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• 2005 AIME II Problems/Problem 11
  == Problem == ...</math>, <math>a_{m-1}a_{m-2} = 3</math>; from the recursion given in the problem <math>a_{m-p+1} = a_{m-p-1} - 3/a_{m-p}</math>, so <math>a_{m-p+1} = 3p/a_{
  3 KB (499 words) - 18:52, 21 November 2022
• 2005 AIME I Problems/Problem 11
  == Problem == [[Image:2005 AIME I Problem 11.png]]
  4 KB (707 words) - 11:11, 16 September 2021
• Mock AIME 3 Pre 2005 Problems/Problem 11
  ==Problem== {{Mock AIME box|year=Pre 2005|n=3|num-b=10|num-a=12}}
  2 KB (379 words) - 01:27, 6 December 2024
• Mock AIME 1 Pre 2005 Problems/Problem 11
  == Problem == {{Mock AIME box|year=Pre 2005|n=1|num-b=10|num-a=12|source=14769}}
  2 KB (272 words) - 10:51, 2 July 2015
• Mock AIME 5 2005-2006 Problems/Problem 11
  == Problem == ...xist an <math>A</math> such that <math>|A| = 620</math> and <math>\mu(A) = 11</math>? (<math>|X|</math> denotes the cardinality of the set <math>X</math>
  786 bytes (131 words) - 21:19, 8 October 2014
• Mock AIME 2 Pre 2005 Problems/Problem 11
  {{Mock AIME box|year=Pre 2005|n=2|num-b=10|num-a=12}} [[Category:Trigonometry Problems]]
  1 KB (192 words) - 18:03, 13 September 2020

Page text matches

• Ellipse
  ==Problems== ...latively prime integers, find <math> p+q. </math> ([[2005 AIME II Problems/Problem 15|Source]])
  5 KB (892 words) - 21:52, 1 May 2021
• Complex number
  == Problems == *[[2007 AMC 12A Problems/Problem 18]]
  5 KB (860 words) - 15:36, 10 December 2023
• 2004 AIME II
  ...contains the full set of test problems. The rest contain each individual problem and its solution. * [[2004 AIME II Problems]]
  1 KB (135 words) - 12:24, 22 March 2011
• 2005 AIME I
  ...contains the full set of test problems. The rest contain each individual problem and its solution. * [[2005 AIME I Problems]]
  1 KB (154 words) - 12:30, 22 March 2011
• 2006 AIME I
  ...contains the full set of test problems. The rest contain each individual problem and its solution. * [[2006 AIME I Problems]]
  1 KB (135 words) - 12:31, 22 March 2011
• 2005 AIME II
  ...contains the full set of test problems. The rest contain each individual problem and its solution. * [[2005 AIME II Problems]]
  1 KB (135 words) - 12:30, 22 March 2011
• Mock AMC
  ...ake. Sometimes, the administrator may ask other people to sign up to write problems for the contest. * Look at past [[AMC]]/[[AHSME]] tests to get a feel for what kind of problems you should write and what difficulty level they should be.
  51 KB (6,175 words) - 21:41, 27 November 2024
• 2006 AIME I Problems
  {{AIME Problems|year=2006|n=I}} == Problem 1 ==
  7 KB (1,173 words) - 03:31, 4 January 2023
• Set
  ...describe sets should be used with extreme caution. One way to avoid this problem is as follows: given a property <math>P</math>, choose a known set <math>T< ==Problems==
  11 KB (2,019 words) - 17:20, 7 July 2024
• 2005 AIME II Problems/Problem 4
  == Problem == ...ve integer]]s that are divisors of at least one of <math> 10^{10},15^7,18^{11}. </math>
  3 KB (377 words) - 18:36, 1 January 2024
• 2005 AIME II Problems/Problem 5
  == Problem == ...og_a b + 6\log_b a=5, 2 \leq a \leq 2005, </math> and <math> 2 \leq b \leq 2005. </math>
  3 KB (547 words) - 19:15, 4 April 2024
• 2005 AIME II Problems
  {{AIME Problems|year=2005|n=II}} == Problem 1 ==
  7 KB (1,119 words) - 21:12, 28 February 2020
• 2005 AIME II Problems/Problem 7
  == Problem == ...4}+y^{12}+y^{10}+y^8+y^6+y^4+y^2+1)(y+1) = (y^{15}+y^{14}+y^{13}+y^{12}+y^{11}+y^{10}+y^9+y^8+y^7+y^6+y^5+y^4+y^3+y^2+y+1)=\frac{y^{16}-1}{y-1}</cmath>
  2 KB (279 words) - 12:33, 27 October 2019
• 2005 AIME II Problems/Problem 12
  == Problem == ...^2</math> equal and solving for <math>x</math> (it is helpful to scale the problem down by a factor of 50 first), we get <math>x = 250\pm 50\sqrt{7}</math>. S
  13 KB (2,080 words) - 13:14, 23 July 2024
• 2005 AIME II Problems/Problem 10
  == Problem == {{AIME box|year=2005|n=II|num-b=9|num-a=11}}
  3 KB (436 words) - 20:35, 13 August 2024
• 2005 AIME I Problems
  {{AIME Problems|year=2005|n=I}} == Problem 1 ==
  6 KB (983 words) - 05:06, 20 February 2019
• 2005 AIME I Problems/Problem 3
  == Problem == ...s less than <math>50</math>. There are fifteen of these (<math>2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43</math> and <math>47</math>) so there ar
  2 KB (249 words) - 09:37, 23 January 2024
• 2005 AIME I Problems/Problem 4
  == Problem == ...th>. When <math>n = 28</math>, this product is <math>980</math>, and since AIME answers are nonnegative integers less than <math>1000</math>, we don't have
  8 KB (1,249 words) - 21:25, 20 November 2024
• 2005 AIME I Problems/Problem 10
  == Problem == ...<math>= -197 - p + 11q</math>. Thus, <math>q = \frac{1}{11}p + \frac{337}{11}</math>.
  5 KB (852 words) - 21:23, 4 October 2023
• 2005 AIME I Problems/Problem 12
  == Problem == ...let <math> b </math> denote the number of positive integers <math> n \leq 2005 </math> with <math> S(n) </math> [[even integer | even]]. Find <math> |a-b|
  4 KB (647 words) - 02:29, 4 May 2021

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