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- ...to take the prestigious [[United States of America Mathematics Olympiad]] (USAMO) for qualification from taking the [[AMC 12]] or [[United States of America ...ministered by the [[Mathematical Association of America]] (MAA). [[Art of Problem Solving]] (AoPS) is a proud sponsor of the AMC.5 KB (669 words) - 17:19, 11 March 2025
- * [[United States of America Mathematics Olympiad]] (USAMO) — high AIME and AMC scorers. The top students on the USAMO are invited to participate in the [[Mathematical Olympiad Summer Program]],5 KB (696 words) - 03:47, 24 December 2019
- Problems from the '''1982 [[United States of America Mathematical Olympiad | USAMO]]'''. ==Problem 1==2 KB (348 words) - 22:36, 19 March 2020
- ==1983 USAMO Problem One==227 bytes (38 words) - 19:19, 13 November 2011
- == Problem == ...chosen on the circle, there are exactly <math>6!</math> ways to label them one through six. Also, this does not affect the probability we wish to calculat2 KB (297 words) - 22:29, 17 July 2016
- == Problem == Obviously, due to the second condition given, they all share at least one point in common.1 KB (225 words) - 18:03, 15 May 2020
- == Problem == ...struct arbitrarily many copies of <math>T</math> by drawing a circle about one of its endpoints through its other endpoint, and then connecting the center5 KB (872 words) - 09:58, 19 July 2016
- == Problem == ...1\leq k\leq \left\lfloor\frac{n+1}{2}\right\rfloor\right\}</math> at most one element from each can be a denominator of a fraction in <math>F_n</math>.1 KB (266 words) - 11:23, 7 December 2022
- ...ementary proof utilizes [[Cauchy Induction]], a variant of induction where one proves a result for <math>2</math>, uses induction to extend this to all po ...<math>a_1+a_2+\cdots +a_n\ge n</math>. ([[Solution to AM - GM Introductory Problem 1|Solution]])5 KB (758 words) - 15:32, 22 February 2024
