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AMC historical results
 This is the '''AMC historical results''' page. This page should include results for the [[AIME

21 KB (2,347 words) - 19:56, 4 March 2025
2001 AMC 12 Problems/Problem 2
...te|[[2001 AMC 12 Problems|2001 AMC 12 #2]] and [[2001 AMC 10 Problems|2001 AMC 10 #6]]}} ...N</math>, respectively. Then <math>N = 10a+b</math>. It follows that <math>10a+b=ab+a+b</math>, which implies that <math>9a=ab</math>. Since <math>a\neq0<

1,007 bytes (165 words) - 19:31, 27 October 2024
AMC 10 Problems and Solutions
| 2024 || [[2024 AMC 10A | AMC 10A]] || [[2024 AMC 10B | AMC 10B]] | 2023 || [[2023 AMC 10A | AMC 10A]] || [[2023 AMC 10B | AMC 10B]]

2 KB (245 words) - 20:02, 2 March 2025
2007 AMC 12A Problems/Problem 22
...roblems|2007 AMC 12A #22]] and [[2007 AMC 10A Problems/Problem 25|2007 AMC 10A #25]]}} ...(D)}</math> solutions, which are <math>1977, 1980, 1983, </math> and <math>2001</math>.

15 KB (2,558 words) - 22:08, 28 July 2024
Mass points
* [[2019 AMC 8 Problems/Problem 24]] * [[2016 AMC 10A Problems/Problem 19]]

5 KB (812 words) - 14:43, 1 March 2025
2002 AMC 10A
'''2002 AMC 10A''' problems and solutions. The first link contains the full set of test pro * [[2002 AMC 10A Problems]]

1 KB (169 words) - 18:05, 26 November 2019
2002 AMC 10A Problems
The ratio <math>\frac{10^{2000}+10^{2002}}{10^{2001}+10^{2001}}</math> is closest to which of the following numbers? [[2002 AMC 10A Problems/Problem 1|Solution]]

12 KB (1,813 words) - 20:39, 19 July 2024
2002 AMC 10B Problems
The ratio <math>\frac{2^{2001}\cdot3^{2003}}{6^{2002}}</math> is: [[2002 AMC 10B Problems/Problem 1|Solution]]

10 KB (1,539 words) - 12:34, 23 July 2024
2002 AMC 10B
'''2002 AMC 10B''' problems and solutions. The first link contains the full set of test * [[2002 AMC 10B Problems]]

1 KB (157 words) - 23:51, 2 February 2015
2004 AMC 10B Problems
[[2004 AMC 10B Problems/Problem 1|Solution]] [[2004 AMC 10B Problems/Problem 2|Solution]]

14 KB (2,137 words) - 14:29, 9 June 2024
2001 AMC 10 Problems
{{AMC10 Problems|year=2001|ab=}} [[2001 AMC 10 Problems/Problem 1|Solution]]

14 KB (1,983 words) - 15:25, 2 June 2022
2001 AMC 10
'''2001 AMC 10''' problems and solutions. The first link contains the full set of test * [[2001 AMC 10 Problems]]

2 KB (153 words) - 17:59, 6 October 2014
Ball-and-urn
*[[2001 AMC 10 Problems/Problem 19]] *[[2003 AMC 10A Problems/Problem 21]]

5 KB (795 words) - 16:39, 31 December 2024
2001 AMC 10 Problems/Problem 6
...te|[[2001 AMC 12 Problems|2001 AMC 12 #2]] and [[2001 AMC 10 Problems|2001 AMC 10 #6]]}} ...N</math>, respectively. Then <math>N = 10a+b</math>. It follows that <math>10a+b=ab+a+b</math>, which implies that <math>9a=ab</math>. Since <math>a\neq0<

1 KB (183 words) - 15:12, 15 July 2024
2018 AMC 10A Problems
[[2018 AMC 10A Problems/Problem 1|Solution]] [[2018 AMC 10A Problems/Problem 2|Solution]]

14 KB (2,173 words) - 00:47, 9 October 2024
Daniel Zhou's Profile
...post on AOPS solutions to various problems including IMO, USA(J)MO, AIME, AMC, ARML, HMMT, PUMaC, CMiMC, and mock contests. # [https://artofproblemsolving.com/community/u530868h17462p31321520 2001 IMO Problem 1]

7 KB (808 words) - 23:26, 3 February 2025
2002 AMC 12P Problems
[[2002 AMC 12P Problems/Problem 1|Solution]] [[2002 AMC 12P Problems/Problem 2|Solution]]

11 KB (1,641 words) - 03:03, 14 July 2024
2002 AMC 10P
The AMC 10P was a mock created by Titu Andreescu and Dick Gibbs of the AMC staff, and was given in Taiwan on January 5, 2002 to 30,000 students. '''2002 AMC 10P''' problems and solutions. The first link contains the full set of tes

2 KB (187 words) - 09:10, 14 August 2024
2002 AMC 10P Problems
[[2002 AMC 10P Problems/Problem 1|Solution]] [[2002 AMC 10P Problems/Problem 2|Solution]]

10 KB (1,535 words) - 17:44, 20 October 2024

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