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  • ...>. Therefore, we have <math> \sum_{k=10}^{2006}\binom{k}{10}=\boxed{\binom{2007}{11}} </math>. [[2006 SMT/Advanced Topics Problems]]
    434 bytes (58 words) - 19:20, 27 May 2012
  • '''2007 [[Stanford Mathematics Tournament|SMT]]''' problems and solutions by category. *[[2007 SMT/Advanced Topics|Advanced Topics]]
    406 bytes (44 words) - 12:53, 21 January 2020