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- ...combinatorics, and number theory, along with sets of accompanying practice problems at the end of every section. ...88606&sprefix=after+school+maths+%2Caps%2C268&sr=8-2 100 Challenging Maths Problems]23 KB (3,038 words) - 18:33, 15 February 2025
- ...ltiple Choice|difficulty=1 - 1.5|breakdown=<u>Problems 1 - 12</u>: 1<br><u>Problems 13 - 25</u>: 1.5}} The AMC 8 exam is a 25 problem exam. There are 40 minutes given in the exam. Problems increase in difficulty as the problem number increases. Students are not pe4 KB (584 words) - 23:33, 15 January 2025
- == Introductory Examples == The exact same logic applies to the third digit; it can be any of the <math>8</math> digits exce13 KB (2,018 words) - 14:31, 10 January 2025
- By logic <math>s=3</math> and <math>sr=5 \implies r=5/3.</math> [[Category:Introductory Geometry Problems]]6 KB (958 words) - 22:29, 28 September 2023
- ==Problems== ===Introductory===11 KB (2,019 words) - 16:20, 7 July 2024
- ...</math> won't be equal to the <math>\sqrt{n}</math>. We can apply the same logic to <math>\sqrt{n+48}</math>, and since we also the difference between two c [[Category:Introductory Number Theory Problems]]8 KB (1,245 words) - 09:53, 4 February 2025
- Not too bad with some logic and the awesome guess and check. Let <math>A=6</math>. Then let <math>B=7,E [[Category:Introductory Algebra Problems]]3 KB (434 words) - 10:01, 22 August 2024
- *Individual Round: The individual round consists of 15 problems, numbered I1-I15. *Team Round: The team round consists of 10 problems, numbered T1-T10.1 KB (183 words) - 12:57, 15 October 2018
- {{duplicate|[[2004 AMC 12A Problems|2004 AMC 12A #17]] and [[2004 AMC 10A Problems/Problem 24|2004 AMC 10A #24]]}} ~Azjps (Fundamental Logic)2 KB (233 words) - 07:14, 6 September 2021
- ~Azjps (Fundamental Logic) ~Rbhale12 (Fundamental Logic)4 KB (663 words) - 06:32, 4 November 2022
- ...ude of <math>\triangle{CBY}</math> so <math>BC = BY.</math> Using the same logic on <math>\triangle{BCX}</math> gives <math>BC = BX \iff BYXC</math> is a rh [[Category:Introductory Geometry Problems]]13 KB (2,248 words) - 13:44, 5 January 2025
- ...your current abilities, you may want to start out with different practice problems, different books, and different areas of the forums. You should also try to ...Alcumus]] tool constantly to practice all of these topics. When you answer problems incorrectly or take a long time to answer one, reread the part in the book14 KB (2,062 words) - 10:59, 15 January 2025
- ...{AD}{CD}=3=\frac{GA}{HC}</math> which means <math>HC=5</math>. By the same logic, <math>JE=3</math>, so <math>\frac{HC}{JE}=\frac{5}{3}</math>. [[Category:Introductory Geometry Problems]]3 KB (439 words) - 21:15, 9 June 2023
- We can solve this problem using logic. [[Category:Introductory Number Theory Problems]]3 KB (457 words) - 14:02, 4 April 2021
- [[Category:Introductory Number Theory Problems]] [[Category:Logic Problems]]1 KB (170 words) - 15:44, 24 May 2023
- [[Category: Introductory Geometry Problems]] ...gorean theorem, <cmath>MR = \sqrt{1^2+2^2} = \sqrt{5}.</cmath> By the same logic, <math>MQ=\sqrt{5}</math>. The area of <math>\triangle QMR</math> is the ar12 KB (1,868 words) - 02:36, 30 September 2023
- Using logic, <math>a+b+c= 10</math>, therefore <math>b+a+1</math>(from the carry over)< [[Category:Introductory Algebra Problems]]1 KB (203 words) - 12:06, 16 August 2020
- ==Video Solution 2 (Logic and Word Analysis)== [[Category:Introductory Geometry Problems]]2 KB (322 words) - 09:55, 18 September 2024
- ...there is a specific point closest to the center of the circle. Using some logic, we realize that as long as said furthest point is not inside or on the gra [[Category:Introductory Geometry Problems]]9 KB (1,646 words) - 22:56, 1 November 2024
- ...is divisible by 3, then the number is also divisible by 3, we reverse that logic to say that <math>N\equiv 19+20+21+22+...+91+92\pmod{3}</math>, and adding [[Category: Introductory Number Theory Problems]]2 KB (342 words) - 12:19, 4 January 2021