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- ...eamnyc.weebly.com/mathcounts.html List of all MathCounts competitions from 2000 to 2017]. [{{SERVER}}/wiki/index.php/AHSME_Problems_and_Solutions AHSME (Old AMC 12) Problems in the AoPS Wiki]14 KB (1,907 words) - 18:41, 2 March 2025
- In 2000, the AHSME was split into the AMC 10 and 12, reduced to only 25 questions, and 2 years5 KB (696 words) - 02:47, 24 December 2019
- The '''American High School Mathematics Examination''' ('''AHSME''') was the first exam in the series of exams used to challenge bright stud High scoring AHSME students after 1983 were invited to take the more challenging [[American In3 KB (390 words) - 11:01, 15 October 2024
- '''2000 AMC 12''' problems and solutions. The first link contains the full set of *[[2000 AMC 12 Problems]]1 KB (126 words) - 12:28, 20 February 2020
- {{AMC12 box|year=2001|before=[[2000 AMC 12]]|after=[[2002 AMC 12A]],[[2002 AMC 12B|B]]}} * [[AHSME Problems and Solutions]]1 KB (127 words) - 20:36, 6 October 2014
- {{AHSME Problems|year=1999}} [[1999 AHSME Problems/Problem 1|Solution]]13 KB (1,945 words) - 20:04, 2 February 2025
- \qquad\mathrm{(E)}\ 2000</math> <cmath>f(1998 + 0) = 1998 + f(0) = 2000 \Rightarrow \mathrm{(E)}</cmath>656 bytes (94 words) - 21:16, 28 March 2024
- '''1999 AHSME''' problems and solutions. The first link contains the full set of test pr * [[1999 AHSME Problems|Entire Exam]]2 KB (178 words) - 12:28, 20 February 2020
- {{AHSME Problems [[1998 AHSME Problems/Problem 1|Solution]]15 KB (2,222 words) - 09:40, 11 August 2020
- '''2000 AMC 10''' problems and solutions. The first link contains the full set of t * [[2000 AMC 10 Problems]]1 KB (125 words) - 13:27, 20 February 2020
- Since all answers are over <math>2000</math>, work backwards and find the cost of the first <math>1999</math> loc ...igits, or <math>2</math> more four digit lockers. These lockers are <math>2000</math> and <math>2001</math>, leading to answer <math> \boxed{\textbf{(A)}}1 KB (197 words) - 06:19, 25 August 2024
- ...2}=\frac{1000^2}{(252-248)(252+248)}=\frac{1000^2}{(4)(500)}=\frac{1000^2}{2000} </math>. {{AHSME box|year=1984|before=First Problem|num-a=2}}685 bytes (80 words) - 11:48, 5 July 2013
- How many years in the millenium between 1000 and 2000 have properties (a) and (b)? ...number, we are looking at palindromes between <math>1100</math> and <math>2000</math>, which also means that the last digit of the three-digit number is <1 KB (195 words) - 11:38, 13 December 2016
- [[1952 AHSME Problems/Problem 1|Solution]] [[1952 AHSME Problems/Problem 2|Solution]]23 KB (3,556 words) - 14:35, 30 December 2023
- {{AHSME Problems|year = 1991}} [[1991 AHSME Problems/Problem 1|Solution]]16 KB (2,451 words) - 03:27, 6 September 2021
- ...gain of }\textdollar 1000 \qquad \textbf{(D) \ }\text{gain of }\textdollar 2000 \qquad \textbf{(E) \ }\text{none of these} </math> {{AHSME 50p box|year=1952|num-b=13|num-a=15}}1 KB (173 words) - 19:09, 19 December 2017
- ...im-olimpiyatlari/icerik-biyoloji ''Biology Olympiad Problems Archive since 2000''] ...mpiyatlari/icerik-bilgisayar ''Informatics Olympiad Problems Archive since 2000'']15 KB (1,864 words) - 17:59, 15 February 2025
- ...ssion]], so <math>(20+x)(100+x) = (50+x)^2</math>. Expanding, we get <math>2000 + 120x + x^2 = 2500 + 100x + x^2</math>; therefore, <math>20x = 500</math>, {{AHSME 50p box|year=1959|num-b=11|num-a=13}}939 bytes (125 words) - 11:25, 21 July 2024
- We can see that <math>A</math> gained <math>\textdollar{2000}</math> out of Mr. <math>B</math>'s expense, but none of the options says t {{AHSME 50p box|year=1955|num-b=25|num-a=27}}1 KB (227 words) - 12:01, 18 November 2020
- - 2000 - 2005: Reconstruction of Newton's Principia Mathematica Gmaasis. (In Engli 371. Gmaas has taken the AHSME/AMC 10, AIME, USAJMO, USAMO, and IMO all the years it has come out. It is r89 KB (15,007 words) - 14:02, 19 February 2025
