Search results

  • ...h> 3 </math> in <math> 1, 2, \cdots, 2006 </math> are <math> 3, 6, \cdots, 2004 </math>, and dividing all of these by <math> 3 </math> we get <math> 1, 2, [[2006 SMT/Algebra Problems]]
    1 KB (214 words) - 07:01, 28 May 2012
  • '''2004 [[Stanford Mathematics Tournament|SMT]]''' problems and solutions by category. *[[2004 SMT/Advanced Topics|Advanced Topics]]
    406 bytes (44 words) - 12:52, 21 January 2020