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- == Problem == {{USAMO newbox|year=2006|num-b=2|num-a=4}}9 KB (1,699 words) - 13:48, 11 April 2020
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- ...e Spring Semester to determine the team each year. The 6 practices include 3 individual tests to help determine the team and some lectures on certain ma *Past [[AMC]], [[AIME]], and [[USAMO]] scores22 KB (3,532 words) - 11:25, 27 September 2024
- ...rks for <math>n=1+1=2</math>, which in turn means it works for <math>n=2+1=3</math>, and so on. ...e. If a problem asks you to prove something for all integers greater than 3, you can use <math>n=4</math> as your base case instead. You might have to5 KB (768 words) - 00:59, 29 September 2024
- ...A number of '''Mock AMC''' competitions have been hosted on the [[Art of Problem Solving]] message boards. They are generally made by one community member ...amous theorems and formulas and see if there's any way you can make a good problem out of them.51 KB (6,175 words) - 21:41, 27 November 2024
- ...k contains the full set of test problems. The rest contain each individual problem and its solution. *[[2006 USAMO Problems]]467 bytes (51 words) - 09:25, 6 August 2014
- === Problem 1 === [[2006 USAMO Problems/Problem 1 | Solution]]3 KB (520 words) - 09:24, 14 May 2021
- == Problem == & = 2k^3 + 3k^2 + 3k2 KB (398 words) - 09:48, 5 August 2014
- == Problem == ...1}{2}>n\Longrightarrow n<9</math>. Thus, we need to check for <math>n=1,2,3,5,7</math>. One is included because it is neither prime nor composite.3 KB (486 words) - 22:43, 5 August 2014
- == Problem == ==Solution 3==5 KB (986 words) - 22:46, 18 May 2015
- ...k contains the full set of test problems. The rest contain each individual problem and its solution. *[[2005 USAMO Problems]]548 bytes (59 words) - 18:13, 17 September 2012
- == Problem 1 == [[2005 USAMO Problems/Problem 1 | Solution]]4 KB (609 words) - 09:24, 14 May 2021
- ...k contains the full set of test problems. The rest contain each individual problem and its solution. *[[2007 USAMO Problems]]471 bytes (52 words) - 20:59, 6 August 2014
- ===Problem 1=== ...ce, when <math>n=9</math> the obtained sequence is <math>9, 1, 2, 0, 3, 3, 3, \ldots</math>. Prove that for any <math>n</math> the sequence <math>a_1,3 KB (539 words) - 13:42, 4 July 2013
- == Problem == <div style="text-align:center;">[[Image:2007 USAMO-4.PNG|350px]]</div>10 KB (1,871 words) - 18:44, 24 February 2025
- # [https://artofproblemsolving.com/community/u530868h596930p27818958 2014 IMO Problem 1] ...ttps://artofproblemsolving.com/community/u530868h1181533p28126160 2013 IMO Problem 4]7 KB (808 words) - 00:26, 4 February 2025
- ...87, building 6758997, room 499. The Great Lecture Hall is located in area 3, Gmaas code 34. Gmaas gives lectures there once in a while, so be sure to c - 2006: Debate on whether to rename Gmaathamatics Gmaasology or Gmaas Studies. Gma89 KB (15,007 words) - 15:02, 19 February 2025