AoPS Wiki talk:Problem of the Day/June 20, 2011


AoPSWiki:Problem of the Day/June 20, 2011


Since it is both a perfect cube and a perfect square, it must be a perfect sixth power. This is because the GCD of $2$ and $3$ is $6$, meaning it will leave an integer power when either the square root or the cube root is taken. The fourth perfect sixth power is $4^6=2^{12}=\boxed{4096}$.

Invalid username
Login to AoPS