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  • &= \frac{3}{8}-\left(-\frac{2}{5}\right)\left\lfloor\frac{-15}{16}\right\rfloor\
    2 KB (257 words) - 09:57, 16 June 2023
  • \ = 2\int_0^1 1 + \frac{3}{8}x dx = 2(x + \frac{3}{16}x^2) \left.\right|_{\;0}^{\;1} \ = 2(1 + \frac{3}{16}1^2) = 2\frac{19}{16} = \frac{19}{8}</math>
    8 KB (1,016 words) - 23:17, 30 December 2023
  • *2016 Regional - Saturday 2/27/16 *2016 State Finals - Saturday 5/7/16
    8 KB (1,182 words) - 13:26, 3 April 2024
  • Nearly 16,000 U.S. students participate in Local Chemistry Olympiad competitions. Ove
    2 KB (267 words) - 09:11, 21 October 2024
  • =\frac{2}{2}+\frac{4}{4}+\frac{6}{8}+\frac{8}{16}+\cdots\ =\frac{1}{2}+\frac{4}{4}+\frac{9}{8}+\frac{16}{16}+\cdots\
    1 KB (193 words) - 20:13, 18 May 2021
  • *AIME Floor: 85.5 (top ~16%) *AIME Floor: 88.5 (top ~16%)
    17 KB (1,900 words) - 19:38, 3 January 2025
  • We can determine that <math>\frac{a+b+c}{3}+d+16=a+b+c+d</math>. This, with some algebra, means that <math>\frac{1}{3}(a+b+c
    1 KB (200 words) - 22:35, 28 August 2020
  • pair A=(-3*sqrt(3)/32,9/32), B=(3*sqrt(3)/32, 9/32), C=(0,9/16); draw((-2/3,9/16)--(2/3,9/16));
    3 KB (415 words) - 17:01, 24 May 2020
  • ...ed using the top 15 winners in West Virginia State Math Field Day. Winners 16-30 are used as potential alternates for the team. West Virginia State Math
    22 KB (3,532 words) - 10:25, 27 September 2024
  • **16 points
    4 KB (632 words) - 17:21, 21 December 2024
  • <cmath>=\sqrt{\frac{4a^2b^2-(a^2+b^2-c^2)^2}{16}}</cmath> <cmath>=\sqrt{\frac{(2ab+a^2+b^2-c^2)(2ab-a^2-b^2+c^2)}{16}}</cmath>
    5 KB (783 words) - 17:58, 1 January 2025
  • ([[2008 AMC 12B Problems/Problem 16|Source]]) A rectangular floor measures <math>a</math> by <math>b</math> fee <math>8=ab-4a-4b+16=(a-4)(b-4)</math>
    4 KB (682 words) - 12:13, 8 December 2024
  • ...te competitions held for [[MathCounts]]. The Countdown Round takes the top 16 students and is unofficial, so countdown winners get separate awards. The s
    1 KB (140 words) - 21:41, 28 July 2024
  • * <math>16! = 20922789888000</math> \left\lfloor\frac {100}{49}\right\rfloor=14+2=16</math>
    10 KB (809 words) - 15:40, 17 March 2024
  • ...)=a^2+16a-80=0</math>. The sum of these values of <math>a</math> is <math>-16</math>.
    4 KB (768 words) - 16:56, 24 June 2024
  • unitsize(16); unitsize(16);
    5 KB (804 words) - 02:01, 12 June 2023
  • *([[2018 AMC 10B Problems/Problem 16|2018 AMC 10B]]) Let <math>a_1,a_2,\dots,a_{2018}</math> be a strictly incre
    4 KB (569 words) - 21:34, 30 December 2024
  • <cmath>16[ABCD]^2=4(ab+cd)^2-(a^2+b^2-c^2-d^2)^2</cmath> <cmath>16[ABCD]^2=(2(ab+cd)+(a^2+b^2-c^2-d^2))(2(ab+cd)-(a^2+b^2-c^2-d^2))</cmath>
    3 KB (543 words) - 18:35, 29 October 2024
  • ...6\}</math> we would be trying to calculate <math>\frac 3{\frac 13 + \frac 16 - \frac 12} = \frac 30</math>, which is obviously problematic.
    1 KB (196 words) - 23:49, 5 January 2021
  • * 2003 - Arnav Tripathy (6), Mikhail Lavrov (16), Michael Lin, Vivek Bhattacharya, Coach: Marla McCrea
    4 KB (582 words) - 20:40, 14 May 2024

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