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Create the page "2004 AIME II Problem 3" on this wiki! See also the search results found.
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- == Problem == ...s close together as possible, which occurs when the smaller block is <math>3 \times 7 \times 11</math>. Then the extra layer makes the entire block <ma2 KB (377 words) - 11:53, 10 March 2014
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- ..., then adding together the totals of each part. Casework is a very general problem-solving approach, and as such has wide applicability. '''Solution''': We divide the problem into cases, based on how long the word is.5 KB (709 words) - 17:40, 24 September 2024
- ...hat the imaginary part of a complex number is real: for example, <math>\Im(3 + 4i) = 4</math>. So, if <math>z\in \mathbb C</math>, we can write <math>z *[[2007 AMC 12A Problems/Problem 18]]5 KB (860 words) - 15:36, 10 December 2023
- ...contains the full set of test problems. The rest contain each individual problem and its solution. * [[2004 AIME I Problems]]1 KB (135 words) - 18:15, 19 April 2021
- ...contains the full set of test problems. The rest contain each individual problem and its solution. * [[2004 AIME II Problems]]1 KB (135 words) - 12:24, 22 March 2011
- ...contains the full set of test problems. The rest contain each individual problem and its solution. * [[2005 AIME I Problems]]1 KB (154 words) - 12:30, 22 March 2011
- {{AIME Problems|year=2005|n=I}} == Problem 1 ==6 KB (983 words) - 05:06, 20 February 2019
- {{AIME Problems|year=2004|n=I}} == Problem 1 ==9 KB (1,434 words) - 13:34, 29 December 2021
- == Problem == Number the squares <math>0, 1, 2, 3, ... 2^{k} - 1</math>. In this case <math>k = 10</math>, but we will consi6 KB (899 words) - 20:58, 12 May 2022
- == Problem == ...<math>b</math>). Then <math>11b + 111c \le 855 + 2b + 3c \le 855 + 2(11) + 3(7) = 898 < 1000</math>, so these values work.11 KB (1,857 words) - 12:57, 18 July 2024
- == Problem == ...B \parallel CE, BC \parallel AD, AC \parallel DE, \angle ABC=120^\circ, AB=3, BC=5, </math> and <math>DE = 15. </math> Given that the [[ratio]] between3 KB (486 words) - 22:15, 7 April 2023
- == Problem == ..., BC=5=DA, </math>and <math> CD=4. </math> Draw [[circle]]s of [[radius]] 3 centered at <math> A </math> and <math> B, </math> and circles of radius 23 KB (431 words) - 23:21, 4 July 2013
- == Problem == ...h>. Setting <math>\theta R=C\implies 800\theta=1200\pi\implies\theta=\frac{3\pi}{2}</math>.2 KB (268 words) - 22:20, 23 March 2023
- == Problem == ...ith the binary string 0001001000 <math>y</math> is 6 and <math>x</math> is 3 (note that it is zero indexed).8 KB (1,283 words) - 19:19, 8 May 2024
- == Problem == From <cmath>a_9 + a_{10} = f(4)^2 + f(4)f(5) = (4x-3)(9x-7) = 646 = 2\cdot 17 \cdot 19</cmath>, we find that by either the [[qua3 KB (535 words) - 22:25, 5 March 2025
- == Problem == ...tive integer divisors of <math>2004^{2004}</math> are divisible by exactly 2004 positive integers?2 KB (359 words) - 19:58, 24 December 2024
- == Problem == ...math> CD. </math> The dimensions <math> AE=8, BE=17, </math> and <math> CF=3 </math> are given. The perimeter of rectangle <math> ABCD </math> is <math>9 KB (1,500 words) - 20:06, 8 October 2024
- == Problem == ...d third monkeys have at the end of the process are in the [[ratio]] <math> 3: 2: 1, </math>what is the least possible total for the number of bananas?6 KB (950 words) - 14:18, 15 January 2024
- ==Problem== ...0}{800}(60)=\frac{150}{8}</math>. The train then has <math>60-15-\frac{50}{3}-\frac{150}{8}=230/24</math> minutes left to travel 250 miles, and doing th4 KB (592 words) - 19:02, 26 September 2020
- == Problem == ...ath>n</math>-digit number, for a total of <math>(2^1 - 2) + (2^2 - 2) + (2^3 -2) + (2^4 - 2) = 22</math> such numbers (or we can list them: <math>AB, BA3 KB (508 words) - 01:16, 19 January 2024
- == Problem == ...s close together as possible, which occurs when the smaller block is <math>3 \times 7 \times 11</math>. Then the extra layer makes the entire block <ma2 KB (377 words) - 11:53, 10 March 2014
