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• Ellipse
  size(200); D((-5,0)--(0,0)--(0,-3));
  5 KB (892 words) - 21:52, 1 May 2021
• Diophantine equation
  ...</math>. Thus, all fourth powers are either <math>0</math> or <math>1 \mod 5</math>. ...\equiv 0\mod 5, y_0^4 \equiv 1\mod 5</math>, so <math>z_0^2 \equiv 1\mod 5</math>.
  9 KB (1,434 words) - 01:15, 4 July 2024
• 2005 AIME II Problems/Problem 12
  == Problem == size(200);
  13 KB (2,080 words) - 13:14, 23 July 2024
• 2004 AIME I Problems
  {{AIME Problems|year=2004|n=I}} == Problem 1 ==
  9 KB (1,434 words) - 13:34, 29 December 2021
• 2004 AIME II Problems/Problem 7
  == Problem == size(200);
  9 KB (1,500 words) - 20:06, 8 October 2024
• 2004 AIME II Problems
  {{AIME Problems|year=2004|n=II}} == Problem 1 ==
  9 KB (1,410 words) - 05:05, 20 February 2019
• 2002 AIME II Problems
  {{AIME Problems|year=2002|n=II}} == Problem 1 ==
  7 KB (1,177 words) - 15:42, 11 August 2023
• 2003 AIME II Problems/Problem 14
  == Problem == ...other cases yield non-convex and/or degenerate hexagons, which violate the problem statement.
  9 KB (1,472 words) - 15:24, 29 December 2024
• 2003 AIME II Problems/Problem 12
  == Problem == ...f votes they received is <math>\frac{100v_i}s</math>. The condition in the problem statement says that <math>\forall i: \frac{100v_i}s + 1 \leq v_i</math>. (
  4 KB (759 words) - 13:00, 11 December 2022
• 2002 AIME II Problems/Problem 7
  == Problem == ...math> such that <math>1^2+2^2+3^2+\ldots+k^2</math> is a multiple of <math>200</math>.
  3 KB (403 words) - 12:10, 9 September 2023
• 2002 AIME II Problems/Problem 4
  == Problem == ...e. The diagram indicates the path of blocks around the garden when <math>n=5</math>.
  2 KB (268 words) - 07:28, 13 September 2020
• 2000 AIME II Problems/Problem 13
  == Problem == The [[equation]] <math>2000x^6+100x^5+10x^3+x-2=0</math> has exactly two real roots, one of which is <math>\frac{
  7 KB (1,098 words) - 00:33, 21 January 2025
• 2000 AIME II Problems/Problem 8
  == Problem == size(200); pathpen = linewidth(0.7);
  4 KB (589 words) - 15:33, 20 January 2025
• 2007 AIME II Problems/Problem 2
  == Problem == ...ath>. Thus, there are <math>0 + 0 + 2 + 3 + 8 + 18 + 23 + 48 + 98 = \boxed{200}</math> solutions of <math>(a,b,c)</math>.
  1 KB (228 words) - 08:41, 4 November 2022
• 2007 AIME II Problems
  {{AIME Problems|year=2007|n=II}} == Problem 1 ==
  9 KB (1,435 words) - 01:45, 6 December 2021
• 2006 AIME II Problems/Problem 3
  == Problem == ...s 195\cdot 197\cdot 199=\frac{1\cdot 2\cdots200}{2\cdot4\cdots200} = \frac{200!}{2^{100}\cdot 100!}</math>
  4 KB (562 words) - 18:37, 30 October 2020
• 2008 AIME I Problems
  {{AIME Problems|year=2008|n=I}} == Problem 1 ==
  9 KB (1,536 words) - 00:46, 26 August 2023
• 2008 AIME II Problems/Problem 11
  == Problem == size(200);
  6 KB (1,092 words) - 22:22, 18 August 2024
• 2011 AIME II Problems
  {{AIME Problems|year=2011|n=II}} == Problem 1 ==
  8 KB (1,301 words) - 08:43, 11 October 2020
• 2015 AIME I Problems
  {{AIME Problems|year=2015|n=I}} ==Problem 1==
  10 KB (1,615 words) - 17:03, 9 October 2024

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