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- == Problem == {{AIME box|year=2006|n=I|num-b=14|after=Last Problem}}8 KB (1,334 words) - 17:37, 15 December 2024
- == Problem == </asy></center><!-- Asymptote replacement for Image:2005_I_AIME-15.png by azjps -->5 KB (906 words) - 23:15, 6 January 2024
- == Problem == D((0,30)--(0,-10),Arrows(4));D((15,0)--(-25,0),Arrows(4));D((0,0)--MP("y=ax",(14,14 * (69/100)^.5),E),EndArrow12 KB (2,001 words) - 20:26, 23 July 2024
- == Problem == We approach the problem by [[recursion]]. We [[partition]] the positive integers into the sets9 KB (1,491 words) - 01:23, 26 December 2022
- == Problem == Now, consider the strip of length <math>1024</math>. The problem asks for <math>s_{941, 10}</math>. We can derive some useful recurrences f6 KB (899 words) - 20:58, 12 May 2022
- == Problem == <!-- [[Image:1983_AIME-15.png|200px]] -->20 KB (3,497 words) - 15:37, 27 May 2024
- == Problem == \frac{x^2}{15}+\frac{y^2}{7}-\frac{z^2}{9}-\frac{w^2}{33}=1\6 KB (1,051 words) - 19:35, 1 August 2024
- == Problem == [[Image:AIME 1985 Problem 15.png]]3 KB (548 words) - 21:40, 28 June 2024
- == Problem == <math>2a^2 + 5b^2 = - \frac {15}{2}ab \ \ \ \ (2)</math></div>11 KB (1,750 words) - 22:46, 5 March 2025
- == Problem == [[Image:1987 AIME-15a.png|360px]]5 KB (838 words) - 18:05, 19 February 2022
- == Problem == Re-stating the problem for clarity, let <math>S</math> be a [[set]] arranged in increasing order.7 KB (1,188 words) - 08:02, 15 August 2024
- == Problem == Now we'll apply these results to the problem at hand.14 KB (2,234 words) - 16:31, 22 December 2024
- == Problem == We first let the answer to this problem be <math>k.</math> Multiplying the first equation by <math>x</math> gives <4 KB (644 words) - 16:24, 28 May 2023
- == Problem == {{AIME box|year=1991|num-b=14|after=Last question}}4 KB (658 words) - 16:58, 10 November 2023
- == Problem == {{AIME box|year=1992|num-b=14|after=Last Question}}2 KB (358 words) - 01:54, 2 October 2020
- == Problem == {{AIME box|year=1993|num-b=14|after=Last question}}3 KB (503 words) - 23:14, 30 January 2025
- == Problem == ...[circumcenter]]s of <math>\triangle PAB, PBC, PCA</math>. According to the problem statement, the circumcenters of the triangles cannot lie within the interio4 KB (717 words) - 22:20, 3 June 2021
- == Problem == Think of the problem as a sequence of <tt>H</tt>'s and <tt>T</tt>'s. No two <tt>T</tt>'s can occ7 KB (1,087 words) - 13:09, 17 November 2024
- == Problem == ...\Longrightarrow \cos 2\theta = \frac{\sqrt{3}}{2} \Longrightarrow \theta = 15^{\circ}</math>. The answer is <math>\lfloor 1000r \rfloor = \left\lfloor 105 KB (710 words) - 21:04, 14 September 2020
- == Problem == [[Image:1997 AIME-15a.PNG|center]]5 KB (811 words) - 21:39, 20 July 2024
Page text matches
- ...e many tools in a good geometer's arsenal. A very large number of geometry problems can be solved by building right triangles and applying the Pythagorean Theo <cmath>8-15-17</cmath>6 KB (978 words) - 12:02, 6 March 2025
- \x+5-13+4x+20&\ge 3x+15 The problem here is that we multiplied by <math>x+5</math> as one of the last steps. W12 KB (1,806 words) - 06:07, 19 June 2024
- ...ed States at the [[International Mathematics Olympiad]] (IMO). While most AIME participants are high school students, some bright middle school students a High scoring AIME students are invited to take the prestigious [[United States of America Mat5 KB (669 words) - 17:19, 11 March 2025
- ...The three top teams usually all place in the top 20, often even in the top 15 or 10. * Performance on problems at practice sessions.22 KB (3,532 words) - 11:25, 27 September 2024
- ...d only once. In particular, memorizing a formula for PIE is a bad idea for problem solving. ==== Problem ====9 KB (1,703 words) - 01:20, 7 December 2024
- * <math>15! = 1307674368000</math> ==Problems==10 KB (809 words) - 16:40, 17 March 2024
- ...contains the full set of test problems. The rest contain each individual problem and its solution. * [[2006 AIME II Problems]]1 KB (133 words) - 12:32, 22 March 2011
- In contest problems, Fermat's Little Theorem is often used in conjunction with the [[Chinese Re == Problems ==15 KB (2,618 words) - 12:03, 19 February 2025
- == Problems == ...e integers. Determine <math>p + q</math>. ([[Mock AIME 3 Pre 2005 Problems/Problem 7|Source]])3 KB (543 words) - 19:35, 29 October 2024
- == Problems == * [[1991 AIME Problems/Problem 12]]1 KB (179 words) - 19:41, 3 January 2025
- This is a problem where constructive counting is not the simplest way to proceed. This next e ...proceed with the construction. If we were to go like before and break the problem down by each box, we'd get a fairly messy solution.13 KB (2,018 words) - 15:31, 10 January 2025
- ==Problems== ...prime integers, find <math> p+q. </math> ([[2005 AIME II Problems/Problem 15|Source]])5 KB (892 words) - 21:52, 1 May 2021
- label("d",(15,0),(0,-1)); ==Problems==6 KB (1,003 words) - 00:02, 20 May 2024
- ==Problems== \qquad \mathrm{(B) \ } 8/\sqrt{15}4 KB (658 words) - 21:52, 4 February 2025
- pair A=(15,15),B=(30,15),C=(30,30),D=(15,30),a=(60,60),b=(120,60),c=(120,120),d=(60,120); == Practice Problem ==3 KB (533 words) - 13:51, 2 September 2024
- == Problems == ...rline{MC}</math> that lies outside of the circle. ([[2020 AMC 12B Problems/Problem 10|Source]])5 KB (948 words) - 17:04, 21 February 2025
- ...contains the full set of test problems. The rest contain each individual problem and its solution. * [[2004 AIME I Problems]]1 KB (135 words) - 18:15, 19 April 2021
- ...contains the full set of test problems. The rest contain each individual problem and its solution. * [[2004 AIME II Problems]]1 KB (135 words) - 12:24, 22 March 2011
- ...contains the full set of test problems. The rest contain each individual problem and its solution. * [[2005 AIME I Problems]]1 KB (154 words) - 12:30, 22 March 2011
- ...contains the full set of test problems. The rest contain each individual problem and its solution. * [[2006 AIME I Problems]]1 KB (135 words) - 12:31, 22 March 2011
