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- == Problem == [[Image:2005_I_AIME-14.png|center]]3 KB (561 words) - 14:11, 18 February 2018
- == Problem == In [[triangle]] <math> ABC, AB=13, BC=15, </math> and <math>CA = 14. </math> Point <math> D </math> is on <math> \overline{BC} </math> with <ma14 KB (2,340 words) - 16:38, 21 August 2024
- ==Problem== {{Mock AIME box|year=Pre 2005|n=3|num-b=13|num-a=15}}3 KB (563 words) - 02:05, 25 November 2023
- == Problem == Note: The problem is meant to be interpreted so that if you cannot produce one arrangement fr692 bytes (107 words) - 13:01, 24 November 2021
- == Problem == {{Mock AIME box|year=2005-2006|n=5|source=76847|num-b=13|num-a=15}}2 KB (282 words) - 10:06, 9 August 2022
- ==Problem==4 KB (690 words) - 14:32, 6 January 2021
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- This is a problem where constructive counting is not the simplest way to proceed. This next e ...proceed with the construction. If we were to go like before and break the problem down by each box, we'd get a fairly messy solution.13 KB (2,018 words) - 15:31, 10 January 2025
- ==Problems== *The ellipse with axis lengths <math>14</math> and <math>16</math> has the general equation of <math>\frac{x^2}{a^25 KB (892 words) - 21:52, 1 May 2021
- == Problems == *[[2007 AMC 12A Problems/Problem 18]]5 KB (860 words) - 15:36, 10 December 2023
- ...c sequence with common difference <math>-8</math>; however, <math>7, 0, 7, 14</math> and <math>4, 12, 36, 108, \ldots</math> are not arithmetic sequences == Problems ==4 KB (736 words) - 02:00, 7 March 2024
- ...contains the full set of test problems. The rest contain each individual problem and its solution. * [[2004 AIME II Problems]]1 KB (135 words) - 12:24, 22 March 2011
- ...contains the full set of test problems. The rest contain each individual problem and its solution. * [[2005 AIME I Problems]]1 KB (154 words) - 12:30, 22 March 2011
- ...contains the full set of test problems. The rest contain each individual problem and its solution. * [[2006 AIME I Problems]]1 KB (135 words) - 12:31, 22 March 2011
- ...contains the full set of test problems. The rest contain each individual problem and its solution. * [[2005 AIME II Problems]]1 KB (135 words) - 12:30, 22 March 2011
- {{AIME Problems|year=2006|n=I}} == Problem 1 ==7 KB (1,173 words) - 03:31, 4 January 2023
- == Problem == ...olutions so <math>P(x)</math> is at least quadratic. Let us first try this problem out as if <math>P(x)</math> is a quadratic polynomial. Thus <math>P(n)-(n+34 KB (642 words) - 02:14, 1 June 2024
- {{AIME Problems|year=2005|n=II}} == Problem 1 ==7 KB (1,119 words) - 21:12, 28 February 2020
- == Problem == <cmath>(y^{12}+y^8+y^4+1)(y^2+1)=(y^{14}+y^{12}+y^{10}+y^8+y^6+y^4+y^2+1)</cmath>2 KB (279 words) - 12:33, 27 October 2019
- == Problem == path cir1 = CR(C1,4.01), cir2 = CR(C2,10), cir3 = CR(C3,14), t = H--T+2*(T-H);4 KB (693 words) - 13:03, 28 December 2021
- {{AIME Problems|year=2005|n=I}} == Problem 1 ==6 KB (983 words) - 05:06, 20 February 2019
- == Problem == ...leq 14</math>. In fact, when <math>n = 14</math> we have <math>n(n + 7) = 14\cdot 21 = 294 = 17^2 + 5</math>, so this number works and no larger number8 KB (1,249 words) - 21:25, 20 November 2024
- == Problem == ...act one triangle from another), and each such calculation gives an area of 14. This is <math>\frac{1}{5}</math> of our needed area, so we simply need th5 KB (852 words) - 21:23, 4 October 2023
- == Problem == ...assign to <math>(0,1,0)</math>. (We will see how this correlates with the problem.) Then define for each lattice point <math>(i,j)</math> its triplet thus:5 KB (897 words) - 00:21, 29 July 2022
- == Problem == [[Image:2005_I_AIME-14.png|center]]3 KB (561 words) - 14:11, 18 February 2018
- == Problem == ...t 18 \cdot 8 \cdot 2} = 24\sqrt{14}</math> and so the answer is <math>24 + 14 = \boxed{038}</math>.5 KB (906 words) - 23:15, 6 January 2024
- == Problem == ...0)--(0,-10),Arrows(4));D((15,0)--(-25,0),Arrows(4));D((0,0)--MP("y=ax",(14,14 * (69/100)^.5),E),EndArrow(4));12 KB (2,001 words) - 20:26, 23 July 2024