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Create the page "2005 AIME I Problem 9" on this wiki! See also the search results found.
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- == Problem == [[Image:2005_I_AIME-9.png]]4 KB (600 words) - 21:44, 20 November 2023
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- ...d only once. In particular, memorizing a formula for PIE is a bad idea for problem solving. ==== Problem ====9 KB (1,703 words) - 01:20, 7 December 2024
- ...e multiply the possibilities for each digit to arrive at our answer: <math>9 \cdot 10 \cdot 10 \cdot 10 = 9000</math>. <math>\square</math> This is a problem where constructive counting is not the simplest way to proceed. This next e13 KB (2,018 words) - 15:31, 10 January 2025
- D(P--P-(9/5,4)); ...latively prime integers, find <math> p+q. </math> ([[2005 AIME II Problems/Problem 15|Source]])5 KB (892 words) - 21:52, 1 May 2021
- ...ver, it is possible to define a number, <math> i </math>, such that <math> i = \sqrt{-1} </math>. If we add this new number to the reals, we will have ...rm <math> a + bi </math> where <math> a,b\in \mathbb{R} </math> and <math> i = \sqrt{-1} </math> is the [[imaginary unit]]. The set of complex numbers i5 KB (860 words) - 15:36, 10 December 2023
- * [[2005_AMC_10A_Problems/Problem_17 | 2005 AMC 10A Problem 17]] * [[2006_AMC_10A_Problems/Problem_19 | 2006 AMC 10A Problem 19]]4 KB (736 words) - 02:00, 7 March 2024
- ...> intersect at <math>R</math>. If <math>AR:BR=1:4</math> and <math>CR:DR=4:9</math>, find the ratio <math>AB:CD</math> . ...rline{MC}</math> that lies outside of the circle. ([[2020 AMC 12B Problems/Problem 10|Source]])5 KB (948 words) - 17:04, 21 February 2025
- ...contains the full set of test problems. The rest contain each individual problem and its solution. * [[2004 AIME II Problems]]1 KB (135 words) - 12:24, 22 March 2011
- ...contains the full set of test problems. The rest contain each individual problem and its solution. * [[2005 AIME I Problems]]1 KB (154 words) - 12:30, 22 March 2011
- ...contains the full set of test problems. The rest contain each individual problem and its solution. * [[2006 AIME I Problems]]1 KB (135 words) - 12:31, 22 March 2011
- ...contains the full set of test problems. The rest contain each individual problem and its solution. * [[2005 AIME II Problems]]1 KB (135 words) - 12:30, 22 March 2011
- {{AIME Problems|year=2006|n=I}} == Problem 1 ==7 KB (1,173 words) - 03:31, 4 January 2023
- == Problem == Suppose <math>b_{i} = \frac {x_{i}}3</math>.8 KB (1,334 words) - 17:37, 15 December 2024
- ...S'</math> and <math>S''</math> are equal if they include the same objects, i.e., if for every object <math>x</math>, we have <math>x\in S'</math> if and ...describe sets should be used with extreme caution. One way to avoid this problem is as follows: given a property <math>P</math>, choose a known set <math>T<11 KB (2,019 words) - 17:20, 7 July 2024
- {{AIME Problems|year=2005|n=II}} == Problem 1 ==7 KB (1,119 words) - 21:12, 28 February 2020
- == Problem == ...9), C=(9,0), D=(0,0), E=(2.5-0.5*sqrt(7),9), F=(6.5-0.5*sqrt(7),9), G=(4.5,9), O=(4.5,4.5); draw(A--B--C--D--A);draw(E--O--F);draw(G--O); dot(A^^B^^C^^D13 KB (2,080 words) - 13:14, 23 July 2024
- {{AIME Problems|year=2005|n=I}} == Problem 1 ==6 KB (983 words) - 05:06, 20 February 2019
- == Problem == <math>n^2 + 7n = (n + 1)^2 + 5n - 1 = (n + 2)^2 + 3n - 4 = (n + 3)^2 + n - 9</math>8 KB (1,249 words) - 21:25, 20 November 2024
- == Problem == There are two separate parts to this problem: one is the color (gold vs silver), and the other is the orientation.5 KB (830 words) - 01:51, 1 March 2023
- == Problem == ...erefore <math>AB=AP+PQ+BQ=5+\sqrt{141}-1+5=9+\sqrt{141} \rightarrow (p,q)=(9,141) \rightarrow \boxed{150}</math>.4 KB (567 words) - 20:20, 3 March 2020
- == Problem == {{AIME box|year=2005|n=I|num-b=7|num-a=9}}1 KB (161 words) - 17:46, 17 September 2024
