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- 2 KB (302 words) - 00:57, 18 October 2024
- ...te|[[2001 AMC 12 Problems|2001 AMC 12 #1]] and [[2001 AMC 10 Problems|2001 AMC 10 #3]]}} ...\textbf{(C)}\ 3S + 6 \qquad\textbf{(D)}\ 2S + 6 \qquad \textbf{(E)}\ 2S + 12</math>904 bytes (136 words) - 15:10, 15 July 2024
- ...te|[[2001 AMC 12 Problems|2001 AMC 12 #2]] and [[2001 AMC 10 Problems|2001 AMC 10 #6]]}}1,007 bytes (165 words) - 19:31, 27 October 2024
- ...te|[[2001 AMC 12 Problems|2001 AMC 12 #3]] and [[2001 AMC 10 Problems|2001 AMC 10 #9]]}}2 KB (221 words) - 20:40, 15 July 2024
- ...te|[[2000 AMC 12 Problems|2000 AMC 12 #1]] and [[2000 AMC 10 Problems|2000 AMC 10 #1]]}} [[Category:Introductory Algebra Problems]]2 KB (320 words) - 18:37, 30 November 2024
- [[AMC 12]] problems and solutions. | 2024 || [[2024_AMC_12A | AMC 12A]] || [[2024_AMC_12B | AMC 12B]]2 KB (264 words) - 17:26, 8 November 2024
- {{AMC12 Problems|year=2000|ab=}} [[2000 AMC 12 Problems/Problem 1|Solution]]13 KB (1,948 words) - 09:35, 16 June 2024
- {{AMC12 Problems|year=2001|ab=}} ...2\qquad \text{(C)}\ 3S + 6 \qquad\text{(D)} 2S + 6 \qquad \text{(E)}\ 2S + 12</math>13 KB (1,957 words) - 11:53, 24 January 2024
- [[Category:Introductory Algebra Problems]]1 KB (239 words) - 21:20, 17 October 2020
- ...[2005 AMC 12B Problems|2005 AMC 12B #12]] and [[2005 AMC 10B Problems|2005 AMC 10B #16]]}} [[Category:Introductory Algebra Problems]]2 KB (322 words) - 01:57, 11 November 2024
- <!-- [[Image:2006 AMC 10A-12.GIF]] --> MP('8', (16,-12),W);3 KB (424 words) - 09:14, 17 December 2021
- ...2A Problems|2006 AMC 12A #12]] and [[2006 AMC 10A Problems/Problem 14|2006 AMC 10A #14]]}} D((12,-10)--(12,10)); MP('20',(12,0),E);2 KB (292 words) - 10:56, 17 December 2021
- [[Category:Introductory Algebra Problems]]1 KB (220 words) - 19:07, 27 November 2023
- ...ft(\frac{1}{12}\right)^{12} \qquad \textbf{(B) } \left(\frac{1}{6}\right)^{12} \qquad \textbf{(C) } 2\left(\frac{1}{6}\right)^{11} \qquad \textbf{(D) } \ ...ity is <math>\dfrac{3}{6}\times\left(\dfrac{1}{6}\right)^{11}\times\dbinom{12}{1} = \dfrac{1}{2}\times\left(\dfrac{1}{6}\right)^{11}\times12=\left(\dfrac3 KB (385 words) - 13:03, 16 June 2022
- * Problems ** [[2001 AMC 12]]649 bytes (76 words) - 19:56, 15 February 2011
- ...te|[[2000 AMC 12 Problems|2000 AMC 12 #2]] and [[2000 AMC 10 Problems|2000 AMC 10 #2]]}} [[Category:Introductory Algebra Problems]]1 KB (171 words) - 18:37, 30 November 2024
- ...te|[[2000 AMC 12 Problems|2000 AMC 12 #3]] and [[2000 AMC 10 Problems|2000 AMC 10 #3]]}} [[Category:Introductory Algebra Problems]]1 KB (177 words) - 23:36, 14 July 2024
- ...te|[[2000 AMC 12 Problems|2000 AMC 12 #5]] and [[2000 AMC 10 Problems|2000 AMC 10 #9]]}} [[Category:Introductory Algebra Problems]]1 KB (232 words) - 23:20, 5 September 2024
- ...0 AMC 12 Problems|2000 AMC 12 #8]] and [[2000 AMC 10 Problems|2000 AMC 10 #12]]}} ...ecursion from solution 1, we see that the first differences of <math>4, 8, 12, ...</math> form an arithmetic progression, and consequently that the secon8 KB (1,221 words) - 10:34, 27 November 2024
- ...te|[[2000 AMC 12 Problems|2000 AMC 12 #6]] and [[2000 AMC 10 Problems|2000 AMC 10 #11]]}} {{AMC10 box|year=2000|num-b=10|num-a=12}}2 KB (244 words) - 01:47, 13 August 2024
Page text matches
- ...e many tools in a good geometer's arsenal. A very large number of geometry problems can be solved by building right triangles and applying the Pythagorean Theo <cmath>5-12-13</cmath>5 KB (885 words) - 22:03, 5 October 2024
- * [[American Mathematics Competitions]] (AMC) are the largest series of national high school competitions in the United **[[AMC 10]]5 KB (608 words) - 08:32, 17 November 2024
- ...tions]]. Look around the AoPSWiki. Individual articles often have sample problems and solutions for many levels of problem solvers. Many also have links to ...[https://www.tmasacademy.com/ace-the-amc10-12-free-book ACE The AMC 10 and 12 book]16 KB (2,192 words) - 22:06, 19 July 2024
- ...is recommended for students grades who are participating in contests like AMC 8/10 and Mathcounts. * Intermediate is recommended for students who can expect to pass the AMC 10/12.24 KB (3,198 words) - 19:44, 4 December 2024
- ...8 and below, hosted annually by the [[American Mathematics Competitions]] (AMC) to students all over the United States. ...more challenging [[AMC 10]] exam. However, there is no requirement for the AMC 10 besides the fact that you have to be 10<math>^\text{th}</math> grade or4 KB (576 words) - 18:36, 22 September 2024
- ...'''American Mathematics Contest 10''' ('''AMC 10'''), along with the [[AMC 12]], is one of the first exams in the series of exams used to challenge brigh High scoring AMC 10 and AMC 12 students are invited to take the [[American Invitational Mathematics Examin4 KB (586 words) - 16:48, 28 October 2024
- ...irst exam in the series of exams used to challenge bright students, grades 12 and below, on the path towards choosing the team that represents the United High scoring AMC 12 students are invited to take the more challenging [[American Invitational M4 KB (529 words) - 08:01, 24 July 2024
- ...ica Junior Mathematics Olympiad (USAJMO) for qualification from taking the AMC 10. ...rica]] (MAA). [[Art of Problem Solving]] (AoPS) is a proud sponsor of the AMC!8 KB (1,067 words) - 19:15, 24 October 2024
- ...sessions for discussion of the problems from each year's [[AMC 10]], [[AMC 12]], and [[AIME]] exams.989 bytes (130 words) - 15:20, 20 August 2020
- ...ion for American Math Contest, used to refer to the AMC 8, AMC 10, and AMC 12. == AMC Contests ==5 KB (696 words) - 02:47, 24 December 2019
- ...ions]] (AMC). [[Art of Problem Solving]] (AoPS) is a proud sponsor of the AMC and of the recent expansion of USAMO participants from around 250 to around ...on the USAMO have considerable experience both solving highly challenging problems and [[writing proofs]].6 KB (874 words) - 22:02, 10 November 2024
- ...are not planning on extending invites to new students unless scores on the AMC exams or the San Diego Math Olympiad (SDMO) are particularly high. * Performance on problems at practice sessions.22 KB (3,532 words) - 10:25, 27 September 2024
- ...nd make the equation factorable. It can be used to solve more than algebra problems, sometimes going into other topics such as number theory. == Fun Practice Problems ==4 KB (678 words) - 12:12, 26 November 2024
- == Example Problems == * (AMC 12 2005) There are two values of <math>a</math> for which the equation <math>44 KB (768 words) - 16:56, 24 June 2024
- In contest problems, Fermat's Little Theorem is often used in conjunction with the [[Chinese Re ...ts, x_n) = \left(a + \frac 12 - x_1, a + \frac 12 - x_2, \ldots, a + \frac 12 - x_p\right),</cmath></center><br>16 KB (2,660 words) - 22:42, 28 August 2024
- ...we would be trying to calculate <math>\frac 3{\frac 13 + \frac 16 - \frac 12} = \frac 30</math>, which is obviously problematic. == Practice Problems ==1 KB (196 words) - 23:49, 5 January 2021
- It's a bad idea to stay up all night solving problems or playing video games because it's easy to get drowsy during the test. Ge ...l aid can help solvers visualize and look for clues. Even in non-geometry problems, drawing pictures can help formulate ideas.3 KB (544 words) - 13:14, 26 August 2024
- ''[[2001 AMC 12 Problems/Problem 16 | 2001 AMC 12 Problem 16]]: A spider has one sock and one shoe for each of its eight legs ''[[2004 AIME I Problems/Problem 6 | 2004 AIME I Problem 6]]: An integer is called snakelike if its12 KB (1,898 words) - 07:42, 19 August 2024
- ...don't want, then subtracts that from the total number of possibilities. In problems that involve complex or tedious [[casework]], complementary counting is oft ''[[2006 AMC 10A Problems/Problem 21 | 2006 AMC 10A Problem 21]]: How many four-digit positive integers have at least one d8 KB (1,192 words) - 16:20, 16 June 2023
- ...te|[[2001 AMC 12 Problems|2001 AMC 12 #1]] and [[2001 AMC 10 Problems|2001 AMC 10 #3]]}} ...\textbf{(C)}\ 3S + 6 \qquad\textbf{(D)}\ 2S + 6 \qquad \textbf{(E)}\ 2S + 12</math>904 bytes (136 words) - 15:10, 15 July 2024