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• 2001 AMC 12 Problems/Problem 2
  ...te|[[2001 AMC 12 Problems|2001 AMC 12 #2]] and [[2001 AMC 10 Problems|2001 AMC 10 #6]]}} ...N</math>, respectively. Then <math>N = 10a+b</math>. It follows that <math>10a+b=ab+a+b</math>, which implies that <math>9a=ab</math>. Since <math>a\neq0<
  1,007 bytes (165 words) - 19:31, 27 October 2024
• 2007 AMC 12A Problems/Problem 22
  ...roblems|2007 AMC 12A #22]] and [[2007 AMC 10A Problems/Problem 25|2007 AMC 10A #25]]}} ...(D)}</math> solutions, which are <math>1977, 1980, 1983, </math> and <math>2001</math>.
  15 KB (2,558 words) - 22:08, 28 July 2024
• Mass points
  ...eorems concerning [[polygon]]s, and is helpful in solving complex geometry problems involving lengths. In essence, it involves using a local [[coordinate syst ...school students made it popular. The technique greatly simplifies certain problems.
  5 KB (812 words) - 14:43, 1 March 2025
• 2002 AMC 10A
  ...0A''' problems and solutions. The first link contains the full set of test problems. The second link contains the answers to each problem. The rest contain eac * [[2002 AMC 10A Problems]]
  1 KB (169 words) - 18:05, 26 November 2019
• 2002 AMC 10A Problems
  {{AMC10 Problems|year=2002|ab=A}} The ratio <math>\frac{10^{2000}+10^{2002}}{10^{2001}+10^{2001}}</math> is closest to which of the following numbers?
  12 KB (1,813 words) - 20:39, 19 July 2024
• 2002 AMC 10B Problems
  {{AMC10 Problems|year=2002|ab=B}} The ratio <math>\frac{2^{2001}\cdot3^{2003}}{6^{2002}}</math> is:
  10 KB (1,539 words) - 12:34, 23 July 2024
• 2002 AMC 10B
  ...0B''' problems and solutions. The first link contains the full set of test problems. The rest contain each individual problem and its solution. * [[2002 AMC 10B Problems]]
  1 KB (157 words) - 23:51, 2 February 2015
• 2004 AMC 10B Problems
  {{AMC10 Problems|year=2004|ab=B}} [[2004 AMC 10B Problems/Problem 1|Solution]]
  14 KB (2,137 words) - 14:29, 9 June 2024
• 2001 AMC 10 Problems
  {{AMC10 Problems|year=2001|ab=}} [[2001 AMC 10 Problems/Problem 1|Solution]]
  14 KB (1,983 words) - 15:25, 2 June 2022
• 2001 AMC 10
  ...10''' problems and solutions. The first link contains the full set of test problems. The rest contain each individual problem and its solution. * [[2001 AMC 10 Problems]]
  2 KB (153 words) - 17:59, 6 October 2014
• Ball-and-urn
  It is used to solve problems of the form: how many ways can one distribute <math>k</math> indistinguisha == Problems ==
  5 KB (795 words) - 16:39, 31 December 2024
• 2001 AMC 10 Problems/Problem 6
  ...te|[[2001 AMC 12 Problems|2001 AMC 12 #2]] and [[2001 AMC 10 Problems|2001 AMC 10 #6]]}} ...N</math>, respectively. Then <math>N = 10a+b</math>. It follows that <math>10a+b=ab+a+b</math>, which implies that <math>9a=ab</math>. Since <math>a\neq0<
  1 KB (183 words) - 15:12, 15 July 2024
• 2018 AMC 10A Problems
  {{AMC10 Problems|year=2018|ab=A}} [[2018 AMC 10A Problems/Problem 1|Solution]]
  14 KB (2,173 words) - 00:47, 9 October 2024
• Daniel Zhou's Profile
  ...post on AOPS solutions to various problems including IMO, USA(J)MO, AIME, AMC, ARML, HMMT, PUMaC, CMiMC, and mock contests. # [https://artofproblemsolving.com/community/u530868h17462p31321520 2001 IMO Problem 1]
  7 KB (808 words) - 23:26, 3 February 2025
• 2002 AMC 12P Problems
  {{AMC12 Problems|year=2002|ab=P}} [[2002 AMC 12P Problems/Problem 1|Solution]]
  11 KB (1,641 words) - 03:03, 14 July 2024
• 2002 AMC 10P
  The AMC 10P was a mock created by Titu Andreescu and Dick Gibbs of the AMC staff, and was given in Taiwan on January 5, 2002 to 30,000 students. ...P''' problems and solutions. The first link contains the full set of test problems. The rest contain each individual problem and its solution.
  2 KB (187 words) - 09:10, 14 August 2024
• 2002 AMC 10P Problems
  {{AMC10 Problems|year=2002|ab=P}} [[2002 AMC 10P Problems/Problem 1|Solution]]
  10 KB (1,535 words) - 17:44, 20 October 2024