1986 AHSME Problems/Problem 15
Problem
A student attempted to compute the average of and by computing the average of and , and then computing the average of the result and . Whenever , the student's final result is
Solution
The true average is , and the student computed , so , which is always positive as and . Thus is always greater than , i.e. .
See also
1986 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 14 |
Followed by Problem 16 | |
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