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- ==Problem== .../math> triangle containing the right-two sides. The answer is <math>\boxed{8}</math>718 bytes (98 words) - 16:23, 11 July 2021
- ==Problem== #[[2021 JMPSC Sprint Problems|Other 2021 JMPSC Sprint Problems]]1 KB (147 words) - 09:44, 12 July 2021
- ==Problem== #[[2021 JMPSC Invitationals Problems|Other 2021 JMPSC Invitationals Problems]]2 KB (272 words) - 09:07, 12 July 2021
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- ==Problem== A standard chess-board is an 8 by 8 grid of squares. A bishop is placed at square C5 (row 5, column C) and a ro1,017 bytes (175 words) - 16:12, 11 July 2021
- ...(Middle School)''' problems and solutions. The test was held on July 10th, 2021. *[[2021 JMPSC Accuracy Problems]]1 KB (125 words) - 16:39, 11 July 2021
- ...Middle School</b> problems and solutions. The test was held on July 10th, 2021. *[[2021 JMPSC Sprint Problems]]1 KB (155 words) - 16:39, 11 July 2021
- ==Problem== ...rac{3+2\sqrt{3}}{3}.</cmath> This gives us an answer of <math>2+3+3=\boxed{8}.</math> ~ samrocksnature2 KB (333 words) - 16:24, 11 July 2021
- #You will receive 4 points for each correct answer, and 0 points for each problem left unanswered or incorrect. ...rasers. No calculators, smartwatches, or computing devices are allowed. No problems on the test will require the use of a calculator.5 KB (729 words) - 17:41, 11 July 2021
- ==Problem== From the problem, we know that1 KB (205 words) - 16:23, 11 July 2021
- ==Problem== .../math> triangle containing the right-two sides. The answer is <math>\boxed{8}</math>718 bytes (98 words) - 16:23, 11 July 2021
- ==Problem== ...be used, specifically only <math>5</math> for the first digit. Only <math>8</math> and <math>9</math> may be used, as there isn't other pair of digits1 KB (194 words) - 09:43, 12 July 2021
- ==Problem== Therefore, Luis has a total of <math>6+2</math> <math>=</math> <math>\boxed{8}</math> dollars total in dimes and nickels.1 KB (175 words) - 16:13, 11 July 2021
- ==Problem== ...incorrect or skipped question. Find the sum of all the possible numbers of problems that the test could have had.1 KB (154 words) - 16:14, 11 July 2021
- ==Problem== ...s <math>17</math> units long and of negligible thickness. The cup is <math>8</math> units tall. The volume of the cup can be written as <math>k \pi</mat1 KB (156 words) - 09:47, 12 July 2021
- ==Problem== ...Ari(<math>3</math> letters) is the shortest in the room and Chandler(<math>8</math> letters) is the second tallest in the room.2 KB (276 words) - 16:15, 11 July 2021
- #You will receive 3 points for each correct answer, and 0 points for each problem left unanswered or incorrect. ...rasers. No calculators, smartwatches, or computing devices are allowed. No problems on the test will require the use of a calculator.7 KB (1,100 words) - 17:40, 11 July 2021
- ...(Middle School)''' problems and solutions. The test was held on July 11th, 2021. *[[2021 JMPSC Invitationals Problems]]1 KB (125 words) - 16:39, 11 July 2021
- #You will receive 15 points for each correct answer, and 0 points for each problem left unanswered or incorrect. ...rasers. No calculators, smartwatches, or computing devices are allowed. No problems on the test will require the use of a calculator.6 KB (985 words) - 17:39, 11 July 2021
- ==Problem== ...od 2</math> must work for <math>xk \le 100</math>. Clearly <math>k=\{2,4,6,8,10 \}</math>, which means the maximum value that <math>xk</math> can take o2 KB (269 words) - 20:06, 11 July 2021
- ==Problem== ...corner square options, so <math>4</math> lines of symmetry dictates <math>8</math> more cases. The answer is <math>\boxed{17}</math>2 KB (245 words) - 14:09, 6 August 2021
- ==Problem== ...e an odd integer (not necessarily positive) such that <cmath>\dfrac{p^{n+p+2021}}{(p+n)^2}</cmath> is an integer. Find the sum of all distinct possible val2 KB (280 words) - 20:17, 11 July 2021
- ==Problem== Abhishek is choosing positive integer factors of <math>2021 \times 2^{2021}</math> with replacement. After a minute passes, he chooses a random factor2 KB (342 words) - 23:02, 11 July 2021