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  • == Problem == ...</math> is [[odd integer | odd]] and <math> a_i>a_{i+1} </math> if <math> i </math> is [[even integer | even]]. How many snakelike integers between 100
    3 KB (562 words) - 18:12, 4 March 2022

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  • An example of a classic problem is as follows: ...hem twice. A number that is divisible by both 2 and 3 must be divisible by 6, and there are 16 such numbers. Thus, there are <math>50+33-16=\boxed{67}</
    4 KB (635 words) - 12:19, 2 January 2022
  • This is a problem where constructive counting is not the simplest way to proceed. This next e ...wer is <math>8 \cdot 7 \cdot 7 \cdot 7 \cdot 7 \cdot 7 \cdot 7 = 8 \cdot 7^6 = 941,192</math>, as desired. <math>\square</math>
    13 KB (2,018 words) - 15:31, 10 January 2025
  • ...iv style="text-align:right">([[2000 AMC 12 Problems/Problem 4|2000 AMC 12, Problem 4]])</div> ...a triangle. <div style="text-align:right">(Manhattan Mathematical Olympiad 2004)</div>
    7 KB (1,111 words) - 14:57, 24 June 2024
  • ...contains the full set of test problems. The rest contain each individual problem and its solution. * [[2004 AIME I Problems]]
    1 KB (135 words) - 18:15, 19 April 2021
  • ...contains the full set of test problems. The rest contain each individual problem and its solution. * [[2004 AIME II Problems]]
    1 KB (135 words) - 12:24, 22 March 2011
  • ...contains the full set of test problems. The rest contain each individual problem and its solution. * [[2005 AIME I Problems]]
    1 KB (154 words) - 12:30, 22 March 2011
  • ...A number of '''Mock AMC''' competitions have been hosted on the [[Art of Problem Solving]] message boards. They are generally made by one community member ...amous theorems and formulas and see if there's any way you can make a good problem out of them.
    51 KB (6,175 words) - 21:41, 27 November 2024
  • {{AIME Problems|year=2005|n=I}} == Problem 1 ==
    6 KB (983 words) - 05:06, 20 February 2019
  • == Problem == ...ath>(501,4)</math>, <math>(668,3)</math>, <math>(1002,2)</math> and <math>(2004,1)</math>, and each of these gives a possible value of <math>k</math>. Thus
    2 KB (303 words) - 01:31, 5 December 2022
  • == Problem == We approach the problem by [[recursion]]. We [[partition]] the positive integers into the sets
    9 KB (1,491 words) - 01:23, 26 December 2022
  • == Problem == real x = 20 - ((750)^.5)/3, CE = 8*(6^.5) - 4*(5^.5), CD = 8*(6^.5), h = 4*CE/CD;
    4 KB (729 words) - 01:00, 27 November 2022
  • == Problem == ...<math>34</math> complex roots of the form <math> z_k = r_k[\cos(2\pi a_k)+i\sin(2\pi a_k)], k=1, 2, 3,\ldots, 34, </math> with <math> 0 < a_1 \le a_2 \
    2 KB (298 words) - 20:02, 4 July 2013
  • == Problem == ...left(\frac{\frac{4}{5}}{1-\frac{1}{25}}\right)= \frac{2}{3} \cdot \frac{5}{6} = \frac{5}{9},</cmath> and the answer is <math>m+n = 5 + 9 = \boxed{014}</
    2 KB (303 words) - 18:43, 16 October 2024
  • == Problem == ...th>r_{ABC} = \frac{[ABC]}{s_{ABC}} = \frac{15 \cdot 36 /2}{(15+36+39)/2} = 6</math>. Thus <math>r_{A'B'C'} = r_{ABC} - 1 = 5</math>, and since the ratio
    5 KB (836 words) - 07:53, 15 October 2023
  • == Problem == ...th> be a [[triangle]] with sides 3, 4, and 5, and <math> DEFG </math> be a 6-by-7 [[rectangle]]. A segment is drawn to divide triangle <math> ABC </math
    4 KB (647 words) - 17:43, 23 November 2024
  • == Problem == ...n + 1) + n = 3210 + 1111n</math>, for <math>n \in \lbrace0, 1, 2, 3, 4, 5, 6\rbrace</math>.
    2 KB (250 words) - 23:56, 2 December 2024
  • == Problem == ...ath> consecutive integers that sum to <math>2m</math>, the middle integer (i.e., the median) must be <math>2</math>. Therefore, the largest element in
    8 KB (1,431 words) - 17:50, 29 December 2024
  • == Problem == Alpha and Beta both took part in a two-day problem-solving competition. At the end of the second day, each had attempted quest
    3 KB (436 words) - 18:31, 9 January 2024
  • == Problem == ...um of the product of each pair of distinct terms, or <math>C = \sum_{1 \le i \neq j}^{15} S_iS_j</math>. Also, we know that
    7 KB (1,099 words) - 13:41, 30 December 2024
  • == Problem == There are no regular 3-pointed, 4-pointed, or 6-pointed stars. All regular 5-pointed stars are similar, but there are two n
    4 KB (620 words) - 21:26, 5 June 2021

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