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- ...plicate|[[2000 AMC 12 Problems|2000 AMC 12 #1]] and [[2000 AMC 10 Problems|2000 AMC 10 #1]]}} {{AMC12 box|year=2000|before=First<br />Question|num-a=2}}2 KB (320 words) - 18:37, 30 November 2024
- '''2000 AMC 12''' problems and solutions. The first link contains the full set of test pr *[[2000 AMC 12 Problems]]1 KB (126 words) - 12:28, 20 February 2020
- {{AMC12 Problems|year=2000|ab=}} [[2000 AMC 12 Problems/Problem 1|Solution]]13 KB (1,948 words) - 09:35, 16 June 2024
- ...plicate|[[2000 AMC 12 Problems|2000 AMC 12 #2]] and [[2000 AMC 10 Problems|2000 AMC 10 #2]]}} <math>2000(2000^{2000}) = ?</math>1 KB (171 words) - 20:36, 22 December 2024
- ...plicate|[[2000 AMC 12 Problems|2000 AMC 12 #3]] and [[2000 AMC 10 Problems|2000 AMC 10 #3]]}} {{AMC12 box|year=2000|num-b=2|num-a=4}}1 KB (177 words) - 23:36, 14 July 2024
- ...plicate|[[2000 AMC 12 Problems|2000 AMC 12 #5]] and [[2000 AMC 10 Problems|2000 AMC 10 #9]]}} {{AMC10 box|year=2000|num-b=8|num-a=10}}1 KB (232 words) - 23:20, 5 September 2024
- ...0 AMC 12 Problems|2000 AMC 12 #8]] and [[2000 AMC 10 Problems|2000 AMC 10 #12]]}} ...ecursion from solution 1, we see that the first differences of <math>4, 8, 12, ...</math> form an arithmetic progression, and consequently that the secon8 KB (1,221 words) - 10:34, 27 November 2024
- ...plicate|[[2000 AMC 12 Problems|2000 AMC 12 #6]] and [[2000 AMC 10 Problems|2000 AMC 10 #11]]}} {{AMC10 box|year=2000|num-b=10|num-a=12}}2 KB (244 words) - 01:47, 13 August 2024
- ...plicate|[[2000 AMC 12 Problems|2000 AMC 12 #4]] and [[2000 AMC 10 Problems|2000 AMC 10 #6]]}} {{AMC12 box|year=2000|num-b=3|num-a=5}}1 KB (162 words) - 23:39, 14 July 2024
- ...th> and <math>C</math> be nonnegative integers such that <math>A + M + C = 12</math>. What is the maximum value of <math>A \cdot M \cdot C + A \cdot M + Since <math>A+M+C=12</math>, we can rewrite this as3 KB (586 words) - 23:03, 14 February 2025
- {{AMC12 box|year=2000|num-b=6|num-a=8}}616 bytes (86 words) - 22:49, 29 December 2023
- ...plicate|[[2000 AMC 12 Problems|2000 AMC 12 #9]] and [[2000 AMC 10 Problems|2000 AMC 10 #14]]}} {{AMC12 box|year=2000|num-b=8|num-a=10}}5 KB (713 words) - 22:43, 8 October 2024
- {{AMC12 box|year=2000|num-b=9|num-a=11}}1 KB (173 words) - 07:56, 21 August 2023
- ...licate|[[2000 AMC 12 Problems|2000 AMC 12 #11]] and [[2000 AMC 10 Problems|2000 AMC 10 #15]]}} {{AMC12 box|year=2000|num-b=10|num-a=12}}3 KB (421 words) - 23:54, 14 July 2024
- ...licate|[[2000 AMC 12 Problems|2000 AMC 12 #13]] and [[2000 AMC 10 Problems|2000 AMC 10 #22]]}} {{AMC12 box|year=2000|num-b=12|num-a=14}}6 KB (1,011 words) - 16:30, 6 October 2024
- ...licate|[[2000 AMC 12 Problems|2000 AMC 12 #14]] and [[2000 AMC 10 Problems|2000 AMC 10 #23]]}} {{AMC12 box|year=2000|num-b=13|num-a=15}}2 KB (278 words) - 00:12, 10 November 2024
- ...licate|[[2000 AMC 12 Problems|2000 AMC 12 #15]] and [[2000 AMC 10 Problems|2000 AMC 10 #24]]}} {{AMC12 box|year=2000|num-b=14|num-a=16}}3 KB (422 words) - 23:22, 15 October 2024
- {{AMC12 box|year=2000|num-b=15|num-a=17}}2 KB (310 words) - 10:28, 3 August 2021
- <math>\text {(A)}\ \sec^2 \theta - \tan \theta \qquad \text {(B)}\ \frac 12 \qquad \text {(C)}\ \frac{\cos^2 \theta}{1 + \sin \theta}\qquad \text {(D)} {{AMC12 box|year=2000|num-b=16|num-a=18}}7 KB (1,072 words) - 23:38, 19 August 2024
- ...licate|[[2000 AMC 12 Problems|2000 AMC 12 #18]] and [[2000 AMC 10 Problems|2000 AMC 10 #25]]}} {{AMC12 box|year=2000|num-b=17|num-a=19}}2 KB (409 words) - 06:46, 24 August 2024
Page text matches
- ...ttps://competifyhub.com/resources/ Free Competition Resources for Grades 1-12] ...[https://www.tmasacademy.com/ace-the-amc10-12-free-book ACE The AMC 10 and 12 book]17 KB (2,329 words) - 04:01, 3 February 2025
- * Intermediate is recommended for students who can expect to pass the AMC 10/12. ...es exposure to advanced topics like probability theory.Great for AMC 8 /10/1223 KB (3,038 words) - 18:33, 15 February 2025
- ...the top 2.5% of scorers on the AMC 10 and the top 5% of scorers on the AMC 12 were invited to participate in the AIME. Since 2020, the AIME qualification Awarded to the top 5.00% of scorers on the AMC 8, AMC 10, and AMC 12, respectively.19 KB (2,028 words) - 03:31, 22 February 2025
- ...ion for American Math Contest, used to refer to the AMC 8, AMC 10, and AMC 12. * [[AMC 12]] — for students grades 12 and under.5 KB (696 words) - 02:47, 24 December 2019
- ([[2000 AMC 12/Problem 6|Source]]) <math>(a,b)=(5,12)</math> or <math>(a,b)=(6,8)</math> yielding <math>\Rightarrow\textbf{(B)}<4 KB (682 words) - 09:25, 18 February 2025
- ...rtofproblemsolving.com/Forum/resources.php?c=182&cid=45&year=2000&p=385891 2000 AIME II Problem 7] ...ing.com/wiki/index.php/2015_AIME_I_Problems/Problem_12 2015 AIME I Problem 12]12 KB (1,993 words) - 21:22, 15 January 2025
- ...h><div style="text-align:right">([[2000 AMC 12 Problems/Problem 4|2000 AMC 12, Problem 4]])</div>7 KB (1,111 words) - 13:57, 24 June 2024
- *[[2000 AIME II Problems/Problem 9|2000 AIME II Problem 9]] *[[2002 AIME I Problems/Problem 12|2002 AIME I Problem 12]]5 KB (860 words) - 14:36, 10 December 2023
- ...plicate|[[2000 AMC 12 Problems|2000 AMC 12 #1]] and [[2000 AMC 10 Problems|2000 AMC 10 #1]]}} {{AMC12 box|year=2000|before=First<br />Question|num-a=2}}2 KB (320 words) - 18:37, 30 November 2024
- [[AMC 12]] problems and solutions. | colspan="2"| [[2001 AMC 12 | AMC 12]]2 KB (264 words) - 17:26, 8 November 2024
- ...irst exam in the series of exams used to challenge bright students, grades 12 and below, and after 1973, was used on the path towards choosing the team t The AHSME was replaced with the [[AMC 10]] and [[AMC 12]] in 2000.3 KB (390 words) - 11:01, 15 October 2024
- '''2000 AMC 12''' problems and solutions. The first link contains the full set of test pr *[[2000 AMC 12 Problems]]1 KB (126 words) - 12:28, 20 February 2020
- '''2001 AMC 12''' problems and solutions. The first link contains the full set of test pr *[[2001 AMC 12 Problems]]1 KB (127 words) - 20:36, 6 October 2014
- {{AMC12 Problems|year=2000|ab=}} [[2000 AMC 12 Problems/Problem 1|Solution]]13 KB (1,948 words) - 09:35, 16 June 2024
- ...2\qquad \text{(C)}\ 3S + 6 \qquad\text{(D)} 2S + 6 \qquad \text{(E)}\ 2S + 12</math> [[2001 AMC 12 Problems/Problem 1|Solution]]13 KB (1,957 words) - 11:53, 24 January 2024
- ...m {A}) 3\qquad (\mathrm {B}) 6 \qquad (\mathrm {C}) 9 \qquad (\mathrm {D}) 12 \qquad (\mathrm {E}) 15</math> ...B}) 9 \qquad (\mathrm {C}) 10 \qquad (\mathrm {D}) 11 \qquad (\mathrm {E}) 12</math>13 KB (2,049 words) - 12:03, 19 February 2020
- Erm, this is very similar to 2000 AMC 12 Q20 ackthually {{AIME box|year=2000|n=I|num-b=6|num-a=8}}5 KB (766 words) - 23:46, 8 November 2024
- ...ate Tournament, achieve one of the top 10 scores in the state on the [[AMC 12]], or achieve one of the top 10 scores in the state on the [[AIME]], receiv ...owa ever since. The MN Gold team has finished in the top ten in Division A 12 times, winning the national championship in 1997. The MN Maroon team has f4 KB (680 words) - 15:45, 10 June 2015
- ...plicate|[[2000 AMC 12 Problems|2000 AMC 12 #2]] and [[2000 AMC 10 Problems|2000 AMC 10 #2]]}} <math>2000(2000^{2000}) = ?</math>1 KB (171 words) - 20:36, 22 December 2024
- ...plicate|[[2000 AMC 12 Problems|2000 AMC 12 #3]] and [[2000 AMC 10 Problems|2000 AMC 10 #3]]}} {{AMC12 box|year=2000|num-b=2|num-a=4}}1 KB (177 words) - 23:36, 14 July 2024