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  • ...- (180 - \angle BAC) - (90 + \angle BAC) = 90</math>. Then <math>\triangle AFO</math> is a right triangle. ...oint of <math>AO</math>, which is also the circumcenter of <math>\triangle AFO</math>, so <math>A,P,N,F,O</math> all lie on a circle.
    20 KB (3,565 words) - 10:54, 1 May 2024
  • Construct <math>EF</math>, <math>FG</math>. <math>\angle AFO = \angle AEO = 90^{\circ}</math>, so <math>AEOF</math> is cyclic. Similarly
    17 KB (2,753 words) - 13:30, 8 December 2024
  • ~Afo
    16 KB (2,240 words) - 22:16, 26 January 2024
  • ~Afo
    16 KB (2,890 words) - 06:27, 29 December 2024