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- ==Problem== ...AC}=\frac{11}{21}\implies \cos{(180^{\circ}-\angle BAC)}=\angle AKB=-\frac{11}{21}</math>14 KB (2,229 words) - 14:57, 27 December 2024
- ==Problem== Before we start thinking about the problem, let’s draw it out;25 KB (4,645 words) - 22:46, 30 January 2025
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- ...ake. Sometimes, the administrator may ask other people to sign up to write problems for the contest. * Look at past [[AMC]]/[[AHSME]] tests to get a feel for what kind of problems you should write and what difficulty level they should be.51 KB (6,175 words) - 21:41, 27 November 2024
- ...n McNugget Theorem''' (or '''Postage Stamp Problem''' or '''Frobenius Coin Problem''') states that for any two [[relatively prime]] [[positive integer]]s <mat ...t Theorem has also been called the Frobenius Coin Problem or the Frobenius Problem, after German mathematician Ferdinand Frobenius inquired about the largest17 KB (2,823 words) - 23:06, 15 November 2024
- It is used to solve problems of the form: how many ways can one distribute <math>k</math> indistinguisha ...ach urn, then there would be <math>{n \choose k}</math> possibilities; the problem is that you can repeat urns, so this does not work.<math>n</math> and then5 KB (795 words) - 17:39, 31 December 2024
- ...into anything. Using that fact, you can use the Games theorem to solve any problem. 11. Gmaas is known to barf entire universes at will. EDIT: Every once in a whi69 KB (11,805 words) - 20:49, 18 December 2019
- ...k contains the full set of test problems. The rest contain each individual problem and its solution. * [[2018 AIME II Problems|Entire Test]]1 KB (133 words) - 18:13, 18 March 2020
- ...k contains the full set of test problems. The rest contain each individual problem and its solution. * [[2019 AIME I Problems|Entire Test]]1 KB (133 words) - 17:41, 29 March 2019
- ...k contains the full set of test problems. The rest contain each individual problem and its solution. * [[2019 AIME II Problems|Entire Test]]1 KB (133 words) - 15:43, 22 March 2019
- ...k contains the full set of test problems. The rest contain each individual problem and its solution. * [[2020 AIME I Problems|Entire Test]]1 KB (133 words) - 18:11, 18 March 2020
- {{AIME Problems|year=2018|n=II}} ==Problem 1==9 KB (1,385 words) - 00:26, 21 January 2024
- Here are the problems from the 2019 AMC 10C, a mock contest created by the AoPS user fidgetboss_4000. ==Problem 1==12 KB (1,917 words) - 12:14, 29 November 2021
- ==Problem== <cmath>\frac{1}{2}h+\frac{7}{8}h=\frac{11}{8}h</cmath>.7 KB (1,053 words) - 14:58, 14 January 2024
- ==Problem== ...21\cdot 25},\frac{16^2+25^2-21^2}{2\cdot 16\cdot 25}= \frac{27}{35}, \frac{11}{20}.</cmath>7 KB (1,129 words) - 16:27, 6 January 2025
- ==Problem== ...pretty. Let <math>S</math> be the sum of positive integers less than <math>2019</math> that are <math>20</math>-pretty. Find <math>\tfrac{S}{20}</math>.3 KB (474 words) - 01:38, 22 December 2024
- ==Problem== ...nds will converge to such a value (since it is unique, as indicated in the problem). Let's keep track of the lower bound.8 KB (1,172 words) - 18:21, 8 August 2024
- ==Problem== ...AC}=\frac{11}{21}\implies \cos{(180^{\circ}-\angle BAC)}=\angle AKB=-\frac{11}{21}</math>14 KB (2,229 words) - 14:57, 27 December 2024
- {{AIME Problems|year=2019|n=I}} ==Problem 1==8 KB (1,331 words) - 06:57, 4 January 2021
- ==Problem== ...omes <math>11...0</math>, where there are <math>322</math> digits in <math>11...0</math>. Then, subtract the <math>321</math> you initially added.3 KB (433 words) - 07:57, 9 February 2023
- {{AIME Problems|year=2019|n=II}} ==Problem 1==7 KB (1,254 words) - 14:45, 21 August 2023
- ==Problem== ...y make as many as <math>3</math> substitutions, where any one of the <math>11</math> players in the game is replaced by one of the substitutes. No player4 KB (551 words) - 10:32, 5 February 2022
- ==Problem== <cmath>P_3 = \frac{11}{16}</cmath>3 KB (526 words) - 21:27, 24 October 2023
