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• 2005 AIME II Problems/Problem 10
  == Problem == {{AIME box|year=2005|n=II|num-b=9|num-a=11}}
  3 KB (436 words) - 20:35, 13 August 2024
• 2005 AIME I Problems/Problem 10
  == Problem == {{AIME box|year=2005|n=I|num-b=9|num-a=11}}
  5 KB (852 words) - 21:23, 4 October 2023
• Mock AIME 3 Pre 2005 Problems/Problem 10
  ==Problem== {{Mock AIME box|year=Pre 2005|n=3|num-b=9|num-a=11}}
  2 KB (306 words) - 10:36, 4 April 2012
• Mock AIME 1 Pre 2005 Problems/Problem 10
  == Problem == {{Mock AIME box|year=Pre 2005|n=1|num-b=9|num-a=11|source=14769}}
  540 bytes (96 words) - 00:28, 23 December 2023
• Mock AIME 5 2005-2006 Problems/Problem 10
  == Problem == ...t <math>{2n \choose n}</math> is divisible by all the primes between <math>10</math> and <math>30</math>.
  328 bytes (45 words) - 14:15, 11 April 2018

Page text matches

• Simon's Favorite Factoring Trick
  ...nd make the equation factorable. It can be used to solve more than algebra problems, sometimes going into other topics such as number theory. == Fun Practice Problems ==
  4 KB (682 words) - 10:25, 18 February 2025
• Principle of Inclusion-Exclusion
  ...d only once. In particular, memorizing a formula for PIE is a bad idea for problem solving. ==== Problem ====
  9 KB (1,703 words) - 01:20, 7 December 2024
• Constructive counting
  ...es for each digit to arrive at our answer: <math>9 \cdot 10 \cdot 10 \cdot 10 = 9000</math>. <math>\square</math> This is a problem where constructive counting is not the simplest way to proceed. This next e
  13 KB (2,018 words) - 15:31, 10 January 2025
• Complex number
  == Problems == *[[2007 AMC 12A Problems/Problem 18]]
  5 KB (860 words) - 15:36, 10 December 2023
• Without loss of generality
  ...0, AMC 12, and AIME competitions it is very common to use WLOG in geometry problems by assuming one undefined side length to be equal to 1. == Problems using WLOG ==
  2 KB (318 words) - 23:35, 13 September 2024
• Arithmetic sequence
  == Problems == Here are some problems with solutions that utilize arithmetic sequences and series.
  4 KB (736 words) - 02:00, 7 March 2024
• Diophantine equation
  ...s for any given Diophantine equations. This is known as [[Hilbert's tenth problem]]. The answer, however, is no. == Problems ==
  9 KB (1,434 words) - 01:15, 4 July 2024
• Power of a Point Theorem
  == Problems == ...}</math> that lies outside of the circle. ([[2020 AMC 12B Problems/Problem 10|Source]])
  5 KB (948 words) - 17:04, 21 February 2025
• 2004 AIME II
  ...contains the full set of test problems. The rest contain each individual problem and its solution. * [[2004 AIME II Problems]]
  1 KB (135 words) - 12:24, 22 March 2011
• 2005 AIME I
  ...contains the full set of test problems. The rest contain each individual problem and its solution. * [[2005 AIME I Problems]]
  1 KB (154 words) - 12:30, 22 March 2011
• 2006 AIME I
  ...contains the full set of test problems. The rest contain each individual problem and its solution. * [[2006 AIME I Problems]]
  1 KB (135 words) - 12:31, 22 March 2011
• 2005 AIME II
  ...contains the full set of test problems. The rest contain each individual problem and its solution. * [[2005 AIME II Problems]]
  1 KB (135 words) - 12:30, 22 March 2011
• Mock AMC
  ...ake. Sometimes, the administrator may ask other people to sign up to write problems for the contest. * Look at past [[AMC]]/[[AHSME]] tests to get a feel for what kind of problems you should write and what difficulty level they should be.
  51 KB (6,175 words) - 21:41, 27 November 2024
• 2006 AIME I Problems
  {{AIME Problems|year=2006|n=I}} == Problem 1 ==
  7 KB (1,173 words) - 03:31, 4 January 2023
• Set
  ...describe sets should be used with extreme caution. One way to avoid this problem is as follows: given a property <math>P</math>, choose a known set <math>T< ==Problems==
  11 KB (2,019 words) - 17:20, 7 July 2024
• 2005 AIME II Problems/Problem 1
  == Problem == ...o <math>9^3=729</math>, we try 8, 9, and 10, which works, so <math>n - 3 = 10</math> and <math>n = \boxed{13}</math>.
  1 KB (239 words) - 11:54, 31 July 2023
• 2005 AIME II Problems/Problem 3
  == Problem == .... A new series, obtained by squaring each term of the original series, has 10 times the sum of the original series. The common [[ratio]] of the original
  3 KB (581 words) - 21:19, 22 September 2024
• 2005 AIME II Problems/Problem 4
  == Problem == ...r of [[positive integer]]s that are divisors of at least one of <math> 10^{10},15^7,18^{11}. </math>
  3 KB (377 words) - 18:36, 1 January 2024
• 2005 AIME II Problems/Problem 13
  == Problem == ...ath> be a polynomial with integer coefficients that satisfies <math> P(17)=10 </math> and <math> P(24)=17. </math> Given that <math> P(n)=n+3 </math> has
  4 KB (642 words) - 02:14, 1 June 2024
• 2005 AIME II Problems
  {{AIME Problems|year=2005|n=II}} == Problem 1 ==
  7 KB (1,119 words) - 21:12, 28 February 2020

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