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- ...t the theorem so later, the mathematician named ARay10 proved it again: [b]Proof of the MAAS theorem[/b]: The GMAAS theorem states that for every math probl ...ntion him being a cat. EDIT: The above post is irrelevant. Gmaas hides his identity under the alias Grayson Maas. EDIT: Gmaas us everything yet nothing. EDIT:69 KB (11,805 words) - 19:49, 18 December 2019
- Proof: Here is one of my favorite proofs of this with vector geometry. Lagrange's Identity states that <math>|\vec{a}|^2|\vec{b}|^2-(\vec{a}\cdot\vec{b})^2=|\vec{a}\t11 KB (1,840 words) - 05:50, 31 December 2024
- ...the theorem, so later, the mathematician named ARay10 proved it again. '''Proof of the Almighty Gmaas theorem''': The Almighty Gmaas theorem states that f ...er. EDIT: Almighty Gmaas has now been proven to be GeorgeNotFound's secret identity.99 KB (14,093 words) - 18:55, 2 January 2025
- [b]Proof of the MAAS theorem[/b]: ...ntion him being a cat. EDIT: The above post is irrelevant. Gmaas hides his identity under the alias Grayson Maas. EDIT: Gmaas us everything yet nothing. EDIT:89 KB (15,003 words) - 22:20, 6 January 2025
- [[2017 AIME I Problems/Problem 11]] Alternative Proof [[Cross-Segment Identity Proof]] Supplement10 KB (1,116 words) - 11:37, 11 June 2024
- ...t the theorem so later, the mathematician named ARay10 proved it again: [b]Proof of the MAAS theorem[/b]: The GMAAS theorem states that for every math probl ...ntion him being a cat. EDIT: The above post is irrelevant. Gmaas hides his identity under the alias Grayson Maas. EDIT: Gmaas us everything yet nothing. EDIT:69 KB (11,828 words) - 18:26, 3 September 2024