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  • ...- (180 - \angle BAC) - (90 + \angle BAC) = 90</math>. Then <math>\triangle AFO</math> is a right triangle. ...oint of <math>AO</math>, which is also the circumcenter of <math>\triangle AFO</math>, so <math>A,P,N,F,O</math> all lie on a circle.
    18 KB (3,253 words) - 18:27, 1 December 2021
  • ...e short leg of <math>AFO</math> is <math>r</math>. Because <math>\triangle AFO</math> ~ <math>\triangle ABC</math>, we have <math>r/(12 - r) = 5/13</math>
    5 KB (762 words) - 03:46, 22 April 2024
  • Construct <math>EF</math>, <math>FG</math>. <math>\angle AFO = \angle AEO = 90^{\circ}</math>, so <math>AEOF</math> is cyclic. Similarly
    16 KB (2,517 words) - 20:22, 31 January 2024
  • ~Afo
    16 KB (2,240 words) - 23:16, 26 January 2024
  • ~Afo
    14 KB (2,569 words) - 09:28, 28 March 2024