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• 1998 AIME Problems/Problem 5
  == Problem == Though the problem may appear to be quite daunting, it is actually not that difficult. <math>\
  1 KB (225 words) - 16:56, 3 February 2025
• 1998 AHSME Problems/Problem 5
  == Problem== If <math>2^{1998}-2^{1997}-2^{1996}+2^{1995} = k \cdot 2^{1995},</math> what is the value of
  878 bytes (110 words) - 14:28, 5 July 2013
• 1998 USAMO Problems/Problem 5
  ==Problem== {{USAMO newbox|year=1998|num-b=4|num-a=6}}
  1 KB (244 words) - 09:44, 20 July 2016
• 1998 AJHSME Problems/Problem 5
  ==Problem== {{AJHSME box|year=1998|num-b=4|num-a=6}}
  1 KB (153 words) - 22:10, 13 January 2023
• 1998 IMO Problems/Problem 5
  ==Problem== {{IMO box|year=1998|num-b=4|num-a=6}}
  1 KB (227 words) - 09:33, 27 July 2024
• 1998 CEMC Gauss (Grade 7) Problems/Problem 5
  == Problem ==
  432 bytes (59 words) - 13:57, 29 January 2021
• 1998 OIM Problems/Problem 5
  == Problem ==
  477 bytes (83 words) - 15:43, 13 December 2023

Page text matches

• MATHCOUNTS
  ...cluding Art of Problem Solving, the focus of MATHCOUNTS is on mathematical problem solving. Students are eligible for up to three years, but cannot compete be ...), 2-2.5 (State/National)<br><u>Target:</u> 1.5 (School), 2 (Chapter), 2-2.5 (State/National)}}
  11 KB (1,517 words) - 14:11, 2 March 2025
• Constructive counting
  This is a problem where constructive counting is not the simplest way to proceed. This next e ...proceed with the construction. If we were to go like before and break the problem down by each box, we'd get a fairly messy solution.
  13 KB (2,018 words) - 15:31, 10 January 2025
• Fibonacci sequence
  ...he sum of the two preceding it. The first few terms are <math>1, 1, 2, 3, 5, 8, 13, 21, 34, 55,...</math>. ...ard, too. Then you get something like <math>\dots -8,5,-3,2,-1,1,0,1,1,2,3,5,8\dots</math> . The ratios between successive terms has you continue backwa
  7 KB (1,111 words) - 14:57, 24 June 2024
• Complex number
  *[[2007 AMC 12A Problems/Problem 18]] *[[1984 AIME Problems/Problem 8|1984 AIME Problem 8]]
  5 KB (860 words) - 15:36, 10 December 2023
• Olimpiada de Mayo/1997
  ...contains the full set of test problems. The rest contain each individual problem and its solution. * [[1997 I Problems/Problem 1|Problem 1]]
  856 bytes (98 words) - 14:53, 3 July 2009
• 1999 AIME
  ...contains the full set of test problems. The rest contain each individual problem and its solution. * [[1999 AIME Problems/Problem 1|Problem 1]]
  1 KB (118 words) - 08:41, 7 September 2011
• 1998 AIME
  ...contains the full set of test problems. The rest contain each individual problem and its solution. * [[1998 AIME Problems]]
  1 KB (114 words) - 08:39, 7 September 2011
• 1997 AIME
  ...contains the full set of test problems. The rest contain each individual problem and its solution. * [[1997 AIME Problems/Problem 1|Problem 1]]
  1 KB (114 words) - 08:39, 7 September 2011
• 1997 AIME Problems
  == Problem 1 == [[1997 AIME Problems/Problem 1|Solution]]
  7 KB (1,098 words) - 17:08, 25 June 2020
• 1998 AIME Problems
  {{AIME Problems|year=1998}} == Problem 1 ==
  7 KB (1,084 words) - 02:01, 28 November 2023
• 1999 AIME Problems
  == Problem 1 == [[1999 AIME Problems/Problem 1|Solution]]
  7 KB (1,094 words) - 13:39, 16 August 2020
• 1998 AIME Problems/Problem 15
  == Problem == ...rdered pairs once. For example, represent (4,7),(7,3),(3,5) as <math>4,7,3,5 .</math> Label the vertices of a regular <math>n</math> -gon <math>1,2,3, \
  9 KB (1,659 words) - 18:35, 20 June 2024
• 1998 AIME Problems/Problem 14
  == Problem == ...9)(3,3)</math>. These give <math>m = 3, n = 11</math> and <math>m = 5, n = 5</math> respectively. Substituting into the numerator, we see that the first
  2 KB (390 words) - 21:05, 29 May 2023
• 1998 AIME Problems/Problem 12
  == Problem == ...<math>x = \frac {\sqrt {5} - 1}{2}</math> and <math>y = \frac {3 - \sqrt {5}}{2}</math>.
  5 KB (884 words) - 14:33, 18 June 2024
• 1998 AIME Problems/Problem 11
  == Problem == ...},</math> and <math>\overline{CD},</math> respectively, so that <math>AP = 5, PB = 15, BQ = 15,</math> and <math>CR = 10.</math> What is the area of th
  7 KB (1,084 words) - 11:48, 13 August 2023
• 1998 AIME Problems/Problem 8
  == Problem == | 0 || 1 || 2 || 3 || 4 || 5 || 6
  2 KB (354 words) - 13:19, 14 December 2024
• 1998 AIME Problems/Problem 7
  == Problem == Note that this is an algebraic bijection, we have simplified the problem and essentially removed the odd condition, so now we can finish with plain
  5 KB (684 words) - 18:52, 19 June 2024
• 1998 AIME Problems/Problem 6
  == Problem == {{AIME box|year=1998|num-b=5|num-a=7}}
  2 KB (254 words) - 19:38, 4 July 2013
• 1998 AIME Problems/Problem 4
  == Problem == ...odd tiles, or two even tiles and an odd tile. Thus, since there are <math>5</math> odd tiles and <math>4</math> even tiles, the only possibility is tha
  5 KB (917 words) - 02:37, 12 December 2022
• 1998 AIME Problems/Problem 2
  == Problem == ...3+3+5+5+7+7 ...., where there will be n terms. Thus, our answer is 1+3+3+5+5.... 29+29+31 = 16*30 = 480.
  6 KB (913 words) - 16:34, 6 August 2020

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