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  • ...ake. Sometimes, the administrator may ask other people to sign up to write problems for the contest. ...AMC]] competition. There is no guarantee that community members will make Mock AMCs in any given year, but there probably will be one.
    51 KB (6,175 words) - 20:41, 27 November 2024
  • The '''Mock AIME 1 2005-2006''' was written by [[Art of Problem Solving]] community member paladin8. * [[Mock AIME 1 2005-2006/Answer Key|Answer Key]]
    1 KB (135 words) - 16:41, 21 January 2017
  • The '''Mock AIME 1 2006-2007''' was written by [[Art of Problem Solving]] community member Altheman. * [[Mock AIME 1 2006-2007/Problems|Entire Exam]]
    1 KB (155 words) - 15:06, 3 April 2012
  • The '''Mock AIME 2 2006-2007''' was written by [[Art of Problem Solving]] community member 4everwise. * [[Mock AIME 2 2006-2007 Problems|Entire Exam]]
    1 KB (145 words) - 09:55, 4 April 2012
  • ...al{S}</math>, we have that <math>\star (n)=12</math> and <math>0\le n< 10^{7}</math>. If <math>m</math> is the number of elements in <math>\mathcal{S}</ ...box and 1 into each of two others. Thus, this gives us <math>m = 18564 - 7 - 42 - 42 - 105 = 18368</math> so <math>\star(m) = 1 + 8 + 3 + 6 + 8 = 026<
    1 KB (188 words) - 14:53, 3 April 2012
  • ...> and <math>a = (a + b) - b = 12</math>, so our three vertices are <math>(-7, 49), (-2, 4)</math> and <math>(12, 144)</math>. *[[Mock AIME 1 2006-2007 Problems/Problem 3 | Previous Problem]]
    1 KB (244 words) - 14:21, 5 November 2012
  • ==Problem== ...eatest common divisor]] of the three numbers is 1, <math>a = 1, b = 5, c = 5</math> and <math>a + b + c = 011</math>.
    3 KB (460 words) - 14:52, 3 April 2012
  • ==Problem== .../2), B=expi(pi*5/12), C=(0,0), D=expi(0), E=expi(0)+expi(pi/12), P=expi(pi*5/12)+expi(0);
    1 KB (244 words) - 13:54, 21 August 2020
  • ==Problem== ...and <math>CA</math> have lengths <math>3</math>, <math>4</math>, and <math>5</math>, respectively. Let the incircle, circle <math>I</math>, of <math>\tr
    1 KB (236 words) - 22:58, 24 April 2013
  • ==Problem== ...7</math>, <math>d_{5}=13</math>, and <math>d_{6}=-16</math>, find <math>d_{7}</math>.
    3 KB (568 words) - 14:50, 3 April 2012
  • ==Problem 1== [[Mock AIME 1 2006-2007 Problems/Problem 1|Solution]]
    8 KB (1,355 words) - 13:54, 21 August 2020
  • ==Problem== ...math>, we see that <math>f(1)=0, f(2)=0, f(3)=0, f(4)=1, f(5)=1, f(6)=2, f(7)=2,
    992 bytes (156 words) - 19:34, 27 September 2019
  • == Problem == ...sors of <math>n</math> less than <math>50</math> (e.g. <math>f(12) = 2+3 = 5</math> and <math>f(101) = 0</math>). Evaluate the remainder when <math>f(1)
    2 KB (209 words) - 11:43, 10 August 2019
  • In the context of problem-solving, the characteristic polynomial is often used to find closed forms f ...can be solved for each constant. Refer to the [[#Introductory|introductory problems]] below to see an example of how to do this. In particular, for the Fibonac
    19 KB (3,412 words) - 13:57, 21 September 2022
  • ...contains the full set of test problems. The rest contain each individual problem and its solution. The Mock AIME 5 2006-2007 was written by Art of Problem Solving community member Altheman.
    1 KB (172 words) - 13:37, 3 July 2012
  • ...contains the full set of test problems. The rest contain each individual problem and its solution. The Mock AIME 6 2006-2007 was written by Art of Problem Solving community member paladin8.
    1 KB (172 words) - 13:39, 3 July 2012
  • ...contains the full set of test problems. The rest contain each individual problem and its solution. The Mock AIME 7 2006-2007 was written by Art of Problem Solving community member Altheman.
    1 KB (160 words) - 13:44, 3 July 2012
  • ==Problem 1== [[Mock AIME 6 2006-2007 Problems/Problem 1|Solution]]
    7 KB (1,173 words) - 20:04, 7 December 2018
  • == Problem == {{Mock AIME box|year=2005-2006|n=5|source=76847|num-b=5|num-a=7}}
    522 bytes (77 words) - 20:17, 8 October 2014
  • == Problem == {{Mock AIME box|year=2005-2006|n=5|source=76847|num-b=7|num-a=9}}
    511 bytes (79 words) - 20:18, 8 October 2014

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