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• Diophantine equation
  ...s for any given Diophantine equations. This is known as [[Hilbert's tenth problem]]. The answer, however, is no. ...ally proven by [[Andrew Wiles]] after he spent over 7 years working on the 200-page proof, and another year fixing an error in the original proof.
  9 KB (1,434 words) - 01:15, 4 July 2024
• 2005 AIME II Problems/Problem 8
  == Problem == ...</math> The radii of <math> C_1 </math> and <math> C_2 </math> are 4 and 10, respectively, and the [[center]]s of the three circles are all [[collinear
  4 KB (693 words) - 13:03, 28 December 2021
• 2005 AIME II Problems/Problem 12
  == Problem == size(200);
  13 KB (2,080 words) - 13:14, 23 July 2024
• 2004 AIME I Problems
  {{AIME Problems|year=2004|n=I}} == Problem 1 ==
  9 KB (1,434 words) - 13:34, 29 December 2021
• 2004 AIME II Problems/Problem 11
  == Problem == ...ne]] has a [[base]] with [[radius]] <math>600</math> and [[height]] <math> 200\sqrt{7}. </math> A fly starts at a point on the surface of the cone whose d
  2 KB (268 words) - 22:20, 23 March 2023
• 2004 AIME II Problems/Problem 7
  == Problem == size(200);
  9 KB (1,500 words) - 20:06, 8 October 2024
• 2004 AIME II Problems
  {{AIME Problems|year=2004|n=II}} == Problem 1 ==
  9 KB (1,410 words) - 05:05, 20 February 2019
• 2002 AIME II Problems
  {{AIME Problems|year=2002|n=II}} == Problem 1 ==
  7 KB (1,177 words) - 15:42, 11 August 2023
• 2003 AIME II Problems/Problem 14
  == Problem == ...dinates of its vertices are distinct elements of the set <math>\{0,2,4,6,8,10\}.</math> The area of the hexagon can be written in the form <math>m\sqrt {
  9 KB (1,472 words) - 15:24, 29 December 2024
• 2002 AIME II Problems/Problem 7
  == Problem == ...math> such that <math>1^2+2^2+3^2+\ldots+k^2</math> is a multiple of <math>200</math>.
  3 KB (403 words) - 12:10, 9 September 2023
• 2000 AIME II Problems/Problem 13
  == Problem == ...sqrt{161}}{40}</math>, and so the final answer is <math>-1+161+40 = \boxed{200}</math>.
  7 KB (1,098 words) - 00:33, 21 January 2025
• 2000 AIME II Problems/Problem 8
  == Problem == ...\sqrt{11}\right)^2 = 1001 \Longrightarrow x^4 - 11x^2 - 11^2 \cdot 9 \cdot 10 = 0</cmath>
  4 KB (589 words) - 15:33, 20 January 2025
• 2007 AIME II Problems
  {{AIME Problems|year=2007|n=II}} == Problem 1 ==
  9 KB (1,435 words) - 01:45, 6 December 2021
• 2008 AIME I Problems
  {{AIME Problems|year=2008|n=I}} == Problem 1 ==
  9 KB (1,536 words) - 00:46, 26 August 2023
• 2008 AIME II Problems/Problem 11
  == Problem == size(200);
  6 KB (1,092 words) - 22:22, 18 August 2024
• 2011 AIME II Problems/Problem 5
  ==Problem== ...of the first <math>2011</math> terms of a [[geometric sequence]] is <math>200</math>. The sum of the first <math>4022</math> terms is <math>380</math>. F
  3 KB (441 words) - 21:32, 20 January 2024
• 2011 AIME II Problems
  {{AIME Problems|year=2011|n=II}} == Problem 1 ==
  8 KB (1,301 words) - 08:43, 11 October 2020
• 2015 AIME I Problems
  {{AIME Problems|year=2015|n=I}} ==Problem 1==
  10 KB (1,615 words) - 17:03, 9 October 2024
• 2013 AIME I Problems
  {{AIME Problems|year=2013|n=I}} == Problem 1 ==
  9 KB (1,580 words) - 13:07, 24 February 2024
• 2013 AIME II Problems/Problem 13
  ==Problem 13== ...implest, we see that <math>[ABC]=3\sqrt{7}</math>, so your answer is <math>10</math>.
  13 KB (2,145 words) - 19:20, 11 August 2024

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