Create the page "200 AIME II Problems/Problem 1" on this wiki! See also the search results found.

• Ellipse
  size(200); MC(90,"\mbox{semiminor axis}",7,D((0,0)--(0,3),green+linewidth(1)),E);
  5 KB (892 words) - 21:52, 1 May 2021
• Diophantine equation
  ...there will always be an infinite number of solutions when <math>\gcd(a,b)=1</math>. If <math>\gcd(a,b)\nmid c</math>, then there are no solutions to t .../math> is an [[odd]] number, then <math>m, \frac {m^2 -1}{2}, \frac {m^2 + 1}{2}</math> is a Pythagorean triple.
  9 KB (1,434 words) - 01:15, 4 July 2024
• 2005 AIME II Problems/Problem 8
  == Problem == size(200);
  4 KB (693 words) - 13:03, 28 December 2021
• 2005 AIME II Problems/Problem 12
  == Problem == === Solution 1 (trigonometry) ===
  13 KB (2,080 words) - 13:14, 23 July 2024
• 2004 AIME I Problems
  {{AIME Problems|year=2004|n=I}} == Problem 1 ==
  9 KB (1,434 words) - 13:34, 29 December 2021
• 2004 AIME II Problems/Problem 7
  == Problem == size(200);
  9 KB (1,500 words) - 20:06, 8 October 2024
• 2004 AIME II Problems
  {{AIME Problems|year=2004|n=II}} == Problem 1 ==
  9 KB (1,410 words) - 05:05, 20 February 2019
• 2002 AIME II Problems
  {{AIME Problems|year=2002|n=II}} == Problem 1 ==
  7 KB (1,177 words) - 15:42, 11 August 2023
• 2003 AIME II Problems/Problem 14
  == Problem == == Solution 1==
  9 KB (1,472 words) - 15:24, 29 December 2024
• 2003 AIME II Problems/Problem 12
  == Problem == ...e, the exact percentage of votes the candidate got was smaller by at least 1 than the number of votes for that candidate. What was the smallest possibl
  4 KB (759 words) - 13:00, 11 December 2022
• 2002 AIME II Problems/Problem 7
  == Problem == <center><math>1^2+2^2+3^2+\ldots+k^{2}=\frac{k(k+1)(2k+1)}6</math>.</center>
  3 KB (403 words) - 12:10, 9 September 2023
• 2002 AIME II Problems/Problem 4
  == Problem == Patio blocks that are hexagons <math>1</math> unit on a side are used to outline a garden by placing the blocks ed
  2 KB (268 words) - 07:28, 13 September 2020
• 2000 AIME II Problems/Problem 13
  == Problem == We may factor the equation as:{{ref|1}}
  7 KB (1,098 words) - 00:33, 21 January 2025
• 2000 AIME II Problems/Problem 8
  == Problem == === Solution 1 ===
  4 KB (589 words) - 15:33, 20 January 2025
• 2007 AIME II Problems/Problem 2
  == Problem == ...ast condition reduces to <math>a(1 + x + y) = 100</math>. Therefore, <math>1 + x + y</math> is equal to one of the 9 factors of <math>100 = 2^25^2</math
  1 KB (228 words) - 08:41, 4 November 2022
• 2007 AIME II Problems
  {{AIME Problems|year=2007|n=II}} == Problem 1 ==
  9 KB (1,435 words) - 01:45, 6 December 2021
• 2006 AIME II Problems/Problem 3
  == Problem == ...s 195\cdot 197\cdot 199=\frac{1\cdot 2\cdots200}{2\cdot4\cdots200} = \frac{200!}{2^{100}\cdot 100!}</math>
  4 KB (562 words) - 18:37, 30 October 2020
• 2008 AIME I Problems
  {{AIME Problems|year=2008|n=I}} == Problem 1 ==
  9 KB (1,536 words) - 00:46, 26 August 2023
• 2008 AIME II Problems/Problem 11
  == Problem == size(200);
  6 KB (1,092 words) - 22:22, 18 August 2024
• 2011 AIME II Problems/Problem 5
  ==Problem== ...of the first <math>2011</math> terms of a [[geometric sequence]] is <math>200</math>. The sum of the first <math>4022</math> terms is <math>380</math>. F
  3 KB (441 words) - 21:32, 20 January 2024

View (previous 20 | next 20) (20 | 50 | 100 | 250 | 500)