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- size(200); size(200);5 KB (892 words) - 21:52, 1 May 2021
- {{AIME Problems|year=2004|n=I}} == Problem 1 ==9 KB (1,434 words) - 13:34, 29 December 2021
- == Problem == size(200);9 KB (1,500 words) - 20:06, 8 October 2024
- {{AIME Problems|year=2004|n=II}} == Problem 1 ==9 KB (1,410 words) - 05:05, 20 February 2019
- {{AIME Problems|year=2002|n=II}} == Problem 1 ==7 KB (1,177 words) - 15:42, 11 August 2023
- == Problem == ...other cases yield non-convex and/or degenerate hexagons, which violate the problem statement.9 KB (1,472 words) - 15:24, 29 December 2024
- == Problem == ...math> such that <math>1^2+2^2+3^2+\ldots+k^2</math> is a multiple of <math>200</math>.3 KB (403 words) - 12:10, 9 September 2023
- {{AIME Problems|year=2007|n=II}} == Problem 1 ==9 KB (1,435 words) - 01:45, 6 December 2021
- == Problem == ...s 195\cdot 197\cdot 199=\frac{1\cdot 2\cdots200}{2\cdot4\cdots200} = \frac{200!}{2^{100}\cdot 100!}</math>4 KB (562 words) - 18:37, 30 October 2020
- {{AIME Problems|year=2008|n=I}} == Problem 1 ==9 KB (1,536 words) - 00:46, 26 August 2023
- {{AIME Problems|year=2011|n=II}} == Problem 1 ==8 KB (1,301 words) - 08:43, 11 October 2020
- {{AIME Problems|year=2015|n=I}} ==Problem 1==10 KB (1,615 words) - 17:03, 9 October 2024
- {{AIME Problems|year=2013|n=I}} == Problem 1 ==9 KB (1,580 words) - 13:07, 24 February 2024
- {{AIME Problems|year=2014|n=I}} ==Problem 1==9 KB (1,472 words) - 13:59, 30 November 2021
- {{AIME Problems|year=2017|n=I}} ==Problem 1==7 KB (1,163 words) - 16:43, 2 June 2022
- ==Problem== ...iangle ABC</math> is <math>100\sqrt 3</math> and the circumradius is <math>200 \sqrt 3</math>. Now, consider the line perpendicular to plane <math>ABC</ma17 KB (2,861 words) - 19:39, 25 November 2024
- ...into anything. Using that fact, you can use the Games theorem to solve any problem. 15. Gmaas won an infinite amount of games against AlphaGo and Gary Kasparov wh69 KB (11,805 words) - 20:49, 18 December 2019
- ==Problem== <asy> size(200); import olympiad; defaultpen(linewidth(1)+fontsize(12));10 KB (1,660 words) - 21:26, 1 December 2024
- ==Problem== ...\triangle ABC</math> are segments of lengths <math>55,45</math>, and <math>15</math>, respectively. Find the perimeter of the triangle whose sides lie on7 KB (1,053 words) - 14:58, 14 January 2024
- ==Problem== ...ath>Y</math>. Suppose <math>XP=10</math>, <math>PQ=25</math>, and <math>QY=15</math>. The value of <math>AB\cdot AC</math> can be written in the form <ma7 KB (1,129 words) - 16:27, 6 January 2025