Create the page "2019 AIME Problems/Problem 16" on this wiki! See also the search results found.

• Mock AMC
  ...ake. Sometimes, the administrator may ask other people to sign up to write problems for the contest. * Look at past [[AMC]]/[[AHSME]] tests to get a feel for what kind of problems you should write and what difficulty level they should be.
  51 KB (6,175 words) - 21:41, 27 November 2024
• Chicken McNugget Theorem
  ...n McNugget Theorem''' (or '''Postage Stamp Problem''' or '''Frobenius Coin Problem''') states that for any two [[relatively prime]] [[positive integer]]s <mat ...t Theorem has also been called the Frobenius Coin Problem or the Frobenius Problem, after German mathematician Ferdinand Frobenius inquired about the largest
  17 KB (2,823 words) - 23:06, 15 November 2024
• Mass points
  ...eorems concerning [[polygon]]s, and is helpful in solving complex geometry problems involving lengths. In essence, it involves using a local [[coordinate syst ...school students made it popular. The technique greatly simplifies certain problems.
  5 KB (812 words) - 15:43, 1 March 2025
• Gmaas
  ...into anything. Using that fact, you can use the Games theorem to solve any problem. 16. Gmaas owns a pet: sseraj. Gmaas likes to play chess with his pets. EDIT: G
  69 KB (11,805 words) - 20:49, 18 December 2019
• 2019 AMC 10C Problems
  Here are the problems from the 2019 AMC 10C, a mock contest created by the AoPS user fidgetboss_4000. ==Problem 1==
  12 KB (1,917 words) - 12:14, 29 November 2021
• 2019 AIME II Problems/Problem 15
  ==Problem== <math>b\cos B=21,c\cos C=16</math>.
  7 KB (1,129 words) - 16:27, 6 January 2025
• 2019 AIME II Problems/Problem 11
  ==Problem== ...16\sqrt{5}}</cmath> Using similar logic we obtain <math>O_{2}A =\frac{189}{16\sqrt{5}}.</math>
  14 KB (2,229 words) - 14:57, 27 December 2024
• 2019 AIME II Problems/Problem 13
  ==Problem== ...ld therefore be \(\frac{1}{8}- \frac{\sqrt{2}}{2}\left(\frac{16}{63}-\frac{16}{64}\right)=\frac{1}{8}- \frac{\sqrt{2}}{504}\). The answer is \(\boxed{504
  7 KB (1,051 words) - 20:45, 27 January 2024
• 2019 AIME I Problems/Problem 3
  ==Problem== dot((12,16));
  6 KB (933 words) - 19:30, 29 January 2025
• 2019 AIME II Problems/Problem 1
  ==Problem== Now by symmetry, <math>D=(16, 8)</math>.
  9 KB (1,508 words) - 14:02, 7 September 2024
• 2019 AIME II Problems/Problem 2
  ==Problem== <cmath>P_3 = \frac{11}{16}</cmath>
  3 KB (526 words) - 21:27, 24 October 2023
• 2019 AIME II Problems/Problem 4
  ==Problem== If there are four 1/4's, then there are <math>2^4=16</math> combinations.
  20 KB (3,220 words) - 03:24, 14 August 2024
• 2019 AIME I Problems/Problem 8
  ==Problem== <cmath>\frac{1}{16}(80z^4+40z^2+1)=\frac{11}{36}.</cmath>
  10 KB (1,878 words) - 13:19, 1 February 2024
• 2019 AIME I Problems/Problem 9
  ==Problem== ...<math>16</math> or <math>16</math> and <math>17</math>. Only <math>\boxed{(16,17)}</math> works.
  7 KB (1,208 words) - 09:21, 4 October 2022
• 2019 AIME I Problems/Problem 13
  == Problem == ...ar triangles also gives us </math>DP=\frac{5}{3}x<math> so </math>DE=\frac{16}{3}x<math>. Now, Stewart's Theorem on </math>\triangle{FEP}<math> and cevia
  10 KB (1,622 words) - 16:51, 28 February 2025
• 2019 AIME I Problems/Problem 14
  ==Problem== Find the least odd prime factor of <math>2019^8+1</math>.
  8 KB (1,264 words) - 01:22, 7 March 2024
• GMAAS
  ...hing. Using that fact, you can use the Almighty Gmaas theorem to solve any problem. 16. Almighty Gmaas owns a pet: sseraj. Almighty Gmaas likes to play chess wi
  99 KB (14,096 words) - 23:49, 19 February 2025
• 2021 AIME II Problems/Problem 8
  ==Problem== [[File:Markov-Chain-AIME.png | 300px | center]]
  17 KB (2,722 words) - 18:32, 23 January 2023
• Know the Facts: Gmaas
  - 2019: The burning of Notre Dame causes many of Gmaas's bibles to be burnt. Immed 1. GMAAS's theorem states that for any math problem, GMAAS knows the answer to it. This theorem was proved by GMAAS. But then G
  89 KB (15,007 words) - 15:02, 19 February 2025
• Mathboy282
  [[2019 AIME II Problems/Problem 15]] Solution 5 [[2023 USAJMO Problems/Problem 6]] Solution 1
  10 KB (1,116 words) - 12:37, 11 June 2024

View (previous 20 | next 20) (20 | 50 | 100 | 250 | 500)