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Create the page "25" on this wiki! See also the search results found.
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- 6 KB (1,037 words) - 22:32, 9 November 2024
- https://www.youtube.com/watch?v=KpABvGFJANU (by Challenge 25)9 KB (1,409 words) - 02:59, 8 December 2024
- 4 KB (495 words) - 00:36, 26 May 2024
- 10 KB (1,840 words) - 14:01, 4 July 2024
- 46 bytes (5 words) - 14:43, 11 July 2020
- 46 bytes (5 words) - 09:57, 20 February 2016
- 5 KB (878 words) - 13:39, 3 December 2023
- ...</math> are left. They can be paired so the sum is <math>125</math>: <math>25+100</math>, <math>26+99</math>, <math>27+98</math>, <math>\ldots</math>, <m ...consider. As <math>62+63</math> gives <math>125</math>, the numbers <math>25</math> to <math>62</math> can be put in subset <math>B</math> without havin3 KB (517 words) - 18:15, 15 October 2023
- 1 KB (172 words) - 23:11, 15 February 2016
- In <math>ABC</math> we have <math> AB = 25 </math>, <math> BC = 39</math>, and <math>AC=42</math>. Points <math>D</mat <cmath>\frac{[ADE]}{[ABC]} = \frac{AD}{AB} \cdot \frac{AE}{AC} = \frac{19}{25} \cdot \frac{14}{42} = \frac{19}{75}.</cmath>6 KB (897 words) - 16:55, 1 December 2024
- 5 KB (831 words) - 16:04, 5 January 2025
- 9 KB (1,606 words) - 10:34, 10 July 2020
- https://youtu.be/HDl_FdA0Jjs?t=492 (by Challenge 25)9 KB (1,461 words) - 22:07, 27 January 2024
- 3 KB (480 words) - 13:50, 17 August 2020
- 7 KB (1,001 words) - 14:31, 23 August 2024
- 1 KB (180 words) - 19:59, 10 February 2019
- \qquad\textbf{(E)}\ 25</math> [[Image:2002_12B_AMC-25.png|center]]2 KB (371 words) - 02:49, 26 September 2024
- 3 KB (383 words) - 19:12, 15 October 2016
- pair A=(0,0), B = (52,0), C=(52-144/13,60/13), D=(25/13,60/13), F=(100/13,240/13); ...,0), B = (52,0), C=(52-144/13,60/13), D=(25/13,60/13), E=(52-144/13,0), F=(25/13,0);8 KB (1,308 words) - 06:05, 19 December 2022
- 6 KB (894 words) - 22:13, 2 September 2024
Page text matches
- <cmath>7-24-25</cmath> <cmath>21-72-75 = (7-24-25)*3</cmath>5 KB (885 words) - 22:03, 5 October 2024
- For every dollar Ben spent on bagels, David spent <math>25</math> cents less. Ben paid <math>$12.50</math> more than David. How much ...aid <math>$ 12.50</math> more than David, then he paid <math>\frac{12.5}{.25}= $ 50.00</math>. Thus, David paid <math>$ 37.50</math>, and they spent <1 KB (176 words) - 09:58, 16 June 2023
- ...competition consists of five members who work together on 20 questions for 25 minutes. A school may field as many five member teams as it wishes. The ind *placing among the top 25 individual scorers in the state in their topic, as determined by raw score8 KB (1,182 words) - 13:26, 3 April 2024
- | 255 KB (724 words) - 11:09, 21 November 2024
- **School receives $25,0004 KB (623 words) - 12:11, 20 February 2024
- ...Silver, and Gold. Approximately the top 5% get Gold, top 12.5% Silver, top 25% Bronze, top 45% HM. Prizes are awarded to high scorers at the end of the y4 KB (613 words) - 21:12, 15 October 2024
- ...difficulty=1 - 1.5|breakdown=<u>Problems 1 - 12</u>: 1<br><u>Problems 13 - 25</u>: 1.5}} The AMC 8 exam is a 25 problem exam. There are 40 minutes given in the exam. Problems increase in4 KB (576 words) - 18:36, 22 September 2024
- ...breakdown=<u>Problem 1-5</u>: 1<br><u>Problem 6-20</u>: 2<br><u>Problem 21-25</u>: 3}} The AMC 10 is a 25 question, 75 minute multiple choice test. Problems generally increase in di4 KB (586 words) - 16:48, 28 October 2024
- ...eakdown=<u>Problem 1-10</u>: 2<br><u>Problem 11-20</u>: 3<br><u>Problem 21-25</u>: 4}} The AMC 12 is a 25 question, 75 minute multiple choice test. Problems generally increase in di4 KB (529 words) - 08:01, 24 July 2024
- In 2000, the AHSME was split into the AMC 10 and 12, reduced to only 25 questions, and 2 years later, the A and B version of the AMC's were introdu5 KB (696 words) - 02:47, 24 December 2019
- label("$\frac{1}{2}$",(.5,.25)); label("$\frac{1}{2}$",(.5,.25));3 KB (415 words) - 17:01, 24 May 2020
- ...l State Mathematics Team. The qualifying floor this year was 11 out of the 25 questions. After an individual is accepted into the SC All State Team, he o22 KB (3,532 words) - 10:25, 27 September 2024
- * <math>25! = 15511210043330985984000000</math>10 KB (809 words) - 15:40, 17 March 2024
- * Compute some examples, for example find <math>3^{31} \pmod{7}, 29^{25} \pmod{11}</math>, and <math>128^{129} \pmod{17}</math>, and check your ans16 KB (2,660 words) - 22:42, 28 August 2024
- * [[2006 AMC 10B Problems/Problem 25]]10 KB (1,572 words) - 21:11, 22 September 2024
- ...s, <math>X</math> and <math>Y</math>. Suppose <math>XP=10</math>, <math>PQ=25</math>, and <math>QY=15</math>. Compute the product <math>AB\cdot AC</math>8 KB (1,408 words) - 08:39, 10 July 2024
- ...g.com/wiki/index.php/2015_AMC_10A_Problems/Problem_25 2015 AMC 10A Problem 25]1 KB (179 words) - 11:04, 28 September 2024
- ...and <math>5</math> options for the second letter, so there are <math>5^2 = 25</math> of these words. Adding all our cases up, there are <math>5 + 25 + 125 = 155</math> words that are less than four letters long and contain o5 KB (709 words) - 16:40, 24 September 2024
- ...a type of number: [[2007_AMC_12A_Problems#Problem_25| 2007 AMC 12A Problem 25]] * [[2019_AMC_10B_Problems#Problem_25| 2019 AMC 10B Problem 25]]2 KB (316 words) - 15:03, 1 January 2024
- ...that a license plate has no palindromes is <cmath>\frac{9}{10} \cdot \frac{25}{26} = \frac{225}{260} = \frac{45}{52}.</cmath> Taking the complement of th8 KB (1,192 words) - 16:20, 16 June 2023