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- ==Problem== ...CD</math> is a concave quadrilateral with <math>AB = 12</math>, <math>BC = 16</math>, <math>AD = CD = 26</math>, and <math>\angle ABC=90^\circ</math>. Fi1 KB (148 words) - 09:39, 12 July 2021
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- ==Problem== What is the leftmost digit of the product <cmath>\underbrace{161616 \cdots 16}_{100 \text{ digits }} \times \underbrace{252525 \cdots 25}_{100 \text{ dig2 KB (209 words) - 16:25, 11 July 2021
- ...Middle School</b> problems and solutions. The test was held on July 10th, 2021. *[[2021 JMPSC Sprint Problems]]1 KB (155 words) - 16:39, 11 July 2021
- #You will receive 4 points for each correct answer, and 0 points for each problem left unanswered or incorrect. ...rasers. No calculators, smartwatches, or computing devices are allowed. No problems on the test will require the use of a calculator.5 KB (729 words) - 17:41, 11 July 2021
- ==Problem== ...incorrect or skipped question. Find the sum of all the possible numbers of problems that the test could have had.1 KB (154 words) - 16:14, 11 July 2021
- ==Problem== ...umbers are in the finite sequence of consecutive perfect squares <cmath>9, 16, 25, \ldots , 2500?</cmath>1 KB (168 words) - 18:55, 7 September 2021
- ==Problem== ...CD</math> is a concave quadrilateral with <math>AB = 12</math>, <math>BC = 16</math>, <math>AD = CD = 26</math>, and <math>\angle ABC=90^\circ</math>. Fi1 KB (148 words) - 09:39, 12 July 2021
- #You will receive 3 points for each correct answer, and 0 points for each problem left unanswered or incorrect. ...rasers. No calculators, smartwatches, or computing devices are allowed. No problems on the test will require the use of a calculator.7 KB (1,100 words) - 17:40, 11 July 2021
- ==Problem== We find that it is possible to construct the maximal <math>\boxed{16}</math> points, where each side of one quadrilateral intersects all four si1 KB (185 words) - 11:45, 12 July 2021
- ==Problem== ...<math>16</math>. Now, subtracting <math>144</math> we have <math>224=4x+28(16-x)</math> for <math>x</math> is the height of <math>\triangle PAB</math>. T1 KB (169 words) - 18:48, 23 September 2024
- ==Problem== ...I = IC = 7-4 = 3</math>. We see <math>CF^2 = CI^2 + IF^2 = 3^2 + 4^2 = 9 + 16 = 25</math>, while <math>CE^2 = CG^2 + GE^2 = 3^2 + 7^2 = 9 + 49 = 58</math3 KB (425 words) - 20:45, 22 December 2021