Search results
Create the page "2021 JMPSC Problems/Problem 20" on this wiki! See also the search results found.
Page title matches
- ==Problem== #[[2021 JMPSC Sprint Problems|Other 2021 JMPSC Sprint Problems]]2 KB (258 words) - 09:00, 12 July 2021
Page text matches
- ...Middle School</b> problems and solutions. The test was held on July 10th, 2021. *[[2021 JMPSC Sprint Problems]]1 KB (155 words) - 16:39, 11 July 2021
- ==Problem== ...444 \cdots )</cmath> Evaluate the last <math>3</math> digits to get <cmath>20+28(10+99+980+700)+4(444)=\boxed{888} \mod 1000</cmath>2 KB (304 words) - 00:19, 12 July 2021
- #You will receive 4 points for each correct answer, and 0 points for each problem left unanswered or incorrect. ...rasers. No calculators, smartwatches, or computing devices are allowed. No problems on the test will require the use of a calculator.5 KB (729 words) - 17:41, 11 July 2021
- ==Problem== ...lasses was to increase by <math>1</math>, then each class would have <math>20</math> students. If the number of classes was to decrease by <math>1</math>1 KB (196 words) - 16:24, 11 July 2021
- ==Problem== ...value of <math>x</math> that satisfies <cmath>\frac{5!x}{2022!}=\frac{20}{2021!}.</cmath>804 bytes (106 words) - 09:04, 12 July 2021
- ==Problem== ...airs, so <math>(2,3)</math> is the only way they can meet. There are <math>20</math> ways for them to choose the <math>2</math> houses to meet, and <math1 KB (197 words) - 09:01, 12 July 2021
- ==Problem== ...l is <math>\frac{2}{5}</math>. Multiplying the fraction by <math>\frac{20}{20}</math>, we get <math>\frac{40}{100}</math>, or <math>40</math> coins out o1 KB (175 words) - 16:13, 11 July 2021
- ==Problem== <cmath>10, 20, 30, 40, 50, 60, 70, 80, 90</cmath>1 KB (147 words) - 09:44, 12 July 2021
- ==Problem== ...t every <math>\frac{20}{5}=4</math> minutes. To split the metal into <math>20</math> pieces, the machine has to make <math>14</math> more cuts. This will797 bytes (121 words) - 16:14, 11 July 2021
- ==Problem== ...We then have that the area of triangle of <math>ADC</math> is <math>\frac{20 \cdot \sqrt{26^2 - 10^2}}{2} = 240</math>, and the area of triangle <math>A1 KB (148 words) - 09:39, 12 July 2021
- ==Problem== ...e want <math>A \times M</math>, so the answer is <math>5 \times 4 = \boxed{20}</math>.2 KB (265 words) - 16:15, 11 July 2021
- #You will receive 3 points for each correct answer, and 0 points for each problem left unanswered or incorrect. ...rasers. No calculators, smartwatches, or computing devices are allowed. No problems on the test will require the use of a calculator.7 KB (1,100 words) - 17:40, 11 July 2021
- #You will receive 15 points for each correct answer, and 0 points for each problem left unanswered or incorrect. ...rasers. No calculators, smartwatches, or computing devices are allowed. No problems on the test will require the use of a calculator.6 KB (985 words) - 17:39, 11 July 2021
- ==Problem== ...or the integers <math>x</math> must be <math>9</math>. The sum is <math>18+20+9</math> or <math>\boxed{47}</math>2 KB (269 words) - 20:06, 11 July 2021
- ==Problem== ...3</math>. We see <math>y=-37</math> and <math>x=39</math>, so <math>39(21)-20(37)=\boxed{79}</math>2 KB (272 words) - 09:07, 12 July 2021
- ==Problem== ...th <math>AB=4</math>, <math>BC=20</math>, <math>CD=28</math>, and <math>DA=20</math>. If the sum of the areas of <math>PBC</math> and <math>PDA</math> is1 KB (169 words) - 18:48, 23 September 2024