Search results

Page title matches

  • ...extbf{(A)}\ 6\qquad\textbf{(B)}\ 7\qquad\textbf{(C)}\ 8\qquad\textbf{(D)}\ 9\qquad\textbf{(E)}\ 10</math> ...th> we have <math>N=63,</math> so our answer is <math>\boxed{\textbf{(D) } 9}.</math>
    2 KB (395 words) - 22:29, 3 December 2024
  • 4 KB (651 words) - 17:27, 22 May 2021
  • 3 KB (409 words) - 16:10, 30 April 2024
  • #REDIRECT [[2006 AMC 12A Problems/Problem 9]]
    45 bytes (5 words) - 13:42, 14 January 2016
  • {{duplicate|[[2005 AMC 12B Problems|2005 AMC 12B #9]] and [[2005 AMC 10B Problems|2005 AMC 10B #19]]}}
    2 KB (280 words) - 14:35, 16 December 2021
  • 6 KB (1,154 words) - 02:30, 11 January 2024
  • #REDIRECT [[2006 AMC 12A Problems/Problem 9]]
    45 bytes (5 words) - 10:02, 20 February 2016
  • [[Image:2005_I_AIME-9.png]] The eight corner cubes each have 9 visible edges from the outside, so the probability that the edge of the non
    4 KB (600 words) - 20:44, 20 November 2023
  • draw((9*4/14,0)--(9*4/14,5*3/14),dashed); ...,(1,3)); label("V2",(5,3)); MP("7",(D+G)/2,S); MP("6",(D+E)/2,W); MP("9/2",(E+H)/2,N);
    4 KB (647 words) - 16:43, 23 November 2024
  • We can find the value of <math>a_{9}</math> by its bounds using three conditions: #<math>0<a_{8} = 2a_{9}-a_{10}</math>
    3 KB (547 words) - 10:41, 7 August 2024
  • <math>f'(y)</math> = <math>9 - 4y^{-2}</math> ...x\sin{x}</math> = <math>\frac{2}{3}</math>, and the answer is <math>\frac{(9)(\frac{2}{3})^2 + 4}{\frac{2}{3}} = \boxed{012}</math>.
    5 KB (824 words) - 18:34, 20 July 2024
  • 6 KB (947 words) - 19:44, 26 November 2021
  • == Solution 1== <!-- Images obsoleted Image:1985_AIME-9.png, Image:1985_AIME-9a.png by asymptote --> multiply both sides by <math>2r</math>, then subtract <math>\sqrt{4-\frac{9}{r^2}}</math> from both sides
    5 KB (784 words) - 20:05, 8 December 2024
  • </asy></center> <!-- Asymptote replacement for Image:1986_AIME-9.png by azjps --> </asy></center> <!-- Asymptote replacement for Image:1986_AIME-9.png by azjps -->
    11 KB (1,879 words) - 20:04, 8 December 2024
  • 1 KB (212 words) - 12:37, 11 December 2024
  • ...}</math>. This is true if the tens digit is either <math>4</math> or <math>9</math>. Casework: *<math>9</math>: Then our cube is <math>(100k + 92)^3 \equiv 3(100k)(92)^2 + 92^3 \e
    6 KB (893 words) - 07:15, 2 February 2023
  • 6 KB (874 words) - 14:50, 20 January 2024
  • ...<math>\frac{144}{1024} = \frac{9}{64}</math>. Thus, our solution is <math>9 + 64 = \boxed{073}</math>. ...d the probability, we get <math>\frac{9}{64}</math>. Our solution is <math>9+64=\boxed{073}</math>.
    3 KB (427 words) - 14:03, 24 June 2024
  • 1 KB (140 words) - 23:54, 1 April 2023
  • == Solution 9 ==
    10 KB (1,590 words) - 13:04, 20 January 2023

Page text matches

  • <cmath>9-40-41</cmath> This makes the sum <math>4+5=9</math>.
    5 KB (885 words) - 22:03, 5 October 2024
  • pair O0=(9,9), O1=(1,1), O2=(3,1), O3=(1,3); pair P0=O0+9*dir(-45), P3=O3+dir(70);
    2 KB (307 words) - 23:58, 17 November 2024
  • {{AMC10 box|year=2016|ab=A|num-b=7|num-a=9}}
    1 KB (169 words) - 13:59, 8 August 2021
  • ...extbf{(A)}\ 6\qquad\textbf{(B)}\ 7\qquad\textbf{(C)}\ 8\qquad\textbf{(D)}\ 9\qquad\textbf{(E)}\ 10</math> ...th> we have <math>N=63,</math> so our answer is <math>\boxed{\textbf{(D) } 9}.</math>
    2 KB (395 words) - 22:29, 3 December 2024
  • {{AMC10 box|year=2016|ab=A|num-b=9|num-a=11}}
    2 KB (335 words) - 04:52, 18 December 2024
  • label("$7$",(9/2,5),dir(90)); label("$1$",(0,9/2),dir(180));
    8 KB (1,016 words) - 23:17, 30 December 2023
  • {{AMC12 box|year=2016|ab=A|num-b=9|num-a=11}}
    2 KB (402 words) - 13:54, 25 June 2023
  • ...ampionnat international des jeux mathématiques et logiques]] for all aged 9+ (expanding and looking for US representatives)
    4 KB (417 words) - 13:10, 29 December 2024
  • *[https://centralmathmeet.yolasite.com/ Central Math Meet](grades 9 - 12)
    4 KB (503 words) - 06:50, 17 September 2024
  • ...]], (grades 4-12). It is divided into three divisions, grades 4-6, 7-8 and 9-12. The contest features an individual competition, where participants take ...at KU]], (grades 5-12). It is divided into three divisions, grades 5-6, 7-9 and 10-12, and is a 40 minute, 5 question test. First, second and third in
    3 KB (473 words) - 15:11, 16 June 2020
  • *[[Kettering Mathematics Olympiad]] designed for grades 9 through 12. [http://www.kettering.edu/%7Eacheng/Olympiad/olympiad.html webs
    2 KB (305 words) - 00:06, 30 November 2023
  • ...sant Valley Excellence in Mathematics]] (grades 6-8)-changed from grades 6-9 in 2010 *[[Junior High Excellence in Mathematics Contest]] -- grades 7-9. [http://www.stlcc.cc.mo.us/fv/math/Excellence%20in%20Math%20Contest.htm we
    3 KB (432 words) - 14:59, 16 June 2020
  • *[[Doane triMATHlon Math Contest]]. Takes place at Doane University for 9-12 graders, includes material up to Algebra II. [https://www.doane.edu/trim ...t]]. Consists of two problem solving rounds and a speed round - for grades 9-12.
    2 KB (200 words) - 09:11, 29 December 2020
  • ...xact answers are correct), and a physical estimation competition. Grades 4-9 compete in this format. Grades 10-12 are slightly different.
    2 KB (216 words) - 15:59, 17 December 2016
  • ...czky and Richard Rusczyk is recommended for avid math students in grades 7-9. ...hoczky and Richard Rusczyk is recommended for avid math students in grades 9-12.
    24 KB (3,198 words) - 19:44, 4 December 2024
  • * Getting Started is recommended for students grades 6 to 9. * Intermediate is recommended for students grades 9 to 12.
    7 KB (901 words) - 13:11, 6 January 2022
  • ...A/B, 1/2</u>: 7<br><u>Problem A/B, 3/4</u>: 8<br><u>Problem A/B, 5/6</u>: 9}}
    4 KB (623 words) - 12:11, 20 February 2024
  • =\frac{1}{2}+\frac{4}{4}+\frac{9}{8}+\frac{16}{16}+\cdots\ 2z=1+\frac{4}{2}+\frac{9}{4}+\frac{16}{8}+\cdots\
    1 KB (193 words) - 20:13, 18 May 2021
  • ==Overview=={{asy image|<math>1\,2\,3\,4\,5\,6\,7\,8\,9\,0</math>|right|The ten [[digit]]s making up <br /> the base ten number sys Algebra can be used to solve equations as simple as <math>3x=9</math> but in some cases so complex that mathematicians have not figured ho
    6 KB (875 words) - 09:59, 30 December 2024
  • *Average score: 9.74 *Average score: 9.43
    17 KB (1,900 words) - 19:38, 3 January 2025

View (previous 20 | next 20) (20 | 50 | 100 | 250 | 500)