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• 2019 AIME II Problems/Problem 15
  ==Problem== ...ath>Y</math>. Suppose <math>XP=10</math>, <math>PQ=25</math>, and <math>QY=15</math>. The value of <math>AB\cdot AC</math> can be written in the form <ma
  7 KB (1,129 words) - 16:27, 6 January 2025
• 2019 AIME I Problems/Problem 15
  ==Problem== By Power of a Point, <math>PX\cdot PY=PA\cdot PB=15</math>. Since <math>PX+PY=XY=11</math> and <math>XQ=11/2</math>, <cmath>XP=
  13 KB (2,252 words) - 13:39, 5 January 2025

Page text matches

• Mock AMC
  ...ake. Sometimes, the administrator may ask other people to sign up to write problems for the contest. * Look at past [[AMC]]/[[AHSME]] tests to get a feel for what kind of problems you should write and what difficulty level they should be.
  51 KB (6,175 words) - 21:41, 27 November 2024
• Mock MathCounts
  ...istered to the AoPS community, while others may be sourced from a group of problem writers. Different users may have a different way of participating; some ma ...ms from one subject. Having a group is also good so they can discuss which problems are good or need improvement, and fix errors. More than one person working
  26 KB (3,260 words) - 19:28, 15 August 2024
• Chicken McNugget Theorem
  ...n McNugget Theorem''' (or '''Postage Stamp Problem''' or '''Frobenius Coin Problem''') states that for any two [[relatively prime]] [[positive integer]]s <mat ...t Theorem has also been called the Frobenius Coin Problem or the Frobenius Problem, after German mathematician Ferdinand Frobenius inquired about the largest
  17 KB (2,823 words) - 23:06, 15 November 2024
• Mass points
  ...eorems concerning [[polygon]]s, and is helpful in solving complex geometry problems involving lengths. In essence, it involves using a local [[coordinate syst ...school students made it popular. The technique greatly simplifies certain problems.
  5 KB (812 words) - 15:43, 1 March 2025
• Ball-and-urn
  ...e number of ways to do such is <math>{4+3-1 \choose 3-1} = {6 \choose 2} = 15</math>. ...ach urn, then there would be <math>{n \choose k}</math> possibilities; the problem is that you can repeat urns, so this does not work.<math>n</math> and then
  5 KB (795 words) - 17:39, 31 December 2024
• Gmaas
  ...into anything. Using that fact, you can use the Games theorem to solve any problem. 15. Gmaas won an infinite amount of games against AlphaGo and Gary Kasparov wh
  69 KB (11,805 words) - 20:49, 18 December 2019
• 2018 AIME II
  ...k contains the full set of test problems. The rest contain each individual problem and its solution. * [[2018 AIME II Problems|Entire Test]]
  1 KB (133 words) - 18:13, 18 March 2020
• 2019 AIME I
  ...k contains the full set of test problems. The rest contain each individual problem and its solution. * [[2019 AIME I Problems|Entire Test]]
  1 KB (133 words) - 17:41, 29 March 2019
• 2019 AIME II
  ...k contains the full set of test problems. The rest contain each individual problem and its solution. * [[2019 AIME II Problems|Entire Test]]
  1 KB (133 words) - 15:43, 22 March 2019
• 2020 AIME I
  ...k contains the full set of test problems. The rest contain each individual problem and its solution. * [[2020 AIME I Problems|Entire Test]]
  1 KB (133 words) - 18:11, 18 March 2020
• 2018 AIME II Problems
  {{AIME Problems|year=2018|n=II}} ==Problem 1==
  9 KB (1,385 words) - 00:26, 21 January 2024
• 2019 AMC 10C Problems
  Here are the problems from the 2019 AMC 10C, a mock contest created by the AoPS user fidgetboss_4000. ==Problem 1==
  12 KB (1,917 words) - 12:14, 29 November 2021
• 2019 AIME II Problems/Problem 7
  ==Problem== ...\triangle ABC</math> are segments of lengths <math>55,45</math>, and <math>15</math>, respectively. Find the perimeter of the triangle whose sides lie on
  7 KB (1,053 words) - 14:58, 14 January 2024
• 2019 AIME II Problems/Problem 15
  ==Problem== ...ath>Y</math>. Suppose <math>XP=10</math>, <math>PQ=25</math>, and <math>QY=15</math>. The value of <math>AB\cdot AC</math> can be written in the form <ma
  7 KB (1,129 words) - 16:27, 6 January 2025
• 2019 AIME II Problems/Problem 11
  ==Problem== ...sqrt{5}}\right)}</cmath> Then factoring yields <cmath>\sqrt{\frac{21^2(8^2-15)}{(8\sqrt{5})^2}} =\frac{147}{8\sqrt{5}}</cmath> The area <cmath>[O_{1}AO_{
  14 KB (2,229 words) - 14:57, 27 December 2024
• 2019 AIME II Problems/Problem 14
  ==Problem== Obviously <math>n\le 90</math>. We see that the problem's condition is equivalent to: 96 is the smallest number that can be formed
  9 KB (1,543 words) - 19:48, 3 January 2025
• 2019 AIME I Problems
  {{AIME Problems|year=2019|n=I}} ==Problem 1==
  8 KB (1,331 words) - 06:57, 4 January 2021
• 2019 AIME II Problems
  {{AIME Problems|year=2019|n=II}} ==Problem 1==
  7 KB (1,254 words) - 14:45, 21 August 2023
• 2019 AIME I Problems/Problem 3
  ==Problem== In <math>\triangle PQR</math>, <math>PR=15</math>, <math>QR=20</math>, and <math>PQ=25</math>. Points <math>A</math> a
  6 KB (933 words) - 19:30, 29 January 2025
• 2019 AIME II Problems/Problem 1
  ==Problem== pair C = (15,8);
  9 KB (1,508 words) - 14:02, 7 September 2024

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