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  • ==Problem== Given that <math> iz^2=1+\frac 2z + \frac{3}{z^2}+\frac{4}{z ^3}+\frac{5}{z^4}+\cdots</math> and <math>z=n\pm \sqrt{-i},</math> find <math> \lfloor
    912 bytes (145 words) - 09:51, 4 April 2012
  • == Problem == ...y tangent to a larger circle <math>\omega_2</math> of radius <math>12\sqrt{2}</math> such that the center of <math>\omega_2</math> lies on <math>\omega_
    752 bytes (117 words) - 20:16, 8 October 2014

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  • ...ed States at the [[International Mathematics Olympiad]] (IMO). While most AIME participants are high school students, some bright middle school students a High scoring AIME students are invited to take the prestigious [[United States of America Mat
    8 KB (1,062 words) - 18:04, 17 January 2025
  • pair A=(-1,5), B=(-4,-1), C=(4,-1), D, O; D = (B+C)/2;
    4 KB (658 words) - 15:19, 28 April 2024
  • ...ake. Sometimes, the administrator may ask other people to sign up to write problems for the contest. ...AMC]] competition. There is no guarantee that community members will make Mock AMCs in any given year, but there probably will be one.
    51 KB (6,175 words) - 20:41, 27 November 2024
  • The '''Mock AIME 1 2005-2006''' was written by [[Art of Problem Solving]] community member paladin8. * [[Mock AIME 1 2005-2006/Answer Key|Answer Key]]
    1 KB (135 words) - 16:41, 21 January 2017
  • The '''Mock AIME 1 2006-2007''' was written by [[Art of Problem Solving]] community member Altheman. * [[Mock AIME 1 2006-2007/Problems|Entire Exam]]
    1 KB (155 words) - 15:06, 3 April 2012
  • The '''Mock AIME 2 2006-2007''' was written by [[Art of Problem Solving]] community member 4everwise. * [[Mock AIME 2 2006-2007 Problems|Entire Exam]]
    1 KB (145 words) - 09:55, 4 April 2012
  • ...place 10 into one box and 2 into a second. <math>7 \cdot \frac{6\cdot 5}{2} = 105</math> place 10 into one box and 1 into each of two others. Thus, t *[[Mock AIME 1 2006-2007 Problems/Problem 1 | Previous Problem]]
    1 KB (188 words) - 14:53, 3 April 2012
  • ...</math> has all of its [[vertex| vertices]] on the [[parabola]] <math>y=x^{2}</math>. The slopes of <math>AB</math> and <math>BC</math> are <math>10</ma ...h>a = (a + b) - b = 12</math>, so our three vertices are <math>(-7, 49), (-2, 4)</math> and <math>(12, 144)</math>.
    1 KB (244 words) - 14:21, 5 November 2012
  • ==Problem== ...}</math> be the common [[tangent line]] of <math>P_{1}</math> and <math>P_{2}</math> that has a [[rational number | rational]] [[slope]]. If <math>\math
    3 KB (460 words) - 14:52, 3 April 2012
  • ==Problem== ...3</math>. Point <math>E</math> is such that <math>CE=1</math> and <math>AE=5</math>. Construct point <math>F</math> on segment <math>BC</math> such that
    3 KB (518 words) - 15:54, 25 November 2015
  • ==Problem== Let <math>ABCDE</math> be a convex pentagon with <math>\frac{AB}{\sqrt{2}}=BC=CD=DE</math>, <math>\angle ABC=150^\circ</math>, <math>\angle BCD=75^\
    1 KB (244 words) - 13:54, 21 August 2020
  • ==Problem== ...4r^{10}</math> so <math>r^{10} = 2^{-10}</math> and <math>r = \frac \omega 2</math>, where <math>\omega</math> can be any of the tenth [[roots of unity]
    5 KB (744 words) - 18:46, 20 October 2020
  • ==Problem== ...and <math>CA</math> have lengths <math>3</math>, <math>4</math>, and <math>5</math>, respectively. Let the incircle, circle <math>I</math>, of <math>\tr
    1 KB (236 words) - 22:58, 24 April 2013
  • ==Problem== ...math>d_{2}=2</math>, <math>d_{3}=3</math>, <math>d_{4}=-7</math>, <math>d_{5}=13</math>, and <math>d_{6}=-16</math>, find <math>d_{7}</math>.
    3 KB (568 words) - 14:50, 3 April 2012
  • ==Problem 1== [[Mock AIME 1 2006-2007 Problems/Problem 1|Solution]]
    8 KB (1,355 words) - 13:54, 21 August 2020
  • == Problem == ...ll as possible and <math>i = \sqrt{-1}</math>. Compute <math>\frac{b^2}{a^2}</math>.
    1 KB (240 words) - 09:50, 4 April 2012
  • == Problem == [[Image:Mock AIME 2 2007 Problem14.jpg]]
    2 KB (284 words) - 09:53, 4 April 2012
  • ...s <math>\frac{a_ng_{n+1}}{r-1}-\frac{x_1}{r-1}-\frac{d(g_{n+1}-g_2)}{(r-1)^2}</math>, where <math>d</math> is the common difference of <math>a_n</math> <math>S_n=a_1g_1+(a_1+d)(g_1r)+(a_1+2d)(g_1r^2)+\ldots+(a_1+(n-1)d)(g_1r^{n-1})</math>
    2 KB (477 words) - 18:39, 17 August 2020
  • ==Problem== ...h>, we see that <math>f(1)=0, f(2)=0, f(3)=0, f(4)=1, f(5)=1, f(6)=2, f(7)=2,
    992 bytes (156 words) - 19:34, 27 September 2019
  • == Problem == ...th> and <math>f(101) = 0</math>). Evaluate the remainder when <math>f(1)+f(2)+\cdots+f(99)</math> is divided by <math>1000</math>.
    2 KB (209 words) - 11:43, 10 August 2019

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