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  • ...th 4 points, and the remaining problems are worth 5 points. No penalty or partial credit is given to unanswered or incorrectly answered questions, so it will ...concepts (logs, complex numbers, trigonometry, set notation, or summation/product notation) whereas AMC 12 does.
    6 KB (949 words) - 21:33, 17 November 2024
  • ...that changes in momentum (acceleration) of fluid particles are simply the product of changes in pressure and dissipative viscous forces (similar to friction) The Navier-Stokes equations are partial [[differential equations]] which describe the motion of a fluid. These equa
    3 KB (553 words) - 21:08, 2 May 2022
  • ...\tilde{A}=\int \int \left(\frac{\partial M}{\partial x}-\frac{\partial L}{\partial y}\right)dxdy=\oint(Ldx+Mdy)</cmath> ...{c}=(x_3-x_1 \quad y_3-y_1 \quad 0)</math> then by definition of the cross product <math>[ABC]=\frac{||\vec{b} \times \vec{c}||}{2}=\frac{1}{2}||(0 \quad 0 \q
    8 KB (1,360 words) - 17:09, 28 September 2024
  • ...sequence, the 10, 20, 30, ..., 90 becomes 1, 2, 3, 4, 1, 6, 7, 8, 9, whose product is 1 mod 25. We have accounted for 9 of the 21 2's thus we still need to mu ...rs four times in <math>\frac{90!}{10^{21}}</math>, the fourth being only a partial
    10 KB (1,553 words) - 19:12, 14 October 2024
  • (The answer will be a product of powers of eight distinct primes.) may be assigned partial credit if you have accurately found most of them, even if you do not
    6 KB (1,037 words) - 14:12, 20 August 2020
  • **Product, quotient, and chain rule ***Partial fraction decomposition
    5 KB (665 words) - 14:27, 3 March 2016
  • What is the value of the product ...aching 1/2, so we guess that 1/2 is the limit/asymptote, and so any finite product would be slightly larger than 1/2. Therefore, by process of elimination and
    4 KB (583 words) - 19:13, 31 December 2024
  • ...{2^{n+1}} - 2^{2^{n+1}}</math>. As we don't have to prove this, we get the product is <math>3^{2^7} - 2^{2^7} = 3^{128} - 2^{128}</math>, and click <math>\box
    8 KB (1,189 words) - 02:09, 31 October 2024
  • In mathematics, a telescoping series is a series whose partial sums eventually only have a finite number of terms after cancellation. This *When simplified the product <math>\left(1-\frac13\right)\left(1-\frac14\right)\left(1-\frac15\right)\cd
    3 KB (558 words) - 15:37, 21 July 2024
  • A '''partial derivative''' of a [[function]] of many [[variable|variables]] is the [[der ...e, if <math>f(x,y,z) = xy + z(x + y),</math> then <math>f</math> has three partial derivatives at the point <math>(3,4,12)</math>:
    4 KB (734 words) - 19:51, 4 May 2022
  • Begin with a [[partial product]] <math>P</math>, initially empty (equal to <math>1</math>) and a factor <m ...er [[Modular arithmetic|modulo]] another integer, in which the size of the partial products remains contained. Also, exponentiation by squaring can be effecti
    4 KB (657 words) - 11:07, 18 May 2022
  • ...of a cube is assigned the value of +1 or -1, and each face is assigned the product of the values assigned to each vertex. What values can the sum of the 14 nu ...nt in Argentina when I was in High School representing Puerto Rico. I got partial points because I probably missed one or two of the cases when I tried all o
    2 KB (284 words) - 08:40, 23 December 2023
  • \frac{\partial f \left( \theta ; x_C \right) }{\partial \theta} \bigg|_{\theta = 60^\circ} = 0 . Taking the derivative of the numerator using product rule:
    21 KB (3,507 words) - 17:06, 28 December 2024