1975 AHSME Problems/Problem 13

Problem

The equation $x^6 - 3x^5 - 6x^3 - x + 8 = 0$ has

$\textbf{(A)} \text{ no real roots} \\ \textbf{(B)} \text{ exactly two distinct negative roots} \\ \textbf{(C)} \text{ exactly one negative root} \\ \textbf{(D)} \text{ no negative roots, but at least one positive roots} \\ \textbf{(E)} \text{ none of these}$

Solution

nothing yet :(

See Also

1975 AHSME (ProblemsAnswer KeyResources)
Preceded by
Problem 12
Followed by
Problem 14
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All AHSME Problems and Solutions

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