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  • ...MC-12 level questions. From this exam, approximately 50-60 (in 2006 it was 49) of the top scorers from the state are selected into the South Carolina All
    22 KB (3,532 words) - 10:25, 27 September 2024
  • * <math>49! = 608281864034267560872252163321295376887552831379210240000000000</math> \left\lfloor\frac {100}{49}\right\rfloor=14+2=16</math>
    10 KB (809 words) - 15:40, 17 March 2024
  • ...math>. Determine the remainder upon dividing <math>a_ {83}</math> by <math>49</math>.
    4 KB (569 words) - 21:34, 30 December 2024
  • * 2024 - Jason Lee (44), Henry Wang (42), Leo Hong (49), Lucas Li, Coach: Erin Roberts
    4 KB (582 words) - 20:40, 14 May 2024
  • ===Divisibility Rule for 49=== Why 49? For taking pesky <math>7^2</math> out of a root.
    10 KB (1,572 words) - 21:11, 22 September 2024
  • ...For instance, <math>50</math> is a factor of <math>2650</math>, and <math>49</math> is a factor of <math>4998</math>. In these cases, a good strategy i
    3 KB (496 words) - 21:14, 5 January 2024
  • ...15 16 18 20 21 22 24 25 26 27 28 30 32 33 34 35 36 38 39 40 42 44 45 46 48 49 50 51 52 54 55 56 57 58 60 62 63 64 65 66 68 69 70 72 74 75 76 77 78 80 81
    6 KB (350 words) - 11:58, 26 September 2023
  • *An [[ellipse]] has [[focus | foci]] at <math>(9,20)</math> and <math>(49,55)</math> in the <math>xy</math>-plane and is [[tangent line | tangent]] t
    5 KB (892 words) - 20:52, 1 May 2021
  • .... To do this, multiply and add <math>6\cdot 8^1+1\cdot 8^0=48+1=49. \sqrt{49}=7.</math> Therefore, the answer is 7.
    4 KB (547 words) - 16:23, 30 December 2020
  • <math>7, 49, 43, 1, 7, 49, 43, 1, \ldots</math> <math>7^{1942} = 7^{1940} \cdot 7^2 \equiv 1 \cdot 7^2 \equiv 49</math> (mod <math>100</math>).
    16 KB (2,410 words) - 13:05, 3 January 2025
  • ...) }\dfrac{41}{16}\qquad\textbf{(B) }\dfrac{11}{4}\qquad\textbf{(C) }\dfrac{49}{16}\qquad\textbf{(D) }\dfrac{27}{8}\qquad\textbf{(E) }\dfrac{55}{16}</math
    12 KB (1,784 words) - 15:49, 1 April 2021
  • ...not divisible by 2, 3, or 5. The three smallest prime-looking numbers are 49, 77, and 91. There are 168 prime numbers less than 1000. How many prime-loo
    13 KB (1,965 words) - 21:18, 7 September 2024
  • <math>\text{(A) } 33 \qquad \text{(B) } 49 \qquad \text{(C) } 50 \qquad \text{(D) } 99 \qquad \text{(E) } 100</math> The sum of <math>49</math> consecutive integers is <math>7^5</math>. What is their median?
    13 KB (1,953 words) - 23:31, 25 January 2023
  • PB^2&=BC^2+PC^2-2\cdot BC\cdot PC\cdot \cos(\alpha) \Rightarrow 49 = 36 + s^2 - 12s\cos(\alpha) \Rightarrow \cos(\alpha) = \dfrac{s^2-13}{12s} <cmath>x^2+(y-s)^2=49 \tag{2}.</cmath>
    7 KB (1,182 words) - 13:31, 1 September 2024
  • ...at are less than or equal to <math>120</math> are <math>\{0,1,4,9,16,25,36,49,64,81,100\}</math>, so there are <math>11</math> values for <math>120-\sqrt
    1 KB (167 words) - 00:27, 26 September 2024
  • ...we get the smallest positive difference - <math>5\cdot 10 - 7\cdot 7 = 50-49 = 1</math>, since we can't make a non-integer with a linear combination of
    3 KB (442 words) - 02:13, 8 August 2022
  • <math> x^2-10x+25+y^2-10y+25 \le 49 </math> ...with a radius of <math>7</math>. So, the area of <math>S_1</math> is <math>49\pi </math>.
    2 KB (280 words) - 16:35, 17 September 2023
  • ...time: <math>8^2=7^2+x^2-2(7)(x)\left( \frac{-1}{7} \right) \rightarrow 64=49+x^2+2x \rightarrow x^2+2x-15=0</math>. The only positive value for <math>x<
    2 KB (299 words) - 14:29, 5 July 2022
  • ...be greater than 0. From this case, there are <math>10*10+11*22+7*7=100+242+49=391</math> possibilities.
    3 KB (377 words) - 17:36, 1 January 2024
  • ...5 = 0</math>. The [[quadratic formula]] yields <math>r = \frac{7 \pm \sqrt{49 - 4(1)(-s^2 - 5)}}{2} = \frac{7 \pm \sqrt{4s^2 + 69}}{2}</math>. <math>\sqr ...<math>n^2 +5 = c(c+7) \implies n^2+5 = \left(c+\frac{7}{2}\right)^2 -\frac{49}{4} \implies n^2 - \left(c+\frac{7}{2}\right)^2 = -\frac{69}{4} \implies \l
    8 KB (1,249 words) - 20:25, 20 November 2024

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