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- ==Problem== ==Solution 1==3 KB (433 words) - 07:57, 9 February 2023
- ==Problem== This means that the area is <math>A=\tfrac{1}{2}(9)(\tfrac{12}{5})=\tfrac{54}{5}</math>. This gets us <math>54+5=\boxed{9 KB (1,508 words) - 14:02, 7 September 2024
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- ...ake. Sometimes, the administrator may ask other people to sign up to write problems for the contest. * Look at past [[AMC]]/[[AHSME]] tests to get a feel for what kind of problems you should write and what difficulty level they should be.51 KB (6,175 words) - 21:41, 27 November 2024
- ==Problem== ..., 20</math>. Bela then randomly chooses a number <math>B</math> from <math>1, 2, 3,\ldots, 19, 20</math> distinct from <math>J</math>. The value of <mat5 KB (831 words) - 18:47, 29 January 2025
- ...istered to the AoPS community, while others may be sourced from a group of problem writers. Different users may have a different way of participating; some ma ...ms from one subject. Having a group is also good so they can discuss which problems are good or need improvement, and fix errors. More than one person working26 KB (3,260 words) - 19:28, 15 August 2024
- ...n McNugget Theorem''' (or '''Postage Stamp Problem''' or '''Frobenius Coin Problem''') states that for any two [[relatively prime]] [[positive integer]]s <mat ...nsequence of the theorem is that there are exactly <math>\frac{(m - 1)(n - 1)}{2}</math> positive integers which cannot be expressed in the form <math>a17 KB (2,823 words) - 23:06, 15 November 2024
- ...eorems concerning [[polygon]]s, and is helpful in solving complex geometry problems involving lengths. In essence, it involves using a local [[coordinate syst ...school students made it popular. The technique greatly simplifies certain problems.5 KB (812 words) - 15:43, 1 March 2025
- ...ath>3</math> bins. The number of ways to do such is <math>{4+3-1 \choose 3-1} = {6 \choose 2} = 15</math>. ...ath>n</math> bins is <math>{n+k-1 \choose n-1}</math> or <math>\dbinom{n+k-1}k</math>.5 KB (795 words) - 17:39, 31 December 2024
- -1. GMAAS looks like this when he is mad: https://cdn.artofproblemsolving.com/ ...into anything. Using that fact, you can use the Games theorem to solve any problem.69 KB (11,805 words) - 20:49, 18 December 2019
- ...k contains the full set of test problems. The rest contain each individual problem and its solution. * [[2018 AIME II Problems|Entire Test]]1 KB (133 words) - 18:13, 18 March 2020
- ...k contains the full set of test problems. The rest contain each individual problem and its solution. * [[2019 AIME I Problems|Entire Test]]1 KB (133 words) - 17:41, 29 March 2019
- ...k contains the full set of test problems. The rest contain each individual problem and its solution. * [[2019 AIME II Problems|Entire Test]]1 KB (133 words) - 15:43, 22 March 2019
- ...k contains the full set of test problems. The rest contain each individual problem and its solution. * [[2020 AIME I Problems|Entire Test]]1 KB (133 words) - 18:11, 18 March 2020
- {{AIME Problems|year=2018|n=II}} ==Problem 1==9 KB (1,385 words) - 00:26, 21 January 2024
- Here are the problems from the 2019 AMC 10C, a mock contest created by the AoPS user fidgetboss_4000. ==Problem 1==12 KB (1,917 words) - 12:14, 29 November 2021
- ==Problem== D = A+1/4*(B-A);7 KB (1,053 words) - 14:58, 14 January 2024
- ==Problem== ==Solution 1==7 KB (1,129 words) - 16:27, 6 January 2025
- ==Problem== ...{3}i}{2}\right)=2015+2019\sqrt{3}i</math>. Find the remainder when <math>f(1)</math> is divided by <math>1000</math>.4 KB (706 words) - 22:18, 28 December 2023
- ==Problem== ...pretty. Let <math>S</math> be the sum of positive integers less than <math>2019</math> that are <math>20</math>-pretty. Find <math>\tfrac{S}{20}</math>.3 KB (474 words) - 01:38, 22 December 2024
- ==Problem== ==Solution 1==8 KB (1,172 words) - 18:21, 8 August 2024
- ==Problem== ==Solution 1==14 KB (2,229 words) - 14:57, 27 December 2024
- ==Problem== ...r arc <math>\widehat{A_6A_7}</math> of the circle is equal to <math>\tfrac{1}{8}-\tfrac{\sqrt2}{n}.</math> Find <math>n.</math>7 KB (1,051 words) - 20:45, 27 January 2024