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Page title matches
- {{AMC12 box|year=2016|ab=A|num-b=2|num-a=4}}2 KB (257 words) - 09:57, 16 June 2023
- 1 KB (249 words) - 12:05, 24 January 2024
- ...ece of length <math>k_i</math> from the end of leg <math>L_i \; (i = 1,2,3,4)</math> and still have a stable table? ...ath>\{2,3,4,5\}</math> was counted in <math>C_5</math>, then <math>\{1,2,3,4\}</math> would have been counted in <math>C_4</math> because subtracting th7 KB (1,276 words) - 19:51, 6 January 2024
- ...at the right end of the decimal representation of the product <math> 1!2!3!4!\cdots99!100!. </math> Find the remainder when <math> N </math> is divided2 KB (353 words) - 21:56, 27 September 2024
- ...t the grocery store. The prices of the items are <math>7.99</math>, <math>4.99</math>, <math>2.99</math>, <math>1.99</math>, and <math>0.99</math>. Ma1 KB (152 words) - 15:11, 8 December 2013
- {{duplicate|[[2005 AMC 12B Problems|2005 AMC 12B #4]] and [[2005 AMC 10B Problems|2005 AMC 10B #6]]}} \textbf{(D) }\ 4 \qquad1 KB (197 words) - 13:16, 14 December 2021
- ...sect at a right angle at <math>E</math> . Given that <math> BE = 16, DE = 4, </math> and <math> AD = 5 </math>, find <math> CE </math>. pair D = (0,4);1 KB (177 words) - 01:14, 26 November 2020
- #REDIRECT [[2006 AIME I Problems/Problem 4]]44 bytes (5 words) - 11:03, 28 June 2009
- 3 KB (377 words) - 17:36, 1 January 2024
- #REDIRECT [[2006 AMC 12A Problems/Problem 4]]45 bytes (5 words) - 09:58, 20 February 2016
- ...lems|2006 AMC 12A #4]] and [[2006 AMC 10A Problems/Problem 4|2006 AMC 10A #4]]}} 1+0&7&4&12 KB (257 words) - 10:20, 2 January 2022
- ...erfect square]] strictly between <math>(n + 3)^2 + 5</math> and <math>(n + 4)^2 + 5</math>. Thus, if the number of columns is <math>n</math>, the numbe ...</math>. The [[quadratic formula]] yields <math>r = \frac{7 \pm \sqrt{49 - 4(1)(-s^2 - 5)}}{2} = \frac{7 \pm \sqrt{4s^2 + 69}}{2}</math>. <math>\sqrt{4s8 KB (1,249 words) - 20:25, 20 November 2024
- ...h> and <math>(0,y)</math>. Because the segment has length 2, <math>x^2+y^2=4</math>. Using the midpoint formula, we find that the midpoint of the segmen \sqrt{\frac{1}{4}\left(x^2+y^2\right)}=\sqrt{\frac{1}{4}(4)}=1</math>. Thus the midpoints lying on the sides determined by vertex <mat3 KB (532 words) - 08:22, 11 July 2023
- ...>-digit number, for a total of <math>(2^1 - 2) + (2^2 - 2) + (2^3 -2) + (2^4 - 2) = 22</math> such numbers (or we can list them: <math>AB, BA, AAB, ABA, ...ve a total of <math>9 +\binom{9}{2}\left(\binom{4}{1}+\binom{4}{2} +\binom{4}{3}\right) + 9 \cdot \left(\binom{3}{1}+\binom{3}{2} +\binom{3}{3}\right)</3 KB (508 words) - 00:16, 19 January 2024
- <cmath> AC = \sqrt{AB^2 + BC^2} = \sqrt{36 + 4} = \sqrt{40} = 2 \sqrt{10}. </cmath> draw(a[0]--a[4]);11 KB (1,747 words) - 19:54, 31 December 2024
- 2 KB (319 words) - 02:38, 16 January 2023
- ...\frac{1}{1985} = 1</math>, where <math>X</math> is the area of the of the 4 triangles.3 KB (484 words) - 20:40, 2 March 2020
- ...ve [[equation]]s gives us <math>6(x_1 + x_2 + x_3 + x_4 + x_5) = 6(1 + 2 + 4 + 8 + 16)</math> so <math>x_1 + x_2 + x_3 + x_4 + x_5 = 31</math>. Subtrac1 KB (212 words) - 15:25, 17 November 2019
- ...of the region enclosed by the [[graph]] of <math>|x-60|+|y|=\left|\frac{x}{4}\right|.</math> [[Image:1987_AIME-4.png]]2 KB (371 words) - 16:25, 13 February 2024
- ...S is <math>1.</math> Similarly testing <math>1,-1,-1,1</math> yields <math>4</math> on the LHS and <math>0</math> on the RHS. It seems for every negativ2 KB (394 words) - 09:21, 27 January 2024
Page text matches
- B = (4, 3); C = (4, 0);5 KB (885 words) - 22:03, 5 October 2024
- label("$s$",(-1.5,4)); draw((-1,4)--midpoint(O3--P3));</asy>2 KB (307 words) - 23:58, 17 November 2024
- ...xtbf{(A)}\ 1 \qquad\textbf{(B)}\ 2\qquad\textbf{(C)}\ 3\qquad\textbf{(D)}\ 4\qquad\textbf{(E)}\ 5</math>1 KB (190 words) - 09:58, 16 June 2023
- ...<math>$12.50</math> more than David, so we can write <math>$12.50\cdot (4+3)=$ 87.50.</math> Then the answer is <math>\boxed{\text{(C)}}.</math> {{AMC10 box|year=2016|ab=A|num-b=2|num-a=4}}1 KB (176 words) - 09:58, 16 June 2023
- {{AMC12 box|year=2016|ab=A|num-b=2|num-a=4}}2 KB (257 words) - 09:57, 16 June 2023
- A rectangular box has integer side lengths in the ratio <math>1: 3: 4</math>. Which of the following could be the volume of the box? ...aking the answer choices and dividing by <math>12</math>, we get <math>(A) 4</math>,1 KB (216 words) - 23:23, 5 September 2024
- filldraw(rectangle((1,1),(6,4)),gray(0.75)); label("$1$",(4.5,2.5));2 KB (335 words) - 04:52, 18 December 2024
- filldraw((7,0)--(8,0)--(8,1)--(0,4)--(0,5)--(1,5)--cycle,gray(0.8)); label("$4$",(8,3),dir(0));8 KB (1,016 words) - 23:17, 30 December 2023
- ...{(A) }1 \qquad \textbf{(B) } 2 \qquad \textbf{(C) } 3 \qquad \textbf{(D) } 4\qquad \textbf{(E) } 5</math> ...occupied and the positioning would not work. So, Edie and Dee are in seats 4 and 5. This means that Bea was originally in seat 1. Ceci must have been in2 KB (402 words) - 13:54, 25 June 2023
- ....mathcon.org MathCON] hosts annual math competition for students in grades 4-12.5 KB (512 words) - 08:27, 17 November 2024
- ....mathcon.org MathCON] hosts annual math competition for students in grades 4-12, with more than 200,000 participants since 2008.7 KB (805 words) - 15:17, 14 December 2024
- ....mathcon.org MathCON] hosts annual math competition for students in grades 4-12, with more than 200,000 participants since 2008.6 KB (625 words) - 15:24, 14 December 2024
- * [http://Perennialmath.com/tournaments UAH Math Tournament] -- Grades 4 - 83 KB (411 words) - 20:32, 8 December 2014
- * [[Crazy 4 Math]] * [[Crazy 4 Math]]4 KB (417 words) - 13:10, 29 December 2024
- 10 problems in 20 minutes for a team of 4 students. These problems typically include some of the most difficult probl ...l have less of a chance to become champion than the top 4, because the top 4 get a bye. Until the semi-finals, the scoring is best out of five advances.10 KB (1,504 words) - 13:10, 1 December 2024
- Notice that <math>...S_4S_3S_2S_1</math> is the base-4 representation of <math>2013</math>, and <math>2013_{10}=133131</math>, so190 bytes (26 words) - 05:13, 16 February 2024
- *Illinois Mathematics League -- grades 4 through 12. [http://www.mathleague.com/ website] *Illinois Mathematics League -- grades 4 through 12. [http://www.mathleague.com/ website]2 KB (305 words) - 06:41, 24 March 2024
- ...of Mathematics offers two areas of math contests: Grade School (Grades 3, 4, 5, 6, 7, 8 + Algebra 1) and High School (Regional and State Finals). *2024 State FInals - Saturday 4/6/248 KB (1,182 words) - 13:26, 3 April 2024
- * [[KCATM]], (grades 4-12). It is divided into three divisions, grades 4-6, 7-8 and 9-12. The contest features an individual competition, where part * [[Barstow Math Contest]], (grades 4-8) It is an individual math competition that is hosted by The Barstow Schoo3 KB (473 words) - 15:11, 16 June 2020
- *[[Missouri Council of Teachers of Mathematics Contests]] for grades 4-12. [http://www.moctm.org/Contests/contests.htm website] * [[Barstow Math Contest]] for grades 4-8. It is hosted by The Barstow School. [https://www.barstowschool.org/ webs3 KB (432 words) - 14:59, 16 June 2020