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  • ...al math competition (where only exact answers are correct), and a physical estimation competition. Grades 4-9 compete in this format. Grades 10-12 are slightly d
    2 KB (216 words) - 15:59, 17 December 2016
  • ===Estimation=== In some problems, estimation can narrow down the possible values. It can also be used to check if an an
    3 KB (544 words) - 13:14, 26 August 2024
  • ==Solution 2 (estimation)==
    6 KB (1,037 words) - 22:32, 9 November 2024
  • (The remainder after this term is positive by the Remainder Estimation Theorem. Since the repeating decimal of <math>\dfrac{10}{7}</math> repeats
    2 KB (316 words) - 18:15, 28 December 2024
  • ==Error estimation==
    2 KB (299 words) - 10:26, 15 February 2025
  • ==Solution 6 (Answer Choices & Estimation)==
    10 KB (1,520 words) - 05:37, 20 September 2024
  • ...s. Every ten questions, there is an estimation question which requires the estimation answer to be within <math>5\%</math> of the number.
    5 KB (801 words) - 11:47, 23 September 2023
  • The answer choices are relatively far apart, so we can use estimation to solve this problem. <math>2100/60</math> is around <math>35</math> hours
    2 KB (253 words) - 10:03, 18 November 2024
  • Estimation of <math>\sqrt[^3\!]{2}</math>. Estimation of <math>\sqrt[^3\!]{4}</math>.
    13 KB (2,131 words) - 16:24, 11 October 2024
  • ...ath> and <math> 87431 </math>. To determine the answer we will have to use estimation and the first two digits of the numbers.
    3 KB (484 words) - 14:49, 27 December 2023
  • == Solution 7 (Estimation and Intuitive Function Analysis)== ...n good strategy for getting an intuition for the problem. In this problem, estimation happens to be a valid solution path. It isn't a proof, but given the constr
    10 KB (1,702 words) - 12:03, 17 August 2024
  • ...<math>B</math> can not be higher for a given <math>a</math>. Third, use [[estimation]] to approximate the lower bound for a given <math>a</math>.
    3 KB (446 words) - 04:07, 16 June 2018
  • ...ger less than <math>\frac{1}{2015}</math>. Therefore, the closest possible estimation is <math>\boxed{090}</math>. We can check this by adding in our corners and
    4 KB (653 words) - 16:40, 1 July 2023
  • ...m event and contributes to the over-all team score. MathFest also includes estimation games and occasionally other activities, such as an escape room (offered 20
    1 KB (158 words) - 19:16, 9 August 2017
  • ...m event and contributes to the over-all team score. MathFest also includes estimation games and occasionally other activities, such as an escape room (offered 20
    1 KB (158 words) - 19:20, 9 August 2017
  • ...> to <math>\textbf{(D)},</math> we have <math>f(-1) = -2018</math> and the estimation becomes <math>x_{1}=-1+{\frac {2018}{f'(-1)}}.</math> Thus we need to minim
    12 KB (2,016 words) - 05:58, 29 July 2024
  • Now we do some estimation. Notice that <math>2^{20} = 1024^2</math>, which means that <math>2^{20}</m
    6 KB (921 words) - 22:23, 11 September 2024
  • ...h> are <math>\textbf{(A)}</math> and <math>\textbf{(D)}.</math> By a quick estimation, <math>\textbf{(A)}</math> is too small, leaving us with <math>\boxed{\text
    3 KB (498 words) - 06:59, 13 November 2023
  • We know that <math>10(90) = 900</math> and <math>10(100) = 1000.</math> Quick estimation reveals that this sum is in between these two numbers, so the only answer a
    891 bytes (111 words) - 07:36, 7 January 2023
  • == Solution 6 (Desperate Final Effort - Estimation Guess) ==
    7 KB (1,111 words) - 20:00, 21 February 2024

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