy to get. On the other hand, IQPs are extremely hard to get<br />
<br />
=CSS's=<br />
[http://www.artofproblemsolving.com/Forum/viewtopic.php?f=624&t=447899 Plants vs Zombies 1 v1.0 CSS]<br />
<br />
=SpamPol=<br />
Original Article: [[User:Scientest/SpamPol|SpamPol]]<br />
<br />
SpamPolice™ is a small corporation in [[User:Scientest|Scientest's]] blog. SpamPol™ is a spam police organization.<br />
<br />
SpamPolice™, or SpamPol™, lives up to its name<br />
==History==<br />
===Foundation and Early History===<br />
dantx5: SpamPol™ was originally created in Aug-Sept 2011 to stop an anonymous person in algebra class 497 to somehow prevent that user from rating all posts 1. The original members were the members between sci and sassman inclusive. The user finally got figured out, it was a SpamPol™ members sibling who was doing this. And now, Since class 497 has ended, SpamPol™ has grown bigger and has improved a little, but it would improve a lot if everyone in SpamPol™ was helping to stop spam. SpamPol™ mostly occurs in Scis blog, but rarely, Root01's blog.<br />
[note: ytao was not part of the original group]<br />
<br />
Blazefang: In truth, there still is a culprit, it wasn't only your little brother, cause there were 2 people, after you said your brother, it wouldn't make sense, you would need 2 to keep your rating lower than it should have been, the 497 spammer is still on the loose. I actually have an idea, maybe he thought rating it one star meant he thought it was "a 1st rate post" which is positive, so he did the opposite on accident, so when everybody was complaining about the rates, he continued, agreeing with them, when he was the culprit, unknowing, cause that's what I did at the very beginning then I found out a few days later that since it goes up and such. i don't know, just a theory.<br />
<br />
dantx5: and we stopped them by rating all posts in the forum a 6. <br />
<br />
The official start of SpamPol was August 23nd, 2011, but we call it August 19th because that's when inspiration hit us and we started scouting.<br />
<br />
In October 2011, Season 1 ended. Season 2 started in December 2011 and reopened in late April 2012. Season 3 started in May and will end around in mid August. <br />
<br />
NAA: This is hilarious. :)<br />
<br />
El_: vote for "no": http://www.artofproblemsolving.com/Forum/viewtopic.php?f=144&t=478068<br />
<br />
However, since the first mission, SpamPol has been interfering with the job of a moderator, and has received lots of criticism from others.<br />
<br />
MG: spampol ended May 3, 2012<br />
<br />
dantx5: yes, spampol lasted for 9 months, because SpamPol was no match for spam itself.<br />
<br />
El_: no, actually SpamPol is no match for '''itself'''<br />
<br />
dantx5: and now this wiki page has disintegrated into spam.<br />
<br />
El_: CD anyone? ok fine ftw then<br />
<br />
dantx5: maybe... but remember how you quickly joined my CD and then left almost immediately?<br />
<br />
Thkim: Wait what?? This is confusing. Can anyone explain this better?<br />
<br />
dantx5: SpamPol is over.<br />
<br />
StarWarsPol has started, go to el_'s link to find it. Please stop it, its backseat moderation.<br />
<br />
The SpamPol died on May 7th, 2012<br />
<br />
Thanks guys<br />
<br />
pi_Plus_45x23: I do not know this person but who cares about someone who rated posts 1. See [[AoPSWiki:FAQ#Someone_is_marking_all_my_posts_as_spam.2C_what_should_I_do.3F]]<br />
<br />
===Death===<br />
The SpamPol died on May 7th, 2012<br />
<br />
===Probabilities===<br />
SpamPol 2 starts = 10000000000000%<br />
<br />
SpamPol 2 actually helps = 0.009%<br />
<br />
SpamPol 3 starts = 0.01%<br />
<br />
SpamPol 2 reaches 100 members = 0.000055%<br />
<br />
Admins support SpamPol 2 = 0.000000025%<br />
<br />
SpamPol 2 reaches 2000 members = 0.000000003%<br />
<br />
SpamPol 2 spreads to several different websites = 0.0000000111%<br />
<br />
SpamPol 2 reaches 10000 members = 0.000000000000123%<br />
<br />
SpamPol 2 lasts for 15 years = 0.000000000000000000007%<br />
<br />
SpamPol 2 gets a fansite = 0.0000000000000000000000000000017%<br />
<br />
SpamPol 2 gains worldwide fame = 0%<br />
<br />
(Note: Edit this if you think the probablties are wrong somehow.)<br />
<br />
===Ranks===<br />
Members of SpamPol:<br />
<br />
1. Chief/General of the Armies: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=101857 Sci] and [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=107809 Blazefang (second in command)]<br />
<br />
2. General of the Army: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=110445 Root01]<br />
<br />
3. General: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=94400 Calculator3000] and [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=108074 dantx5]<br />
<br />
<math>\pi.</math> Person who like tomatoes and does combinatorics: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=78673 NAA]<br />
<br />
4. Lieutenant General: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=126113 ytao]<br />
<br />
5. Major General: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=110468 avaj]<br />
<br />
6. Brigadier General: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=109650 kev2010]<br />
<br />
7. Colonel: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=101862 sassman]<br />
<br />
8. Lieutenant Colonel: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=101205 teddys123]<br />
<br />
9. Major: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=101119 ChipDale]<br />
<br />
10. Captain: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=101567 mathletepower]<br />
<br />
11. First Lieutenant: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=49043 musicnmath]<br />
<br />
12. Second Lieutenant: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=88673 in8]<br />
<br />
13. Sergeant: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=123093 Daemonheim]<br />
<br />
14. Corporal: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=124048 genesis2]<br />
<br />
15. Specialist: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=141966 StarWarsLiam]<br />
<br />
16. Private First Class:<br />
<br />
17. Private:<br />
<br />
18. Training:<br />
<br />
19. Civilian<br />
<br />
20. Baby Sitting in a Bathtub!<br />
<br />
==Objective==<br />
SpamSpamSpam<br />
<br />
Spam Pol has evolved into spam itself. Anyways, the sine law is cool.<br />
<br />
==Awards==<br />
There is a special award to mathgenius64, because of the fact that he has helped prevent the stopping of spam, and stopped people from backseat moderating<br />
<br />
Sci: I also must blame the policemen/women themselves. This was made for boosting up ratings, not backseat moderating<br />
<br />
Also, I blame myself for getting this snowball rolling in the first place<br />
<br />
===SpamPol Awards 2012===<br />
====dantx5====<br />
''' Gets "2nd most contributors" award'''<br />
<br />
====Scientest====<br />
Spammed in the games forum multiple times<br />
<br />
'''Gets "best spam policeman" award'''<br />
<br />
====AkshajK====<br />
Made an Annoying CSS, made a spammy blog, holds title of most contributors<br />
<br />
'''Gets "most contributors" award'''<br />
====ytao====<br />
Because I'm editing this now.<br />
<br />
''' Gets "best editor" award '''<br />
=SpamPol II=<br />
Was just founded.<br />
<br />
=Fun Facts=<br />
In his old blog, Sci posted Locker must-haves, a graphing calculator, books, and a picture of his crush<br />
<br />
Sci has played violin for approximately 6 years<br />
<br />
=Mathemagical Carreer=<br />
*NOTE TO SELF: FILL OUT</div>Scientesthttps://artofproblemsolving.com/wiki/index.php?title=User:Scientest&diff=49351User:Scientest2012-11-07T18:19:21Z<p>Scientest: /* Ranks */</p>
<hr />
<div> [[File:Warning.gif]]<br />
"Let us blow this popsicle stand! Okay, so maybe it's an ice pop stand, but whatever." –Sci at a school athletic event<br />
<br />
Hi there. Welcome to my Wiki page. I wrote this mainly in third person, so enjoy this while it lasts. And take heed of my warning. Scroll all the way down. Yikes. Well, have fun here! If you get bored, you can always go the forums.<br />
=Bio=<br />
Scientest is almost 12. He loves using <math>\text{\text\LaTeX}</math> and playing Plants vs. Zombies. He goes by the nickname Sci. He has done Algebra 1 (Summer 2011) and Counting and Probability (Fall-Spring 2011-2012) Sci plays the violin and the viola and loves math. He enjoys Plants vs. Zombies and cannot wait for P vs. Z 2 to come out. He also enjoys ClubPenguin (Look out for Inventapeng), Poptropica, Ninjago, and Pokemon<br />
==Name==<br />
His first name is Andrew. He snipped his last name from an FF post<br />
<br />
==Favorites==<br />
===Color===<br />
Pink: "It rocks"<br />
===Schoolhouse Rock song=== <br />
"I like them all, but my personal favorite is ''Interplanet Janet''"<br />
===Games on iPod/iPad=== <br />
Plants vs. Zombies: "I especially like it when the zombies eat your brains. Lol."<br />
<br />
Anthill<br />
<br />
Ouch!<br />
<br />
===Favorite Avatar Game=== <br />
Club Penguin, Runner-up: Poptropica<br />
===TV Show=== <br />
''Wild Kratts'': "Who knew how amazing nature is?"<br />
<br />
Runner-up: Pokémon Anime<br />
<br />
===Subject=== <br />
Math!<br />
===Catch Phrases===<br />
"Technically speaking... uh, no" and "Let us blow this popsicle stand!"<br />
<br />
===Comic===<br />
''Foxtrot'': "Jason is so funny." <br />
<br />
Comments: Dantx5: I agree.<br />
<br />
==Websites==<br />
Sci has an account on Poptropica, Club Penguin, Art of Problem Solving, Animal Jam, and EarIAm.<br />
<br />
==AoPS History==<br />
Sci posts a lot in the Fun Factory.<br />
===Stats===<br />
Sci joined AoPS on Feb 22, 2011, 8:44 am<br />
===Games and FF===<br />
Currently, Sci has started the Experimental game [http://www.artofproblemsolving.com/Forum/viewtopic.php?f=535&t=494960 Pokémon Battle]<br />
<br />
=Currency=<br />
IQ Points (IQP) are his currency. He also has Coins.<br />
<br />
==Conversions==<br />
One IQP is the same as 6 [[User:Knittingfrenzy18 |RC]], or 10 [[User:EuclidGenius |Qwerty]]<br />
<br />
One coin is 90 IPQs<br />
<br />
==Value==<br />
Coins are low in value, so they are easy to get. On the other hand, IQPs are extremely hard to get<br />
<br />
=CSS's=<br />
[http://www.artofproblemsolving.com/Forum/viewtopic.php?f=624&t=447899 Plants vs Zombies 1 v1.0 CSS]<br />
<br />
=SpamPol=<br />
Original Article: [[User:Scientest/SpamPol|SpamPol]]<br />
<br />
SpamPolice™ is a small corporation in [[User:Scientest|Scientest's]] blog. SpamPol™ is a spam police organization.<br />
<br />
SpamPolice™, or SpamPol™, lives up to its name<br />
==History==<br />
===Foundation and Early History===<br />
dantx5: SpamPol™ was originally created in Aug-Sept 2011 to stop an anonymous person in algebra class 497 to somehow prevent that user from rating all posts 1. The original members were the members between sci and sassman inclusive. The user finally got figured out, it was a SpamPol™ members sibling who was doing this. And now, Since class 497 has ended, SpamPol™ has grown bigger and has improved a little, but it would improve a lot if everyone in SpamPol™ was helping to stop spam. SpamPol™ mostly occurs in Scis blog, but rarely, Root01's blog.<br />
[note: ytao was not part of the original group]<br />
<br />
Blazefang: In truth, there still is a culprit, it wasn't only your little brother, cause there were 2 people, after you said your brother, it wouldn't make sense, you would need 2 to keep your rating lower than it should have been, the 497 spammer is still on the loose. I actually have an idea, maybe he thought rating it one star meant he thought it was "a 1st rate post" which is positive, so he did the opposite on accident, so when everybody was complaining about the rates, he continued, agreeing with them, when he was the culprit, unknowing, cause that's what I did at the very beginning then I found out a few days later that since it goes up and such. i don't know, just a theory.<br />
<br />
dantx5: and we stopped them by rating all posts in the forum a 6. <br />
<br />
The official start of SpamPol was August 23nd, 2011, but we call it August 19th because that's when inspiration hit us and we started scouting.<br />
<br />
In October 2011, Season 1 ended. Season 2 started in December 2011 and reopened in late April 2012. Season 3 started in May and will end around in mid August. <br />
<br />
NAA: This is hilarious. :)<br />
<br />
El_: vote for "no": http://www.artofproblemsolving.com/Forum/viewtopic.php?f=144&t=478068<br />
<br />
However, since the first mission, SpamPol has been interfering with the job of a moderator, and has received lots of criticism from others.<br />
<br />
MG: spampol ended May 3, 2012<br />
<br />
dantx5: yes, spampol lasted for 9 months, because SpamPol was no match for spam itself.<br />
<br />
El_: no, actually SpamPol is no match for '''itself'''<br />
<br />
dantx5: and now this wiki page has disintegrated into spam.<br />
<br />
El_: CD anyone? ok fine ftw then<br />
<br />
dantx5: maybe... but remember how you quickly joined my CD and then left almost immediately?<br />
<br />
Thkim: Wait what?? This is confusing. Can anyone explain this better?<br />
<br />
dantx5: SpamPol is over.<br />
<br />
StarWarsPol has started, go to el_'s link to find it. Please stop it, its backseat moderation.<br />
<br />
The SpamPol died on May 7th, 2012<br />
<br />
Thanks guys<br />
<br />
pi_Plus_45x23: I do not know this person but who cares about someone who rated posts 1. See [[AoPSWiki:FAQ#Someone_is_marking_all_my_posts_as_spam.2C_what_should_I_do.3F]]<br />
<br />
===Death===<br />
The SpamPol died on May 7th, 2012<br />
<br />
===Probabilities===<br />
SpamPol 2 starts = 10000000000000%<br />
<br />
SpamPol 2 actually helps = 0.009%<br />
<br />
SpamPol 3 starts = 0.01%<br />
<br />
SpamPol 2 reaches 100 members = 0.000055%<br />
<br />
Admins support SpamPol 2 = 0.000000025%<br />
<br />
SpamPol 2 reaches 2000 members = 0.000000003%<br />
<br />
SpamPol 2 spreads to several different websites = 0.0000000111%<br />
<br />
SpamPol 2 reaches 10000 members = 0.000000000000123%<br />
<br />
SpamPol 2 lasts for 15 years = 0.000000000000000000007%<br />
<br />
SpamPol 2 gets a fansite = 0.0000000000000000000000000000017%<br />
<br />
SpamPol 2 gains worldwide fame = 0%<br />
<br />
(Note: Edit this if you think the probablties are wrong somehow.)<br />
<br />
===Ranks===<br />
Members of SpamPol:<br />
<br />
1. Chief/General of the Armies: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=101857 Sci] and [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=107809 Blazefang (second in command)]<br />
<br />
2. General of the Army: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=110445 Root01]<br />
<br />
3. General: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=94400 Calculator3000] and [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=108074 dantx5]<br />
<br />
<math>\pi.</math> Person who like tomatoes and does combinatorics: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=78673 NAA]<br />
<br />
4. Lieutenant General: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=126113 ytao]<br />
<br />
5. Major General: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=110468 avaj]<br />
<br />
6. Brigadier General: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=109650 kev2010]<br />
<br />
7. Colonel: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=101862 sassman]<br />
<br />
8. Lieutenant Colonel: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=101205 teddys123]<br />
<br />
9. Major: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=101119 ChipDale]<br />
<br />
10. Captain: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=101567 mathletepower]<br />
<br />
11. First Lieutenant: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=49043 musicnmath]<br />
<br />
12. Second Lieutenant: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=88673 in8]<br />
<br />
13. Sergeant: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=123093 Daemonheim]<br />
<br />
14. Corporal: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=124048 genesis2]<br />
<br />
15. Specialist: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=141966 StarWarsLiam]<br />
<br />
16. Private First Class:<br />
<br />
17. Private:<br />
<br />
18. Training:<br />
<br />
19. Civilian<br />
<br />
20. Baby Sitting in a Bathtub!<br />
<br />
==Objective==<br />
SpamSpamSpam<br />
<br />
Spam Pol has evolved into spam itself. Anyways, the sine law is cool.<br />
<br />
==Awards==<br />
There is a special award to mathgenius64, because of the fact that he has helped prevent the stopping of spam, and stopped people from backseat moderating<br />
<br />
Sci: I also must blame the policemen/women themselves. This was made for boosting up ratings, not backseat moderating<br />
<br />
Also, I blame myself for getting this snowball rolling in the first place<br />
<br />
===SpamPol Awards 2012===<br />
====dantx5====<br />
''' Gets "2nd most contributors" award'''<br />
<br />
====Scientest====<br />
Spammed in the games forum multiple times<br />
<br />
'''Gets "best spam policeman" award'''<br />
<br />
====AkshajK====<br />
Made an Annoying CSS, made a spammy blog, holds title of most contributors<br />
<br />
'''Gets "most contributors" award'''<br />
====ytao====<br />
Because I'm editing this now.<br />
<br />
''' Gets "best editor" award '''<br />
====pi_Plus_45x23====<br />
What?? I'm not in SpamPol??<br />
<br />
'''Gets "Best Non-Policeman" award'''<br />
<br />
=SpamPol II=<br />
Was just founded.<br />
<br />
=Fun Facts=<br />
In his old blog, Sci posted Locker must-haves, a graphing calculator, books, and a picture of his crush<br />
<br />
Sci has played violin for approximately 6 years<br />
<br />
=Mathemagical Carreer=<br />
*NOTE TO SELF: FILL OUT</div>Scientesthttps://artofproblemsolving.com/wiki/index.php?title=User:Scientest&diff=48910User:Scientest2012-10-24T01:28:33Z<p>Scientest: /* Currency */</p>
<hr />
<div> [[File:Warning.gif]]<br />
"Let us blow this popsicle stand! Okay, so maybe it's an ice pop stand, but whatever." –Sci at a school athletic event<br />
<br />
Hi there. Welcome to my Wiki page. I wrote this mainly in third person, so enjoy this while it lasts. And take heed of my warning. Scroll all the way down. Yikes. Well, have fun here! If you get bored, you can always go the forums.<br />
=Bio=<br />
Scientest is almost 12. He loves using <math>\text{\text\LaTeX}</math> and playing Plants vs. Zombies. He goes by the nickname Sci. He has done Algebra 1 (Summer 2011) and Counting and Probability (Fall-Spring 2011-2012) Sci plays the violin and the viola and loves math. He enjoys Plants vs. Zombies and cannot wait for P vs. Z 2 to come out. He also enjoys ClubPenguin (Look out for Inventapeng), Poptropica, Ninjago, and Pokemon<br />
==Name==<br />
His first name is Andrew. He snipped his last name from an FF post<br />
<br />
==Favorites==<br />
===Color===<br />
Pink: "It rocks"<br />
===Schoolhouse Rock song=== <br />
"I like them all, but my personal favorite is ''Interplanet Janet''"<br />
===Games on iPod/iPad=== <br />
Plants vs. Zombies: "I especially like it when the zombies eat your brains. Lol."<br />
<br />
Anthill<br />
<br />
Ouch!<br />
<br />
===Favorite Avatar Game=== <br />
Club Penguin, Runner-up: Poptropica<br />
===TV Show=== <br />
''Wild Kratts'': "Who knew how amazing nature is?"<br />
<br />
Runner-up: Pokémon Anime<br />
<br />
===Subject=== <br />
Math!<br />
===Catch Phrases===<br />
"Technically speaking... uh, no" and "Let us blow this popsicle stand!"<br />
<br />
===Comic===<br />
''Foxtrot'': "Jason is so funny." <br />
<br />
Comments: Dantx5: I agree.<br />
<br />
==Websites==<br />
Sci has an account on Poptropica, Club Penguin, Art of Problem Solving, Animal Jam, and EarIAm.<br />
<br />
==AoPS History==<br />
Sci posts a lot in the Fun Factory.<br />
===Stats===<br />
Sci joined AoPS on Feb 22, 2011, 8:44 am<br />
===Games and FF===<br />
Currently, Sci has started the Experimental game [http://www.artofproblemsolving.com/Forum/viewtopic.php?f=535&t=494960 Pokémon Battle]<br />
<br />
=Currency=<br />
IQ Points (IQP) are his currency. He also has Coins.<br />
<br />
==Conversions==<br />
One IQP is the same as 6 [[User:Knittingfrenzy18 |RC]], or 10 [[User:EuclidGenius |Qwerty]]<br />
<br />
One coin is 90 IPQs<br />
<br />
==Value==<br />
Coins are low in value, so they are easy to get. On the other hand, IQPs are extremely hard to get<br />
<br />
=CSS's=<br />
[http://www.artofproblemsolving.com/Forum/viewtopic.php?f=624&t=447899 Plants vs Zombies 1 v1.0 CSS]<br />
<br />
=SpamPol=<br />
Original Article: [[User:Scientest/SpamPol|SpamPol]]<br />
<br />
SpamPolice™ is a small corporation in [[User:Scientest|Scientest's]] blog. SpamPol™ is a spam police organization.<br />
<br />
SpamPolice™, or SpamPol™, lives up to its name<br />
==History==<br />
===Foundation and Early History===<br />
dantx5: SpamPol™ was originally created in Aug-Sept 2011 to stop an anonymous person in algebra class 497 to somehow prevent that user from rating all posts 1. The original members were the members between sci and sassman inclusive. The user finally got figured out, it was a SpamPol™ members sibling who was doing this. And now, Since class 497 has ended, SpamPol™ has grown bigger and has improved a little, but it would improve a lot if everyone in SpamPol™ was helping to stop spam. SpamPol™ mostly occurs in Scis blog, but rarely, Root01's blog.<br />
[note: ytao was not part of the original group]<br />
<br />
Blazefang: In truth, there still is a culprit, it wasn't only your little brother, cause there were 2 people, after you said your brother, it wouldn't make sense, you would need 2 to keep your rating lower than it should have been, the 497 spammer is still on the loose. I actually have an idea, maybe he thought rating it one star meant he thought it was "a 1st rate post" which is positive, so he did the opposite on accident, so when everybody was complaining about the rates, he continued, agreeing with them, when he was the culprit, unknowing, cause that's what I did at the very beginning then I found out a few days later that since it goes up and such. i don't know, just a theory.<br />
<br />
dantx5: and we stopped them by rating all posts in the forum a 6. <br />
<br />
The official start of SpamPol was August 23nd, 2011, but we call it August 19th because that's when inspiration hit us and we started scouting.<br />
<br />
In October 2011, Season 1 ended. Season 2 started in December 2011 and reopened in late April 2012. Season 3 started in May and will end around in mid August. <br />
<br />
NAA: This is hilarious. :)<br />
<br />
El_: vote for "no": http://www.artofproblemsolving.com/Forum/viewtopic.php?f=144&t=478068<br />
<br />
However, since the first mission, SpamPol has been interfering with the job of a moderator, and has received lots of criticism from others.<br />
<br />
MG: spampol ended May 3, 2012<br />
<br />
dantx5: yes, spampol lasted for 9 months, because SpamPol was no match for spam itself.<br />
<br />
El_: no, actually SpamPol is no match for '''itself'''<br />
<br />
dantx5: and now this wiki page has disintegrated into spam.<br />
<br />
El_: CD anyone? ok fine ftw then<br />
<br />
dantx5: maybe... but remember how you quickly joined my CD and then left almost immediately?<br />
<br />
Thkim: Wait what?? This is confusing. Can anyone explain this better?<br />
<br />
dantx5: SpamPol is over.<br />
<br />
StarWarsPol has started, go to el_'s link to find it. Please stop it, its backseat moderation.<br />
<br />
The SpamPol died on May 7th, 2012<br />
<br />
Thanks guys<br />
<br />
===Death===<br />
The SpamPol died on May 7th, 2012<br />
<br />
===Probabilities===<br />
SpamPol 2 starts = 10000000000000%<br />
<br />
SpamPol 2 actually helps = 0.009%<br />
<br />
SpamPol 3 starts = 0.01%<br />
<br />
SpamPol 2 reaches 100 members = 0.000055%<br />
<br />
Admins support SpamPol 2 = 0.000000025%<br />
<br />
SpamPol 2 reaches 2000 members = 0.000000003%<br />
<br />
SpamPol 2 spreads to several different websites = 0.0000000111%<br />
<br />
SpamPol 2 reaches 10000 members = 0.000000000000123%<br />
<br />
SpamPol 2 lasts for 15 years = 0.000000000000000000007%<br />
<br />
SpamPol 2 gets a fansite = 0.0000000000000000000000000000017%<br />
<br />
SpamPol 2 gains worldwide fame = 0.0000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000002%<br />
<br />
(Note: Edit this if you think the probablties are wrong somehow.)<br />
<br />
===Ranks===<br />
Members of SpamPol:<br />
<br />
<br />
<br />
1. Chief/General of the Armies: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=101857 Sci] and [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=107809 Blazefang (second in command)]<br />
<br />
2. General of the Army: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=110445 Root01]<br />
<br />
3. General: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=94400 Calculator3000] and [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=108074 dantx5]<br />
<br />
<math>\pi.</math> Person who like tomatoes and does combinatorics: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=78673 NAA]<br />
<br />
4. Lieutenant General: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=126113 ytao]<br />
<br />
5. Major General: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=110468 avaj]<br />
<br />
6. Brigadier General: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=109650 kev2010]<br />
<br />
7. Colonel: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=101862 sassman]<br />
<br />
8. Lieutenant Colonel: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=101205 teddys123]<br />
<br />
9. Major: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=101119 ChipDale]<br />
<br />
10. Captain: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=101567 mathletepower]<br />
<br />
11. First Lieutenant: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=49043 musicnmath]<br />
<br />
12. Second Lieutenant: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=88673 in8]<br />
<br />
13. Sergeant: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=123093 Daemonheim]<br />
<br />
14. Corporal: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=124048 genesis2]<br />
<br />
15. Specialist: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=141966 StarWarsLiam]<br />
<br />
16. Private First Class:<br />
<br />
17. Private:<br />
<br />
18. Training:<br />
<br />
19. Civilian<br />
<br />
20. Baby Sitting in a Bathtub!<br />
<br />
==Objective==<br />
SpamSpamSpam<br />
<br />
Spam Pol has evolved into spam itself. Anyways, the sine law is cool.<br />
<br />
==Awards==<br />
There is a special award to mathgenius64, because of the fact that he has helped prevent the stopping of spam, and stopped people from backseat moderating<br />
<br />
Sci: I also must blame the policemen/women themselves. This was made for boosting up ratings, not backseat moderating<br />
<br />
Also, I blame myself for getting this snowball rolling in the first place<br />
<br />
===SpamPol Awards 2012===<br />
====dantx5====<br />
''' Gets "2nd most contributors" award'''<br />
<br />
====Scientest====<br />
Spammed in the games forum multiple times<br />
<br />
'''Gets "best spam policeman" award'''<br />
<br />
====AkshajK====<br />
Made an Annoying CSS, made a spammy blog, holds title of most contributors<br />
<br />
'''Gets "most contributors" award'''<br />
====ytao====<br />
Because I'm editing this now.<br />
<br />
''' Gets "best editor" award '''<br />
<br />
=SpamPol II=<br />
Was just founded.<br />
<br />
=Fun Facts=<br />
In his old blog, Sci posted Locker must-haves, a graphing calculator, books, and a picture of his crush<br />
<br />
Sci has played violin for approximately 6 years<br />
<br />
=Mathemagical Carreer=<br />
*NOTE TO SELF: FILL OUT</div>Scientesthttps://artofproblemsolving.com/wiki/index.php?title=User:Scientest&diff=48909User:Scientest2012-10-24T00:54:16Z<p>Scientest: /* Blog */</p>
<hr />
<div> [[File:Warning.gif]]<br />
"Let us blow this popsicle stand! Okay, so maybe it's an ice pop stand, but whatever." –Sci at a school athletic event<br />
<br />
Hi there. Welcome to my Wiki page. I wrote this mainly in third person, so enjoy this while it lasts. And take heed of my warning. Scroll all the way down. Yikes. Well, have fun here! If you get bored, you can always go the forums.<br />
=Bio=<br />
Scientest is almost 12. He loves using <math>\text{\text\LaTeX}</math> and playing Plants vs. Zombies. He goes by the nickname Sci. He has done Algebra 1 (Summer 2011) and Counting and Probability (Fall-Spring 2011-2012) Sci plays the violin and the viola and loves math. He enjoys Plants vs. Zombies and cannot wait for P vs. Z 2 to come out. He also enjoys ClubPenguin (Look out for Inventapeng), Poptropica, Ninjago, and Pokemon<br />
==Name==<br />
His first name is Andrew. He snipped his last name from an FF post<br />
<br />
==Favorites==<br />
===Color===<br />
Pink: "It rocks"<br />
===Schoolhouse Rock song=== <br />
"I like them all, but my personal favorite is ''Interplanet Janet''"<br />
===Games on iPod/iPad=== <br />
Plants vs. Zombies: "I especially like it when the zombies eat your brains. Lol."<br />
<br />
Anthill<br />
<br />
Ouch!<br />
<br />
===Favorite Avatar Game=== <br />
Club Penguin, Runner-up: Poptropica<br />
===TV Show=== <br />
''Wild Kratts'': "Who knew how amazing nature is?"<br />
<br />
Runner-up: Pokémon Anime<br />
<br />
===Subject=== <br />
Math!<br />
===Catch Phrases===<br />
"Technically speaking... uh, no" and "Let us blow this popsicle stand!"<br />
<br />
===Comic===<br />
''Foxtrot'': "Jason is so funny." <br />
<br />
Comments: Dantx5: I agree.<br />
<br />
==Websites==<br />
Sci has an account on Poptropica, Club Penguin, Art of Problem Solving, Animal Jam, and EarIAm.<br />
<br />
==AoPS History==<br />
Sci posts a lot in the Fun Factory.<br />
===Stats===<br />
Sci joined AoPS on Feb 22, 2011, 8:44 am<br />
===Games and FF===<br />
Currently, Sci has started the Experimental game [http://www.artofproblemsolving.com/Forum/viewtopic.php?f=535&t=494960 Pokémon Battle]<br />
<br />
=Currency=<br />
IQ Points (IQP) are his currency. He also has Kendo Dollars.<br />
<br />
==Conversions==<br />
One IQP is the same as 6 [[User:Knittingfrenzy18 |RC]], or 10 [[User:EuclidGenius |Qwerty]]<br />
<br />
One Kendo Dollar is 90 IPQs<br />
<br />
==Value==<br />
IQPs are low in value, so they are easy to get. On the other hand, Kendo Dollars are extremely hard to get<br />
<br />
=CSS's=<br />
[http://www.artofproblemsolving.com/Forum/viewtopic.php?f=624&t=447899 Plants vs Zombies 1 v1.0 CSS]<br />
<br />
=SpamPol=<br />
Original Article: [[User:Scientest/SpamPol|SpamPol]]<br />
<br />
SpamPolice™ is a small corporation in [[User:Scientest|Scientest's]] blog. SpamPol™ is a spam police organization.<br />
<br />
SpamPolice™, or SpamPol™, lives up to its name<br />
==History==<br />
===Foundation and Early History===<br />
dantx5: SpamPol™ was originally created in Aug-Sept 2011 to stop an anonymous person in algebra class 497 to somehow prevent that user from rating all posts 1. The original members were the members between sci and sassman inclusive. The user finally got figured out, it was a SpamPol™ members sibling who was doing this. And now, Since class 497 has ended, SpamPol™ has grown bigger and has improved a little, but it would improve a lot if everyone in SpamPol™ was helping to stop spam. SpamPol™ mostly occurs in Scis blog, but rarely, Root01's blog.<br />
[note: ytao was not part of the original group]<br />
<br />
Blazefang: In truth, there still is a culprit, it wasn't only your little brother, cause there were 2 people, after you said your brother, it wouldn't make sense, you would need 2 to keep your rating lower than it should have been, the 497 spammer is still on the loose. I actually have an idea, maybe he thought rating it one star meant he thought it was "a 1st rate post" which is positive, so he did the opposite on accident, so when everybody was complaining about the rates, he continued, agreeing with them, when he was the culprit, unknowing, cause that's what I did at the very beginning then I found out a few days later that since it goes up and such. i don't know, just a theory.<br />
<br />
dantx5: and we stopped them by rating all posts in the forum a 6. <br />
<br />
The official start of SpamPol was August 23nd, 2011, but we call it August 19th because that's when inspiration hit us and we started scouting.<br />
<br />
In October 2011, Season 1 ended. Season 2 started in December 2011 and reopened in late April 2012. Season 3 started in May and will end around in mid August. <br />
<br />
NAA: This is hilarious. :)<br />
<br />
El_: vote for "no": http://www.artofproblemsolving.com/Forum/viewtopic.php?f=144&t=478068<br />
<br />
However, since the first mission, SpamPol has been interfering with the job of a moderator, and has received lots of criticism from others.<br />
<br />
MG: spampol ended May 3, 2012<br />
<br />
dantx5: yes, spampol lasted for 9 months, because SpamPol was no match for spam itself.<br />
<br />
El_: no, actually SpamPol is no match for '''itself'''<br />
<br />
dantx5: and now this wiki page has disintegrated into spam.<br />
<br />
El_: CD anyone? ok fine ftw then<br />
<br />
dantx5: maybe... but remember how you quickly joined my CD and then left almost immediately?<br />
<br />
Thkim: Wait what?? This is confusing. Can anyone explain this better?<br />
<br />
dantx5: SpamPol is over.<br />
<br />
StarWarsPol has started, go to el_'s link to find it. Please stop it, its backseat moderation.<br />
<br />
The SpamPol died on May 7th, 2012<br />
<br />
Thanks guys<br />
<br />
===Death===<br />
The SpamPol died on May 7th, 2012<br />
<br />
===Probabilities===<br />
SpamPol 2 starts = 10000000000000%<br />
<br />
SpamPol 2 actually helps = 0.009%<br />
<br />
SpamPol 3 starts = 0.01%<br />
<br />
SpamPol 2 reaches 100 members = 0.000055%<br />
<br />
Admins support SpamPol 2 = 0.000000025%<br />
<br />
SpamPol 2 reaches 2000 members = 0.000000003%<br />
<br />
SpamPol 2 spreads to several different websites = 0.0000000111%<br />
<br />
SpamPol 2 reaches 10000 members = 0.000000000000123%<br />
<br />
SpamPol 2 lasts for 15 years = 0.000000000000000000007%<br />
<br />
SpamPol 2 gets a fansite = 0.0000000000000000000000000000017%<br />
<br />
SpamPol 2 gains worldwide fame = 0.0000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000002%<br />
<br />
(Note: Edit this if you think the probablties are wrong somehow.)<br />
<br />
===Ranks===<br />
Members of SpamPol:<br />
<br />
<br />
<br />
1. Chief/General of the Armies: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=101857 Sci] and [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=107809 Blazefang (second in command)]<br />
<br />
2. General of the Army: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=110445 Root01]<br />
<br />
3. General: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=94400 Calculator3000] and [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=108074 dantx5]<br />
<br />
<math>\pi.</math> Person who like tomatoes and does combinatorics: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=78673 NAA]<br />
<br />
4. Lieutenant General: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=126113 ytao]<br />
<br />
5. Major General: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=110468 avaj]<br />
<br />
6. Brigadier General: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=109650 kev2010]<br />
<br />
7. Colonel: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=101862 sassman]<br />
<br />
8. Lieutenant Colonel: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=101205 teddys123]<br />
<br />
9. Major: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=101119 ChipDale]<br />
<br />
10. Captain: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=101567 mathletepower]<br />
<br />
11. First Lieutenant: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=49043 musicnmath]<br />
<br />
12. Second Lieutenant: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=88673 in8]<br />
<br />
13. Sergeant: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=123093 Daemonheim]<br />
<br />
14. Corporal: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=124048 genesis2]<br />
<br />
15. Specialist: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=141966 StarWarsLiam]<br />
<br />
16. Private First Class:<br />
<br />
17. Private:<br />
<br />
18. Training:<br />
<br />
19. Civilian<br />
<br />
20. Baby Sitting in a Bathtub!<br />
<br />
==Objective==<br />
SpamSpamSpam<br />
<br />
Spam Pol has evolved into spam itself. Anyways, the sine law is cool.<br />
<br />
==Awards==<br />
There is a special award to mathgenius64, because of the fact that he has helped prevent the stopping of spam, and stopped people from backseat moderating<br />
<br />
Sci: I also must blame the policemen/women themselves. This was made for boosting up ratings, not backseat moderating<br />
<br />
Also, I blame myself for getting this snowball rolling in the first place<br />
<br />
===SpamPol Awards 2012===<br />
====dantx5====<br />
''' Gets "2nd most contributors" award'''<br />
<br />
====Scientest====<br />
Spammed in the games forum multiple times<br />
<br />
'''Gets "best spam policeman" award'''<br />
<br />
====AkshajK====<br />
Made an Annoying CSS, made a spammy blog, holds title of most contributors<br />
<br />
'''Gets "most contributors" award'''<br />
====ytao====<br />
Because I'm editing this now.<br />
<br />
''' Gets "best editor" award '''<br />
<br />
=SpamPol II=<br />
Was just founded.<br />
<br />
=Fun Facts=<br />
In his old blog, Sci posted Locker must-haves, a graphing calculator, books, and a picture of his crush<br />
<br />
Sci has played violin for approximately 6 years<br />
<br />
=Mathemagical Carreer=<br />
*NOTE TO SELF: FILL OUT</div>Scientesthttps://artofproblemsolving.com/wiki/index.php?title=User:Scientest&diff=48908User:Scientest2012-10-24T00:53:49Z<p>Scientest: /* TV Show */</p>
<hr />
<div> [[File:Warning.gif]]<br />
"Let us blow this popsicle stand! Okay, so maybe it's an ice pop stand, but whatever." –Sci at a school athletic event<br />
<br />
Hi there. Welcome to my Wiki page. I wrote this mainly in third person, so enjoy this while it lasts. And take heed of my warning. Scroll all the way down. Yikes. Well, have fun here! If you get bored, you can always go the forums.<br />
=Bio=<br />
Scientest is almost 12. He loves using <math>\text{\text\LaTeX}</math> and playing Plants vs. Zombies. He goes by the nickname Sci. He has done Algebra 1 (Summer 2011) and Counting and Probability (Fall-Spring 2011-2012) Sci plays the violin and the viola and loves math. He enjoys Plants vs. Zombies and cannot wait for P vs. Z 2 to come out. He also enjoys ClubPenguin (Look out for Inventapeng), Poptropica, Ninjago, and Pokemon<br />
==Name==<br />
His first name is Andrew. He snipped his last name from an FF post<br />
<br />
==Favorites==<br />
===Color===<br />
Pink: "It rocks"<br />
===Schoolhouse Rock song=== <br />
"I like them all, but my personal favorite is ''Interplanet Janet''"<br />
===Games on iPod/iPad=== <br />
Plants vs. Zombies: "I especially like it when the zombies eat your brains. Lol."<br />
<br />
Anthill<br />
<br />
Ouch!<br />
<br />
===Favorite Avatar Game=== <br />
Club Penguin, Runner-up: Poptropica<br />
===TV Show=== <br />
''Wild Kratts'': "Who knew how amazing nature is?"<br />
<br />
Runner-up: Pokémon Anime<br />
<br />
===Subject=== <br />
Math!<br />
===Catch Phrases===<br />
"Technically speaking... uh, no" and "Let us blow this popsicle stand!"<br />
<br />
===Comic===<br />
''Foxtrot'': "Jason is so funny." <br />
<br />
Comments: Dantx5: I agree.<br />
<br />
==Websites==<br />
Sci has an account on Poptropica, Club Penguin, Art of Problem Solving, Animal Jam, and EarIAm.<br />
<br />
==AoPS History==<br />
Sci posts a lot in the Fun Factory.<br />
===Stats===<br />
Sci joined AoPS on Feb 22, 2011, 8:44 am<br />
===Blog===<br />
"My blog is SpamPol's HQ, and it's closed to everyone except the Spam Police. It will reopen in late April."<br />
===Games and FF===<br />
Currently, Sci has started the Experimental game [http://www.artofproblemsolving.com/Forum/viewtopic.php?f=535&t=494960 Pokémon Battle]<br />
<br />
=Currency=<br />
IQ Points (IQP) are his currency. He also has Kendo Dollars.<br />
<br />
==Conversions==<br />
One IQP is the same as 6 [[User:Knittingfrenzy18 |RC]], or 10 [[User:EuclidGenius |Qwerty]]<br />
<br />
One Kendo Dollar is 90 IPQs<br />
<br />
==Value==<br />
IQPs are low in value, so they are easy to get. On the other hand, Kendo Dollars are extremely hard to get<br />
<br />
=CSS's=<br />
[http://www.artofproblemsolving.com/Forum/viewtopic.php?f=624&t=447899 Plants vs Zombies 1 v1.0 CSS]<br />
<br />
=SpamPol=<br />
Original Article: [[User:Scientest/SpamPol|SpamPol]]<br />
<br />
SpamPolice™ is a small corporation in [[User:Scientest|Scientest's]] blog. SpamPol™ is a spam police organization.<br />
<br />
SpamPolice™, or SpamPol™, lives up to its name<br />
==History==<br />
===Foundation and Early History===<br />
dantx5: SpamPol™ was originally created in Aug-Sept 2011 to stop an anonymous person in algebra class 497 to somehow prevent that user from rating all posts 1. The original members were the members between sci and sassman inclusive. The user finally got figured out, it was a SpamPol™ members sibling who was doing this. And now, Since class 497 has ended, SpamPol™ has grown bigger and has improved a little, but it would improve a lot if everyone in SpamPol™ was helping to stop spam. SpamPol™ mostly occurs in Scis blog, but rarely, Root01's blog.<br />
[note: ytao was not part of the original group]<br />
<br />
Blazefang: In truth, there still is a culprit, it wasn't only your little brother, cause there were 2 people, after you said your brother, it wouldn't make sense, you would need 2 to keep your rating lower than it should have been, the 497 spammer is still on the loose. I actually have an idea, maybe he thought rating it one star meant he thought it was "a 1st rate post" which is positive, so he did the opposite on accident, so when everybody was complaining about the rates, he continued, agreeing with them, when he was the culprit, unknowing, cause that's what I did at the very beginning then I found out a few days later that since it goes up and such. i don't know, just a theory.<br />
<br />
dantx5: and we stopped them by rating all posts in the forum a 6. <br />
<br />
The official start of SpamPol was August 23nd, 2011, but we call it August 19th because that's when inspiration hit us and we started scouting.<br />
<br />
In October 2011, Season 1 ended. Season 2 started in December 2011 and reopened in late April 2012. Season 3 started in May and will end around in mid August. <br />
<br />
NAA: This is hilarious. :)<br />
<br />
El_: vote for "no": http://www.artofproblemsolving.com/Forum/viewtopic.php?f=144&t=478068<br />
<br />
However, since the first mission, SpamPol has been interfering with the job of a moderator, and has received lots of criticism from others.<br />
<br />
MG: spampol ended May 3, 2012<br />
<br />
dantx5: yes, spampol lasted for 9 months, because SpamPol was no match for spam itself.<br />
<br />
El_: no, actually SpamPol is no match for '''itself'''<br />
<br />
dantx5: and now this wiki page has disintegrated into spam.<br />
<br />
El_: CD anyone? ok fine ftw then<br />
<br />
dantx5: maybe... but remember how you quickly joined my CD and then left almost immediately?<br />
<br />
Thkim: Wait what?? This is confusing. Can anyone explain this better?<br />
<br />
dantx5: SpamPol is over.<br />
<br />
StarWarsPol has started, go to el_'s link to find it. Please stop it, its backseat moderation.<br />
<br />
The SpamPol died on May 7th, 2012<br />
<br />
Thanks guys<br />
<br />
===Death===<br />
The SpamPol died on May 7th, 2012<br />
<br />
===Probabilities===<br />
SpamPol 2 starts = 10000000000000%<br />
<br />
SpamPol 2 actually helps = 0.009%<br />
<br />
SpamPol 3 starts = 0.01%<br />
<br />
SpamPol 2 reaches 100 members = 0.000055%<br />
<br />
Admins support SpamPol 2 = 0.000000025%<br />
<br />
SpamPol 2 reaches 2000 members = 0.000000003%<br />
<br />
SpamPol 2 spreads to several different websites = 0.0000000111%<br />
<br />
SpamPol 2 reaches 10000 members = 0.000000000000123%<br />
<br />
SpamPol 2 lasts for 15 years = 0.000000000000000000007%<br />
<br />
SpamPol 2 gets a fansite = 0.0000000000000000000000000000017%<br />
<br />
SpamPol 2 gains worldwide fame = 0.0000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000002%<br />
<br />
(Note: Edit this if you think the probablties are wrong somehow.)<br />
<br />
===Ranks===<br />
Members of SpamPol:<br />
<br />
<br />
<br />
1. Chief/General of the Armies: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=101857 Sci] and [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=107809 Blazefang (second in command)]<br />
<br />
2. General of the Army: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=110445 Root01]<br />
<br />
3. General: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=94400 Calculator3000] and [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=108074 dantx5]<br />
<br />
<math>\pi.</math> Person who like tomatoes and does combinatorics: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=78673 NAA]<br />
<br />
4. Lieutenant General: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=126113 ytao]<br />
<br />
5. Major General: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=110468 avaj]<br />
<br />
6. Brigadier General: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=109650 kev2010]<br />
<br />
7. Colonel: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=101862 sassman]<br />
<br />
8. Lieutenant Colonel: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=101205 teddys123]<br />
<br />
9. Major: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=101119 ChipDale]<br />
<br />
10. Captain: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=101567 mathletepower]<br />
<br />
11. First Lieutenant: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=49043 musicnmath]<br />
<br />
12. Second Lieutenant: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=88673 in8]<br />
<br />
13. Sergeant: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=123093 Daemonheim]<br />
<br />
14. Corporal: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=124048 genesis2]<br />
<br />
15. Specialist: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=141966 StarWarsLiam]<br />
<br />
16. Private First Class:<br />
<br />
17. Private:<br />
<br />
18. Training:<br />
<br />
19. Civilian<br />
<br />
20. Baby Sitting in a Bathtub!<br />
<br />
==Objective==<br />
SpamSpamSpam<br />
<br />
Spam Pol has evolved into spam itself. Anyways, the sine law is cool.<br />
<br />
==Awards==<br />
There is a special award to mathgenius64, because of the fact that he has helped prevent the stopping of spam, and stopped people from backseat moderating<br />
<br />
Sci: I also must blame the policemen/women themselves. This was made for boosting up ratings, not backseat moderating<br />
<br />
Also, I blame myself for getting this snowball rolling in the first place<br />
<br />
===SpamPol Awards 2012===<br />
====dantx5====<br />
''' Gets "2nd most contributors" award'''<br />
<br />
====Scientest====<br />
Spammed in the games forum multiple times<br />
<br />
'''Gets "best spam policeman" award'''<br />
<br />
====AkshajK====<br />
Made an Annoying CSS, made a spammy blog, holds title of most contributors<br />
<br />
'''Gets "most contributors" award'''<br />
====ytao====<br />
Because I'm editing this now.<br />
<br />
''' Gets "best editor" award '''<br />
<br />
=SpamPol II=<br />
Was just founded.<br />
<br />
=Fun Facts=<br />
In his old blog, Sci posted Locker must-haves, a graphing calculator, books, and a picture of his crush<br />
<br />
Sci has played violin for approximately 6 years<br />
<br />
=Mathemagical Carreer=<br />
*NOTE TO SELF: FILL OUT</div>Scientesthttps://artofproblemsolving.com/wiki/index.php?title=User:Scientest&diff=48836User:Scientest2012-10-13T01:42:15Z<p>Scientest: /* Bio */</p>
<hr />
<div> [[File:Warning.gif]]<br />
"Let us blow this popsicle stand! Okay, so maybe it's an ice pop stand, but whatever." –Sci at a school athletic event<br />
<br />
Hi there. Welcome to my Wiki page. I wrote this mainly in third person, so enjoy this while it lasts. And take heed of my warning. Scroll all the way down. Yikes. Well, have fun here! If you get bored, you can always go the forums.<br />
=Bio=<br />
Scientest is almost 12. He loves using <math>\text{\text\LaTeX}</math> and playing Plants vs. Zombies. He goes by the nickname Sci. He has done Algebra 1 (Summer 2011) and Counting and Probability (Fall-Spring 2011-2012) Sci plays the violin and the viola and loves math. He enjoys Plants vs. Zombies and cannot wait for P vs. Z 2 to come out. He also enjoys ClubPenguin (Look out for Inventapeng), Poptropica, Ninjago, and Pokemon<br />
==Name==<br />
His first name is Andrew. He snipped his last name from an FF post<br />
<br />
==Favorites==<br />
===Color===<br />
Pink: "It rocks"<br />
===Schoolhouse Rock song=== <br />
"I like them all, but my personal favorite is ''Interplanet Janet''"<br />
===Games on iPod/iPad=== <br />
Plants vs. Zombies: "I especially like it when the zombies eat your brains. Lol."<br />
<br />
Anthill<br />
<br />
Ouch!<br />
<br />
===Favorite Avatar Game=== <br />
Club Penguin, Runner-up: Poptropica<br />
===TV Show=== <br />
''Wild Kratts'': "Who knew how amazing nature is?"<br />
<br />
Runner-up: Pokémon: Black and White<br />
<br />
===Subject=== <br />
Math!<br />
===Catch Phrases===<br />
"Technically speaking... uh, no" and "Let us blow this popsicle stand!"<br />
<br />
===Comic===<br />
''Foxtrot'': "Jason is so funny." <br />
<br />
Comments: Dantx5: I agree.<br />
<br />
==Websites==<br />
Sci has an account on Poptropica, Club Penguin, Art of Problem Solving, Animal Jam, and EarIAm.<br />
<br />
==AoPS History==<br />
Sci posts a lot in the Fun Factory.<br />
===Stats===<br />
Sci joined AoPS on Feb 22, 2011, 8:44 am<br />
===Blog===<br />
"My blog is SpamPol's HQ, and it's closed to everyone except the Spam Police. It will reopen in late April."<br />
===Games and FF===<br />
Currently, Sci has started the Experimental game [http://www.artofproblemsolving.com/Forum/viewtopic.php?f=535&t=494960 Pokémon Battle]<br />
<br />
=Currency=<br />
IQ Points (IQP) are his currency. He also has Kendo Dollars.<br />
<br />
==Conversions==<br />
One IQP is the same as 6 [[User:Knittingfrenzy18 |RC]], or 10 [[User:EuclidGenius |Qwerty]]<br />
<br />
One Kendo Dollar is 90 IPQs<br />
<br />
==Value==<br />
IQPs are low in value, so they are easy to get. On the other hand, Kendo Dollars are extremely hard to get<br />
<br />
=CSS's=<br />
[http://www.artofproblemsolving.com/Forum/viewtopic.php?f=624&t=447899 Plants vs Zombies 1 v1.0 CSS]<br />
<br />
=SpamPol=<br />
Original Article: [[User:Scientest/SpamPol|SpamPol]]<br />
<br />
SpamPolice™ is a small corporation in [[User:Scientest|Scientest's]] blog. SpamPol™ is a spam police organization.<br />
<br />
SpamPolice™, or SpamPol™, lives up to its name<br />
==History==<br />
===Foundation and Early History===<br />
dantx5: SpamPol™ was originally created in Aug-Sept 2011 to stop an anonymous person in algebra class 497 to somehow prevent that user from rating all posts 1. The original members were the members between sci and sassman inclusive. The user finally got figured out, it was a SpamPol™ members sibling who was doing this. And now, Since class 497 has ended, SpamPol™ has grown bigger and has improved a little, but it would improve a lot if everyone in SpamPol™ was helping to stop spam. SpamPol™ mostly occurs in Scis blog, but rarely, Root01's blog.<br />
[note: ytao was not part of the original group]<br />
<br />
Blazefang: In truth, there still is a culprit, it wasn't only your little brother, cause there were 2 people, after you said your brother, it wouldn't make sense, you would need 2 to keep your rating lower than it should have been, the 497 spammer is still on the loose. I actually have an idea, maybe he thought rating it one star meant he thought it was "a 1st rate post" which is positive, so he did the opposite on accident, so when everybody was complaining about the rates, he continued, agreeing with them, when he was the culprit, unknowing, cause that's what I did at the very beginning then I found out a few days later that since it goes up and such. i don't know, just a theory.<br />
<br />
dantx5: and we stopped them by rating all posts in the forum a 6. <br />
<br />
The official start of SpamPol was August 23nd, 2011, but we call it August 19th because that's when inspiration hit us and we started scouting.<br />
<br />
In October 2011, Season 1 ended. Season 2 started in December 2011 and reopened in late April 2012. Season 3 started in May and will end around in mid August. <br />
<br />
NAA: This is hilarious. :)<br />
<br />
El_: vote for "no": http://www.artofproblemsolving.com/Forum/viewtopic.php?f=144&t=478068<br />
<br />
However, since the first mission, SpamPol has been interfering with the job of a moderator, and has received lots of criticism from others.<br />
<br />
MG: spampol ended May 3, 2012<br />
<br />
dantx5: yes, spampol lasted for 9 months, because SpamPol was no match for spam itself.<br />
<br />
El_: no, actually SpamPol is no match for '''itself'''<br />
<br />
dantx5: and now this wiki page has disintegrated into spam.<br />
<br />
El_: CD anyone? ok fine ftw then<br />
<br />
dantx5: maybe... but remember how you quickly joined my CD and then left almost immediately?<br />
<br />
Thkim: Wait what?? This is confusing. Can anyone explain this better?<br />
<br />
dantx5: SpamPol is over.<br />
<br />
StarWarsPol has started, go to el_'s link to find it. Please stop it, its backseat moderation.<br />
<br />
The SpamPol died on May 7th, 2012<br />
<br />
Thanks guys<br />
<br />
===Death===<br />
The SpamPol died on May 7th, 2012<br />
<br />
===Probabilities===<br />
SpamPol 2 starts = 10000000000000%<br />
<br />
SpamPol 2 actually helps = 0.009%<br />
<br />
SpamPol 3 starts = 0.01%<br />
<br />
SpamPol 2 reaches 100 members = 0.000055%<br />
<br />
Admins support SpamPol 2 = 0.000000025%<br />
<br />
SpamPol 2 reaches 2000 members = 0.000000003%<br />
<br />
SpamPol 2 spreads to several different websites = 0.0000000111%<br />
<br />
SpamPol 2 reaches 10000 members = 0.000000000000123%<br />
<br />
SpamPol 2 lasts for 15 years = 0.000000000000000000007%<br />
<br />
SpamPol 2 gets a fansite = 0.0000000000000000000000000000017%<br />
<br />
SpamPol 2 gains worldwide fame = 0.0000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000002%<br />
<br />
(Note: Edit this if you think the probablties are wrong somehow.)<br />
<br />
===Ranks===<br />
Members of SpamPol:<br />
<br />
<br />
<br />
1. Chief/General of the Armies: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=101857 Sci] and [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=107809 Blazefang (second in command)]<br />
<br />
2. General of the Army: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=110445 Root01]<br />
<br />
3. General: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=94400 Calculator3000] and [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=108074 dantx5]<br />
<br />
<math>\pi.</math> Person who like tomatoes and does combinatorics: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=78673 NAA]<br />
<br />
4. Lieutenant General: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=126113 ytao]<br />
<br />
5. Major General: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=110468 avaj]<br />
<br />
6. Brigadier General: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=109650 kev2010]<br />
<br />
7. Colonel: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=101862 sassman]<br />
<br />
8. Lieutenant Colonel: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=101205 teddys123]<br />
<br />
9. Major: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=101119 ChipDale]<br />
<br />
10. Captain: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=101567 mathletepower]<br />
<br />
11. First Lieutenant: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=49043 musicnmath]<br />
<br />
12. Second Lieutenant: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=88673 in8]<br />
<br />
13. Sergeant: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=123093 Daemonheim]<br />
<br />
14. Corporal: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=124048 genesis2]<br />
<br />
15. Specialist: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=141966 StarWarsLiam]<br />
<br />
16. Private First Class:<br />
<br />
17. Private:<br />
<br />
18. Training:<br />
<br />
19. Civilian<br />
<br />
20. Baby Sitting in a Bathtub!<br />
<br />
==Objective==<br />
SpamSpamSpam<br />
<br />
Spam Pol has evolved into spam itself. Anyways, the sine law is cool.<br />
<br />
==Awards==<br />
There is a special award to mathgenius64, because of the fact that he has helped prevent the stopping of spam, and stopped people from backseat moderating<br />
<br />
Sci: I also must blame the policemen/women themselves. This was made for boosting up ratings, not backseat moderating<br />
<br />
Also, I blame myself for getting this snowball rolling in the first place<br />
<br />
===SpamPol Awards 2012===<br />
====dantx5====<br />
''' Gets "2nd most contributors" award'''<br />
<br />
====Scientest====<br />
Spammed in the games forum multiple times<br />
<br />
'''Gets "best spam policeman" award'''<br />
<br />
====AkshajK====<br />
Made an Annoying CSS, made a spammy blog, holds title of most contributors<br />
<br />
'''Gets "most contributors" award'''<br />
====ytao====<br />
Because I'm editing this now.<br />
<br />
''' Gets "best editor" award '''<br />
<br />
=SpamPol II=<br />
Was just founded.<br />
<br />
=Fun Facts=<br />
In his old blog, Sci posted Locker must-haves, a graphing calculator, books, and a picture of his crush<br />
<br />
Sci has played violin for approximately 6 years<br />
<br />
=Mathemagical Carreer=<br />
*NOTE TO SELF: FILL OUT</div>Scientesthttps://artofproblemsolving.com/wiki/index.php?title=User:Scientest&diff=48178User:Scientest2012-09-01T19:38:49Z<p>Scientest: /* Games and FF */</p>
<hr />
<div> [[File:Warning.gif]]<br />
"Let us blow this popsicle stand! Okay, so maybe it's an ice pop stand, but whatever." –Sci at a school athletic event<br />
<br />
Hi there. Welcome to my Wiki page. I wrote this mainly in third person, so enjoy this while it lasts. And take heed of my warning. Scroll all the way down. Yikes. Well, have fun here! If you get bored, you can always go the forums.<br />
=Bio=<br />
Scientest is an tweenager. He loves using <math>\text{\text\LaTeX}</math> and playing Plants vs. Zombies. He goes by the nickname Sci. He has done Algebra 1 (Summer 2011) and Counting and Probability (Fall-Spring 2011-2012) Sci plays the violin and loves math. He enjoys Plants vs. Zombies and cannot wait for P vs. Z 2 to come out. He also enjoys ClubPenguin (Look out for Inventapeng), Poptropica, Ninjago, and Phineas and Ferb<br />
==Name==<br />
His first name is Andrew. He snipped his last name from an FF post<br />
<br />
==Favorites==<br />
===Color===<br />
Pink: "It rocks"<br />
===Schoolhouse Rock song=== <br />
"I like them all, but my personal favorite is ''Interplanet Janet''"<br />
===Games on iPod/iPad=== <br />
Plants vs. Zombies: "I especially like it when the zombies eat your brains. Lol."<br />
<br />
Anthill<br />
<br />
Ouch!<br />
<br />
===Favorite Avatar Game=== <br />
Club Penguin, Runner-up: Poptropica<br />
===TV Show=== <br />
''Wild Kratts'': "Who knew how amazing nature is?"<br />
<br />
Runner-up: Pokémon: Black and White<br />
<br />
===Subject=== <br />
Math!<br />
===Catch Phrases===<br />
"Technically speaking... uh, no" and "Let us blow this popsicle stand!"<br />
<br />
===Comic===<br />
''Foxtrot'': "Jason is so funny." <br />
<br />
Comments: Dantx5: I agree.<br />
<br />
==Websites==<br />
Sci has an account on Poptropica, Club Penguin, Art of Problem Solving, Animal Jam, and EarIAm.<br />
<br />
==AoPS History==<br />
Sci posts a lot in the Fun Factory.<br />
===Stats===<br />
Sci joined AoPS on Feb 22, 2011, 8:44 am<br />
===Blog===<br />
"My blog is SpamPol's HQ, and it's closed to everyone except the Spam Police. It will reopen in late April."<br />
===Games and FF===<br />
Currently, Sci has started the Experimental game [http://www.artofproblemsolving.com/Forum/viewtopic.php?f=535&t=494960 Pokémon Battle]<br />
<br />
=Currency=<br />
IQ Points (IQP) are his currency. He also has Kendo Dollars.<br />
<br />
==Conversions==<br />
One IQP is the same as 6 [[User:Knittingfrenzy18 |RC]], or 10 [[User:EuclidGenius |Qwerty]]<br />
<br />
One Kendo Dollar is 90 IPQs<br />
<br />
==Value==<br />
IQPs are low in value, so they are easy to get. On the other hand, Kendo Dollars are extremely hard to get<br />
<br />
=CSS's=<br />
[http://www.artofproblemsolving.com/Forum/viewtopic.php?f=624&t=447899 Plants vs Zombies 1 v1.0 CSS]<br />
<br />
=SpamPol=<br />
Original Article: [[User:Scientest/SpamPol|SpamPol]]<br />
<br />
SpamPolice™ is a small corporation in [[User:Scientest|Scientest's]] blog. SpamPol™ is a spam police organization.<br />
<br />
SpamPolice™, or SpamPol™, lives up to its name<br />
==History==<br />
===Foundation and Early History===<br />
dantx5: SpamPol™ was originally created in Aug-Sept 2011 to stop an anonymous person in algebra class 497 to somehow prevent that user from rating all posts 1. The original members were the members between sci and sassman inclusive. The user finally got figured out, it was a SpamPol™ members sibling who was doing this. And now, Since class 497 has ended, SpamPol™ has grown bigger and has improved a little, but it would improve a lot if everyone in SpamPol™ was helping to stop spam. SpamPol™ mostly occurs in Scis blog, but rarely, Root01's blog.<br />
[note: ytao was not part of the original group]<br />
<br />
Blazefang: In truth, there still is a culprit, it wasn't only your little brother, cause there were 2 people, after you said your brother, it wouldn't make sense, you would need 2 to keep your rating lower than it should have been, the 497 spammer is still on the loose. I actually have an idea, maybe he thought rating it one star meant he thought it was "a 1st rate post" which is positive, so he did the opposite on accident, so when everybody was complaining about the rates, he continued, agreeing with them, when he was the culprit, unknowing, cause that's what I did at the very beginning then I found out a few days later that since it goes up and such. i don't know, just a theory.<br />
<br />
dantx5: and we stopped them by rating all posts in the forum a 6. <br />
<br />
The official start of SpamPol was August 23nd, 2011, but we call it August 19th because that's when inspiration hit us and we started scouting.<br />
<br />
In October 2011, Season 1 ended. Season 2 started in December 2011 and reopened in late April 2012. Season 3 started in May and will end around in mid August. <br />
<br />
NAA: This is hilarious. :)<br />
<br />
El_: vote for "no": http://www.artofproblemsolving.com/Forum/viewtopic.php?f=144&t=478068<br />
<br />
However, since the first mission, SpamPol has been interfering with the job of a moderator, and has received lots of criticism from others.<br />
<br />
MG: spampol ended May 3, 2012<br />
<br />
dantx5: yes, spampol lasted for 9 months, because SpamPol was no match for spam itself.<br />
<br />
El_: no, actually SpamPol is no match for '''itself'''<br />
<br />
dantx5: and now this wiki page has disintegrated into spam.<br />
<br />
El_: CD anyone? ok fine ftw then<br />
<br />
dantx5: maybe... but remember how you quickly joined my CD and then left almost immediately?<br />
<br />
Thkim: Wait what?? This is confusing. Can anyone explain this better?<br />
<br />
dantx5: SpamPol is over.<br />
<br />
StarWarsPol has started, go to el_'s link to find it. Please stop it, its backseat moderation.<br />
<br />
The SpamPol died on May 7th, 2012<br />
<br />
Thanks guys<br />
<br />
===Death===<br />
The SpamPol died on May 7th, 2012<br />
<br />
===Probabilities===<br />
SpamPol 2 starts = 10000000000000%<br />
<br />
SpamPol 2 actually helps = 0.009%<br />
<br />
SpamPol 3 starts = 0.01%<br />
<br />
SpamPol 2 reaches 100 members = 0.000055%<br />
<br />
Admins support SpamPol 2 = 0.000000025%<br />
<br />
SpamPol 2 reaches 2000 members = 0.000000003%<br />
<br />
SpamPol 2 spreads to several different websites = 0.0000000111%<br />
<br />
SpamPol 2 reaches 10000 members = 0.000000000000123%<br />
<br />
SpamPol 2 lasts for 15 years = 0.000000000000000000007%<br />
<br />
SpamPol 2 gets a fansite = 0.0000000000000000000000000000017%<br />
<br />
SpamPol 2 gains worldwide fame = 0.0000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000002%<br />
<br />
(Note: Edit this if you think the probablties are wrong somehow.)<br />
<br />
===Ranks===<br />
Members of SpamPol:<br />
<br />
<br />
<br />
1. Chief/General of the Armies: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=101857 Sci] and [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=107809 Blazefang (second in command)]<br />
<br />
2. General of the Army: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=110445 Root01]<br />
<br />
3. General: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=94400 Calculator3000] and [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=108074 dantx5]<br />
<br />
<math>\pi.</math> Person who like tomatoes and does combinatorics: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=78673 NAA]<br />
<br />
4. Lieutenant General: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=126113 ytao]<br />
<br />
5. Major General: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=110468 avaj]<br />
<br />
6. Brigadier General: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=109650 kev2010]<br />
<br />
7. Colonel: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=101862 sassman]<br />
<br />
8. Lieutenant Colonel: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=101205 teddys123]<br />
<br />
9. Major: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=101119 ChipDale]<br />
<br />
10. Captain: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=101567 mathletepower]<br />
<br />
11. First Lieutenant: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=49043 musicnmath]<br />
<br />
12. Second Lieutenant: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=88673 in8]<br />
<br />
13. Sergeant: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=123093 Daemonheim]<br />
<br />
14. Corporal: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=124048 genesis2]<br />
<br />
15. Specialist: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=141966 StarWarsLiam]<br />
<br />
16. Private First Class:<br />
<br />
17. Private:<br />
<br />
18. Training:<br />
<br />
19. Civilian<br />
<br />
20. Baby Sitting in a Bathtub!<br />
<br />
==Objective==<br />
SpamSpamSpam<br />
<br />
Spam Pol has evolved into spam itself. Anyways, the sine law is cool.<br />
<br />
==Awards==<br />
There is a special award to mathgenius64, because of the fact that he has helped prevent the stopping of spam, and stopped people from backseat moderating<br />
<br />
Sci: I also must blame the policemen/women themselves. This was made for boosting up ratings, not backseat moderating<br />
<br />
Also, I blame myself for getting this snowball rolling in the first place<br />
<br />
===SpamPol Awards 2012===<br />
====dantx5====<br />
''' Gets "2nd most contributors" award'''<br />
<br />
====Scientest====<br />
Spammed in the games forum multiple times<br />
<br />
'''Gets "best spam policeman" award'''<br />
<br />
====AkshajK====<br />
Made an Annoying CSS, made a spammy blog, holds title of most contributors<br />
<br />
'''Gets "most contributors" award'''<br />
====ytao====<br />
Because I'm editing this now.<br />
<br />
''' Gets "best editor" award '''<br />
<br />
=Fun Facts=<br />
In his old blog, Sci posted Locker must-haves, a graphing calculator, books, and a picture of his crush<br />
<br />
Sci has played violin for approximately 6 years<br />
<br />
=Mathemagical Carreer=<br />
*NOTE TO SELF: FILL OUT</div>Scientesthttps://artofproblemsolving.com/wiki/index.php?title=User:Scientest&diff=48177User:Scientest2012-09-01T19:38:03Z<p>Scientest: /* Games and FF */</p>
<hr />
<div> [[File:Warning.gif]]<br />
"Let us blow this popsicle stand! Okay, so maybe it's an ice pop stand, but whatever." –Sci at a school athletic event<br />
<br />
Hi there. Welcome to my Wiki page. I wrote this mainly in third person, so enjoy this while it lasts. And take heed of my warning. Scroll all the way down. Yikes. Well, have fun here! If you get bored, you can always go the forums.<br />
=Bio=<br />
Scientest is an tweenager. He loves using <math>\text{\text\LaTeX}</math> and playing Plants vs. Zombies. He goes by the nickname Sci. He has done Algebra 1 (Summer 2011) and Counting and Probability (Fall-Spring 2011-2012) Sci plays the violin and loves math. He enjoys Plants vs. Zombies and cannot wait for P vs. Z 2 to come out. He also enjoys ClubPenguin (Look out for Inventapeng), Poptropica, Ninjago, and Phineas and Ferb<br />
==Name==<br />
His first name is Andrew. He snipped his last name from an FF post<br />
<br />
==Favorites==<br />
===Color===<br />
Pink: "It rocks"<br />
===Schoolhouse Rock song=== <br />
"I like them all, but my personal favorite is ''Interplanet Janet''"<br />
===Games on iPod/iPad=== <br />
Plants vs. Zombies: "I especially like it when the zombies eat your brains. Lol."<br />
<br />
Anthill<br />
<br />
Ouch!<br />
<br />
===Favorite Avatar Game=== <br />
Club Penguin, Runner-up: Poptropica<br />
===TV Show=== <br />
''Wild Kratts'': "Who knew how amazing nature is?"<br />
<br />
Runner-up: Pokémon: Black and White<br />
<br />
===Subject=== <br />
Math!<br />
===Catch Phrases===<br />
"Technically speaking... uh, no" and "Let us blow this popsicle stand!"<br />
<br />
===Comic===<br />
''Foxtrot'': "Jason is so funny." <br />
<br />
Comments: Dantx5: I agree.<br />
<br />
==Websites==<br />
Sci has an account on Poptropica, Club Penguin, Art of Problem Solving, Animal Jam, and EarIAm.<br />
<br />
==AoPS History==<br />
Sci posts a lot in the Fun Factory.<br />
===Stats===<br />
Sci joined AoPS on Feb 22, 2011, 8:44 am<br />
===Blog===<br />
"My blog is SpamPol's HQ, and it's closed to everyone except the Spam Police. It will reopen in late April."<br />
===Games and FF===<br />
Currently, Sci has started [http://www.artofproblemsolving.com/Forum/viewtopic.php?f=535&t=494960 Pokémon Battle [EXPERIMENTAL]]<br />
<br />
=Currency=<br />
IQ Points (IQP) are his currency. He also has Kendo Dollars.<br />
<br />
==Conversions==<br />
One IQP is the same as 6 [[User:Knittingfrenzy18 |RC]], or 10 [[User:EuclidGenius |Qwerty]]<br />
<br />
One Kendo Dollar is 90 IPQs<br />
<br />
==Value==<br />
IQPs are low in value, so they are easy to get. On the other hand, Kendo Dollars are extremely hard to get<br />
<br />
=CSS's=<br />
[http://www.artofproblemsolving.com/Forum/viewtopic.php?f=624&t=447899 Plants vs Zombies 1 v1.0 CSS]<br />
<br />
=SpamPol=<br />
Original Article: [[User:Scientest/SpamPol|SpamPol]]<br />
<br />
SpamPolice™ is a small corporation in [[User:Scientest|Scientest's]] blog. SpamPol™ is a spam police organization.<br />
<br />
SpamPolice™, or SpamPol™, lives up to its name<br />
==History==<br />
===Foundation and Early History===<br />
dantx5: SpamPol™ was originally created in Aug-Sept 2011 to stop an anonymous person in algebra class 497 to somehow prevent that user from rating all posts 1. The original members were the members between sci and sassman inclusive. The user finally got figured out, it was a SpamPol™ members sibling who was doing this. And now, Since class 497 has ended, SpamPol™ has grown bigger and has improved a little, but it would improve a lot if everyone in SpamPol™ was helping to stop spam. SpamPol™ mostly occurs in Scis blog, but rarely, Root01's blog.<br />
[note: ytao was not part of the original group]<br />
<br />
Blazefang: In truth, there still is a culprit, it wasn't only your little brother, cause there were 2 people, after you said your brother, it wouldn't make sense, you would need 2 to keep your rating lower than it should have been, the 497 spammer is still on the loose. I actually have an idea, maybe he thought rating it one star meant he thought it was "a 1st rate post" which is positive, so he did the opposite on accident, so when everybody was complaining about the rates, he continued, agreeing with them, when he was the culprit, unknowing, cause that's what I did at the very beginning then I found out a few days later that since it goes up and such. i don't know, just a theory.<br />
<br />
dantx5: and we stopped them by rating all posts in the forum a 6. <br />
<br />
The official start of SpamPol was August 23nd, 2011, but we call it August 19th because that's when inspiration hit us and we started scouting.<br />
<br />
In October 2011, Season 1 ended. Season 2 started in December 2011 and reopened in late April 2012. Season 3 started in May and will end around in mid August. <br />
<br />
NAA: This is hilarious. :)<br />
<br />
El_: vote for "no": http://www.artofproblemsolving.com/Forum/viewtopic.php?f=144&t=478068<br />
<br />
However, since the first mission, SpamPol has been interfering with the job of a moderator, and has received lots of criticism from others.<br />
<br />
MG: spampol ended May 3, 2012<br />
<br />
dantx5: yes, spampol lasted for 9 months, because SpamPol was no match for spam itself.<br />
<br />
El_: no, actually SpamPol is no match for '''itself'''<br />
<br />
dantx5: and now this wiki page has disintegrated into spam.<br />
<br />
El_: CD anyone? ok fine ftw then<br />
<br />
dantx5: maybe... but remember how you quickly joined my CD and then left almost immediately?<br />
<br />
Thkim: Wait what?? This is confusing. Can anyone explain this better?<br />
<br />
dantx5: SpamPol is over.<br />
<br />
StarWarsPol has started, go to el_'s link to find it. Please stop it, its backseat moderation.<br />
<br />
The SpamPol died on May 7th, 2012<br />
<br />
Thanks guys<br />
<br />
===Death===<br />
The SpamPol died on May 7th, 2012<br />
<br />
===Probabilities===<br />
SpamPol 2 starts = 10000000000000%<br />
<br />
SpamPol 2 actually helps = 0.009%<br />
<br />
SpamPol 3 starts = 0.01%<br />
<br />
SpamPol 2 reaches 100 members = 0.000055%<br />
<br />
Admins support SpamPol 2 = 0.000000025%<br />
<br />
SpamPol 2 reaches 2000 members = 0.000000003%<br />
<br />
SpamPol 2 spreads to several different websites = 0.0000000111%<br />
<br />
SpamPol 2 reaches 10000 members = 0.000000000000123%<br />
<br />
SpamPol 2 lasts for 15 years = 0.000000000000000000007%<br />
<br />
SpamPol 2 gets a fansite = 0.0000000000000000000000000000017%<br />
<br />
SpamPol 2 gains worldwide fame = 0.0000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000002%<br />
<br />
(Note: Edit this if you think the probablties are wrong somehow.)<br />
<br />
===Ranks===<br />
Members of SpamPol:<br />
<br />
<br />
<br />
1. Chief/General of the Armies: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=101857 Sci] and [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=107809 Blazefang (second in command)]<br />
<br />
2. General of the Army: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=110445 Root01]<br />
<br />
3. General: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=94400 Calculator3000] and [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=108074 dantx5]<br />
<br />
<math>\pi.</math> Person who like tomatoes and does combinatorics: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=78673 NAA]<br />
<br />
4. Lieutenant General: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=126113 ytao]<br />
<br />
5. Major General: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=110468 avaj]<br />
<br />
6. Brigadier General: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=109650 kev2010]<br />
<br />
7. Colonel: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=101862 sassman]<br />
<br />
8. Lieutenant Colonel: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=101205 teddys123]<br />
<br />
9. Major: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=101119 ChipDale]<br />
<br />
10. Captain: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=101567 mathletepower]<br />
<br />
11. First Lieutenant: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=49043 musicnmath]<br />
<br />
12. Second Lieutenant: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=88673 in8]<br />
<br />
13. Sergeant: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=123093 Daemonheim]<br />
<br />
14. Corporal: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=124048 genesis2]<br />
<br />
15. Specialist: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=141966 StarWarsLiam]<br />
<br />
16. Private First Class:<br />
<br />
17. Private:<br />
<br />
18. Training:<br />
<br />
19. Civilian<br />
<br />
20. Baby Sitting in a Bathtub!<br />
<br />
==Objective==<br />
SpamSpamSpam<br />
<br />
Spam Pol has evolved into spam itself. Anyways, the sine law is cool.<br />
<br />
==Awards==<br />
There is a special award to mathgenius64, because of the fact that he has helped prevent the stopping of spam, and stopped people from backseat moderating<br />
<br />
Sci: I also must blame the policemen/women themselves. This was made for boosting up ratings, not backseat moderating<br />
<br />
Also, I blame myself for getting this snowball rolling in the first place<br />
<br />
===SpamPol Awards 2012===<br />
====dantx5====<br />
''' Gets "2nd most contributors" award'''<br />
<br />
====Scientest====<br />
Spammed in the games forum multiple times<br />
<br />
'''Gets "best spam policeman" award'''<br />
<br />
====AkshajK====<br />
Made an Annoying CSS, made a spammy blog, holds title of most contributors<br />
<br />
'''Gets "most contributors" award'''<br />
====ytao====<br />
Because I'm editing this now.<br />
<br />
''' Gets "best editor" award '''<br />
<br />
=Fun Facts=<br />
In his old blog, Sci posted Locker must-haves, a graphing calculator, books, and a picture of his crush<br />
<br />
Sci has played violin for approximately 6 years<br />
<br />
=Mathemagical Carreer=<br />
*NOTE TO SELF: FILL OUT</div>Scientesthttps://artofproblemsolving.com/wiki/index.php?title=User:Scientest&diff=48176User:Scientest2012-09-01T19:08:51Z<p>Scientest: /* Websites */</p>
<hr />
<div> [[File:Warning.gif]]<br />
"Let us blow this popsicle stand! Okay, so maybe it's an ice pop stand, but whatever." –Sci at a school athletic event<br />
<br />
Hi there. Welcome to my Wiki page. I wrote this mainly in third person, so enjoy this while it lasts. And take heed of my warning. Scroll all the way down. Yikes. Well, have fun here! If you get bored, you can always go the forums.<br />
=Bio=<br />
Scientest is an tweenager. He loves using <math>\text{\text\LaTeX}</math> and playing Plants vs. Zombies. He goes by the nickname Sci. He has done Algebra 1 (Summer 2011) and Counting and Probability (Fall-Spring 2011-2012) Sci plays the violin and loves math. He enjoys Plants vs. Zombies and cannot wait for P vs. Z 2 to come out. He also enjoys ClubPenguin (Look out for Inventapeng), Poptropica, Ninjago, and Phineas and Ferb<br />
==Name==<br />
His first name is Andrew. He snipped his last name from an FF post<br />
<br />
==Favorites==<br />
===Color===<br />
Pink: "It rocks"<br />
===Schoolhouse Rock song=== <br />
"I like them all, but my personal favorite is ''Interplanet Janet''"<br />
===Games on iPod/iPad=== <br />
Plants vs. Zombies: "I especially like it when the zombies eat your brains. Lol."<br />
<br />
Anthill<br />
<br />
Ouch!<br />
<br />
===Favorite Avatar Game=== <br />
Club Penguin, Runner-up: Poptropica<br />
===TV Show=== <br />
''Wild Kratts'': "Who knew how amazing nature is?"<br />
<br />
Runner-up: Pokémon: Black and White<br />
<br />
===Subject=== <br />
Math!<br />
===Catch Phrases===<br />
"Technically speaking... uh, no" and "Let us blow this popsicle stand!"<br />
<br />
===Comic===<br />
''Foxtrot'': "Jason is so funny." <br />
<br />
Comments: Dantx5: I agree.<br />
<br />
==Websites==<br />
Sci has an account on Poptropica, Club Penguin, Art of Problem Solving, Animal Jam, and EarIAm.<br />
<br />
==AoPS History==<br />
Sci posts a lot in the Fun Factory.<br />
===Stats===<br />
Sci joined AoPS on Feb 22, 2011, 8:44 am<br />
===Blog===<br />
"My blog is SpamPol's HQ, and it's closed to everyone except the Spam Police. It will reopen in late April."<br />
===Games and FF===<br />
Currently, Sci has no main games<br />
<br />
=Currency=<br />
IQ Points (IQP) are his currency. He also has Kendo Dollars.<br />
<br />
==Conversions==<br />
One IQP is the same as 6 [[User:Knittingfrenzy18 |RC]], or 10 [[User:EuclidGenius |Qwerty]]<br />
<br />
One Kendo Dollar is 90 IPQs<br />
<br />
==Value==<br />
IQPs are low in value, so they are easy to get. On the other hand, Kendo Dollars are extremely hard to get<br />
<br />
=CSS's=<br />
[http://www.artofproblemsolving.com/Forum/viewtopic.php?f=624&t=447899 Plants vs Zombies 1 v1.0 CSS]<br />
<br />
=SpamPol=<br />
Original Article: [[User:Scientest/SpamPol|SpamPol]]<br />
<br />
SpamPolice™ is a small corporation in [[User:Scientest|Scientest's]] blog. SpamPol™ is a spam police organization.<br />
<br />
SpamPolice™, or SpamPol™, lives up to its name<br />
==History==<br />
===Foundation and Early History===<br />
dantx5: SpamPol™ was originally created in Aug-Sept 2011 to stop an anonymous person in algebra class 497 to somehow prevent that user from rating all posts 1. The original members were the members between sci and sassman inclusive. The user finally got figured out, it was a SpamPol™ members sibling who was doing this. And now, Since class 497 has ended, SpamPol™ has grown bigger and has improved a little, but it would improve a lot if everyone in SpamPol™ was helping to stop spam. SpamPol™ mostly occurs in Scis blog, but rarely, Root01's blog.<br />
[note: ytao was not part of the original group]<br />
<br />
Blazefang: In truth, there still is a culprit, it wasn't only your little brother, cause there were 2 people, after you said your brother, it wouldn't make sense, you would need 2 to keep your rating lower than it should have been, the 497 spammer is still on the loose. I actually have an idea, maybe he thought rating it one star meant he thought it was "a 1st rate post" which is positive, so he did the opposite on accident, so when everybody was complaining about the rates, he continued, agreeing with them, when he was the culprit, unknowing, cause that's what I did at the very beginning then I found out a few days later that since it goes up and such. i don't know, just a theory.<br />
<br />
dantx5: and we stopped them by rating all posts in the forum a 6. <br />
<br />
The official start of SpamPol was August 23nd, 2011, but we call it August 19th because that's when inspiration hit us and we started scouting.<br />
<br />
In October 2011, Season 1 ended. Season 2 started in December 2011 and reopened in late April 2012. Season 3 started in May and will end around in mid August. <br />
<br />
NAA: This is hilarious. :)<br />
<br />
El_: vote for "no": http://www.artofproblemsolving.com/Forum/viewtopic.php?f=144&t=478068<br />
<br />
However, since the first mission, SpamPol has been interfering with the job of a moderator, and has received lots of criticism from others.<br />
<br />
MG: spampol ended May 3, 2012<br />
<br />
dantx5: yes, spampol lasted for 9 months, because SpamPol was no match for spam itself.<br />
<br />
El_: no, actually SpamPol is no match for '''itself'''<br />
<br />
dantx5: and now this wiki page has disintegrated into spam.<br />
<br />
El_: CD anyone? ok fine ftw then<br />
<br />
dantx5: maybe... but remember how you quickly joined my CD and then left almost immediately?<br />
<br />
Thkim: Wait what?? This is confusing. Can anyone explain this better?<br />
<br />
dantx5: SpamPol is over.<br />
<br />
StarWarsPol has started, go to el_'s link to find it. Please stop it, its backseat moderation.<br />
<br />
The SpamPol died on May 7th, 2012<br />
<br />
Thanks guys<br />
<br />
===Death===<br />
The SpamPol died on May 7th, 2012<br />
<br />
===Probabilities===<br />
SpamPol 2 starts = 10000000000000%<br />
<br />
SpamPol 2 actually helps = 0.009%<br />
<br />
SpamPol 3 starts = 0.01%<br />
<br />
SpamPol 2 reaches 100 members = 0.000055%<br />
<br />
Admins support SpamPol 2 = 0.000000025%<br />
<br />
SpamPol 2 reaches 2000 members = 0.000000003%<br />
<br />
SpamPol 2 spreads to several different websites = 0.0000000111%<br />
<br />
SpamPol 2 reaches 10000 members = 0.000000000000123%<br />
<br />
SpamPol 2 lasts for 15 years = 0.000000000000000000007%<br />
<br />
SpamPol 2 gets a fansite = 0.0000000000000000000000000000017%<br />
<br />
SpamPol 2 gains worldwide fame = 0.0000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000002%<br />
<br />
(Note: Edit this if you think the probablties are wrong somehow.)<br />
<br />
===Ranks===<br />
Members of SpamPol:<br />
<br />
<br />
<br />
1. Chief/General of the Armies: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=101857 Sci] and [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=107809 Blazefang (second in command)]<br />
<br />
2. General of the Army: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=110445 Root01]<br />
<br />
3. General: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=94400 Calculator3000] and [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=108074 dantx5]<br />
<br />
<math>\pi.</math> Person who like tomatoes and does combinatorics: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=78673 NAA]<br />
<br />
4. Lieutenant General: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=126113 ytao]<br />
<br />
5. Major General: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=110468 avaj]<br />
<br />
6. Brigadier General: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=109650 kev2010]<br />
<br />
7. Colonel: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=101862 sassman]<br />
<br />
8. Lieutenant Colonel: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=101205 teddys123]<br />
<br />
9. Major: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=101119 ChipDale]<br />
<br />
10. Captain: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=101567 mathletepower]<br />
<br />
11. First Lieutenant: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=49043 musicnmath]<br />
<br />
12. Second Lieutenant: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=88673 in8]<br />
<br />
13. Sergeant: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=123093 Daemonheim]<br />
<br />
14. Corporal: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=124048 genesis2]<br />
<br />
15. Specialist: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=141966 StarWarsLiam]<br />
<br />
16. Private First Class:<br />
<br />
17. Private:<br />
<br />
18. Training:<br />
<br />
19. Civilian<br />
<br />
20. Baby Sitting in a Bathtub!<br />
<br />
==Objective==<br />
SpamSpamSpam<br />
<br />
Spam Pol has evolved into spam itself. Anyways, the sine law is cool.<br />
<br />
==Awards==<br />
There is a special award to mathgenius64, because of the fact that he has helped prevent the stopping of spam, and stopped people from backseat moderating<br />
<br />
Sci: I also must blame the policemen/women themselves. This was made for boosting up ratings, not backseat moderating<br />
<br />
Also, I blame myself for getting this snowball rolling in the first place<br />
<br />
===SpamPol Awards 2012===<br />
====dantx5====<br />
''' Gets "2nd most contributors" award'''<br />
<br />
====Scientest====<br />
Spammed in the games forum multiple times<br />
<br />
'''Gets "best spam policeman" award'''<br />
<br />
====AkshajK====<br />
Made an Annoying CSS, made a spammy blog, holds title of most contributors<br />
<br />
'''Gets "most contributors" award'''<br />
====ytao====<br />
Because I'm editing this now.<br />
<br />
''' Gets "best editor" award '''<br />
<br />
=Fun Facts=<br />
In his old blog, Sci posted Locker must-haves, a graphing calculator, books, and a picture of his crush<br />
<br />
Sci has played violin for approximately 6 years<br />
<br />
=Mathemagical Carreer=<br />
*NOTE TO SELF: FILL OUT</div>Scientesthttps://artofproblemsolving.com/wiki/index.php?title=User:Scientest&diff=48174User:Scientest2012-09-01T19:08:13Z<p>Scientest: /* TV Show */</p>
<hr />
<div> [[File:Warning.gif]]<br />
"Let us blow this popsicle stand! Okay, so maybe it's an ice pop stand, but whatever." –Sci at a school athletic event<br />
<br />
Hi there. Welcome to my Wiki page. I wrote this mainly in third person, so enjoy this while it lasts. And take heed of my warning. Scroll all the way down. Yikes. Well, have fun here! If you get bored, you can always go the forums.<br />
=Bio=<br />
Scientest is an tweenager. He loves using <math>\text{\text\LaTeX}</math> and playing Plants vs. Zombies. He goes by the nickname Sci. He has done Algebra 1 (Summer 2011) and Counting and Probability (Fall-Spring 2011-2012) Sci plays the violin and loves math. He enjoys Plants vs. Zombies and cannot wait for P vs. Z 2 to come out. He also enjoys ClubPenguin (Look out for Inventapeng), Poptropica, Ninjago, and Phineas and Ferb<br />
==Name==<br />
His first name is Andrew. He snipped his last name from an FF post<br />
<br />
==Favorites==<br />
===Color===<br />
Pink: "It rocks"<br />
===Schoolhouse Rock song=== <br />
"I like them all, but my personal favorite is ''Interplanet Janet''"<br />
===Games on iPod/iPad=== <br />
Plants vs. Zombies: "I especially like it when the zombies eat your brains. Lol."<br />
<br />
Anthill<br />
<br />
Ouch!<br />
<br />
===Favorite Avatar Game=== <br />
Club Penguin, Runner-up: Poptropica<br />
===TV Show=== <br />
''Wild Kratts'': "Who knew how amazing nature is?"<br />
<br />
Runner-up: Pokémon: Black and White<br />
<br />
===Subject=== <br />
Math!<br />
===Catch Phrases===<br />
"Technically speaking... uh, no" and "Let us blow this popsicle stand!"<br />
<br />
===Comic===<br />
''Foxtrot'': "Jason is so funny." <br />
<br />
Comments: Dantx5: I agree.<br />
<br />
==Websites==<br />
Sci has an account on Poptropica, Club Penguin, Art of Problem Solving, and EarIAm.<br />
==AoPS History==<br />
Sci posts a lot in the Fun Factory.<br />
===Stats===<br />
Sci joined AoPS on Feb 22, 2011, 8:44 am<br />
===Blog===<br />
"My blog is SpamPol's HQ, and it's closed to everyone except the Spam Police. It will reopen in late April."<br />
===Games and FF===<br />
Currently, Sci has no main games<br />
<br />
=Currency=<br />
IQ Points (IQP) are his currency. He also has Kendo Dollars.<br />
<br />
==Conversions==<br />
One IQP is the same as 6 [[User:Knittingfrenzy18 |RC]], or 10 [[User:EuclidGenius |Qwerty]]<br />
<br />
One Kendo Dollar is 90 IPQs<br />
<br />
==Value==<br />
IQPs are low in value, so they are easy to get. On the other hand, Kendo Dollars are extremely hard to get<br />
<br />
=CSS's=<br />
[http://www.artofproblemsolving.com/Forum/viewtopic.php?f=624&t=447899 Plants vs Zombies 1 v1.0 CSS]<br />
<br />
=SpamPol=<br />
Original Article: [[User:Scientest/SpamPol|SpamPol]]<br />
<br />
SpamPolice™ is a small corporation in [[User:Scientest|Scientest's]] blog. SpamPol™ is a spam police organization.<br />
<br />
SpamPolice™, or SpamPol™, lives up to its name<br />
==History==<br />
===Foundation and Early History===<br />
dantx5: SpamPol™ was originally created in Aug-Sept 2011 to stop an anonymous person in algebra class 497 to somehow prevent that user from rating all posts 1. The original members were the members between sci and sassman inclusive. The user finally got figured out, it was a SpamPol™ members sibling who was doing this. And now, Since class 497 has ended, SpamPol™ has grown bigger and has improved a little, but it would improve a lot if everyone in SpamPol™ was helping to stop spam. SpamPol™ mostly occurs in Scis blog, but rarely, Root01's blog.<br />
[note: ytao was not part of the original group]<br />
<br />
Blazefang: In truth, there still is a culprit, it wasn't only your little brother, cause there were 2 people, after you said your brother, it wouldn't make sense, you would need 2 to keep your rating lower than it should have been, the 497 spammer is still on the loose. I actually have an idea, maybe he thought rating it one star meant he thought it was "a 1st rate post" which is positive, so he did the opposite on accident, so when everybody was complaining about the rates, he continued, agreeing with them, when he was the culprit, unknowing, cause that's what I did at the very beginning then I found out a few days later that since it goes up and such. i don't know, just a theory.<br />
<br />
dantx5: and we stopped them by rating all posts in the forum a 6. <br />
<br />
The official start of SpamPol was August 23nd, 2011, but we call it August 19th because that's when inspiration hit us and we started scouting.<br />
<br />
In October 2011, Season 1 ended. Season 2 started in December 2011 and reopened in late April 2012. Season 3 started in May and will end around in mid August. <br />
<br />
NAA: This is hilarious. :)<br />
<br />
El_: vote for "no": http://www.artofproblemsolving.com/Forum/viewtopic.php?f=144&t=478068<br />
<br />
However, since the first mission, SpamPol has been interfering with the job of a moderator, and has received lots of criticism from others.<br />
<br />
MG: spampol ended May 3, 2012<br />
<br />
dantx5: yes, spampol lasted for 9 months, because SpamPol was no match for spam itself.<br />
<br />
El_: no, actually SpamPol is no match for '''itself'''<br />
<br />
dantx5: and now this wiki page has disintegrated into spam.<br />
<br />
El_: CD anyone? ok fine ftw then<br />
<br />
dantx5: maybe... but remember how you quickly joined my CD and then left almost immediately?<br />
<br />
Thkim: Wait what?? This is confusing. Can anyone explain this better?<br />
<br />
dantx5: SpamPol is over.<br />
<br />
StarWarsPol has started, go to el_'s link to find it. Please stop it, its backseat moderation.<br />
<br />
The SpamPol died on May 7th, 2012<br />
<br />
Thanks guys<br />
<br />
===Death===<br />
The SpamPol died on May 7th, 2012<br />
<br />
===Probabilities===<br />
SpamPol 2 starts = 10000000000000%<br />
<br />
SpamPol 2 actually helps = 0.009%<br />
<br />
SpamPol 3 starts = 0.01%<br />
<br />
SpamPol 2 reaches 100 members = 0.000055%<br />
<br />
Admins support SpamPol 2 = 0.000000025%<br />
<br />
SpamPol 2 reaches 2000 members = 0.000000003%<br />
<br />
SpamPol 2 spreads to several different websites = 0.0000000111%<br />
<br />
SpamPol 2 reaches 10000 members = 0.000000000000123%<br />
<br />
SpamPol 2 lasts for 15 years = 0.000000000000000000007%<br />
<br />
SpamPol 2 gets a fansite = 0.0000000000000000000000000000017%<br />
<br />
SpamPol 2 gains worldwide fame = 0.0000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000002%<br />
<br />
(Note: Edit this if you think the probablties are wrong somehow.)<br />
<br />
===Ranks===<br />
Members of SpamPol:<br />
<br />
<br />
<br />
1. Chief/General of the Armies: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=101857 Sci] and [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=107809 Blazefang (second in command)]<br />
<br />
2. General of the Army: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=110445 Root01]<br />
<br />
3. General: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=94400 Calculator3000] and [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=108074 dantx5]<br />
<br />
<math>\pi.</math> Person who like tomatoes and does combinatorics: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=78673 NAA]<br />
<br />
4. Lieutenant General: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=126113 ytao]<br />
<br />
5. Major General: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=110468 avaj]<br />
<br />
6. Brigadier General: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=109650 kev2010]<br />
<br />
7. Colonel: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=101862 sassman]<br />
<br />
8. Lieutenant Colonel: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=101205 teddys123]<br />
<br />
9. Major: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=101119 ChipDale]<br />
<br />
10. Captain: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=101567 mathletepower]<br />
<br />
11. First Lieutenant: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=49043 musicnmath]<br />
<br />
12. Second Lieutenant: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=88673 in8]<br />
<br />
13. Sergeant: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=123093 Daemonheim]<br />
<br />
14. Corporal: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=124048 genesis2]<br />
<br />
15. Specialist: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=141966 StarWarsLiam]<br />
<br />
16. Private First Class:<br />
<br />
17. Private:<br />
<br />
18. Training:<br />
<br />
19. Civilian<br />
<br />
20. Baby Sitting in a Bathtub!<br />
<br />
==Objective==<br />
SpamSpamSpam<br />
<br />
Spam Pol has evolved into spam itself. Anyways, the sine law is cool.<br />
<br />
==Awards==<br />
There is a special award to mathgenius64, because of the fact that he has helped prevent the stopping of spam, and stopped people from backseat moderating<br />
<br />
Sci: I also must blame the policemen/women themselves. This was made for boosting up ratings, not backseat moderating<br />
<br />
Also, I blame myself for getting this snowball rolling in the first place<br />
<br />
===SpamPol Awards 2012===<br />
====dantx5====<br />
''' Gets "2nd most contributors" award'''<br />
<br />
====Scientest====<br />
Spammed in the games forum multiple times<br />
<br />
'''Gets "best spam policeman" award'''<br />
<br />
====AkshajK====<br />
Made an Annoying CSS, made a spammy blog, holds title of most contributors<br />
<br />
'''Gets "most contributors" award'''<br />
====ytao====<br />
Because I'm editing this now.<br />
<br />
''' Gets "best editor" award '''<br />
<br />
=Fun Facts=<br />
In his old blog, Sci posted Locker must-haves, a graphing calculator, books, and a picture of his crush<br />
<br />
Sci has played violin for approximately 6 years<br />
<br />
=Mathemagical Carreer=<br />
*NOTE TO SELF: FILL OUT</div>Scientesthttps://artofproblemsolving.com/wiki/index.php?title=User:Scientest&diff=48173User:Scientest2012-09-01T19:07:41Z<p>Scientest: </p>
<hr />
<div> [[File:Warning.gif]]<br />
"Let us blow this popsicle stand! Okay, so maybe it's an ice pop stand, but whatever." –Sci at a school athletic event<br />
<br />
Hi there. Welcome to my Wiki page. I wrote this mainly in third person, so enjoy this while it lasts. And take heed of my warning. Scroll all the way down. Yikes. Well, have fun here! If you get bored, you can always go the forums.<br />
=Bio=<br />
Scientest is an tweenager. He loves using <math>\text{\text\LaTeX}</math> and playing Plants vs. Zombies. He goes by the nickname Sci. He has done Algebra 1 (Summer 2011) and Counting and Probability (Fall-Spring 2011-2012) Sci plays the violin and loves math. He enjoys Plants vs. Zombies and cannot wait for P vs. Z 2 to come out. He also enjoys ClubPenguin (Look out for Inventapeng), Poptropica, Ninjago, and Phineas and Ferb<br />
==Name==<br />
His first name is Andrew. He snipped his last name from an FF post<br />
<br />
==Favorites==<br />
===Color===<br />
Pink: "It rocks"<br />
===Schoolhouse Rock song=== <br />
"I like them all, but my personal favorite is ''Interplanet Janet''"<br />
===Games on iPod/iPad=== <br />
Plants vs. Zombies: "I especially like it when the zombies eat your brains. Lol."<br />
<br />
Anthill<br />
<br />
Ouch!<br />
<br />
===Favorite Avatar Game=== <br />
Club Penguin, Runner-up: Poptropica<br />
===TV Show=== <br />
''Wild Kratts'': "Who knew how amazing nature is?"<br />
<br />
Runner-up: Phineas and Ferb<br />
===Subject=== <br />
Math!<br />
===Catch Phrases===<br />
"Technically speaking... uh, no" and "Let us blow this popsicle stand!"<br />
<br />
===Comic===<br />
''Foxtrot'': "Jason is so funny." <br />
<br />
Comments: Dantx5: I agree.<br />
<br />
==Websites==<br />
Sci has an account on Poptropica, Club Penguin, Art of Problem Solving, and EarIAm.<br />
==AoPS History==<br />
Sci posts a lot in the Fun Factory.<br />
===Stats===<br />
Sci joined AoPS on Feb 22, 2011, 8:44 am<br />
===Blog===<br />
"My blog is SpamPol's HQ, and it's closed to everyone except the Spam Police. It will reopen in late April."<br />
===Games and FF===<br />
Currently, Sci has no main games<br />
<br />
=Currency=<br />
IQ Points (IQP) are his currency. He also has Kendo Dollars.<br />
<br />
==Conversions==<br />
One IQP is the same as 6 [[User:Knittingfrenzy18 |RC]], or 10 [[User:EuclidGenius |Qwerty]]<br />
<br />
One Kendo Dollar is 90 IPQs<br />
<br />
==Value==<br />
IQPs are low in value, so they are easy to get. On the other hand, Kendo Dollars are extremely hard to get<br />
<br />
=CSS's=<br />
[http://www.artofproblemsolving.com/Forum/viewtopic.php?f=624&t=447899 Plants vs Zombies 1 v1.0 CSS]<br />
<br />
=SpamPol=<br />
Original Article: [[User:Scientest/SpamPol|SpamPol]]<br />
<br />
SpamPolice™ is a small corporation in [[User:Scientest|Scientest's]] blog. SpamPol™ is a spam police organization.<br />
<br />
SpamPolice™, or SpamPol™, lives up to its name<br />
==History==<br />
===Foundation and Early History===<br />
dantx5: SpamPol™ was originally created in Aug-Sept 2011 to stop an anonymous person in algebra class 497 to somehow prevent that user from rating all posts 1. The original members were the members between sci and sassman inclusive. The user finally got figured out, it was a SpamPol™ members sibling who was doing this. And now, Since class 497 has ended, SpamPol™ has grown bigger and has improved a little, but it would improve a lot if everyone in SpamPol™ was helping to stop spam. SpamPol™ mostly occurs in Scis blog, but rarely, Root01's blog.<br />
[note: ytao was not part of the original group]<br />
<br />
Blazefang: In truth, there still is a culprit, it wasn't only your little brother, cause there were 2 people, after you said your brother, it wouldn't make sense, you would need 2 to keep your rating lower than it should have been, the 497 spammer is still on the loose. I actually have an idea, maybe he thought rating it one star meant he thought it was "a 1st rate post" which is positive, so he did the opposite on accident, so when everybody was complaining about the rates, he continued, agreeing with them, when he was the culprit, unknowing, cause that's what I did at the very beginning then I found out a few days later that since it goes up and such. i don't know, just a theory.<br />
<br />
dantx5: and we stopped them by rating all posts in the forum a 6. <br />
<br />
The official start of SpamPol was August 23nd, 2011, but we call it August 19th because that's when inspiration hit us and we started scouting.<br />
<br />
In October 2011, Season 1 ended. Season 2 started in December 2011 and reopened in late April 2012. Season 3 started in May and will end around in mid August. <br />
<br />
NAA: This is hilarious. :)<br />
<br />
El_: vote for "no": http://www.artofproblemsolving.com/Forum/viewtopic.php?f=144&t=478068<br />
<br />
However, since the first mission, SpamPol has been interfering with the job of a moderator, and has received lots of criticism from others.<br />
<br />
MG: spampol ended May 3, 2012<br />
<br />
dantx5: yes, spampol lasted for 9 months, because SpamPol was no match for spam itself.<br />
<br />
El_: no, actually SpamPol is no match for '''itself'''<br />
<br />
dantx5: and now this wiki page has disintegrated into spam.<br />
<br />
El_: CD anyone? ok fine ftw then<br />
<br />
dantx5: maybe... but remember how you quickly joined my CD and then left almost immediately?<br />
<br />
Thkim: Wait what?? This is confusing. Can anyone explain this better?<br />
<br />
dantx5: SpamPol is over.<br />
<br />
StarWarsPol has started, go to el_'s link to find it. Please stop it, its backseat moderation.<br />
<br />
The SpamPol died on May 7th, 2012<br />
<br />
Thanks guys<br />
<br />
===Death===<br />
The SpamPol died on May 7th, 2012<br />
<br />
===Probabilities===<br />
SpamPol 2 starts = 10000000000000%<br />
<br />
SpamPol 2 actually helps = 0.009%<br />
<br />
SpamPol 3 starts = 0.01%<br />
<br />
SpamPol 2 reaches 100 members = 0.000055%<br />
<br />
Admins support SpamPol 2 = 0.000000025%<br />
<br />
SpamPol 2 reaches 2000 members = 0.000000003%<br />
<br />
SpamPol 2 spreads to several different websites = 0.0000000111%<br />
<br />
SpamPol 2 reaches 10000 members = 0.000000000000123%<br />
<br />
SpamPol 2 lasts for 15 years = 0.000000000000000000007%<br />
<br />
SpamPol 2 gets a fansite = 0.0000000000000000000000000000017%<br />
<br />
SpamPol 2 gains worldwide fame = 0.0000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000002%<br />
<br />
(Note: Edit this if you think the probablties are wrong somehow.)<br />
<br />
===Ranks===<br />
Members of SpamPol:<br />
<br />
<br />
<br />
1. Chief/General of the Armies: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=101857 Sci] and [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=107809 Blazefang (second in command)]<br />
<br />
2. General of the Army: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=110445 Root01]<br />
<br />
3. General: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=94400 Calculator3000] and [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=108074 dantx5]<br />
<br />
<math>\pi.</math> Person who like tomatoes and does combinatorics: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=78673 NAA]<br />
<br />
4. Lieutenant General: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=126113 ytao]<br />
<br />
5. Major General: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=110468 avaj]<br />
<br />
6. Brigadier General: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=109650 kev2010]<br />
<br />
7. Colonel: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=101862 sassman]<br />
<br />
8. Lieutenant Colonel: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=101205 teddys123]<br />
<br />
9. Major: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=101119 ChipDale]<br />
<br />
10. Captain: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=101567 mathletepower]<br />
<br />
11. First Lieutenant: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=49043 musicnmath]<br />
<br />
12. Second Lieutenant: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=88673 in8]<br />
<br />
13. Sergeant: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=123093 Daemonheim]<br />
<br />
14. Corporal: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=124048 genesis2]<br />
<br />
15. Specialist: [http://www.artofproblemsolving.com/Forum/memberlist.php?mode=viewprofile&u=141966 StarWarsLiam]<br />
<br />
16. Private First Class:<br />
<br />
17. Private:<br />
<br />
18. Training:<br />
<br />
19. Civilian<br />
<br />
20. Baby Sitting in a Bathtub!<br />
<br />
==Objective==<br />
SpamSpamSpam<br />
<br />
Spam Pol has evolved into spam itself. Anyways, the sine law is cool.<br />
<br />
==Awards==<br />
There is a special award to mathgenius64, because of the fact that he has helped prevent the stopping of spam, and stopped people from backseat moderating<br />
<br />
Sci: I also must blame the policemen/women themselves. This was made for boosting up ratings, not backseat moderating<br />
<br />
Also, I blame myself for getting this snowball rolling in the first place<br />
<br />
===SpamPol Awards 2012===<br />
====dantx5====<br />
''' Gets "2nd most contributors" award'''<br />
<br />
====Scientest====<br />
Spammed in the games forum multiple times<br />
<br />
'''Gets "best spam policeman" award'''<br />
<br />
====AkshajK====<br />
Made an Annoying CSS, made a spammy blog, holds title of most contributors<br />
<br />
'''Gets "most contributors" award'''<br />
====ytao====<br />
Because I'm editing this now.<br />
<br />
''' Gets "best editor" award '''<br />
<br />
=Fun Facts=<br />
In his old blog, Sci posted Locker must-haves, a graphing calculator, books, and a picture of his crush<br />
<br />
Sci has played violin for approximately 6 years<br />
<br />
=Mathemagical Carreer=<br />
*NOTE TO SELF: FILL OUT</div>Scientesthttps://artofproblemsolving.com/wiki/index.php?title=File:4828_pi_wallpaper.jpg&diff=47936File:4828 pi wallpaper.jpg2012-08-18T17:09:40Z<p>Scientest: Pi</p>
<hr />
<div>Pi</div>Scientesthttps://artofproblemsolving.com/wiki/index.php?title=User_talk:Scientest&diff=47925User talk:Scientest2012-08-17T14:47:02Z<p>Scientest: /* On AoPS and I Know It */ new section</p>
<hr />
<div>= Wiki Puzzles =<br />
<br />
Used with Permission<br />
[[File:Foxtrot nerd search comic.gif]]<br />
[[File:Foxtrot Sudoku.gif]]<br />
[[File:foxtrot.paint.by.numbers.gif]]<br />
[[File:Level 4 Numerical Number-Letter Cryptography.gif]]<br />
[[File:Foxtrot Jason's Easter Eggcryption.gif]]<br />
<br />
<br />
Post your solutions here! Good luck!<br />
<br />
Lol I love the last one, "Please steal my candy basket" Lol!! :P -- EG<br />
<br />
== The Funnies ==<br />
<br />
[[File:Optimism.jpg]]<br />
[[File:MusicComic.jpg]]<br />
<br />
== On AoPS and I Know It ==<br />
<br />
[http://www.youtube.com/watch?v=Q_cttlOLzuU Click here to see levans rap]</div>Scientest