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- ...>\triangle HGJ</math> and <math>\triangle HLJ</math>, and we know <math>JG=HL=1</math>, so we must have <math>\triangle HGJ\cong\triangle JLH</math> by H ...efore, <math>GA=\sqrt{3}/2</math> and <math>DG=1-\sqrt{3}/2</math>. But by similarity, <math>\triangle DHG</math> is also a 30-60-90 triangle, hence <math>DH=\sq8 KB (1,307 words) - 01:07, 1 January 2023
- ...math> to <math>P</math> and <math>Q</math>, as seen in the diagram. By SAS Similarity, we find that <math>\triangle CBA \sim \triangle CQM</math> and <math>\tria ...et <math>S</math> be on <math>AD</math> where <math>IS \perp AD</math>. By HL Congruency, <math>\triangle ITQ \cong \triangle ISP</math>, so <math>PS = Q3 KB (586 words) - 22:47, 8 January 2019
- ...th>AB</math>, and let <math>F</math> be the point of intersection. By SAS Similarity, <math>\triangle AOB \sim \triangle COD</math>, so <math>\angle BAO = \angl By HL Congruency, <math>\triangle AOF \cong \triangle BOF</math>, so <math>AF = B4 KB (710 words) - 13:01, 23 December 2019
- <math>\text{SSS Similarity states that if there are two triangles (shown below), then if }\dfrac{\over [[Category:Similarity]]795 bytes (113 words) - 13:02, 29 December 2023
- ...s some number. Furthermore, <math>XM=MY=\frac{\sqrt{6}}{2}</math>. By [[AA similarity]], <math>\triangle MXC \sim \triangle BAC</math>, so <math>\frac{MX}{MC}=\f3 KB (508 words) - 15:54, 19 July 2024