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- == Problem == {{USAMO newbox|year=2006|num-b=5|after=Last Question}}5 KB (986 words) - 22:46, 18 May 2015
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- ...tices held during the Spring Semester to determine the team each year. The 6 practices include 3 individual tests to help determine the team and some le *Past [[AMC]], [[AIME]], and [[USAMO]] scores22 KB (3,532 words) - 11:25, 27 September 2024
- Other, odder inductions are possible. If a problem asks you to prove something for all integers greater than 3, you can use <m ...p://www.artofproblemsolving.com/Forum/viewtopic.php?p=490682#p490682 USAMO 2006/5].5 KB (768 words) - 00:59, 29 September 2024
- ...A number of '''Mock AMC''' competitions have been hosted on the [[Art of Problem Solving]] message boards. They are generally made by one community member ...amous theorems and formulas and see if there's any way you can make a good problem out of them.51 KB (6,175 words) - 21:41, 27 November 2024
- ...k contains the full set of test problems. The rest contain each individual problem and its solution. *[[2006 USAMO Problems]]467 bytes (51 words) - 09:25, 6 August 2014
- === Problem 1 === [[2006 USAMO Problems/Problem 1 | Solution]]3 KB (520 words) - 09:24, 14 May 2021
- == Problem == {{USAMO newbox|year=2006|num-b=4|num-a=6}}7 KB (1,280 words) - 17:23, 26 March 2016
- == Problem == ...owing three numbers. <math>a_1=\frac{9}{2}, a_2=\frac{4}{3}, a_3=\frac{7}{6}</math> shows that <math>n=7</math> is possible.3 KB (486 words) - 22:43, 5 August 2014
- ...k contains the full set of test problems. The rest contain each individual problem and its solution. *[[2005 USAMO Problems]]548 bytes (59 words) - 18:13, 17 September 2012
- == Problem 1 == [[2005 USAMO Problems/Problem 1 | Solution]]4 KB (609 words) - 09:24, 14 May 2021
- ...k contains the full set of test problems. The rest contain each individual problem and its solution. *[[2007 USAMO Problems]]471 bytes (52 words) - 20:59, 6 August 2014
- ===Problem 1=== [[2007 USAMO Problems/Problem 1 | Solution]]3 KB (539 words) - 13:42, 4 July 2013
- == Problem == '''Lemma 1.''' The problem statement holds for <math>k=2</math>.3 KB (704 words) - 14:42, 7 September 2021
- - 2006: Debate on whether to rename Gmaathamatics Gmaasology or Gmaas Studies. Gma 1. GMAAS's theorem states that for any math problem, GMAAS knows the answer to it. This theorem was proved by GMAAS. But then G89 KB (15,007 words) - 15:02, 19 February 2025