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  • <cmath>7-24-25</cmath> <cmath>21-72-75 = (7-24-25)*3</cmath>
    5 KB (885 words) - 22:03, 5 October 2024
  • For every dollar Ben spent on bagels, David spent <math>25</math> cents less. Ben paid <math>$12.50</math> more than David. How much ...aid <math>$ 12.50</math> more than David, then he paid <math>\frac{12.5}{.25}= $ 50.00</math>. Thus, David paid <math>$ 37.50</math>, and they spent <
    1 KB (176 words) - 09:58, 16 June 2023
  • ...competition consists of five members who work together on 20 questions for 25 minutes. A school may field as many five member teams as it wishes. The ind *placing among the top 25 individual scorers in the state in their topic, as determined by raw score
    8 KB (1,182 words) - 13:26, 3 April 2024
  • | 25
    5 KB (724 words) - 11:09, 21 November 2024
  • **School receives &#36;25,000
    4 KB (623 words) - 12:11, 20 February 2024
  • ...Silver, and Gold. Approximately the top 5% get Gold, top 12.5% Silver, top 25% Bronze, top 45% HM. Prizes are awarded to high scorers at the end of the y
    4 KB (613 words) - 21:12, 15 October 2024
  • ...difficulty=1 - 1.5|breakdown=<u>Problems 1 - 12</u>: 1<br><u>Problems 13 - 25</u>: 1.5}} The AMC 8 exam is a 25 problem exam. There are 40 minutes given in the exam. Problems increase in
    4 KB (576 words) - 18:36, 22 September 2024
  • ...breakdown=<u>Problem 1-5</u>: 1<br><u>Problem 6-20</u>: 2<br><u>Problem 21-25</u>: 3}} The AMC 10 is a 25 question, 75 minute multiple choice test. Problems generally increase in di
    4 KB (586 words) - 16:48, 28 October 2024
  • ...eakdown=<u>Problem 1-10</u>: 2<br><u>Problem 11-20</u>: 3<br><u>Problem 21-25</u>: 4}} The AMC 12 is a 25 question, 75 minute multiple choice test. Problems generally increase in di
    4 KB (529 words) - 08:01, 24 July 2024
  • In 2000, the AHSME was split into the AMC 10 and 12, reduced to only 25 questions, and 2 years later, the A and B version of the AMC's were introdu
    5 KB (696 words) - 02:47, 24 December 2019
  • label("$\frac{1}{2}$",(.5,.25)); label("$\frac{1}{2}$",(.5,.25));
    3 KB (415 words) - 17:01, 24 May 2020
  • ...l State Mathematics Team. The qualifying floor this year was 11 out of the 25 questions. After an individual is accepted into the SC All State Team, he o
    22 KB (3,532 words) - 10:25, 27 September 2024
  • * <math>25! = 15511210043330985984000000</math>
    10 KB (809 words) - 15:40, 17 March 2024
  • * Compute some examples, for example find <math>3^{31} \pmod{7}, 29^{25} \pmod{11}</math>, and <math>128^{129} \pmod{17}</math>, and check your ans
    16 KB (2,660 words) - 22:42, 28 August 2024
  • * [[2006 AMC 10B Problems/Problem 25]]
    10 KB (1,572 words) - 21:11, 22 September 2024
  • ...s, <math>X</math> and <math>Y</math>. Suppose <math>XP=10</math>, <math>PQ=25</math>, and <math>QY=15</math>. Compute the product <math>AB\cdot AC</math>
    8 KB (1,408 words) - 08:39, 10 July 2024
  • ...g.com/wiki/index.php/2015_AMC_10A_Problems/Problem_25 2015 AMC 10A Problem 25]
    1 KB (179 words) - 11:04, 28 September 2024
  • ...and <math>5</math> options for the second letter, so there are <math>5^2 = 25</math> of these words. Adding all our cases up, there are <math>5 + 25 + 125 = 155</math> words that are less than four letters long and contain o
    5 KB (709 words) - 16:40, 24 September 2024
  • ...a type of number: [[2007_AMC_12A_Problems#Problem_25| 2007 AMC 12A Problem 25]] * [[2019_AMC_10B_Problems#Problem_25| 2019 AMC 10B Problem 25]]
    2 KB (316 words) - 15:03, 1 January 2024
  • ...that a license plate has no palindromes is <cmath>\frac{9}{10} \cdot \frac{25}{26} = \frac{225}{260} = \frac{45}{52}.</cmath> Taking the complement of th
    8 KB (1,192 words) - 16:20, 16 June 2023

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