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- == Problem == {{AIME box|year=1983|before=First Question|num-a=2}}4 KB (641 words) - 09:19, 6 January 2025
- == Problem == {{AIME box|year=1983|num-b=1|num-a=3}}1 KB (184 words) - 21:11, 4 February 2025
- == Problem == {{AIME box|year=1983|num-b=2|num-a=4}}3 KB (532 words) - 12:05, 29 November 2024
- ==Problem== {{AIME box|year=1983|num-b=3|num-a=5}}11 KB (1,747 words) - 19:54, 31 December 2024
- == Problem == One way to solve this problem is by [[substitution]]. We have4 KB (672 words) - 09:17, 17 March 2023
- == Problem == {{AIME box|year=1983|num-b=5|num-a=7}}3 KB (361 words) - 19:20, 14 January 2023
- == Problem == We simplify this problem by using complementary counting and fixing one knight in place. Then, eithe9 KB (1,458 words) - 21:34, 2 February 2025
- == Problem == {{AIME box|year=1983|num-b=7|num-a=9}}3 KB (399 words) - 10:53, 30 October 2024
- == Problem == {{AIME box|year=1983|num-b=8|num-a=10}}5 KB (824 words) - 18:34, 20 July 2024
- == Problem == {{AIME box|year=1983|num-b=9|num-a=11}}5 KB (855 words) - 19:26, 14 January 2023
- == Problem == {{AIME box|year=1983|num-b=10|num-a=12}}6 KB (971 words) - 14:35, 27 May 2024
- == Problem == {{AIME box|year=1983|num-b=11|num-a=13}}2 KB (412 words) - 17:23, 1 January 2024
- == Problem == This solution is not a proof and since the AIME does not require proof, it is okay to finsh the answer like this. If you wo6 KB (1,083 words) - 20:10, 10 January 2025
- == Problem == ...hat circle bisects the chord, so <math>QM = MP = PN = NR</math>, since the problem told us <math>QP = PR</math>.14 KB (2,351 words) - 20:06, 8 December 2024
- == Problem == Applied to this problem, this means that <math>D</math> is the only point that lies on both (1) the20 KB (3,497 words) - 14:37, 27 May 2024
Page text matches
- ...ed States at the [[International Mathematics Olympiad]] (IMO). While most AIME participants are high school students, some bright middle school students a High scoring AIME students are invited to take the prestigious [[United States of America Mat5 KB (669 words) - 03:52, 3 February 2025
- * [[American Invitational Mathematics Examination]] (AIME) — high scorers from the AMC 10/12 exams. * [[United States of America Mathematics Olympiad]] (USAMO) — high AIME and AMC scorers.5 KB (696 words) - 02:47, 24 December 2019
- ==Problems== ...ast two digits of <math> 7^{81}-3^{81} </math>. ([[Euler's Totient Theorem Problem 1 Solution|Solution]])4 KB (569 words) - 21:34, 30 December 2024
- ...ke the more challenging [[American Invitational Mathematics Examination]] (AIME). ...nute, multiple choice exam (except in 1973, in which it had 35 questions). Problems generally increased in difficulty as the exam progresses. Calculators were3 KB (390 words) - 11:01, 15 October 2024
- ...in the AoPSWiki, please consider adding them. Also, if you notice that a problem in the Wiki differs from the original wording, feel free to correct it. Fi | 2025 || [[2025 AIME I | AIME I]] || [[2025 AIME II | AIME II]]3 KB (400 words) - 19:21, 13 February 2025
- ...contains the full set of test problems. The rest contain each individual problem and its solution. * [[1984 AIME Problems|Problems]]1 KB (112 words) - 12:46, 13 December 2007
- ...contains the full set of test problems. The rest contain each individual problem and its solution. * [[1983 AIME Problems|Entire Test]]1 KB (114 words) - 19:35, 31 October 2020
- {{AIME Problems|year=1983}} == Problem 1 ==7 KB (1,104 words) - 02:13, 27 May 2024
- {{AIME Problems|year=1984}} == Problem 1 ==6 KB (933 words) - 00:15, 19 June 2022
- == Problem == {{AIME box|year=1983|before=First Question|num-a=2}}4 KB (641 words) - 09:19, 6 January 2025
- == Problem == {{AIME box|year=1983|num-b=1|num-a=3}}1 KB (184 words) - 21:11, 4 February 2025
- == Problem == {{AIME box|year=1983|num-b=2|num-a=4}}3 KB (532 words) - 12:05, 29 November 2024
- ==Problem== {{AIME box|year=1983|num-b=3|num-a=5}}11 KB (1,747 words) - 19:54, 31 December 2024
- == Problem == One way to solve this problem is by [[substitution]]. We have4 KB (672 words) - 09:17, 17 March 2023
- == Problem == {{AIME box|year=1983|num-b=5|num-a=7}}3 KB (361 words) - 19:20, 14 January 2023
- == Problem == We simplify this problem by using complementary counting and fixing one knight in place. Then, eithe9 KB (1,458 words) - 21:34, 2 February 2025
- == Problem == {{AIME box|year=1983|num-b=7|num-a=9}}3 KB (399 words) - 10:53, 30 October 2024
- == Problem == {{AIME box|year=1983|num-b=8|num-a=10}}5 KB (824 words) - 18:34, 20 July 2024
- == Problem == {{AIME box|year=1983|num-b=9|num-a=11}}5 KB (855 words) - 19:26, 14 January 2023
- == Problem == {{AIME box|year=1983|num-b=10|num-a=12}}6 KB (971 words) - 14:35, 27 May 2024